I need to take someone’s age, and then outputs a key event from every year they have lived through.
dYearlyEvents = {
"1993": "Bill Clinton is inaugurated as the 42nd president.",
"1994": "The People's Republic of China gets its first connection to the Internet.",
"1995": "eBay is founded by Pierre Omidyar.",
"1996": "Murder of Tupac Shakur.",
"1997": "The first episode of Pokémon airs on TV Tokyo.",
"1998": "Death of Frank Sinatra.",
"1999": "The Columbine High School massacre in Colorado, United States, causes 15 deaths.",
"2000": "The Sony PlayStation 2 releases in Japan. ",
}
sBirthYear = (input("What year were you born in: \n"))
while True:
if sBirthYear in dYearlyEvents:
print(dYearlyEvents[sBirthYear])
sBirthYear += 1
This is what I tried but obviously as the input is a string it wont add a year every time it loops to print all events from 1993 to 2000 instead just prints 1993.
Related
How do I extract a specific word after keyword in R.
I have the following input text which contains details about policy. I need to extract specific words value like FirstName , SurName , FatherName and dob.
input.txt
In Case of unit linked plan, Investment risk in Investment Portfolio is borne by the policyholder.
ly
c I ROPOSAL FORM z
Insurance
Proposal Form Number: 342525 PF 42242
Advisor Coe aranch Code 2
Ff roanumber =F SSOS™S™~™S~S rancid ate = |
IBR. Code S535353424
re GFN ——
INSTRUCTION FOR FILLING THES APPLICATION FORM ; 1. Compiets the proocsal form in CAPITAL LETTERS using = Black Ball Point P]n. 2. Sless= mark your selection by marking “X" insides the
Boe. 3. Slnsse bases 2 Blank soece after eect word, letter or initial 4. Slssse write "MA" for questions whic are not apolicatie. 5.00 NOT USE the Sor") to identify your initial or seperate the sddressiiine.
6. Sulmissson of age proof ie mandatory along wall Ge propel fonm.
IMPORTANT INSTRUCTIONS WITH REGARD TO DISCLOSURE OF INFORMATION: Inturance it a contract of UTMOST GOOD FAITH and itis required by disclose all material and nelevant
fach: complebehy, DO) NOT suppress any fac: in response by the questions in the priposal form. FAILURE TO PROVIDE COMPLETE AND ACCURATE INFORMATION OR
MISREPRESENTATION OF THE FACTS COULD DECLARE THES POLICY CONTRACT NULL AND VOID AFTER PAYMENT OF SURRENDER VALUE, IF ANY, SUBJECT TO SECTION 45 OF
INSURANCE ACT, 1998 As AMENDED FROM TIME TO TIME,
Section I - Details of the Life to be Assured
1. Tite E-] Mr. LJ Mrs. LJ Miss [J Or. LJ Others (Specify)
2. FirstName PETER PAUL
3. Surname T
44. Father's Name
46, Mother's Name ERIKA RESWE D
5. Date of Birth 13/02/1990 6, Gender E] Male ] Female
7. Age Proof L] School Certificate [] Driving License [] Passport {Birth Certificate E"] PAN Card
3, Marital Status D) Single EF] Married 0 Widower) 0 Civorcee
9, Spouse Name ERISEWQ FR
10. Maiden Name
iL. Nationality -] Resident Indian National [J Non Resident Indian (MRI) L] Others (Specify)
12, Education J Postgraduate / Doctorate Ee) Graduate [] 12thstd. Pass [J 10thstd. Pass [J Below 10th std.
OO Dliterate / Uneducated CJ Others (Specify)
13. Address For No 7¥%a vaigai street Flower
Communication Nagar selaiyur
Landmark
City Salem
Pin Code BO00 73: State TAMIL NADU
Address proof [] Passport ([] Driving License [] Voter ID [] Bank Statement [] Utility Bill G4 Others (Specify) Aadhaar Card
14, Permanent No 7¥a vaigai street Flower
Address :
Nagar selaiyur
Landmark
City Salem
Pin Code 5353535 state (TAMIL NADU
Address proof CJ] Passport [9 DrivingLicense [J Voter ID [ Bank Statement [ Utility Bill B] Others (Specify) Aadhaar Card
15. Contact Details Mobile 424242424 Phone (Home)
Office / Business
E-mail fdgrgtr13#yahoo.com
Preferred mode: ((] Letter EF) E-Mail
Preferred Language for Letter {other than English): [] Hindi [] Kannada [-] Tamil J Telugu C] Malayalam C) Gujarati
Bengali GOriya =D] Marathi
16. Occupation CL] Salaried-Govt /PSU ( Salaried-other [9 Self Employed Professional [J Aagriculturist {Farmer [Part Time Business
LJ Retired ] Landlord J Student (current Std) -] Others (Specify) Salaried - MNC
17. Full Name of the Capio software
Employers Businnes/
School/College
18, Designation & Exact nature of Work / Business Manager
19. AnnualIncomein 1,200,000.00 20. Annual Income of Husband / Father = 1,500,000.00
Figures (%) (for female and minor lives)
21. Exact nature of work / business of Husband / Father for female and minor lives Government Employee
Page 10fé
The below code works for me but the problem is if line order changes everything get changed. Is there a way to extract keyword value irrespective of line order. ?
Current Code
path <- getwd()
my_txt <- readLines(paste(path, "/input.txt", sep = ""))
fName <- sub('.*FirstName', '', my_txt[7])
SName <- sub('.*Surname', '', my_txt[8])
FatherNm <- sub(".*Father's Name", '', my_txt[9])
dob <- sub("6, Gender.*", '',sub(".*Date of Birth", '', my_txt[11]))
You can combine the text together as one string and extract the values based on pattern in the data. This approach will work irrespective of the line number in the data provided the pattern in the data is always valid for all the files.
my_txt <- readLines(paste(path, "/input.txt", sep = ""))
#Collapse data in one string
text <- paste0(my_txt, collapse = '\n')
#Extract text after FirstName till '\n'
fName <- sub('.*FirstName (.*?)\n.*', '\\1', text)
fName
#[1] "John Woo"
#Extract text after Surname till '\n'
SName <- sub('.*Surname (.*?)\n.*', '\\1', text)
SName
#[1] "T"
#Extract text after Father's Name till '\n'
FatherNm <- sub(".*Father's Name (.*?)\n.*", '\\1', text)
FatherNm
#[1] "Bill Woo"
#Extract numbers which come after Date of Birth.
dob <- sub(".*Date of Birth (\\d+/\\d+/\\d+).*", '\\1', text)
dob
#[1] "13/07/1970"
I have a list of >1.000 companies which I could use to invest in. I need the ticker symbol id's from all these companies. I find difficulties when I am trying to strip the output of the soup, and when I am trying to loop through all the company names.
Please see an example of the site: https://finance.yahoo.com/lookup?s=asml. The idea is to replace asml and put 'https://finance.yahoo.com/lookup?s='+ Companies., so I can loop through all the companies.
companies=df
Company name
0 Abbott Laboratories
1 ABBVIE
2 Abercrombie
3 Abiomed
4 Accenture Plc
This is the code I have now, where the strip code doesn't work, and where the loop for all the company isn't working as well.
#Create a function to scrape the data
def scrape_stock_symbols():
Companies=df
url= 'https://finance.yahoo.com/lookup?s='+ Companies
page= requests.get(url)
soup = BeautifulSoup(page.text, "html.parser")
Company_Symbol=Soup.find_all('td',attrs ={'class':'data-col0 Ta(start) Pstart(6px) Pend(15px)'})
for i in company_symbol:
try:
row = i.find_all('td')
company_symbol.append(row[0].text.strip())
except Exception:
if company not in company_symbol:
next(Company)
return (company_symbol)
#Loop through every company in companies to get all of the tickers from the website
for Company in companies:
try:
(temp_company_symbol) = scrape_stock_symbols(company)
except Exception:
if company not in companies:
next(Company)
Another difficulty is that the symbol look up from yahoo finance will retrieve many companies names.
I will have to clear the data afterwards. I want to set the AMS exchange as the standard, hence if a company is listed on multiple exchanges, I am only interested in the AMS ticker symbol. The final goal is to create a new dataframe:
Comapny name Company_symbol
0 Abbott Laboratories ABT
1 ABBVIE ABBV
2 Abercrombie ANF
Here's a solution that doesn't require any scraping. It uses a package called yahooquery (disclaimer: I'm the author), which utilizes an API endpoint that returns symbols for a user's query. You can do something like this:
import pandas as pd
import yahooquery as yq
def get_symbol(query, preferred_exchange='AMS'):
try:
data = yq.search(query)
except ValueError: # Will catch JSONDecodeError
print(query)
else:
quotes = data['quotes']
if len(quotes) == 0:
return 'No Symbol Found'
symbol = quotes[0]['symbol']
for quote in quotes:
if quote['exchange'] == preferred_exchange:
symbol = quote['symbol']
break
return symbol
companies = ['Abbott Laboratories', 'ABBVIE', 'Abercrombie', 'Abiomed', 'Accenture Plc']
df = pd.DataFrame({'Company name': companies})
df['Company symbol'] = df.apply(lambda x: get_symbol(x['Company name']), axis=1)
Company name Company symbol
0 Abbott Laboratories ABT
1 ABBVIE ABBV
2 Abercrombie ANF
3 Abiomed ABMD
4 Accenture Plc ACN
I have 4 databases relating to the America's Cup.
SELECT * FROM teams
>
Code | Country | TeamName
ITA |Italy | Luna Rossa Prada Pirelli Team
NZ |New Zealand | Emirates Team New Zealand
UK |United Kingdom | INEOS Team UK
USA |United States of America | NYYC American Magic
4 rows
SELECT * FROM races
>
Race Tournament Date Racedate
RR1R1 RR 15-Jan 18642
RR1R2 RR 15-Jan 18642
RR1R3 RR 16-Jan 18643
RR2R1 RR 16-Jan 18643
RR2R2 RR 17-Jan 18644
RR2R3 RR 17-Jan 18644
RR3R1 RR 23-Jan 18650
RR3R2 RR 23-Jan 18650
RR3R3 RR 23-Jan 18650
SFR1 SF 29-Jan 18656
1-10 of 31 rows
SELECT * FROM tournaments
>
Tournament Event TournamentName
RR Prada Cup Round Robin
SF Prada Cup Semi-Final
F Prada Cup Final
AC America's Cup Americas Cup
4 rows
SELECT *
FROM results
>
Race Code Result
FR1 ITA Win
FR1 UK Loss
FR2 UK Loss
FR2 ITA Win
FR3 UK Loss
FR3 ITA Win
FR4 ITA Win
FR4 UK Loss
FR5 ITA Win
FR5 UK Loss
1-10 of 62 rows
and I'm trying to write an SQL query that will output the number of races each team won by tournament, and show the output. The output table should include the full name of the Event, the Tournament and the full name of each team. My query at the moment looks like this:
SELECT TeamName, Result, Event, tournaments.Tournament
FROM teams LEFT JOIN results
ON teams.Code = results.Code
LEFT JOIN races
ON results.Race = races.Race
LEFT JOIN tournaments
ON races.Tournament = tournaments.Tournament
WHERE Result = 'Win'
ORDER BY tournaments.Tournament
which outputs:
TeamName Result Event Tournament
Emirates Team New Zealand Win America's Cup AC
Emirates Team New Zealand Win America's Cup AC
Luna Rossa Prada Pirelli Team Win America's Cup AC
Luna Rossa Prada Pirelli Team Win America's Cup AC
Emirates Team New Zealand Win America's Cup AC
Luna Rossa Prada Pirelli Team Win America's Cup AC
Emirates Team New Zealand Win America's Cup AC
Emirates Team New Zealand Win America's Cup AC
Emirates Team New Zealand Win America's Cup AC
Emirates Team New Zealand Win America's Cup AC
When I try to COUNT(Result) AS NumberOfWins, I get:
TeamName Result NumberOfWins Event Tournament
Luna Rossa Prada Pirelli Team Win 31 Prada Cup F
1 row
Why does adding the count count only Luna Rossa's wins? How can I change the query to fix it?
Why does adding the count count only Luna Rossa's wins?
Count() is an aggregate function and produces one result per GROUP.
As you have no GROUP BY clause the entire result set is a single group and hence the single result.
The reason why you got Tournament F is due to
If the SELECT statement is an aggregate query without a GROUP BY clause, then each aggregate expression in the result-set is evaluated once across the entire dataset. Each non-aggregate expression in the result-set is evaluated once for an arbitrarily selected row of the dataset. The same arbitrarily selected row is used for each non-aggregate expression. Or, if the dataset contains zero rows, then each non-aggregate expression is evaluated against a row consisting entirely of NULL values. As per SQLite SELECT -
How can I change the query to fix it?
So you need a GROUP BY clause. To create groups upon which the count() function will work on.
You probably want GROUP BY Tournament,TeamName
e.g.
SELECT TeamName, Result, Event, tournaments.Tournament, count(*)
FROM teams LEFT JOIN results
ON teams.Code = results.Code
LEFT JOIN races
ON results.Race = races.Race
LEFT JOIN tournaments
ON races.Tournament = tournaments.Tournament
WHERE Result = 'Win'
GROUP BY Tournament,Teamname
ORDER BY tournaments.Tournament
I'm new to extracting data from XML file. I'm trying to process the following an XML file using R XML packages. The information I want is in the attribute values.
I encounter two difficulties:
some attribute values exist in one node, but not in another node. For example, "DRP" has the information in the second but not in the first
some attributes has multiple values for an individual and i don't know how to link them to that individual. For example, "EmpHs" has multiple records for an individual (identified by indvlPK).
Ideally I want the output data has the structure similar to the following:
lastNm
firstNm
indvlPK
fromDt
orgNm
hasCustComp
GIGAX
JEFFREY
2783477
03/2004
GATEWAY FINANCIAL ADVISORS, INC
GIGAX
JEFFREY
2783477
03/2004
GFA IN
GIGAX
JEFFREY
2783477
01/2007
UNITED FIRST
HINSON
BRIAN
2783737
07/1996
LINCOLN FINANCIAL ADVISORS CORPORATION
Y
HINSON
BRIAN
2783737
07/1996
FIRST FINANCIAL GROUP
Y
Is there any way I can parse the data correctly? Thanks!
The code I used but didn't give me what I want:
doc <- "Test.xml"
ind <- xmlParse(doc)
xmltop = xmlRoot(ind)
temp1 <- data.frame(unlist(getNodeSet(xmltop,"//Info/#lastNm")))
temp2 <- data.frame(unlist(getNodeSet(xmltop,"//Info/#firstNm")))
temp3 <- data.frame(unlist(getNodeSet(xmltop,"//Info/#indvlPK")))
temp4 <- data.frame(unlist(getNodeSet(xmltop,"//EmpHs/#fromDt")))
temp5 <- data.frame(unlist(getNodeSet(xmltop,"//DRP/#hasCustComp")))
The data is here:
<?xml version="1.0" encoding="ISO-8859-1"?>
<IAPDIndividualReport GenOn="2021-03-29">
<Indvls>
<Indvl>
<Info lastNm="GIGAX" firstNm="JEFFREY" midNm="W" indvlPK="2783477" actvAGReg="Y" link="https://adviserinfo.sec.gov/individual/summary/2783477"/>
<OthrNms/>
<CrntEmps>
<CrntEmp orgNm="CAMBRIDGE INVESTMENT RESEARCH ADVISORS, INC." orgPK="134139" str1="1776 PLEASANT PLAIN RD." city="FAIRFIELD" state="IA" cntry="United States" postlCd="52556-8757">
<CrntRgstns>
<CrntRgstn regAuth="MO" regCat="RA" st="APPROVED" stDt="2010-09-09"/>
</CrntRgstns>
<BrnchOfLocs>
<BrnchOfLoc city="O'FALLON" state="MO" cntry="United States"/>
</BrnchOfLocs>
</CrntEmp>
</CrntEmps>
<Exms>
<Exm exmCd="S63" exmNm="Uniform Securities Agent State Law Examination" exmDt="1996-08-20"/>
<Exm exmCd="S65" exmNm="Uniform Investment Adviser Law Examination" exmDt="1999-12-21"/>
</Exms>
<Dsgntns/>
<PrevRgstns>
<PrevRgstn orgNm="WOODBURY FINANCIAL SERVICES, INC." orgPK="421" regBeginDt="2009-01-05" regEndDt="2009-12-03">
<BrnchOfLocs>
<BrnchOfLoc city="OFALLON" state="MO"/>
<BrnchOfLoc city="OFALLON" state="MO"/>
<BrnchOfLoc city="DUBLIN" state="CA"/>
</BrnchOfLocs>
</PrevRgstn>
<PrevRgstn orgNm="FSC SECURITIES CORPORATION" orgPK="7461" regBeginDt="2004-10-29" regEndDt="2008-12-01">
<BrnchOfLocs>
<BrnchOfLoc city="O'FALLON" state="MO"/>
<BrnchOfLoc city="ST. PETERS" state="MO"/>
</BrnchOfLocs>
</PrevRgstn>
<PrevRgstn orgNm="GATEWAY FINANCIAL ADVISORS, INC." orgPK="115025" regBeginDt="2004-11-11" regEndDt="2006-10-11">
<BrnchOfLocs>
<BrnchOfLoc city="ST. PETERS" state="MO"/>
</BrnchOfLocs>
</PrevRgstn>
</PrevRgstns>
<EmpHss>
<EmpHs fromDt="03/2004" orgNm="GATEWAY FINANCIAL ADVISORS, INC" city="OFALLON" state="MO"/>
<EmpHs fromDt="03/2004" orgNm="GFA INC" city="OFALLON" state="MO"/>
<EmpHs fromDt="01/2007" orgNm="UNITED FIRST" city="OFALLON" state="MO"/>
<EmpHs fromDt="09/2010" orgNm="CAMBRIDGE INVESTMENT RESEARCH ADVISORS, INC" city="FAIRFIELD" state="IA"/>
<EmpHs fromDt="09/2010" orgNm="CAMBRIDGE INVESTMENT RESEARCH, INC" city="FAIRFIELD" state="IA"/>
</EmpHss>
<OthrBuss>
<OthrBus desc="1)STONEBRIDGE WEALTH MANAGEMENT GROUP, 728 HAWK RUN DR, O'FALLON, MO, 3/2008 AS INDEPENDENT INSURANCE AGENT FOR VARIOUS INDEPENDENT INSURANCE COMPANIES. INV REL - 40/MO - 20/TRADING. 2)UNITED FIRST FINANCIAL MORTGAGE SOFTWARE SALES. START 6/1/07, 10 HOURS PER MONTH, 5 DURING TRADING HOURS. NO OWNERSHIP INTEREST. 3)MORTGAGE STOP INC., 728 HAWK RUN DR., OFALLON, MO 63368. LOAN OFFICER PROCESSING LOAN APPS FOR CLIENTS. START 6/1/2002, 25 HOURS PER MONTH, 10 DURING TRADING HOURS. NO OWNERSHIP. 4)CIRA, 1776 PLEASANT PLAIN RD, FAIRFIELD, IA, AS ADVISORY REP OF A RIA. INV REL - 40 HR/WK - 40/TRADING. SEE EMPLOYMENT HISTORY FOR START DATE. 5) THE MORTGAGE SHOP, 355 MID RIVERS MALL DRIVE, STE E, ST. PETERS, MO 63376. MORTGAGE ORIGINATOR SINCE 01/01/99. NOT INVESTMENT RELATED. WORKS 60 HOURS PER MONTH, 20 OF WHICH ARE DURING TRADING HOURS. 6.365 PROPERTIES LLC, O'FALLON, MO, 8/2018 AS OWNER OF LLC THAT BUYS, SELLS, & HOLDS REAL ESTATE. NIR - 20/MO - 0/TRADING. 7. BEST OFFER HOMES, LLC, 728 HAWK RUN DRIVE, O'FALLON, MO, REAL ESTATE SALES/MORTGAGE ORIGINATION/ ACCOUNTING/FINANCIAL ACTIVITIES, 06/16/20, NIR, 20/MO- 0/TRADING 8. GIGAX WEALTH MANAGEMENT, 728 HAWK RUN DRIVE, OFALLON, MO, INDEPENDENT INSURANCE AGENT FOR VARIOUS INDEPENDENT INSURANCE COMPANIES,11/23/20, INV REL, 10 HR/WK- 10 TRADING HR."/>
</OthrBuss>
<DRPs/>
</Indvl>
<Indvl>
<Info lastNm="HINSON" firstNm="BRIAN" midNm="TROY" indvlPK="2783737" actvAGReg="Y" link="https://adviserinfo.sec.gov/individual/summary/2783737"/>
<OthrNms/>
<CrntEmps>
<CrntEmp orgNm="BRIDGEWORTH WEALTH MANAGEMENT" orgPK="164100" str1="101 25TH STREET NORTH" city="BIRMINGHAM" state="AL" cntry="United States" postlCd="35203">
<CrntRgstns>
<CrntRgstn regAuth="AL" regCat="RA" st="APPROVED" stDt="2015-05-12"/>
<CrntRgstn regAuth="TX" regCat="RA" st="APPROVED_RES" stDt="2015-05-01"/>
</CrntRgstns>
<BrnchOfLocs>
<BrnchOfLoc str1="400 MERIDIAN STREET" str2="SUITE 200" city="HUNTSVILLE" state="AL" cntry="United States" postlCd="35801"/>
<BrnchOfLoc str1="101 25TH STREET NORTH" city="BIRMINGHAM" state="AL" cntry="United States" postlCd="35203"/>
</BrnchOfLocs>
</CrntEmp>
</CrntEmps>
<Exms>
<Exm exmCd="S63" exmNm="Uniform Securities Agent State Law Examination" exmDt="1996-10-11"/>
</Exms>
<Dsgntns>
<Dsgntn dsgntnNm="Certified Financial Planner"/>
<Dsgntn dsgntnNm="Chartered Financial Consultant"/>
<Dsgntn dsgntnNm="Personal Financial Specialist"/>
</Dsgntns>
<PrevRgstns>
<PrevRgstn orgNm="LINCOLN FINANCIAL ADVISORS CORPORATION" orgPK="3978" regBeginDt="2000-04-25" regEndDt="2015-05-11">
<BrnchOfLocs>
<BrnchOfLoc city="HUNTSVILLE" state="AL"/>
<BrnchOfLoc city="HUNTSVILLE" state="AL"/>
</BrnchOfLocs>
</PrevRgstn>
</PrevRgstns>
<EmpHss>
<EmpHs fromDt="04/2015" orgNm="BRIDGEWORTH, LLC" city="HUNTSVILLE" state="AL"/>
<EmpHs fromDt="07/1996" toDt="04/2015" orgNm="LINCOLN FINANCIAL ADVISORS CORPORATION" city="HUNTSVILLE" state="AL"/>
<EmpHs fromDt="07/1996" toDt="04/2015" orgNm="FIRST FINANCIAL GROUP" city="BIRMINGHAM" state="AL"/>
<EmpHs fromDt="04/2015" orgNm="LPL FINANCIAL LLC" city="HUNTSVILLE" state="AL"/>
</EmpHss>
<OthrBuss>
<OthrBus desc="1) 04/30/2015: BRIDGEWORTH FINANCIAL, LLC - DBA FOR LPL BUSINESS (ENTITY FOR LPL BUSINESS) - INV REL - AT REPORTED BUSINESS LOCATIONS - START 01/01/2015 - 1% OF TIME SPENT 2) 04/30/2015: BRIDGEWORTH, LLC - INV REL - AT REPORTED BUSINESS LOCATION(S) - REGISTERED INVESTMENT ADVISOR HYBRID - START 01/2015 - 99% OF TIME SPENT. 3) 5/11/2015: NO BUSINESS NAME - INVESTMENT RELATED - AT REPORTED BUSINESS LOCATION(S) - NON-VARIABLE INSURANCE - STARTED 4/1/2015 - TIME SPENT 1% - LINES OF INSURANCE INCLUDE TERM, WHOLE, UNIVERSAL, LTC, DISABILITY. 4) 6/2/2017 - Bridgeworth Financial - Investment Related - At Reported Business Location(s) - DBA for LPL Business (entity for LPL business) - Started 04/30/2015 - 5 Hours Per Month/3 Hours During Securities Trading. 5) 5/8/2018 - Foster Properties Ltd - Not Investment Related - Home Based - Other-Family Business - Started 12/22/1997 - 1 Hours Per Month/0 Hours During Securities Trading - Handle the majority of business matters for this family business."/>
</OthrBuss>
<DRPs>
<DRP hasRegAction="N" hasCriminal="N" hasBankrupt="N" hasCivilJudc="N" hasBond="N" hasJudgment="N" hasInvstgn="N" hasCustComp="Y" hasTermination="N"/>
</DRPs>
</Indvl>
</Indvls>
</IAPDIndividualReport>
In my subreport I want do display for eg.
Number of clients born in 1972: 34
So in the database I have a list of their birth years
How can I display this number in a field?
Here is a Sample of the data:
<Born> <Name> <BleBle>
1981 Mnr EH Van Niekerk 9517
1982 MEV A BELL 9520
1972 Mnr GI van der Westhuize 9517
1987 Mnr A Juyn 9517
1983 Mev MJC Prinsloo 9513
1972 Mnr WA Van Rensburg 9517
1989 Kmdt EL Van Der Colff 9514
1972 Mnr JS Jansen Van Vuuren 9517
So if this was all the data the output would have to be
Number of clients born in 1972: 3
Create a variable BORN_IN_1972.
Set its "Variable class" to java.lang.Integer.
Set "Calculation" to "Count".
Set "Variable Expression" to $F{Born}.
Set "Initial Value Expression" to 0.
Than add "Summary" band to your report. And put static text "Number of clients born in 1972:" and text field "$V{BORN_IN_1972}" into it.
Assuming birth year is a string:
SELECT COUNT(*)
FROM MyClients
WHERE birth_year = '1972'
And if birth year is being used as an input control:
SELECT COUNT(*)
FROM MyClients
WHERE birth_year = $P{birth_year}
To count non-zero records in jasper use the expression below -
( $F{test} == 0.0 ? null : $F{test} )