I tried to search but I have not found anything. I am trying to add two columns to a table withe a default value (Teradata). I am trying with this statement
ALTER TABLE TEST
add (DWH_Change_dt date default CURRENT_DATE, dwh_create_dt date default current_date);
This does not work with default clause. I get this error
Syntax error, expected something like a 'BETWEEN' keyword or an 'IN' keyword or a 'LIKE' keyword or a 'CONTAINS' keyword between the word 'DWH_Change_dt' and the 'date'
If I add one column at a time it works (without parenthesis). Anyone has any idea? What is wrong?
Thanks,
Umberto
If you want to add multiple columns you need multiple ADDs:
ALTER TABLE TEST
add DWH_Change_dt date default CURRENT_DATE,
add dwh_create_dt date default current_date;
Related
I am a completely new to SQL and I am follow a tutorial verbatim to try and create a new table in my first database. However I am getting the following error.
USE menu;
CREATE TABLE Burgers
(
`Burger Number` TINYINT,
Burger VARCHAR(50),
Price DECIMAL(5,2),
Description VARCHAR(300),
);
Yields SQL Error 1064:
SQL Error (1064): You have an errror in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near ')' at line 8
I made sure to use commas to separate each column and used parenthesis to what I understand is the proper way to do so. I am not sure if version is relevant but I am using version 10.5.8 of MariaDB. Any insight is appreciated!
You have one comma too many.
...
Description VARCHAR(300),
);
You need commas between each column, index, or constraint within the CREATE TABLE statement, except for the last one before the closing parenthesis.
It should be like this:
...
Description VARCHAR(300)
);
General tip about syntax errors: They tell you exactly where to look for the problem, because it reports the place in your SQL statement where the syntax parser got confused.
In this case it reported:
...right syntax to use near ')' at line 8
This tells you the problem is at that point in the syntax. The ) didn't belong there, because the syntax was expecting something else. Because commas separate columns, it was expecting another column definition following a comma.
My data is string like:
'湯姆 is a boy.'
or '梅isagirl.'
or '約翰,is,a,boy.'.
And I want to split the string and only choose the Chinese name.
In R, I can use the command
tmp=strsplit(string,[A-z% ])
unlist(lapply(tmp,function(x)x[1]))
And then getting the Chinese name I want.
But in PostgreSQL
select regexp_split_to_array(string,'[A-z% ]') from db.table
I get a array like {'湯姆','','',''},{'梅','','',''},...
And I don't know how to choose the item in the array.
I try to use the command
select regexp_split_to_array(string,'[A-z% ]')[1] from db.table
and I get an error.
I don't think that regexp_split_to_array is the appropriate function for what you are trying to do here. Instead, use regexp_replace to selectively remove all ASCII characters:
SELECT string, regexp_replace(string, '[[:ascii:]~:;,"]+', '', 'g') AS name
FROM yourTable;
Demo
Note that you might have to adjust the set of characters to be removed, depending on what other non Chinese characters you expect to have in the string column. This answer gives you a general suggestion for how you might proceed here.
I have a two tables in first table i filled the values with name id,
on second table if i gave the id the table needs to fill the name automatically, how can i do this please help.
You commented that the error is in the following line:
axsl.TransDate = DateTimeUtil::utcNow();
This is logic because axsl.TransDate is Date and DateTimeUtil::utcNow() return a UtcDateTime when you compile get this error Operand types are not compatible with the operator.
There are many ways to fix this error.
Try this:
axsl.TransDate = DateTimeUtil::date(DateTimeUtil::utcNow())
DateTimeUtil::date() convert UtcDateTime in Date.
or you can use today() method to return the actual date.
I made a stupid mistake and created a column like this:
CREATE TABLE mytable (mycol INTEGER, ...)
As you can see, I forgot to define a default value like "DEFAULT 0".
In my code, I need to raise the value in "mycol" by 1.
I was baffled when I found out that this code didn't have any effect.
UPDATE mytable SET mycol=(mycol+1)
The column value stays as it is. In my case "EMPTY" (=no value at all).
I would like to avoid re-creating the table if possible.
I would like to ask if there is any easy way to fix this in the SQL statement so that an EMPTY value is seen as 0 so that
UPDATE mytable SET mycol=(mycol+1)
on a column value of EMPTY would finally produce the new column value of 1.
You can use such as below if your column has null value:
UPDATE mytable SET mycol= ifnull(mycol,0)+1
I have read the docs for MariaDB's REGEX_REPLACE but cannot get my query to work. I am storing links in a column, link and want to change the end of the link:
From www.example.com/<code> to www.example.com/#/results/<code> where <code> is some hexidecimal hash, e.g. 55770abb384c06ee00e0c579. What I am trying is:
SELECT REGEX_REPLACE("link", "www\\.example\\.com\\/(.*)", "www\\.example\\.com\\/#\\/results\\/\\1");
The result is:
Showing rows 0 - 0.
I wasn't able to figure out what the first argument was--the documentation says "subject". Turns out it's just the column name. So this works:
UPDATE my_table
SET my_link = REGEXP_REPLACE(
my_link,
"http:\\/\\/www\\.example\\.com\\/(.*)",
"http:\\/\\/www\\.example\\.com\\/#\\/results\\/\\1")
WHERE my_link IS NOT NULL