I want to calculate the business days for 3 columns with respective columns.
Eg:
REC_ENTER_BUSS_DAY will calculate the business day between REC_CREATED_DATE and ENTER_DATE.
REC_SCAN_BUSS_DAY will calculate between REC_CREATED_DATE and SCAN_DT
INDX_BUS_DAY between REC_CREATED_DATE and INDX_DT.
I have calendar table having business day indicator BUS_DT_IND='Y' and 'N'.
I want output for all three port at a time.
Any one help me out with query.
Select A.REC_ENTR_B_DY
, B.REC_SCAN_B_DY
, C.INDX_B_DY
from (select ENTR_DT
, REC_CREATED_DT
, SUM(WHEN BUS_DT_IND='Y' then 1 else 0) as REC_ENTR_B_DY
from RECORD
join calendar
on calendar.Calendar_date between ENTR_DT and REC_CREATED_DT
group by 1,2) A
LEFT JOIN (select SCAN_DT
, REC_CREATED_DT
, SUM(WHEN BUS_DT_IND='Y' then 1 else 0) as REC_SCAN_B_DY
from RECORD
join calendar on calendar.Calendar_date between SCAN_DT and REC_CREATED_DT
group by 1,2) B
on A.REC_CREATED_DT=B.REC_CREATED_DT
LEFT JOIN (select INDX_DT
, REC_CREATED_DT
, SUM(WHEN BUS_DT_IND='Y' then 1 else 0) as REC_SCAN_B_DY
from RECORD
join calendar
on calendar.Calendar_date between INDX_DT and REC_CREATED_DT
group by 1,2)C
on A.REC_CREATED_DT=C.REC_CREATED_DT
Related
I'm very new to learning SQL, I apologize if my question isn't completely accurate.
The question I'm trying to answer with this query is "What is the most popular music genre in each country?" I've had to use a subquery and it works, but I found that for a few countries in the table, more than one genre has the MAX value. I'm stuck with how to edit my query so that all genres with the max value show in the results. Here is my code, using DB Browser for SQLite:
SELECT BillingCountry AS Country , name AS Genre , MAX(genre_count) AS Purchases
FROM (
SELECT i.BillingCountry, g.name, COUNT(g.genreid) AS genre_count
FROM Invoice i
JOIN InvoiceLine il
ON il.InvoiceId = i.InvoiceId
JOIN TRACK t
ON il.trackid = t.TrackId
JOIN Genre g
ON t.genreid = g.GenreId
GROUP BY 1,2
) sub
GROUP BY 1
Here is an example of the result:
| Country | Genre |Purchase|
|---------|-------|--------|
|Agrentina| Punk | 9 |
|Australia| Rock | 22 |
BUT in running just the subquery to COUNT the purchases, Argentina has two Genres with 9 Purchases (the max number for that country). How do I adjust my query to include both and not just the first one in the row?
You can do it with RANK() window function:
SELECT BillingCountry, name, genre_count
FROM (
SELECT i.BillingCountry, g.name, COUNT(*) AS genre_count,
RANK() OVER (PARTITION BY i.BillingCountry ORDER BY COUNT(*) DESC) rnk
FROM Invoice i
INNER JOIN InvoiceLine il ON il.InvoiceId = i.InvoiceId
INNER JOIN TRACK t ON il.trackid = t.TrackId
INNER JOIN Genre g ON t.genreid = g.GenreId
GROUP BY i.BillingCountry, g.name
)
WHERE rnk = 1
This will return the ties in separate rows.
If you want 1 row for each country, you could also use GROUP_CONCAT():
SELECT BillingCountry, GROUP_CONCAT(name) AS name, MAX(genre_count) AS genre_count
FROM (
SELECT i.BillingCountry, g.name, COUNT(*) AS genre_count,
RANK() OVER (PARTITION BY i.BillingCountry ORDER BY COUNT(*) DESC) rnk
FROM Invoice i
INNER JOIN InvoiceLine il ON il.InvoiceId = i.InvoiceId
INNER JOIN TRACK t ON il.trackid = t.TrackId
INNER JOIN Genre g ON t.genreid = g.GenreId
GROUP BY i.BillingCountry, g.name
)
WHERE rnk = 1
GROUP BY BillingCountry
I'm trying to combine 3 different tables into one with certain criteria.
Table 2 - Calculate the Total Weight of the shipments base on Shipper Number and Ship Date
Table 3 - Calaculate the Total Revenue Amount base on Shipper Number and Ship Date
Result - Combined the tables into a single table.
Additionally, the SQL should also filter for "Customer Since" <= 720 and "Ship Date" <= 360
(Note: Customer Number = Shipper Number)
It's difficult to tell what you're looking for, but this could get you started
SELECT t2.Shipper_Number, t2.Ship_Date, t2.Total_Weight, t3.Total_Revenue
FROM (
SELECT Shipper_Number, Ship_Date, SUM(Weight) AS Total_Weight
FROM Table2
GROUP BY Shipper_Number, Ship_Date
) t2
INNER JOIN (
SELECT Shipper_Number, Ship_Date, SUM(Revenue) AS Total_Revenue
FROM Table3
GROUP BY Shipper_Number, Ship_Date
) t3 ON t2.<PK_column> = t3.<PK_column>
A few notes:
INNER JOIN will only return rows that match in both tables
You can add your "Customer Since" and "Ship Date" restrictions as WHERE clauses in the sub-queries
Update
If you want to get one row per (Shipper_Number, Ship_Date) group, then you need to make your JOIN condition for those two derived tables using that column combination (Shipper_Number, Ship_Date).
And if you want to further filter your rows on "Customer Since", then just JOIN to the source table and add the filtering condition. Something like this:
SELECT t2.Shipper_Number, t2.Ship_Date, t2.Total_Weight, t3.Total_Revenue
FROM (
SELECT Shipper_Number, Ship_Date, SUM(Weight) AS Total_Weight
FROM Table2
WHERE Ship_Date <= Ship_Date - INTERVAL '360' DAY -- Assumes you want only order that shipped within the last 360 days
GROUP BY Shipper_Number, Ship_Date
) t2
INNER JOIN (
SELECT Shipper_Number, Ship_Date, SUM(Revenue) AS Total_Revenue
FROM Table3
WHERE Ship_Date <= Ship_Date - INTERVAL '360' DAY -- Assumes you want only order that shipped within the last 360 days
GROUP BY Shipper_Number, Ship_Date
) t3 ON t2.Shipper_Number = t3.Shipper_Number AND t2.Ship_Date = t3.Ship_Date
INNER JOIN Table1 t1 ON t2.Shipper_Number = t1.Customer_Number -- Get shipper/customer info
WHERE t1."Customer Since" <= "Customer Since" - INTERVAL '720' DAY -- Assuming you want to get customers that are fewer than 720 days old
Again, using an INNER JOIN, this assumes that matching rows exist in both tables for (Shipper_Number and Ship_Date), otherwise it won't return that row.
Also, if feasible, you may want to consider combining your t2 and t3 tables into a single table based on a common key (shipper_number, shipping_number) or just shipping_number if it's a unique value.
The task is to get know how much money player earned during the year.
So I want to write a select where by the known player_id I will aggregate his total win like.
FIRST_PLAYER_ID is an id of player who got the first place and FIRST_PRICE accordingly.
What I need:
player_id | total_prize_sum_over_all_tournaments_played_by_him
Code i tried so far:
SELECT PLAYER.SUNAME, TOURNAMENT.NAME FROM PLAYER
JOIN TOURNAMENT
ON PLAYER.ID = TOURNAMENT.FIRST_PLAYER_ID
OR PLAYER.ID = TOURNAMENT.SECOND_PLAYER_ID
OR PLAYER.ID = TOURNAMENT.THIRD_PLAYER_ID
ORDER BY PLAYER.BIRTH_DATE
Also, please help me to name this question correctly.
The following sql statement aggregates the prize money won by each player. The idea is to aggregate by each rank individually, summing up the results for each player afterwards.
SELECT pt.p_id
, SUM(pt.tl)
FROM (
SELECT p.p_id
, sum(t.first_prize) tl
FROM player p
JOIN tournament t on ( t.first_player_id = p.p_id )
GROUP BY p.p_id
UNION ALL
SELECT p.p_id
, sum(t.second_prize) tl
FROM player p
JOIN tournament t on ( t.second_player_id = p.p_id )
GROUP BY p.p_id
UNION ALL
SELECT p.p_id
, sum(t.third_prize) tl
FROM player p
JOIN tournament t on ( t.third_player_id = p.p_id )
GROUP BY p.p_id
) pt
GROUP BY pt.p_id
;
This sql fiddle is a full-fledged example (with restricted table definitons).
I'm looking to improve this query I wrote for a small web application in ASP.NET 4.0 using SQL-Server 2005. This application will allow the user to search by Product ID and have it return the following information:
Highest Purchase Price + Most Recent Date of purchase # this price
Lowest Purchase Price + Most Recent Date of purchase # this price
Most Recent Purchase Price + Date
Average Purchase Price (optional, i thought this might improve the usefulness of the app)
Here is the structure of the Products table (I'm only including relevant columns, this is a DB already in production and these are non-pk columns)
product_id (nvarchar(20))
price (decimal(19,2))
pDate (datetime)
Before I put down the query I have so far I just want to say that I can get this information easily through multiple queries, so if this is the best practice then disregard improving the query, but I was aiming to minimize the number of queries needed to get all needed information.
What I have so far: (Note: There are rows with price = 0 so I ignored those in the bottom select looking for the MIN price)
SELECT price, MAX(pDate)
FROM Products
WHERE product_id = #product_id AND
(price = (SELECT MAX(price)
FROM Products
WHERE product_id =#product_id) OR
price = (SELECT MIN(price)
FROM Products
WHERE product_id = #product_id AND price > 0))
GROUP BY price
Now this is returning 2 rows:
first = the lowest price + date
second row = high price + date
What I would like ideally is to have a query return 1 row with all the needed information stated above if possible, as it would simplify displaying the information in ASP for me. And like I said earlier, if multiple queries is the be approach then no need to re-write a complex query here.
Edit
Here is some sample data
Desired query results: (ignore the format as I typed this in excel)
Here is the query I will be using thanks to Ken Benson:
SELECT TOP 1 prod.product_id,
minp.price AS minprice, minp.pDate as minlastdate,
maxp.price AS maxprice, maxp.pDate as maxlastdate,
ag.price AS averageprice
FROM products AS prod
LEFT JOIN (SELECT lmd.product_id,max(lmd.pDate) as pDate,mn.price FROM products as lmd INNER JOIN
(SELECT product_id, min(price) AS price from products WHERE price > 0 group by product_id) as mn ON lmd.product_id=mn.product_id AND lmd.price=mn.price
group by lmd.product_id,mn.price ) AS minp ON minp.product_id=prod.product_id
LEFT JOIN (SELECT lxd.product_id,max(lxd.pDate) as pDate,mx.price FROM products as lxd INNER JOIN
(SELECT product_id, max(price) AS price from products group by product_id) as mx ON lxd.product_id=mx.product_id AND lxd.price=mx.price
group by lxd.product_id,mx.price ) AS maxp ON maxp.product_id=prod.product_id
LEFT JOIN (SELECT product_id,avg(price) as price FROM products WHERE price > 0 GROUP BY product_id) AS ag ON ag.product_id=prod.product_id
WHERE prod.product_id=#product_id
I think you can do a couple of joins back to the table ...
Select product_id, min.price, min.pDate, max.price, max.pDate
FROM products as p
LEFT JOIN (Select Min(price), pDate, product_id FROM products GROUP BY product_id)
as min on min.product_id=p.product_id
LEFT JOIN (Select max(price), pDate, product_id FROM products GROUP BY product_id)
as max on max.product_id=p.product_id
Where p.product_id = #product_id
This second bit of code should produce desired results....
SELECT prod.product_id,
minp.price AS minprice, minp.pDate as minlastdate,
maxp.price AS maxprice, maxp.pDate as maxlastdate,
ag.price AS averageprice
FROM products AS prod
LEFT JOIN (SELECT lmd.product_id,max(lmd.pDate) as pDate,mn.price FROM products as lmd INNER JOIN
(SELECT product_id, min(price) AS price from products group by product_id) as mn ON lmd.product_id=mn.product_id
group by lmd.product_id,mn.price ) AS minp ON minp.product_id=prod.product_id
LEFT JOIN (SELECT lxd.product_id,max(lxd.pDate) as pDate,mx.price FROM products as lxd INNER JOIN
(SELECT product_id, max(price) AS price from products group by product_id) as mx ON lxd.product_id=mx.product_id
group by lxd.product_id,mx.price ) AS maxp ON maxp.product_id=prod.product_id
LEFT JOIN (SELECT product_id,avg(price) as price FROM products GROUP BY product_id) AS ag ON ag.product_id=prod.product_id
WHERE prod.product_id=1
LIMIT 1
Yep - left out an 'and' condition:
SELECT TOP 1
prod.product_id,
minp.price AS minprice, minp.pDate as minlastdate,
maxp.price AS maxprice, maxp.pDate as maxlastdate,
ag.price AS averageprice
FROM products AS prod
LEFT JOIN (SELECT lmd.product_id,max(lmd.pDate) as pDate,mn.price FROM products as lmd INNER JOIN
(SELECT product_id, min(price) AS price from products group by product_id) as mn ON lmd.product_id=mn.product_id **AND lmd.price=mn.price**
group by lmd.product_id,mn.price ) AS minp ON minp.product_id=prod.product_id
LEFT JOIN (SELECT lxd.product_id,max(lxd.pDate) as pDate,mx.price FROM products as lxd INNER JOIN
(SELECT product_id, max(price) AS price from products group by product_id) as mx ON lxd.product_id=mx.product_id AND **lxd.price=mx.price**
group by lxd.product_id,mx.price ) AS maxp ON maxp.product_id=prod.product_id
LEFT JOIN (SELECT product_id,avg(price) as price FROM products GROUP BY product_id) AS ag ON ag.product_id=prod.product_id
WHERE prod.product_id=#product_id
I would do this with a combination of ranking functions and conditional aggregations:
select product_id,
max(case when seqnum_hi = 1 then price end) as highPrice,
max(case when seqnum_hi = 1 then pdate end) as highPrice_date
max(case when seqnum_low = 1 then price end) as lowPrice,
max(case when seqnum_low = 1 then pdate end) as lowPrice_date,
max(case when seqnum_rec = 1 then price end) as recentPrice,
max(case when seqnum_rec = 1 then pdate end) as recentPrice_date,
avg(price) as avg_price
from (select p.*,
row_number() over (partition by product_id order by price asc) as seqnum_low,
row_number() over (partition by product_id order by price desc) as seqnum_hi,
row_number() over (partition by product_id order by pdate desc) as seqnum_rec
from price
where product_id = #product_id
group by product_id
The seguence numbers identify the rows with the particular attributes you care about (high price, low price, most recent). The conditional max then just selects information from those rows.
The following should get what you want. It's pretty long, but is readable so should be easily modified by anyone who needs to:
;WITH CTE_MaxPrice AS
(
SELECT product_id, MAX(P.price) AS MaxPrice
FROM Products P
GROUP BY product_id
HAVING product_id = #product_id
),
CTE_MinPrice AS
(
SELECT product_id, MIN(P.price) AS MinPrice
FROM Products P
GROUP BY product_id
HAVING product_id = #product_id
),
CTE_MaxPriceDate AS
(
SELECT P.product_id, MAX(P.pDate) AS MaxDate
FROM Products P
INNER JOIN CTE_MaxPrice MaxP ON P.product_id = MaxP.product_id
AND P.price = MaxP.MaxPrice
GROUP BY P.product_id
),
CTE_MinPriceDate AS
(
SELECT P.product_id, MAX(P.pDate) AS MinDate
FROM Products P
INNER JOIN CTE_MinPrice MinP ON P.product_id = MinP.product_id
AND P.price = MinP.MinPrice
GROUP BY P.product_id
)
SELECT MaxP.MaxPrice, MaxPD.MaxDate,
MinP.MinPrice, MinPD.MinDate,
RP.price AS RecentPrice, MAX(RP.pDate) AS RecentDate,
AVG(AP.price) AS AveragePrice
FROM Products P
INNER JOIN CTE_MaxPrice MaxP ON P.product_id = MaxP.product_id
INNER JOIN CTE_MinPrice MinP ON P.product_id = MinP.product_id
AND MinP.MinPrice > 0
INNER JOIN CTE_MaxPriceDate MaxPD ON P.product_id = MaxPD.product_id
INNER JOIN CTE_MinPriceDate MinPD ON P.product_id = MinPD.product_id
INNER JOIN Products RP ON P.product_id = RP.product_id
INNER JOIN Products AP ON P.product_id = AP.product_id
GROUP BY MaxP.MaxPrice, MaxPD.MaxDate,
MinP.MinPrice, MinPD.MinDate, RP.price
HAVING P.product_id = #product_id
Well since there have been three attempts to answer, and none have worked quite how you want, I'll tell you how I would do it - and this assumes you can use a stored procedure and also assumes that the product table is not so huge that multiple seperate queries would be a problem:
CREATE PROCEDURE myproc AS
DECLARE #Price1 money
DECLARE #Date1 smalldatetime
DECLARE #Price2 money
DECLARE #Date2 smalldatetime
DECLARE #Price3 money
DECLARE #Date3 smalldatetime
DECLARE #Price4 money
SELECT #Price1 = MAX(Price) FROM Products
SELECT #Date1 = MAX(pDate) FROM Products WHERE Price=#Price1
SELECT #Price2 = Min(Price) FROM Products WHERE Price >0
SELECT #Date2 = MAX(pDate) FROM Products WHERE Price=#Price2
SELECT #Date3 = Max(pDate) FROM Products
SELECT #Price3 = MAX(Price) FROM Products WHERE pDate=#Date3 --max in case there are more than one purchases with the same date.
SELECT #Price4 = AVG(Price) FROM Products WHERE Price>0
SELECT #Price1 As MaxPrice,
#Date1 As MaxPriceDate,
#Price2 As LowPrice,
#Date2 As LowPriceDate,
#Price4 As AveragePrice,
#Price3 As RecentPrice,
#Price3 As RecentPriceDate
GO
Forgive any typographical errors, I didn't test this, but if you can use stored procedures, this will work.
So this is not much different than doing your multiple queries from the client, but should perform better putting them all into a single SP. You could also cut the number of queries down a bit by using some of the code from your other answers, but I have left it this way for clarity.
My table contains pk_id,reviewer_id,rating.
There are 4 type of rating.
1-very good.
2-good.
3-bad.
4-very bad.
I want to calculate how much rating given by each reviewer.
Means:
If Akee having id 200 has given 2 very good,4 good,3 bad and zero very bad rating to different code.
I want result
count--- rate
2---------1
4---------2
3---------3
0---------4
My query is
SELECT COUNT(RATE),RATE
FROM CODE_REVIEW WHERE CODE_REVIEWER_ID= 200
GROUP BY RATE;
It is showing result
count--- rate
2---------1
4---------2
3---------3
I want to show the fourth row that is 4 rating zero.
How can it be done??
If Rate is not the primary key in another table then you need define your own list of rates so MySQL knows what the permutations of rate are:
SELECT Rates.Rate,
COUNT(Code_Review.Rate) AS CountOfRate
FROM ( SELECT 1 AS Rate UNION ALL
SELECT 2 AS Rate UNION ALL
SELECT 3 AS Rate UNION ALL
SELECT 4
) AS Rates
LEFT JOIN Code_Review
ON Code_Review.Rate = Rates.Rate
AND CODE_REVIEWER_ID = 200
GROUP BY Rates.Rate
Try this query:
SELECT coalesce(c.cnt, 0), r.rate
FROM (SELECT 1 AS rate UNION ALL SELECT 2
UNION ALL SELECT 3 UNION ALL SELECT 4) AS r
LEFT JOIN (SELECT COUNT(RATE),RATE
FROM CODE_REVIEW WHERE CODE_REVIEWER_ID= 200
GROUP BY RATE) AS c
ON r.rate = c.rate;
The first subquery creates a list of possible rates. You can avoid it if you have a table which defines all rates;
Second subquery is yours;
LEFT JOIN guarantees that all rates will be shown;
coalesce() is needed to convert NULL into 0.
Assuming that you do not have a separate table where the rates are defined.
SElECT * from (
SELECT distinct(m.rate), countrate from code_review m
LEFT JOIN
(SELECT COUNT(rate) as countrate,rate FROM code_review
WHERE code_reviewer_id=200 GROUP BY rate) t
ON m.rate=t.rate) a
You could do it somthing like this
SELECT
rates.RATE
, SUM(COUNT) COUNT
FROM
(
SELECT 1 RATE, 0 COUNT UNION ALL
SELECT 2 RATE, 0 COUNT UNION ALL
SELECT 3 RATE, 0 COUNT UNION ALL
SELECT 4 RATE, 0 COUNT
) Rates
LEFT JOIN
(
SELECT
RATE
, COUNT(RATE) COUNT
FROM
CODE_REVIEW
WHERE
CODE_REVIEWER_ID= 200
GROUP BY RATE
) Ratings200
ON Ratings200.RATE = Rates.RATE
If you can, you should push to try to get it in column format as it is simple as:
SELECT
SUM(rate = 1) AS 1,
SUM(rate = 2) AS 2,
SUM(rate = 3) AS 3,
SUM(rate = 4) AS 4
FROM
code_review
WHERE
code_reviewer_id = 200
But if you really need a row format, you could do:
SELECT
a.rate,
COUNT(b.rate) AS cnt
FROM
(
SELECT 1 AS rate UNION ALL
SELECT 2 AS rate UNION ALL
SELECT 3 AS rate UNION ALL
SELECT 4 AS rate
) a
LEFT JOIN
code_review b ON a.rate = b.rate AND code_reviewer_id = 200
GROUP BY
a.rate
SELECT
Rate,
totCount
FROM
(
Select
Rate,
count(Rate) as totCount
from
Code_Review
where
CODE_REVIEWER_ID = 200
group by
Rate
union
select 4, 0
union
select 3, 0
union
select 2, 0
union
select 1, 0
) AS T
group by
T.Rate