I have 30 columns, of which based on every distinct VEHICLE_ABBR, BLOCK_NO poulate Trip column based on Incresing order of DEPARTURE_TIME .
VEHICLE_ABBR BLOCK_NO DEPARTURE_TIME Trip
SXXB1410D 21,760,010 19,500 1
SXXB1410D 21,760,010 24,900 2
SXXB1410D 21,760,010 31,020 3
TXXB1102R 21,760,026 19,800 1
TXXB1102R 21,760,026 24,480 2
MXXB1410P 21,760,011 17,500 1
MXXB1410P 21,760,011 19,900 2
JXXB1102K 21,760,027 20,800 1
JXXB1102K 21,760,027 22,480 2
JXXB1102K 21,760,027 23,480 3
SELECT
BLOCK_NO
,VEHICLE_ABBR
,DEPARTURE_TIME
,SUM(CASE WHEN TRIP = 1 THEN 1 ELSE 0 END)
OVER (PARTITION BY BLOCK_NO,VEHICLE_ABBR ORDER BY DEPARTURE_TIME, TRIP ROWS UNBOUNDED PRECEDING) AS TRIP_NUM
FROM
(
SELECT
BLOCK_NO
,VEHICLE_ABBR
,DEPARTURE_TIME
,ROW_NUMBER() OVER (PARTITION BY BLOCK_NO,VEHICLE_ABBR,DEPARTURE_TIME ORDER BY DEPARTURE_TIME ) AS TRIP
FROM tab
) AS dt;
Related
I have 3 columns(CustomerId, Amount, ProcessDate) in a table (Customer).
Values are inserted daily in this table.
I want to get all the rows whose current day Amount is greater than previous day Amount.
CustomerId Amount Process_date
1 20 12/05/2021
2 30 12/05/2021
1 40 13/05/2021
2 25 13/05/2022
We have to print (1 40 13/05/2021) as 20 (previous day amount) is smaller than 40 (next day amount).
Query which I tried :-
select b.customerId, b.amount, b.process_date from customer a
join (select customerId, amount, process_date from customer where process_date = current_date ) as b
on
a.customerId = b.customerId and
a.process_date = current_date - 1 and a.amount < b.amount
I want to display the hourly based report for the last 24 hour. I have tried but the problem is that it will display count only where particular hour contains data.
But I want to display count for an hour and if count not found then display 0 over there.
select
datepart(hour, upload_date) as [hour], count(*)
from
tbl_stories
where
upload_date > getdate() - 1
group by
datepart(hour, upload_date)
Output:
hour count
-------------
11 2
16 1
17 1
but I want to get a record in the following way.
hour count
-------------
1 0
2 0
3 5
.
.
.
.
24 1
You can use a value() clause to generate all the hours and then use left join:
select v.hh, count(s.upload_date)
from (values (0), (1), . . . (23)
) v(hh) left join
tbl_stories s
on datepart(hour, s.upload_date) = v.hh and
s.upload_date > getdate() - 1
group by v.hh
order by v.hh;
Note that hours go from 0 to 23.
If you don't want to list out the hours, a convenient generation method is a recursive CTE:
with hours as (
select 1 as hh
union all
select hh + 1
from hours
where hh < 23
)
select h.hh, count(s.upload_date)
from hours h
tbl_stories s
on datepart(hour, s.upload_date) = h.hh and
s.upload_date > getdate() - 1
group by h.hh
order by h.hh;
I have gone through a similar post in Stack overflow...
but my query is :
If my table generates a flag in run time execution,then how can I increase Grp_number(generate run time) every time my flag changes.
my Oracle query:
Select emp_id,
Case when MOD(rownum/3)=1 and rownum>1 then 'Y' else 'N' as flag
from Transaction_table
Desired o/p Data format:
emp_id Flag GRP_number
1 N 1
2 N 1
3 N 1
4 Y 2
5 N 2
6 N 2
7 Y 3
You cannot reference a column in another column in the same select list. You need to use sub query to avoid INVALID IDENTIFIER error.
Do it like -
WITH DATA AS(
SELECT emp_id,
CASE
WHEN MOD(rownum/3)=1
AND rownum >1
THEN 'Y'
ELSE 'N' AS flag
FROM Transaction_table
)
SELECT emp_id, flag, SUM(gap) over (PARTITION BY person
ORDER BY DAY) grp
FROM(
SELECT emp_id, flag,
CASE WHEN flag = lag(flag) over (PARTITION BY person
ORDER BY DAY)
THEN 0
ELSE 1
END gap
FROM DATA)
I'm writing a query like this...
select to_char(e_date, 'MON/YYYY') as Month , location_code, count(employee_number) from...
Now I want to group by Month and Location_code. so how to use to_char(e_date, 'MON/YYYY') as Month in group by clause?
EDIT:
select to_char(vheda.e_date, 'MON/YYYY') as Months , hla.location_code, count(vheda.employee_number) emp_count from
virtu.virt_hr_emp_daily_attendance vheda
inner join per_all_people_f papf on vheda.party_id = papf.party_id
inner join per_all_assignments_f paaf on papf.person_id = paaf.person_id
inner join hr_locations_all hla on paaf.location_id = hla.location_id
where (trunc(sysdate) between PAPF.EFFECTIVE_START_DATE and PAPF.EFFECTIVE_END_DATE)
--and (vheda.e_in_time is not null)
and vheda.e_duration <> 0
and (trunc(sysdate) between PAAF.EFFECTIVE_START_DATE and PAAF.EFFECTIVE_END_DATE)
and vheda.e_date between '1-aug-2014' and '31-oct-2014'
group by hla.location_code, vheda.e_date
order by vheda.e_date
OUT PUT WHEN USE GROUP BY CLAUSE group by to_char(vheda.e_date, 'MON/YYYY'), hla.location_code:
ORA-00979: not a GROUP BY expression
00979. 00000 - "not a GROUP BY expression"
*Cause:
*Action:
Error at Line: 58 Column: 37
select to_char(e_date, 'MON/YYYY') as Month , location_code, count(employee_number)
from ...
group by to_char(e_date, 'MON/YYYY'), location_code
You need to group by To_char(vheda.e_date, 'MON/YYYY') and hla.location_code.
SELECT To_char(vheda.e_date, 'MON/YYYY') AS Months,
hla.location_code,
Count(vheda.employee_number) emp_count
FROM virtu.virt_hr_emp_daily_attendance vheda
inner join per_all_people_f papf
ON vheda.party_id = papf.party_id
inner join per_all_assignments_f paaf
ON papf.person_id = paaf.person_id
inner join hr_locations_all hla
ON paaf.location_id = hla.location_id
WHERE ( Trunc(SYSDATE) BETWEEN PAPF.effective_start_date AND
PAPF.effective_end_date )
--and (vheda.e_in_time is not null)
AND vheda.e_duration <> 0
AND ( Trunc(SYSDATE) BETWEEN PAAF.effective_start_date AND
PAAF.effective_end_date )
AND vheda.e_date BETWEEN '1-aug-2014' AND '31-oct-2014'
GROUP BY To_char(vheda.e_date, 'MON/YYYY'),
hla.location_code
ORDER BY vheda.e_date
For example, let's see the same with EMP table,
SQL> SELECT To_char(hiredate, 'MON/YYYY') AS Months,
2 deptno,
3 Count(empno) emp_count
4 FROM emp
5 GROUP BY To_char(hiredate, 'MON/YYYY'),
6 deptno
7 /
MONTHS DEPTNO EMP_COUNT
-------- ---------- ----------
DEC/1980 20 1
JUN/1981 10 1
NOV/1981 10 1
MAY/1987 20 1
FEB/1981 30 2
MAY/1981 30 1
DEC/1981 30 1
JAN/1982 10 1
SEP/1981 30 2
DEC/1981 20 1
APR/1981 20 1
APR/1987 20 1
12 rows selected.
SQL>
select EXTRACT(MONTH FROM e_date)||'/'|| EXTRACT(Year FROM e_date) as months , location_code, count(employee_number)
FROM ...
group by EXTRACT(MONTH FROM e_date)||'/'|| EXTRACT(Year FROM e_date), location_code
You can also use EXTRACT function in GROUP BY clause..
i hope it helps..
I have the records using the query
SELECT trunc(createdon,'hh') CREATEDON,count(*)
FROM WHERE LABSTATUS=1 AND
CREATEDON >=TO_DATE('01/07/2010 10','DD/MM/YYYY hh')
GROUP BY trunc(createdon,'hh')
in an hourly basis.. I need to place the count value in corresponding time column in the grid.
How can I do?? any idea
You can do it like this:
Hours are in columns
SELECT TRUNC(createdon,'hh'), SUM(CASE WHEN hh=1 THEN 1 ELSE 0) h1,
SUM(CASE WHEN hh=2 THEN 1 ELSE 0) h2 .....
FROM TABLle1,
(SELECT 1 AS hh FROM dual
UNION
SELECT 2 AS hh FROM dual
UNION
SELECT 3 AS hh FROM dual
....
) hours
WHERE LABSTATUS=1 AND CREATEDON >=TO_DATE('01/07/2010 10','DD/MM/YYYY hh') AND
TRUNC(createdon,'hh')= hours.hh
GROUP BY TRUNC(createdon,'hh')
Hours are in rows:
SELECT hours.hh, SUM(CASE WHEN TRUNC(createdon,'hh')= hours.hh THEN 1 ELSE 0 END) hh,
FROM TABLle1,
(SELECT 1 AS hh FROM dual
UNION
SELECT 2 AS hh FROM dual
UNION
SELECT 3 AS hh FROM dual
....
) hours
WHERE LABSTATUS=1 AND CREATEDON >=TO_DATE('01/07/2010 10','DD/MM/YYYY hh')
GROUP BY hours.hh
This query will result like this
row 1 12
row 2 0
row 3 4
...