Extract arguments - unix

Question

I am working on automating CUPS (Create user provided services) in Cloud Foundry. I have a cups.sh file which contains the corresponding cf cups commands to be executed for a particular application. Below is sample:
cf cups service-A -p '{"uri": "https://sample uri"}'
cf cups service-B -p '{"uri": "https://sample uri","id": "abcd","token": "xyz"}'
I am trying to write a script will perform below use case:
Parse the cups.sh, line by line and extract the service name (e.g. service-A) and the argument following -p (e.g: '{"uri": "https://sample uri","id": "abcd","token": "xyz"}').
I am currently using below script:
File=cups.sh
sed -e 's/[[:space:]]*#.*// ; /^[[:space:]]*$/d' "$File" | while read line
do
temp=$(echo $line | cut -d' ' -f4)
echo $temp
done
This is not accurate as it returns me "https://sample uri"}'. Is there a more accurate way of extracting the argument -p and using it for further operations?

Answer 1

Extract what we need:
$> sed -n -r '/^\s*cf\s+cups\s+.+.*-p\s+'"'"'.+'"'"'/{s/\s*cf\s+cups\s+(.+)\s.*-p\s+('"'"'.+'"'"').*$/\1 \2/;p}' cups.sh
service-A '{"uri": "https://sample uri"}'
service-B '{"uri": "https://sample uri","id": "abcd","token": "xyz"}'
Now, form commands to push all results into 2 arrays (_srv and _cmd):
$> sed -n -r '/^\s*cf\s+cups\s+.+.*-p\s+'"'"'.+'"'"'/{s/\s*cf\s+cups\s+(.+)\s.*-p\s+('"'"'.+'"'"').*$/_srv+=('"'"'\1'"'"') _cmd+=(\2)/;p}' cups.sh
_srv+=('service-A') _cmd+=('{"uri": "https://sample uri"}')
_srv+=('service-B') _cmd+=('{"uri": "https://sample uri","id": "abcd","token": "xyz"}')
Finally, put everything in a bash file
#!/bin/bash
_fil=cups.sh
_srv=()
_cmd=()
eval `sed -n -r '/^\s*cf\s+cups\s+.+.*-p\s+'"'"'.+'"'"'/{s/\s*cf\s+cups\s+(.+)\s.*-p\s+('"'"'.+'"'"').*$/_srv+=('"'"'\1'"'"') _cmd+=(\2)/;p}' "$_fil"`
# test
_len=${#_srv[#]}
for (( i=-1;++i<_len; )); do
echo ${_srv[$i]} ${_cmd[$i]}
done
^\s*cf\s+cups\s+: search for lines starting with cf cups ...
\s+(.+)\s: extract the third column (delimited by \s (spaces)) as \1
-p\s+('"'"'.+'"'"'): extract the stuff between '' right after -p as \2 ('' included)

Answer 2

Is this what you are looking for?
$ # only lines with successful substitutions will be printed
$ sed -n 's/.*service-A -p //p' ip.txt
'{"uri": "https://sample uri"}'
$ sed -n 's/.*service-B -p //p' ip.txt
'{"uri": "https://sample uri","id": "abcd","token": "xyz"}'
$ # to save results in variable
$ a=$(sed -n 's/.*service-A -p //p' ip.txt)
$ echo "$a"
'{"uri": "https://sample uri"}'
With awk
$ awk -F"'" -v sq="'" '/service-A/{print sq $2 sq}' ip.txt
'{"uri": "https://sample uri"}'
To pass search term as variable
$ st='service-A'
$ sed -n 's/.*'"$st"' -p //p' ip.txt
'{"uri": "https://sample uri"}'
$ awk -F"'" -v s="$st" -v sq="'" '$0 ~ s{print sq $2 sq}' ip.txt
'{"uri": "https://sample uri"}'