How do i serialize a JSchema as part of another object? - json.net

Question

I have an object who as a property that is a Json Schema (JSchema).
JSchema aSchema;
object foo = new {propA = "x", schema = aSchema};
However, when this is serialized:
string str = JsonConvert.SerializeObject(foo);
The JSchema object is serialized along with all its other properties ... and not a clean Json Schema, like the output of its ToString() which just emits the Json Schema string.
What I want is the schema property serialized as a Json Schema object like this:
{
"propA": "x",
"schema": {
"id": "",
"description": "",
"definitions": {
"number": {
"type": "number"
},
"string": {
"type": "string"
}
},
"properties": {
"title": {
"title": "Title",
"type": "string"
}
}
}
}
How would you do this?

Answer 1

public class Number
{
public string type { get; set; }
}
public class String
{
public string type { get; set; }
}
public class Definitions
{
public Number number { get; set; }
public String #string { get; set; }
}
public class Title
{
public string title { get; set; }
public string type { get; set; }
}
public class Properties
{
public Title title { get; set; }
}
public class Schema
{
public string id { get; set; }
public string description { get; set; }
public Definitions definitions { get; set; }
public Properties properties { get; set; }
}
public class RootObject
{
public string propA { get; set; }
public Schema schema { get; set; }
}
Serialize method
dynamic coll = new
{
Root = new RootObject()
{
propA = "x",
schema = new Schema
{
id = "",
description = "",
definitions = new Definitions()
{
number = new Number()
{
type = "number"
},
#string = new String()
{
type = "number"
}
},
properties = new Properties ()
{
title = new Title ()
{
title = "Title",
type = "string"
}
}
}
}
};
var output = JsonConvert.SerializeObject(coll);
Fiddler: https://dotnetfiddle.net/f2wG2G
Update
var jsonSchemaGenerator = new JsonSchemaGenerator();
var myType = typeof(RootObject);
var schema = jsonSchemaGenerator.Generate(myType);
schema.Id = "";
schema.Description = "";
schema.Title = myType.Name;
Fiddler: https://dotnetfiddle.net/FwJX69