What is the easiest way to strip milliseconds from a timestamp field. I am extracting data from a table and I want the data to be in YYYY-MM-DD hh:mi:ss format. but I am getting ss.ssssss in the data.
The following method should work:
SELECT CURRENT_TIMESTAMP
, CAST(CAST(CURRENT_TIMESTAMP AS CHAR(19)) AS TIMESTAMP(0));
Related
I need to query a cell that contains a datetime but its formatted by default when I import it to only show the date.
31/7/2020 19:18:58 (in reality it's like this)
31/7/2020 (but it shows this)
So when I run this query:
=QUERY(A5:R10, "select K")
It returns only the date no matter what I do:
31/07/2020
I've tried:
Options
Formatted like "yyyy-MM-dd HH:mm" it returns 00:00
Filter by datetime or timestamp
Used '"&Text(now(), "yyyy-mm-dd HH:mm"&"' or something like that
The question is:
Is there a way to do what I'm trying to do without reformatting the imported cells?
link to test it:
https://docs.google.com/spreadsheets/d/14rGPngGvFXGP8txMS2yFo1v4gPcI4K1oYWj_8yt2Uq8/edit?usp=sharing
when I select one cell with F2 it shows the time:
Thanks a lot for your time!
select column B and format it as date time
or without reformating it:
=ARRAYFORMULA(QUERY(1*(B2:B4&""), "format Col1 'yyyy-mm-dd hh:mm:ss'"))
or:
=ARRAYFORMULA(QUERY(TEXT(B2:B4, "yyy-mm-dd hh:mm:ss"), "select *"))
Just make sure your cells are formatted as Automatic
If not, even if you use the format clause of the query, the clause will be ignored
In SQLite DB I m saving time as datetime('now') which as expected saving the time in YYYY-MM-DD HH:MM:SS.SSS format.
Now I want to retrieve time from that row in DD-MMM HH:MM format.
Is there any straight way of doing this?
Please Help.
Thanks.
Sample Code:
db.execSQL("INSERT INTO SessionInfo VALUES (00,'Demo Session',10,'Complete',7,datetime('now'),'"+usr_email+"');");
db.execSQL("INSERT INTO SessionInfo VALUES (01,'Demo Session',18,'Complete',8,datetime('now'),'"+usr_email+"');");
db.execSQL("INSERT INTO SessionInfo VALUES (02,'Demo Session',40,'Complete',4,datetime('now'),'"+usr_email+"');");
i want to retrieve data from any one row and the time should be in DD-MMM HH:MM format.
SQLite has the strftime() function, but there is no MMM format (whatever that may mean).
You should format dates in your application.
A is in the format of timestamp(6). I need it in timestamp(0). The code I am using is the following:
cast(cast(A AS date) as timestamp(0))
FROM 'table'
where A >= '?StartDT'
After inputing the date I want for the parameter I get the 'Invalid timestamp' error.
If A is truly a Timestamp(6) then casting it first as a DATE will affectively trim off the time elements, so when you cast the result to a TIMESTAMP(0) you are going to end up with a time of 00:00:00.
You'll need to also cast the TIMESTAMP(6) field as a time and then add the results together like:
CAST(CAST(A AS DATE) AS TIMESTAMP(0)) + (CAST(A AS TIME(6)) - TIME '00:00:00' HOUR TO SECOND)
You can also use SUBSTRING() to snip off the last 6 characters of the TIMESTAMP(6) field and cast that resulting string to a TIMESTAMP(0):
CAST(SUBSTRING(CAST(A AS CHAR(26)) FROM 1 FOR 19) AS TIMESTAMP(0))
This doesn't address the INVALID TIMESTAMP error you are getting though. Are you certain that field A is a TIMESTAMP(6) and not a VARCHAR() that looks like a Timestamp? What happens when you remove the outer cast, are their any dates in the result that look like they wouldn't convert nicely to a timestamp? Something is not quite right here, and I suspect that it's in your data.
I am having a column in my sql server database table with datatype bigint.
Now i need to convert this column into HH:MM:SS formate.
For this i use this command
SELECT cast(CONVERT(VARCHAR,DATEADD(MS,SUM(mFld),0),8) as Time) FROM tblm
But this command doesn't show right time duration.
For right time duration i use this command
SELECT rtrim(LTRIM(cast((mFld/(60*60)) as char)))+':' +rtrim(LTRIM(cast((mFld%(60*60))/(60)as char)))+':'+rtrim(LTRIM(cast(((mFld%(60*60))%(60)) as char))) FROM tblm
This command shows right result.But resulted data type is varchar.How can i convert this column in to time column with same result.
Example
DECLARE #minites bigint;
SET #minites = 5200020;
SELECT rtrim(LTRIM(cast((#minites/(60*60)) as char)))+':' +rtrim(LTRIM(cast((#minites%(60*60))/(60)as char)))+':'+rtrim(LTRIM(cast(((#minites%(60*60))%(60)) as char)))
SELECT cast(CONVERT(VARCHAR,DATEADD(MS,SUM(#minites),0),8) as Time)
How can i convert this column in to time column with same result.
You can't. Time has the range 00:00:00.0000000 to 23:59:59.9999999.
time (Transact-SQL)
I have a column of data with this date format mm/dd/yyyy. I would like to covert to this to the format yyyy-mm-dd for (SQLite usage). How could I achieve this?
UPDATE Table_Name
SET Column_Name = 'yyyy-mm-dd' format
I have tried substr, ltrim, rtrim (None of this work for my case).
My data are dynamic.
Sample
Column_Name
6/1/2004
06/25/2004
7/1/2003
6/1/2004
6/1/2004
09/19/2003
09/30/2003
09/30/2003
09/30/2003
09/30/2003
The Goal: Extract only month from this Column (Without displaying unnecessary stuff)
Thank you.
The syntax for extracting a specific date element from a date field is to use strftime.
SELECT strftime('%m', Column_Name) AS month which is your second question. For reconstituting the date data you could use (at least in JavaScript) substr to split the date out then format it as you require. Also see this post:Get month from DATETIME in sqlite