Cypress Reading values from a cell in a tab - css

When i try to read values from a single cell in a tab using cypress it returns {specwindow: , chainerid: ch-https://app.trahop.com-218} instead of returning values inside the cell.
This is the line of code which returns the meesage above:
cy.log(cy.get("tr:nth-child(1) td:nth-child(1)")) .Im sorry if this is a stupid question but i cant find any way to read the values inside the cell.

cy.get() does not yield a text variable, but instead yields a Cypress-wrapped DOM element. In order to see the value, you'll need to include it in a chained Cypress command, or yield it into a .then() (or similar) Cypress statement.
cy.get('tr:nth-child(1) td:nth-child(1)')
.should('have.text', 'foo');
cy.get('tr:nth-child(1) td:nth-child(1)')
.then(($el) => {
cy.log($el.text());
});

Related

Custom sorting issue in MarkLogic?

xquery version "1.0-ml";
declare function local:sortit(){
for $i in ('a','e','f','b','d','c')
order by $i
return
element Result{
element N{1},
element File{$i}
}
};
local:sortit()
the above code is sample, I need the data in this format. This sorting function is used multiple places, and I need only element N data some places and only File element data at other places.
But the moment I use the local:sortit()//File. It removes the sorting order and gives the random output. Please let me know what is the best way to do this or how to handle it.
All these data in File element is calculated and comes from multiple files, after doing all the joins and calculation, it will be formed as XML with many elements in it. So sorting using index and all is not possible here. Only order by clause can be used.
XPath expressions are always returned in document order.
You lose the sorting when you apply an XPath to the sequence returned from that function call.
If you want to select only the File in sorted order, try using the simple mapping operator !, and then plucking the F element from the item as you are mapping each item in the sequence:
local:sortit() ! File
Or, if you like typing, you can use a FLWOR to iterate over the sequence and return the File:
for $result in local:sortit()
return $result/File

When does pressing the Enter (Return) key matter when creating a regex matching expression?

I want to search for multiple codes appearing in a cell. There are so many codes that I'd like to write parts of the code in succeeding lines. For example, let's say I am looking for "^a11","^b12", "^c67$" or "^d13[[:blank:]]". I am using:
^a11|^b12|^c67$|^d13[[:blank:]]
This seems to work. Now, I tried:
^a11|^b12|
^c67$|^d13[[:blank:]]
That also seemed to work. However when I tried:
^a11|^b12|^c67$|
^d13[[:blank:]]
It did not count the last one.
Note that my code is wrapped into a function. So the above is an argument that I feed the function. I'm thinking that's the problem, but I still don't know why one truncation works while the other does not.
I realized the answer today. The problem is that since I am feeding the regex argument, it will count the next line in the succeeding code.
Thus, the code below was only "working" because ^c67$ is empty.
^a11|^b12|
^c67$|^d13[[:blank:]]
And the code below was not working because ^d13 is not empty but also this setup looks for (next line)^d13[[:blank:]] instead of just ^d13[[:blank:]]
^a11|^b12|^c67$|
^d13[[:blank:]]
So an inelegant fix is:
^a11|^b12|^c67$|
^nothinghere|^d13[[:blank:]]
This inserts a burner code that is empty which is affected by the line break.

code executes outside function, but not inside it

my problem is, that some code gets executed outside a function, but not in it. In my example, the content of certain cells should be transferred from the input table to the output table. In case of removal or adding of rows/cols I don't access the cells by their index (e.g input[3,4]), but by application of a condition (e.g. input[(which(input$code=="A1")),(which(colnames(input)=="kg"))].
so here's a minimized version of my data:
input<-data.frame(animal=c("cat","dog","mouse","deer","lion"),
m=c(0.5,1,0.1,1.5,3),
kg=c(5,20,0.2,50,100),
code=c("A4","A5","A3","A1","A2"))
output<-data.frame(code=c("A1","A2","A3","A4","A5"),
kg=numeric(5))
execution outside the function, that works (the content of a cell of the input table should be copied to a suitable one in the output table):
row_out<-which(output$code=="A1")
col_out<-which(colnames(output)=="kg")
row_in<-which(input$code=="A1")
col_in<-which(colnames(input)=="kg")
output[row_out,col_out]<-input[row_in,col_in]
and the function, that contains the same code, which worked outside, except for the substitution of the quoted code expression for a function argument (codeexpression):
fun_transfer<-function(codeexpression){
row_out<-which(output$code==codeexpression)
col_out<-which(colnames(output)=="kg")
row_in<-which(input$code==codeexpression)
col_in<-which(colnames(input)=="kg")
output[row_out,col_out]<-input[row_in,col_in]
}
Problem: now the execution of
fun_transfer("A4")
does not lead to an error, nor to a result in the output table.
Why doesn't this function work or rather what does it do? Is there a problem with quotation marks?
any help would be appreciated
thanks,
Michel
In the best case, data enters a function as argument and leaves it as a return value.
Outside of a function
output[row_out,col_out] <- input[row_in,col_in]
changes the existing data.frame. You can (or better: should) not change some variable outside the function from within the function.
Just end your function with a return statement to return the changed dataframe to the caller
Edit
It appears as if what you try to write is a lesser version of merge. If the following answers your question it will probably be more concise, faster and more idiomatic:
input<-data.frame(animal=c("cat","dog","mouse","deer","lion"),
m=c(0.5,1,0.1,1.5,3),
kg=c(5,20,0.2,50,100),
code=c("A4","A5","A3","A1","A2"))
output<-data.frame(code=c("A1","A2","A3","A4","A5"))
output <- merge(output, input[, c("code", "kg")], by = "code",
all.x = TRUE, all.y = FALSE)
print(output)

How to get the expression used in an Assign activity

In the line below, "ThenActivity" is an Assign activity nested inside the Then part of an If activity. Im trying to get at the expression, but this snippet isnt working.
((Assign)ThenActivity).To.Expression.ToString();
This returns "1.13: CSharpReference"
When it should read R = 44.5M, which is the expression text, how do I get at it?
The statement should read something like this
((CSharpValue)(((Assign)ThenActivity).Value.Expression)).ExpressionText
Note: You need to get the assignment, then its expression, cast that as a CSharpValue, then finally you can get the ExpressionText.

QTP - getting value of element

I am beginning with QTP and just cannot find out how to get value of element. For example when I just want to compare the number of results found by google. I tried to select the element with object spy and use Val(Element) to assign the value into variable..but it doesnt work. Could anyone help with this? BTW, I am not sure whether selecting the text (element) to compare with Object spy is correct.
Thanks!
You should use GetROProperty in order to get the text and then parse it for the value.
Looking at a Google results page I see that the result is in a paragraph with id=resultStats in the 3rd bold tag.
<p id="resultStats"> Results <b>1</b> - <b>10</b> of about
<b>2,920,000</b>
for <b>qtp</b>. (<b>0.22</b> seconds)</p>
So the following script gets the number (as a string with commas).
Browser("micclass:=Browser")
.Page("micclass:=Page")
.WebElement("html id:=resultStats")
.WebElement("html tag:=b","index:=2").GetROProperty("innertext")

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