I have created a subnet with primary IP address and this subnet is serving instances which are part of instance groups. Now I want to modify the IP address range to R2 but, I am facing issue with the CIDR range.
Now I want to change the CIDR range by modifying IP address.
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How to allocate/generate new IP address in ec2 instance in same subnet range?
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My main requirement is to set up two new ec2 instance with in same AZ and VPC with both of their Primary IP having same subnet.
Additionally if possible when I allocate new ELASTIC IP, They also should be in same subnet range.
How can I achieve this?
You have no control over the range of a Public IP address or Elastic IP address.
A random address will be assigned out of a pool of available IP addresses.
I presume that your desire is to be able to whitelist a range of IP addresses rather than having to specify them individually. A strategy for meeting this requirement is to put the instances in a private subnet, then put a NAT Gateway in the public subnet. All traffic from the instances will then come from the Elastic IP address associated with the NAT Gateway.
Another option is to Bring Your Own IP Addresses (BYOIP) - Amazon Elastic Compute Cloud, which would then allow you to assign your own specific IP addresses to the instances.
What is the exact difference between Local IP, External Ip, Static IP, Dynamic IP?
And what does it mean you should be connected on the same local network?
Local v External
static v dynamic
Every IP address has a network and host part, determined by the subnet mask.
A device has an IP and subnet mask of:
192.168.0.5;255.255.255.0 means that it has an network address of 192.168.0 and the rest of the ip address is allocated to hosts on the network (for a host to be on the same network it would need an ip in the range of 192.168.0.1 -> 192.168.0.254; 192.168.0.0 is the subnet address and 192.168.0.255 is the broadcast address)
another example:
A device has an IP and subnet mask of:
192.168.0.5;255.0.0.0 means that it has an network address of 192 and the rest of the ip address is allocated to hosts on the network (for a host to be on the same network it would need an ip in the range of 192.0.0.1 -> 192.255.255.254; 192.0.0.0 is the subnet address and 192.255.255.255 is the broadcast address)
As a final, more complicated example, A device has an IP and subnet mask of:
192.168.200.5;255.255.240.0. To find the network we convert the mask to binary
255.255.240.0
11111111.11111111.11110000.00000000
then convert the ip to binary, and apply the mask to find our ip range of the network
192.168.200.5
11000000.10101000.11001000.00000101 apply mask ->
11111111.11111111.11110000.00000000 logical AND to get our network portion:
11000000.10101000.11000000.00000000 (192.168.192.0)
to get our first and last host address on the same network, fill in the network portion plus all 0's for the first, and all 1's for the last address:
11000000.10101000.11000000.00000000(192.168.192.0 -> subnet)
11000000.10101000.11001111.11111111(192.168.207.255-> broadcast)
so to be on the same network as 192.168.200.5;255.255.240.0; a device would need an ip in the range of 192.168.192.1;255.255.240.0 -> 192.168.240.254;255.255.240.0
I recently got to know about DHCP that it dynamically assigns ip addresses to a computer. But what if two DHCP servers across the world assign a same ip address to two different computers. Doesn't it conflicts with the uniqueness property of ip addresses.
For example two DHCP servers assign ip address x to computer1 and computer2 and i wanted to send a mail to computer1 by looking at DNS server it should be send to ip address x. But there is a conflict as two different computers have same ip address x. could someone please clear my doubt.
Let say I want to contact a server whose domain name is example.Com and ip address stored in DNS server is 127.18.1.1 and DHCP changes the ip address for this server to some random value 127.19.1.1 then how is the address resolved since I'm contacting to example.com which has 127.18.1.1
There are a number of ways that this problem is avoided.
Firstly, by keeping networks small, segregating machines into specific functions, geographic areas, etc you reduce the risk of having a large pool of addresses in use.
Secondly, if you must have multiple DHCP servers on a network, then the address space should be split between them. So if you have 192.168.0.0/24, one server would handle 192.168.0.0/25 and another would handle 192.168.127.0/25
Thirdly, most DHCP servers will ping the IP address that they are going to offer before offering it. If the address gets a response it will be marked as Conflicted and won't be offered again.
Very Much confused about assigning IP address to WAN Interface and LAN Interface on Router/Firewall.
I know the process of assigning IP address but don't know which IP address to assign. Support My default gateway for ISP is 14.141.46.129, then what IP should I assign to my WAN Interface? And what Subnet Mask I have to assign?
Now What IP address I should assign to LAN Interface? And what Subnet Mask I have to assign?
After Assigning IP, I have to get Internet access from My LAN interface to WAN Interface.....
How to find the route to WAN Interface so that I Can ping google.com??
First, 14.141.46.129 is a valid IP address. The WAN interface needs a public IP address which should be given by your ISP provider.you can covert through cyberoam interface A port for-wan, B port for local lan & new range of 192.168.2.1 to 192.168.2.255 subnet mask 255.255.255.0 as u need you have to covert in subnetmask 192.168.2.1/32 to as per your needing (You assing your local ip for Lan The LAN interface can be in the range 192.168.2.2-254 with a mask of 255.255.255.0, )
First, 14.141.46.129 is not a valid IP address.
The WAN interface needs a public IP address which should be given by your ISP provider.
The LAN interface can be in the range 192.168.1.2-254 with a mask of 255.255.255.0
I was studying about IP addresses when I came Across an address of type 127.0.0.1/8. I know that127.0.0.1 is a loop-back address but what did /8 mean in the address.what /8 (in 127.0.0.1/8) specify
the /8 in your ip is the subnet mask.
It allows you to know on which subnetwork you are, find your broadcast and unicast IP.
Take a look at http://en.wikipedia.org/wiki/Subnetwork to have more informations
/8 is a subnet mask written in CIDR notation and which is used by hosts to determine if they are on the same network as some other host and can communicate directly or they need to use a router (default gateway). In your case this is a loopback address, and actually all IP addresses from 127.0.0.0/8 network (from 127.0.0.0 to 127.255.255.255) are reserved loopback addresses as defined in rfc6890: Special-Purpose Address Registries