When a user gets an Access Denied page, how can you use drupal_add_css to load a particular stylesheet? Is this possible?
It is possible. The following code can add a CSS file when Drupal returns a access denied page.
Take in mind that when Drupal returns such error, the URL shown in the browser doesn't change; in example, if I am trying to access /admin/content, and I am not allowed to access that page, the shown URL doesn't change. You need to check the headers output from Drupal to verify if it output the access denied header.
function custom_module_preprocess_page(&$variables) {
if (preg_match('#HTTP/1\.[01]\x20+403[^a-zA-Z0-9]#', drupal_get_headers())) {
$variables['css'] = drupal_add_css($css_file_to_add);
$variables['styles'] = drupal_get_css();
}
}
The equivalent for Drupal 7 is the following one.
function custom_module_preprocess_page(&$variables) {
if (drupal_get_http_header('Status') == '403 Forbidden') {
$variables['css'] = drupal_add_css($css_file_to_add);
$variables['styles'] = drupal_get_css();
}
}
The same code can be used for a preprocess function implemented by a theme.
Related
PageSpeed Insights is showing this error message for my wordpress website (MyBGMI.Com
I can't fix this problem. To be very honest can't understand the problem.
**Errors logged to the console indicate unresolved problems. They can come from network request failures and other browser concerns. Learn more
Source
Description
TypeError: Cannot read properties of null (reading 'parentNode') at data:text/javascript;base64,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:1:200**
I tired figured out the issue but did not understand anything. Just checked the page with chrome browser developers tool.
And where i found two erros. but can't understand how to fix them.
enter image description here
This is base64 encoded JavaScript (usually bad when found on WordPress site)
(you can decode it online here: https://www.base64decode.org/)
Decoded it says:
var downloadButton=document.getElementById("download");
var counter=40;
var newElement=document.createElement("p");
newElement.innerHTML="You can download the file in 40 seconds.";
var id;
downloadButton.parentNode.replaceChild(newElement,downloadButton);
id=setInterval(function(){
counter--;
if(counter<0){
newElement.parentNode.replaceChild(downloadButton,newElement);
clearInterval(id)
}else{
newElement.innerHTML="JUST WAIT "+counter.toString()+" SECONDS."+"YOUR BGMI 2.3 DOWNLOAD LINK IS GENERATING"
}
},1000)
it appears that newElement.parentNode is null and that's what's causing the error.
if this is your code, and a desired code-piece on your WordPress website - try changing if(counter<0){ into if (newElement.parentNode && counter<0) { . otherwise, find where this is coming from, and remove it from your code base.
Update
Try this:
var downloadButton=document.getElementById("download");
var counter=40;
var newElement=document.createElement("p");
newElement.innerHTML="You can download the file in 40 seconds.";
var id;
if (downloadButton && newElement.parentNode) {
downloadButton.parentNode.replaceChild(newElement,downloadButton);
id=setInterval(function(){
counter--;
if(counter<0){
newElement.parentNode.replaceChild(downloadButton,newElement);
clearInterval(id)
}else{
newElement.innerHTML="JUST WAIT "+counter.toString()+" SECONDS."+"YOUR BGMI 2.3 DOWNLOAD LINK IS GENERATING"
}
},1000)
}
I'm setting up Ninja Forms in Wordpress. And I want to use the Webhooks extension to post a code to an external URL. If the code is correct Ninja Forms should submit the data on move on. If the code is wrong then the user should get an error message and try again.
How can I do this, I see no way if interrupting the submit?
In Ninja Form when you use webhook, I guess you may catch the error respond from the API with this code
$data['errors']['form'][] = $this->submit_response->result[0]->error;
So when the API respond error, in this case user has no chance to re-submit the form again unless reload the page.
When the form contain the error, Ninja form prevent the form to submit, so you need to find a way to clear/remove this error.
Few workarounds can fix this problem.
An easy way is that, you cache the respond error differently with the following code:
$data['errors']['last']['message'] = $this->submit_response->result[0]->error;
With this code, your form will not display the error message respond from API but it is possible for user to re-submit the form again and you can use the javascript code below to display the error to some HTML element
var customFormController = Marionette.Object.extend({
initialize: function() {
// Listen to submit respond
this.listenTo(nfRadio.channel( 'forms' ), 'submit:response', this.checkSubmitRespond);
},
checkSubmitRespond: function(response, textStatus, jqXHR, formID) {
if ('undefined' != typeof response.errors.last) {
var msg = response.errors.last.message;
// display error on some pre-defined element
jQuery('.error-container').html(msg);
}
}
});
jQuery(document).ready(function($) {
new customFormController();
});
Hope this help.
I have a section that requires login and a certain role ("higher than 19"). Whenever I logout from it, I get
Error: permission_denied: Client doesn't have permission to access the desired data.
Reason for this are my security settings:
".read": "root.child('users').child(auth.uid).child('data').child('role').val() > 19",
My logout function:
// Sign out functionality
App.controller('SignOutCtrl', function($scope, $state, Auth) {
$scope.logout = function() {
// Go to landing page
$state.go('home');
// Log user out
Auth.$unauth();
};
});
App.factory('Auth', ['$firebaseAuth', function($firebaseAuth) {
var firebase = new Firebase('https://mysite.firebaseio.com/');
return $firebaseAuth(firebase);
}]);
The $state 'home' doesn't have any reading restrictions, looks like the log out actually happens before I'm being redirected to the 'home'-$state, which triggers the security restrictions.
I guess I'm struggling to understand the very basic concept of how to log out from a restricted site without triggering the security setting, can anyone please explain me how to do that properly?
I would suggest unauthenticating when the logout page is loaded instead of before leaving the restricted page.
I have added custom payment method to woocommerce and its working fine . I just have one problem that it calls a callback url for saving transaction information to db. I have created new function for this in my plugin file but i cant excess it directly .
This is how i have done it:
//add_action('wp_ajax_nopriv_payment_callback_action', 'payment_callback_action');
//function
function payment_callback_action() {
echo "Its Working!";
}
I am trying to access it by :
url:"<?=site_url( '/' );?>wp-admin/admin-ajax.php?action=payment_callback_action
It seemd that it because of i dnt have privillage to use it directly but how can i do this ?.
Thanks
# for users not logged in
add_action('wp_ajax_nopriv_payment_callback_action', 'dixipay_callback_action');
# for users logged in
add_action('wp_ajax_payment_callback_action', 'dixipay_callback_action');
# Your callback
function dixipay_callback_action() {
echo "Its Working!";
}
read more: http://codex.wordpress.org/AJAX_in_Plugins
I am at the intermediate level in php and am new with facebook development. I have looked through the facebook documents and Stack Overflow previous comments.
All I basically wanted to do was let the user log in with their Facebook account and display their name.
My php page has a graph, and the page auto refreshes every 2 or 5 min.
I authenticate and get the facebook first_name to put on the page.
$graph = $facebook->api('/me');
echo $graph['first_name'] to get the first name of the user .. (for which I thought that no access token was required).
After about 90 min. I have been receiving the error:
fatal error: Uncaught OAuthException: An active access token must be used to query information about the current user......
and I have no value ( 0 ), in the $facebook->getUser(); parameter
I do know that off line access permission has been depreciated, (and I have have this enabled in my apps advanced settings)
I am trying to get an extended access token. In the FB docs. I see:
https://graph.facebook.com/oauth/access_token?
client_id=APP_ID&
client_secret=APP_SECRET&
grant_type=fb_exchange_token&
fb_exchange_token=EXISTING_ACCESS_TOKEN
I included my information in the link(an existing valid access token and all) and received a access token:
access_token=AAADbZBPuUyWwBAFubPaK9E6CnNsPfNYBjQ9OZC63ZBN2Ml9TCu9BYz89frzUF2EnLttuZAcG2fWZAHbWozrvop9bQjQclxVYle7igvoZCYUAg2KNQLMgNP&expires=4050
Yet this token expired in about 1 hour or so.(....expires=4050)
I assume I am using server side auth because I am using PHP?
I assume you need to enable "deprecate offline_access" in your Apps Advanced Settings page. As this worked for me:
//added code in base_facebook.php inside the facebook class
public function getExtendedAccessToken(){
try {
// need to circumvent json_decode by calling _oauthRequest
// directly, since response isn't JSON format.
$access_token_response =
$this->_oauthRequest(
$this->getUrl('graph', '/oauth/access_token'),
$params = array( 'client_id' => $this->getAppId(),
'client_secret' => $this->getAppSecret(),
'grant_type'=>'fb_exchange_token',
'fb_exchange_token'=>$this->getAccessToken(),
));
} catch (FacebookApiException $e) {
// most likely that user very recently revoked authorization.
// In any event, we don't have an access token, so say so.
return false;
}
if (empty($access_token_response)) {
return false;
}
$response_params = array();
parse_str($access_token_response, $response_params);
if (!isset($response_params['access_token'])) {
return false;
}
return $response_params['access_token'];
}
The token can still be invalid for several reasons, See How-To: Handle expired access tokens.
Hope it helps
There's a bug on this:
https://developers.facebook.com/bugs/241373692605971
But, another question on SO has a workaround (user uninstalls and re-installs):
fb_exchange_token for PHP only working once user removes app