I want to develop rssreader in codename so i use rssreader component in codename.
And I use the following url:
feed://codenameone.blogspot.com/feeds/posts/default?alt=rss
which displays list of title and when I click on the list ,it shows the detial of the news. It is looking ok.
But my problem is when i use the following link of bbc:
feed://feeds.bbci.co.uk/news/video_and_audio/news_front_page/rss.xml?edition=uk
it displays list and when i click it displays only description only , I want to display detail of the news , How can I do it?
You will need to derive the RSSReader class and override the method protected void showRSSEntry(Hashtable h) where you can do pretty much anything you want to show the specific entry.
Related
So I would like to be able to have a print button for entries in our database so users can print an entry via a print friendly "form".
My thought was to create a separate page, add labels and have those labels pull the relevant information.
I know I can add the open widget information via this code:
app.datasources.ModelName.selectKey(widget.datasource.item._key);
app.showPage(app.pages.TestPrint);
But I'm running into a few problems:
I can't get the page to open in a new window. Is this possible?
window.open(app.pages.TestPrint);
Just gives me a blank page. Does the browser lose the widget source once the new window opens?
I can't get the print option (either onClick or onDataLoad) to print JUST the image (or widget). I run
window.print();
And it includes headers + scroll bars. Do I need to be running a client side script instead?
Any help would be appreciated. Thank you!
To get exactly what you'd want you'd have to do a lot of work.
Here is my suggested, simpler answer:
Don't open up a new tab. If you use showPage like you mention, and provide a "back" button on the page to go back to where you were, you'll get pretty much everything you need. If you don't want the back to show up when you print, then you can setVisibility(false) on the button before you print, then print, then setVisibility(true).
I'll give a quick summary of how you could do this with a new tab, but it's pretty involved so I can't go into details without trying it myself. The basic idea, is you want to open the page with a full URL, just like a user was navigating to it.
You can use #TestPrint to indicate which page you want to load. You also need the URL of your application, which as far as I can remember is only available in a server-side script using the Apps Script method: ScriptApp.getService().getUrl(). On top of this, you'll probably need to pass in the key so that your page knows what data to load.
So given this, you need to assemble a url by calling a server script, then appending the key property to it. In the end you want a url something like:
https://www.script.google.com/yourappaddress#TestPage?key=keyOfYourModel.
Then on TestPage you need to read the key, and load data for that key. (You can read the key using google.script.url).
Alternatively, I think there are some tricks you can play by opening a blank window and then writing directly to its DOM, but I've never tried that, and since Apps Script runs inside an iframe I'm not sure if it's possible. If I get a chance I'll play with it and update this answer, but for your own reference you could look here: create html page and print to new tab in javascript
I'm imagining something like that, except that your page an write it's html content. Something like:
var winPrint = window.open('', '_blank', 'left=0,top=0,width=800,height=600,toolbar=0,scrollbars=0,status=0');
winPrint.document.write(app.pages.TestPage.getElement().innerHTML);
winPrint.document.close();
winPrint.focus();
winPrint.print();
winPrint.close();
Hope one of those three options helps :)
So here is what I ended up doing. It isn't elegant, but it works.
I added a Print Button to a Page Fragment that pops up when a user edits a database entry.
Database Edit Button code:
app.datasources.ModelName.selectKey(widget.datasource.item._key);
app.showDialog(app.pageFragments.FragmentName);
That Print Button goes to a different (full) Page and closes the Fragment.
Print Button Code:
app.datasources.ModelName.selectKey(widget.datasource.item._key);
app.showPage(app.pages.ModelName_Print);
app.closeDialog();
I made sure to make the new Print Page was small enough so that Chrome fits it properly into a 8.5 x 11" page (728x975).
I then created a Panel that fills the page and populated the page with Labels
#datasource.item.FieldName
I then put the following into the onDataLoad for the Panel
window.print();
So now when the user presses the Print Button in the Fragment they are taken to this new page and after the data loads they automatically get a print dialog.
The only downside is that after printing the user has to use a back button I added to return to the database page.
1.
As far as I know, you cannot combine window.open with app.pages.*, because
window.open would require url parameter at least, while app.pages.* is essentially an internal routing mechanism provided by App Maker, and it returns page object back, suitable for for switching between pages, or opening dialogs.
2.
You would probably need to style your page first, so like it includes things you would like to have printed out. To do so please use #media print
ex: We have a button on the page and would like to hide it from print page
#media print {
.app-NewPage-Button1 {
display : none;
}
}
Hope it helps.
1. Here is how it is done, in a pop up window, without messing up the current page (client script):
function print(widget, title){
var content=widget.getElement().innerHTML;
var win = window.open('', 'printWindow', 'height=600,width=800');
win.document.write('<head><title>'+title+'/title></head>');
win.document.write('<body>'+content+'</body>');
win.document.close();
win.focus();
win.print();
win.close();
}
and the onclick handler for the button is:
print(widget.root.descendants.PageFragment1, 'test');
In this example, PageFragment1 is a page fragment on the current page, hidden by adding a style with namehidden with definition .hidden{display:none;} (this is different than visible which in App Maker seems to remove the item from the DOM). Works perfectly...
2. You cannot open pages from the app in another tab. In principle something like this would do it:
var w=window.parent.parent;
w.open(w.location.protocol+'//'+w.location.host+w.location.pathname+'#PrintPage', '_blank');
But since the app is running in frame nested two deep from the launching page, and with a different origin, you will not be able to access the url that you need (the above code results in a cross origin frame access error). So you would have to hard code the URL, which changes at deployment, so it gets ugly very fast. Not that you want to anyway, the load time of an app should discourage you from wanting to do that anyway.
I had a requirement to create a report based on individual user whom having SR waiting for approval, On click on Ticket id the URL's should redirect to SR detailed page where he can check request approve or disapprove.
using hyper link in birt properties unable to pass the ticketid by using below url's
http://google.com/maximo/ui/maximo.jsp?event=loadapp&value=asset&additionaleventvalue=Ticketid
Could you anybody help in this regards.
If the cell you made clickable contains the ticketId, go to Properties -> Hyperlink -> Edit...
Select hyperlink type URI, and click the dropdown to the right of 'Location' to go to the Javascript window.
If you're going to use it more than once, I would make the static part of your hyperlink a variable. Then add the ticketId by clicking "column bindings" in the left-lower column in the JavaScript window and selecting the appropriate cells in the middle and right columns. You'd get something like
vars["staticPartOfHyperlink"] + row[TICKETID]
If you'd rather not use a variable, you can hard-code the static part (don't do this, it's ugly and asking for trouble):
"http://google.com/maximo/ui/maximo.jsp?event=loadapp&value=asset&additionaleventvalue=" + row[TICKETID]
I have a Grid, which have a TopToolbar and BottomToolbar. In the BottomToolbar, I added a CSVDataExporter:
CSVDataExporter csvDataExporter = new CSVDataExporter();
csvDataExporter.setDataFormatNameModel(new ResourceModel("csv.export.link.name"));
csvDataExporter.setDelimiter('|');
addBottomToolbar(new ExportToolbar(this).addDataExporter(csvDataExporter));
I have the link, so I can export the table to CSV fine!
BUT! How could I change the CSV export link to be a Button, but do the same and be at the same place as it was? Thank you!
The Link is generated by your ExportToolbar using the createExportLink method. To generate something else (as in any other component) you can extend the ExportToolbar to override this method. If this is the only place where you need this functionality, you can do so by implementing an anonymous inner class.
Generally you'll want this method to return a Component that has it's own markup, like a Panel, that contains whatever you want to display as your Exportlink or -button.
I don't have so much experience using AJAX in a MVC application, in fact is my first facing. Please check the below image and note the rectangles.
The image is just an example that I took from internet.
The biggest rectangle is a partial view in my application and I have to render it when the user press Continue or Continuar button. The application should replace the current view for another without refresh the page.
This is the code which I'm testing, note first that I'm passing the first element of a list, but when the user press the button, render the view with the next element index = 2.
public ActionResult DoTest()
{
if (!Request.IsAjaxRequest())
{ }
List<Worksheet> worksheets = new List<Worksheet>()
{
new Worksheet("Hoja 1", ...),
new Worksheet("Hoja 2", ...)
};
return View(worksheets[0]);
}
Can orient me a little bit to know how to implement this feature? I just know that I need to use Ajax.
Have a look through the tutorials and examples here. There's plenty of other material around on the web with information on this subject.
There are many different ways you can achieve this. One way would be to write a custom paging Helper (HtmlHelper) that accepts new content upon the post event. You can view all about Helpers here : Custom HTML Helpers
Another way could be to use partial page rendering to achieve the partial page update upon post event.
If I was you I would combine a partial view with a jquery function to update the content. You can view some help on that here: Change dive content with Jquery
I have two questions, both related to the same view: so there is view called ProductDetails which shows the details of a product.
Each product can have the status:
Available - in this case, two button are available "edit" and "remove"(which will change the status of the product to "Not available" but will not remove it from DB)
Not available - in this case, the page displays the product but no options to edit or remove are
visible.
The controller ProductsController has an action Details that shows that view.
The problem is that I don't know how to implement the two buttons (Edit and Remove) because:
Edit sends to another action method (Edit which display another view) <- this works
Remove should do (IMO) a post on the current page. In the post action, the status of the product is changed and the view is shown again.
I want both button to look like links. If I put a form for remove, then it will be displayed as a button. I would like to avoid making the button look like a link with css. Or... at least I want to use the same HTML element for both 'buttons'.
This is more an issue of displaying the elements so I have added the CSS tag to your question as some alternative answers may rely on this.
Personally I think trying to make a button look like a text link would be quite awkward, even once you turn off the border and background you have issues with lining up the text etc.
I'd say you have 2 "simple" options.
Firstly you could make the delete not post a delete request but link to a delete confirmation page (or bring up a JS modal window with your delete form and button).
Secondly you could make them both look like buttons, while you requested that it looks like a link I figured that the main point was consistency in UI than the link look specifically. You could use JQueryUI and invoke .button() on both elements, invoking JQueryUI for 1 feature is a bit overkill but it's a quick change, of course you could replicate the same idea of styling the link like the buttons but would have to spend time dealing with browser CSS issues.
the Remove link should post to the Remove action, which should in turn (after validation and DB update) redirect to the details action.
public ActionResult Details(int productId)
{
// Your current action method
return View(model);
}
public ActionResult Remove(int productId)
{
// Validate productId
// Update DB
return RedirectToAction("Details", new { productId = productId } );
}
You easily can solve your link vs button problem by using a GET instead of a POST. Don't be blinded by best practices.
Or you can use a Remove link that executes a one-liner Javascript function that posts the form:
Remove