I am trying to implement a function printGreater() that takes a list of numbers and a numeric value as parameter. It prints the numbers in the list that are greater than the value, all on one line with a space between them. If an empty list is provided as the first parameter, the function doesn't print anything.
This is what I have so far:
def printGreater(nums, value):
lstN = (int[nums],value)
if nums > value:
print(nums, end=", ")
def printGreater(nums, value):
#First create an empty list to hold onto all the numbers larger than value
greater = [];
#Loop overall the input values, saving all large ones
for num in nums:
if num > value:
#Convert to a string for printing
greater.append(str(num))
#Print them out with spaces in between
print( ' '.join(greater) )
#Then test with this
printGreater([1, 2, 3, 4, 5, 6, 7], 3)
Here, you'll want to use a for loop. I'll place the code, then explain what's going on.
def print_greater(nums_list, value):
string = ''
for num in nums_list:
if num > value:
string += str(num) + ' '
return string
First, I'm initializing a new string variable:
string = ''
Next, I start an iteration loop:
for num in nums_list:
...
What that iteration (for) loop is going to do, is to start with the first item in a list a give it, and make that item 'num'. Then I can do whatever I want with that item. Once I'm finished, it will move on to the second item, and so on.
if num > value:
string += str(num) + ' '
In this case, I want to compare num to value. If num is great, I want to add onto the string I initialized earlier. That's what the += means...
string += str(num) + ' '
is the same as
string = string + str(num) + ' '
Finally, at the end, I return the string.
Hope that helps!
Related
for my code I want all numbers from a dictionary under 70 to be deleted, I'm unsure of how to specify this and I need it to also delete the associated name with that number as well, either that or only diplay numbers that are 70 or above.
Below is the code that I have in it's entirety:
name = []
number =[]
name_grade = {}
counter = 0
counter_bool= True
num_loop = True
while counter_bool:
stu = int(input("please enter the number of students: "))
if stu < 2:
print("value is too low, try again")
continue
else:
break
while counter != stu:
name_inp = str(input("Enter your name: "))
while num_loop:
number_inp = int(input("Enter your number: "))
if number_inp < 0 or number_inp > 100:
print("The value is too high or too low, please enter a number between 0 and 100.")
continue
else:
break
name_grade[name_inp] = number_inp
name.append(name_inp)
number.append(number_inp)
counter += 1
print(name_grade)
sorted_numbers = sorted(name_grade.items(), key= lambda x:x[1])
print(sorted_numbers)
if number > 70:
resorted_numbers = number < 70
print(resorted numbers)
how would I go about this?
Also if it's also not too much trouble could someone explain in detail about dictionary keys and how the lambda function I've used works? I got help but I would prefer to know the small details on how it's applied and formatted but don't worry if it's a pain to explain.
You can just iterate over the dictionary and filter for values less than 70:
resorted_numbers = {k:v for k,v in name_grade.items() if v<70}
dict.items method returns a list of key-value tuple pairs of a dictionary, so the lambda function is telling the sorted function to sort by the second element in each tuple.
How can I access the name property of a ProtoField after I declare it?
For example, something along the lines of:
myproto = Proto("myproto", "My Proto")
myproto.fields.foo = ProtoField.int8("myproto.foo", "Foo", base.DEC)
print(myproto.fields.foo.name)
Where I get the output:
Foo
An alternate method that's a bit more terse:
local fieldString = tostring(field)
local i, j = string.find(fieldString, ": .* myproto")
print(string.sub(fieldString, i + 2, j - (1 + string.len("myproto")))
EDIT: Or an even simpler solution that works for any protocol:
local fieldString = tostring(field)
local i, j = string.find(fieldString, ": .* ")
print(string.sub(fieldString, i + 2, j - 1))
Of course the 2nd method only works as long as there are no spaces in the field name. Since that's not necessarily always going to be the case, the 1st method is more robust. Here is the 1st method wrapped up in a function that ought to be usable by any dissector:
-- The field is the field whose name you want to print.
-- The proto is the name of the relevant protocol
function printFieldName(field, protoStr)
local fieldString = tostring(field)
local i, j = string.find(fieldString, ": .* " .. protoStr)
print(string.sub(fieldString, i + 2, j - (1 + string.len(protoStr)))
end
... and here it is in use:
printFieldName(myproto.fields.foo, "myproto")
printFieldName(someproto.fields.bar, "someproto")
Ok, this is janky, and certainly not the 'right' way to do it, but it seems to work.
I discovered this after looking at the output of
print(tostring(myproto.fields.foo))
This seems to spit out the value of each of the members of ProtoField, but I couldn't figure out the correct way to access them. So, instead, I decided to parse the string. This function will return 'Foo', but could be adapted to return the other fields as well.
function getname(field)
--First, convert the field into a string
--this is going to result in a long string with
--a bunch of info we dont need
local fieldString= tostring(field)
-- fieldString looks like:
-- ProtoField(188403): Foo myproto.foo base.DEC 0000000000000000 00000000 (null)
--Split the string on '.' characters
a,b=fieldString:match"([^.]*).(.*)"
--Split the first half of the previous result (a) on ':' characters
a,b=a:match"([^.]*):(.*)"
--At this point, b will equal " Foo myproto"
--and we want to strip out that abreviation "abvr" part
--Count the number of times spaces occur in the string
local spaceCount = select(2, string.gsub(b, " ", ""))
--Declare a counter
local counter = 0
--Declare the name we are going to return
local constructedName = ''
--Step though each word in (b) separated by spaces
for word in b:gmatch("%w+") do
--If we hav reached the last space, go ahead and return
if counter == spaceCount-1 then
return constructedName
end
--Add the current word to our name
constructedName = constructedName .. word .. " "
--Increment counter
counter = counter+1
end
end
I need to get a 4/5 digit number which always comes directly after a #
For example it'll be "Item Title (#1234)" however it's not always in the same place or at the end.
Not sure how I go about doing that
You need to manually parse the string.
I've made a quick function for this:
'//return the number after delimeter string, if exists (first occurance only)
'//in case no number exists, returns Empty value
Function FindNumberAfter(rawValue, delimeterString)
Dim index, x, curChar
Dim sBuffer
FindNumberAfter = vbEmpty
index = InStr(rawValue, delimeterString)
If index>0 Then
For x=index+Len(delimeterString) To Len(rawValue)
curChar = Mid(rawValue, x, 1)
If IsNumeric(curChar) Then
sBuffer = sBuffer & curChar
Else
Exit For
End If
Next
If Len(sBuffer)>0 Then FindNumberAfter = CLng(sBuffer)
End If
End Function
Usage in your case:
Response.Write(FindNumberAfter("Item Title (#1234)", "#"))
I'm failing the last test case, which is the one with the spaces and single quotation mark.
I used s.strip, but the error still persists.
Is there another way to go about this?
Thank you.
from test import testEqual
def removeWhite(s):
s.strip()
s.strip("'")
return s
def isPal(s):
if s == "" or len(s) == 1:
return True
if removeWhite(s[0]) != removeWhite(s[-1]):
return False
return isPal(removeWhite(s[1:-1]))
testEqual(isPal(removeWhite("x")),True)
testEqual(isPal(removeWhite("radar")),True)
testEqual(isPal(removeWhite("hello")),False)
testEqual(isPal(removeWhite("")),True)
testEqual(isPal(removeWhite("hannah")),True)
testEqual(isPal(removeWhite("madam i'm adam")),True)
At first your removeWhite function doesn't return all spaces because strip only removes from the end and the beginning of a string. See:
>>> " a ".strip()
'a'
>>> " a a ".strip()
'a a'
So i suggest this approach:
def removeWhite(s):
return ''.join(filter(lambda x: x not in " '", s))
Please note that I use join because filter returns an iterator which needs to be converted back to a string.
For finding the palindromes i would suggest this function:
def isPal(s):
if len(s) <= 1: # Special case to prevent KeyError later
return True
stripped = removeWhite(s) # Strip off all whitespaces
first = stripped[:len(stripped) // 2] # First half of the string
if len(stripped) % 2: # Length of string is even?
second = stripped[len(stripped) // 2 + 1:] # Drop the middle character
else:
second = stripped[len(stripped) // 2:] # Else keep it
secondrev = ''.join(reversed(second)) # Reverse the second half
return first == secondrev # And return wether they're equal.
This holds for all your examples. But it think your isPal function should work too if you fix your removeWhite function
I am working in classic ASP; using getRows to get multidimension array of rows and column.
while iterating a row; I want to pass that single row into another function to build the column layout.
with C# I can do this:
obj[][] multiDimArray = FunctionCall_To_InitializeArray_4X16();
for (int rowId = 0 ; rowId < 4 ; rowId++)
{
FunctionCall_to_ProcessSingleRow(multiDimArray[rowId][]);
//this function only accept single dimension array
}
How can I do this is asp classic/vbscript:
1. I have a function that accept single dimension array as parameter.
2. Call that function and pass 1 part of 2 dimension array.
Thank you
I think you will need to populate a new array or dictionary object with the single dimension you want to process.
here a piece from working code, should get you going..
aResults = oRst.Getrows
oRst.Close
Set oRst = Nothing
Call SubCloseDatabaseOracle
iRows = UBound(aResults, 2)
iCols = UBound(aResults, 1)
row = 1 'first row
line = ""
separator = ""
FOR col = 0 TO iCols
line = line & separator & cStr(aResults(col,row))
separator = ";"
NEXT
aSingleDimensionArray = split(line,";")