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I want to run a binary logistic regression in R but I see this error:
Error in if (!length(fname) || !any(fname == zname)) { :
missing value where TRUE/FALSE needed
It happens because I use variables with $. For example data$HEIGHT.
I use read.table() for importing .txt file.
How can I use HEIGHT instead of data$HEIGHT?
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Is there a function such as kable to output character vectors in a way that doesn't look as ugly as the default console type?
See eg p from the pander package or the generic pander method:
> pander::pander(sample(letters, 5))
_p_, _r_, _v_, _f_ and _t_
If you want to override the default formatting, see panderOptions or specify directly in the p function.
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I am trying to write this (SAS) comand in R. x is a variable with this specific format: j61915035t
x1 = trim(upcase(substr(x,1,1)));
I really appreciate what you are doing in this site!
You want to remove leading/trailing blanks from a character string that is the uppercase first letter of the string x. So this should do it.
library(stringr)
x1 = str_trim(str_to_upper(str_sub(x,1,1)))
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For the auto.arima function in forecast package of R, is there a way to let the function omit a model of arima(0,0,0), as I simply assume there must be some correlation within the dataset.
You could try looking at the help for the function
auto.arima(). Check the arguments start.p, start.q,
d,max.d
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I would like to get this loop to work. I am trying to save different dataframes with different names at once. I don't know how to get the path part of the code to vary with i:
for (i in specific) {
write.dta(get(paste0("degreeS", i)), "D:/Educacion/PeerEffects/",paste0( "degreeS", i,".dta"))
}
I needed to use the command file.path(). This solved the problem
for (i in specific) {
write.dta(get(paste0("degreeS", i)), file.path("D://Educacion//PeerEffects//", paste0("degreeS", i,".dta")))
}
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Given the following setup:
area.factor <- cut(state.x77[,"Area"],
breaks=quantile(state.x77[,"Area"],c(0,.25,.75,1)),
labels=c("small","medium","large"),
include.lowest=TRUE)
state <- data.frame(pop=state.x77[,"Population"],
inc=state.x77[,"Income"],
area=area.factor,
region=state.region)
pop.area.region <- with(state,ftable(pop,area,region))
The following two lines of code are show the same result:
head(ftable(prop.table(pop.area.region,margin=2)))
head(prop.table(pop.area.region,margin=2))
I don't understand what effect adding ftable has, if any, in:
head(ftable(prop.table(pop.area.region,margin=2)))
Adding ftable witll try to coerce the pop.area.region to a ftable class. Here
No need to add ftable since pop.area.region is already an ftable.
identical(ftable(prop.table(pop.area.region,margin=2)),
prop.table(pop.area.region,margin=2))
TRUE