How to accept more than one connection with ztcp - tcp

How do I make ZSH's ZTCP module accept more than one connection? Here is my code so far:
zmodload zsh/net/tcp
ztcp -ld3 7000
lfd=3
while true;
do
ztcp -ad4 $lfd
done &
pid=$!
talkfd=4
while true; do read -r line <&$talkfd; echo $line >&$talkfd;
kill $pid
but that doesn't seem to work. Any ideas?

Related

Enter a command for a user

I have written a ZSH function whose output is a command line which runs a program I need the user to be able to interact with.
At the moment I just echo the command line and instruct the user to copy-paste it so that they have the necessary access to its pipes, however is there a way I can just have the function finish by entering the command for the user as if they had copied and pasted it themselves?
I have looked into using zle but that seems to require a key binding, whereas I just want the user to be able to run: myzshfunction arg1 and the ultimate result to be their terminal attached to the program launched as a result of some processing of their arg1.
$ myzshfunction arg2*2
Run this command! foobar baz4
$ foobar baz4
...
The function looks something like this:
myzshfunction() {
if [[ $# = 0 ]]
then
echo "usage: myzshfunction 1.2.3.4"
return
fi
local creds=`curl "https://xxx/$1/latest" | jq -r 'x'`
local cred_arr=("${(#s|/|)creds}")
local pwd_pipe=$(mktemp -u)
mkfifo $pwd_pipe
exec 3<>$pwd_pipe
rm $pwd_pipe
echo $cred_arr[2] >&3
echo "Run this: sshpass -d3 ssh -o StrictHostKeyChecking=no -o UserKnownHostsFile=/dev/null "$cred_arr[1]#$1"
exec 3>&-
}
TIA
Use print -z to add text to the buffer. From the documentation:
-z Push the arguments onto the editing buffer stack, separated by spaces.
Calling foo, defined below, will result in hi being placed on the command line as if the user had typed it. For example,
% foo () { print -z hi; }
% foo
% hi
The best solution I could come up with was to use zle - the Zsh Line Editor.
This lets you update the command the user is currently editing, which to me feels a bit hacky. I would prefer a solution that lets you call a function, hit return, and then cleanly run a function with STDIO attached to your terminal as if you had run the resulting command line.
Perhaps you could emulate this by bindkey'ing the return key and doing some sort of decision/routing from there to see if the user wants to call myfunc. For now, my solution requires the Esc+i sequence is entered after typing a target for $host.
zle-myfunc() {
apikey=$(keychain-environment-variable api-key)
if [ $? -ne 0 ]; then
echo "Add your api-key to the keychain: "
BUFFER='security add-generic-password -U -a ${USER} -D "environment variable" -s "api-key" -w'
zle accept-line
return 1
fi
local host=$BUFFER
zle kill-buffer
local creds=`curl ..." | jq -r ...`
if [ -z creds ]; then
echo "Couldn't get creds, check your network"
return 1
fi
local creds_arr=("${(#s|/|)creds}")
local pwd_pipe=$(mktemp -u)
mkfifo $pwd_pipe
exec 3<>$pwd_pipe
# anonymise the pipe
rm $pwd_pipe
echo "$creds_arr[2]" >&3
BUFFER="sshpass -d3 ssh -o StrictHostKeyChecking=no -o UserKnownHostsFile=/dev/null $creds_arr[1]#$host"
zle accept-line
# exec 3>&-
}
zle -N zle-myfunc
bindkey '\ei' zle-myfunc

Running custom zsh function for tmux status bar not displaying output

I'm wrote a function called test_status that I am trying to incorporate in my tmux status bar. To give some background, my tests will output to a file called .guard_result with either success or failure and the test_status function reads from that file and echoes a 💚 if my tests are passing and a ❤️ if they are failing.
The good news is running test_status works just fine, I'm just having trouble getting it to work with tmux. What am I missing here?
# ~/.oh-my-zsh/custom/aliases.zsh
function test_status {
if [ ! -f "./.guard_result" ]; then
echo "?"
return 1
fi
result="$(cat ./.guard_result)"
if [[ $result == *"success"* ]]
then
echo "💚";
elif [[ $result == *"fail"* ]]
then
echo "❤️";
fi
}
This function works... Here is Tmux configuration (which doesn't show result):
# ~/.tmux.conf
set -g status-right "#(test_status) #[fg=colour245]%d %b %Y #[fg=white]:: #[fg=colour245]%l:%M %p"
I know I must be missing something simple... Thanks for your help!
tmux passes shell commands to /bin/sh not zsh. And even if tmux would use zsh, the function would not be available in that context as ~/.zshrc, which loads oh-my-zsh, is only read for interactive shells.
In order to get the the output of test_status into tmux, I would suggest to put the function into a zsh script and call that.
You can either source ~/.oh-my-zsh/custom/aliases.zsh from within the script and then call test_status:
#!/usr/bin/zsh
# ^ make sure this reflects the path to zsh (`type zsh`)
source ~/.oh-my-zsh/custom/aliases.zsh
test_status
Or you can just put the entire function into the script, so as to not clutter alias.zsh:
#!/usr/bin/zsh
function test_status {
if [ ! -f "./.guard_result" ]; then
echo "?"
return 1
fi
result="$(cat ./.guard_result)"
if [[ $result == *"success"* ]]
then
echo "💚";
elif [[ $result == *"fail"* ]]
then
echo "❤️";
fi
}
Safe the script somewhere (e.g. /path/to/test_status.zsh), make it executable (chmod a+x /path/to/test_status.zsh) and call it by path in the tmux configuration.

Unix grep multiple patterns every hour

Suppose, there are 4 different types of patterns(errors) in a log each may occur time to time. Eg: "timeout exception", "ldap error "," db error "," error four". Can any one place provide me a script about:- how to grep multiple patterns in a log every hour and if the script finds the any pattern then it should send alert to me only once, no duplicate alerts. Please help me. Thank you
#!/bin/bash
while true; do
export ERRORS=`cat YOUR_LOG_FILE | grep -e "(timeout exception)|(ldap error)|(db error)|(error four)"
if [ $ERRORS ]; then
# sendmail or any other kind of "alert" you prefer.
echo $ERRORS | sendmail "your#email.com"
fi
sleep 1h
done
Make a crontab entry that will run once an hour. That entry can call your script:
logfile=/path/to/logfile/application.out
function send_alert {
# Some sendmail or other tool to send your alert using the args
printf "I want to alert about %s" "$*"
}
# Solution only announcing errors without sending them
grep -qE "timeout exception|ldap error|db error|error four" ${logfile} &&
send_alert "grep found something"
# Solution sending number of errorlines
errorlinecount=$(grep -c "timeout exception|ldap error|db error|error four" )
if [ ${errorcount} -gt 0 ]; then
send_alert "grep found ${errorcount} disturbing lines"
fi

Error Handling while running sqlplus from shell scripts

I need to validate whether DB connection is success/failure.
This is my code
report=`sqlplus -S /nolog << EOF
WHENEVER OSERROR EXIT 9;
WHENEVER SQLERROR EXIT SQL.SQLCODE;
connect <<username>>/<<Password>>#hostname:port
set linesize 1500
set trimspool on
set verify off
set termout off
set echo off
set feedback off
set heading on
set pagesize 0
spool extract.csv
<<My SQL Query>>
spool off;
exit;
EOF`
I have tried the below option based on the thread Managing error handling while running sqlplus from shell scripts but its picking the first cell value rather than the connection status.
if [ $report != 0 ]
then
echo "Connection Issue"
echo "Error code $sql_return_code"
exit 0;`enter code here`
fi
Please advise.
I needed something similar but executed it a bit differently.
First, I have list.txt which contains the databases that I would like to test. I am using wallet connections but this could be edited to hold username/password.
list.txt:
DB01 INSTANCE1.SCHEMA1
DB02 INSTANCE2.SCHEMA2
DB03 INSTANCE3.SCHEMA3
DB04 INSTANCE4.SCHEMA4
I have OK.sql which contains the query that I want to run on each database.
OK.sql:
select 'OK' from dual;
exit
Last, I user test.sh to read list.txt, attempt to connect and run OK.sql on each line, and record the result in (drumroll) result.txt.
test.sh:
. /etc/profile
rm result.txt
while read -r name wallet; do
echo "BEGIN-"$name
if (sqlplus -S /#$wallet #OK.sql < /dev/null | grep -e 'OK'); then
echo $name "GOOD" >> result.txt
else
echo $name "BAD" >> result.txt
fi
echo "END-"$name
done < list.txt
After the run check your result.txt.
result.txt:
DB01 BAD
DB02 GOOD
DB03 GOOD
DB04 GOOD
I hope this helps.

UNIX valid_password

why in Cygwin Terminal - the if statement work
and ubuntu - unix - not working for
this code :
#!/bin/sh
valid_password="pass"
echo "Please enter the password:"
read password
if [ "$password" == "$valid_password" ]
then
echo "You have access!"
else
echo "Access denied!"
fi
#emil pointed the answer:
if [ "$password" = "$valid_password" ]
instead of
if [ "$password" == "$valid_password" ]
Also: did you give the script executing permissions? Try
chmod +x script_name
because the correct syntax to [ is:
[ a = b ]
From your error message it sounds like you wrote:
if ["$password" = "$valid_password" ]
change this to:
if [ "$password" = "$valid_password" ]
notice the space after [. if just takes a shell command, try to run it and depending if the exit code from the program is 0 it will run the commands inside the if statement.
In your terminal, write i.e.:
user#localhost$ true; echo $?
0
to test your if statement:
user#localhost$ pass=pass; valid=pass
user#localhost$ if [ "$pass" = "$valid" ]; then echo 'You have access!'; fi
As #nullrevolution said, the ! is evaluated if you use double quotes, it will try to run last command in your shell history, in this case that is matching u.
user#localhost$ uname
Linux
user#localhost$ !u
uname
Linux
user#localhost$ echo "!"
sh: !: event not found
This is because the ! is evaluated before the double quotes are matched, and echo is run. If you still want to use double quotes, you will have to escape the ! outside the quotes:
echo "Access denied"\!
#nullrevolution also said you could try with bash, which has a builtin syntax for the expression inside if statements.
#!/bin/bash
valid_password=pass
echo "Please enter the password:"
read password
if [[ "$password" == "$valid_password" ]]; then
echo 'You have access!'
else
echo 'Access denied!'
fi
Also in your program I guess you do not want to echo the password in the terminal, to turn off echo temporary change:
read password
to
stty -echo
read password
stty echo
if you forgot to write stty echo to turn on echo again, just write reset in your terminal, and it will reset the terminal to default settings.
A useful tutorial for bourn shell script can be found here:
http://www.grymoire.com/Unix/Sh.html

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