I'm looking to copy a set of files from multiple directories into one new folder using this code:
file.copy(from = paste0('directory1', all_files),
to = paste0('directory2', all_files))
all_files is a character vector of files including their full path location.
I've also tried using basename(all_files) with no luck.
I've tried using the code above
Just following up - I've figured it out.
It wasn't working because the paste was redundant, this code fixed it:
for (n in 1:length(all_files)) {
file.copy(from = all_files[n],
to = 'directory2')
}
I think you need to use the below code, in the to argument we need to use the new folder path where the files need to the copied over
file.copy(from = paste0('directory1', all_files),
to = directory2)
Related
In my main folder i have many sub folders like AA,BB,CC,DD ...etc. and all folders have a common script named run_script.R and i want to run this script in every folder. folder can be any amount.
Its working abut running in first folder only ,but i wanted it to run in every folder.
also when i am using setwd(folder) then showing error
Error in setwd(folder) : cannot change working directory
data_folder <- "C:/Users/mosho/Desktop/New folder (2)/"
allfolders <- data.frame(Folders = list.dirs(path = data_folder, recursive = F, full.names = F))
r_scripts <- "run_script.R"
for (folder in allfolders$Folders) {
#setwd(folder)
message(folder)
source(paste0(data_folder,folder,"/",r_scripts))
}
You are on a right path, I did some minor tweaks to your script which will resolve the issue. The points missing in your scripts are;
the allfolders contains the folder name not the entire explicit path. To set the working directory you need to set give the explicit path, by only calling the folder name will result into error unless you existing working directory is contains that folder. Anyways, its best practice to work with full path names.
also to simplify setting up allfolders as list for iterator will make your life lot easier than a data frame
Below is my work-out;
I created some dummy folders (DIC01, DIC02, DIC03...) under path "C:\Users\XXXXXX\Documents\TEST MAIN", and placed code run_script.R inside each one. This run_script.R contains simple code print("Hello World !!")
Next I set initial working directory where to the path where all the folders present i.e. to path "C:\Users\XXXXXX\Documents\TEST MAIN". Next listed the folders/directories present within this path as a list instead of data frame. Next is for loop which iterate over list of folder names. Inside we reset the working directory by the folder name and source the R code.
data_folder <- "C:\\Users\\XXXXXX\\Documents\\TEST MAIN"
setwd(data_folder)
allfolders <- list.dirs(path = data_folder, recursive = F, full.names = F)
r_scripts <- "run_script.R"
for (folder in allfolders) {
print(folder)
setwd(paste0(data_folder,"\\",folder))
source(paste0(data_folder,"\\",folder,"\\",r_scripts))
}
The result I get after the execution is something like this. First the name of the directory and then execution result.
I hope this resolves you problem. If yes Like/Up vote the answer and let me know.
I have tried looking at File extension renaming in R and using the script without any luck. My question is very much the same.
I have a bunch of files with the a file extension that I want to change. I have used the following code but cannot get the last step to work.
I know similar questions have been asked before but I'm simply stuck and therefore reaching out anyway.
startingDir<-"/Users/anders/Documents/Juni 2019/DATA"
endDir<-"/Users/anders/Documents/Juni 2019/DATA/formatted"
#List over files in startingDir with the extension .zipwblibcurl that I want to replace
old_files<-list.files(startingDir,pattern = "\\.zipwblibcurl")
#View(old_files)
#Renaming the file extension and making a new list i R changing the file extension from .zipwblibcurl to .zip
new_files <- gsub(".zipwblibcurl", ".zip", old_files)
#View(new_files)
#Replacing the old files in the startingDir. Eventually I would like to move them to newDir. For simplicity I have just tried as in the other post without any luck:...
file.rename( old_files, new_files)
After running file.rename I get the output FALSE for every entry.
The full answer here, including comment from #StephaneLaurent: make sure that you have full.names = TRUE inside the list.files(); otherwise the path to the file will not be captured, just the file name.
Full working snippet:
old = list.files(startingDir,
pattern = "\\.zipwblibcurl",
full.names = TRUE) #
# replace the file names
new <- gsub(".zipwblibcurl", ".zip", old )
# Rename old files names to the new file names
file.rename(old, new)
Like #StéphaneLaurent said, it's most likely that R tries to look in the current working directory for the files and can't find them. You can correct this by adding
file.rename(paste(startingDir, old_files, sep = "/"), paste(newDir, new_files, sep = "/"))
I am trying to copy a large number of files from one folder to another. We need to restructure the folders, so there is a translation from the old folder path to a new one. The old folder structure is also nested.
Currently the code I have is not throwing any errors, but is returning false on executing the file.copy for all files.
ETA: When I copy a single file, it works.
allFilePaths <- list.files('./oldTopLevelFolder', recursive = TRUE)
testIds <- c(1:4)
otherTestIds <- c(5:8)
allNewFolders <- paste('newTopLevelFolder', testIds, 'aFolderName', otherTestIds, sep = '/')
lapply(allNewFolders, dir.create, recursive = TRUE)
file.copy(from=allFilePaths, to=allNewFolders,
copy.mode = TRUE)
file.copy can copy multiple files, but only to a single destination folder by the looks of it.
In order to copy a bunch of files into varying destination folders, the following will do the job, where allOldFilePaths is a column containing the old filepath where each file currently exists, and allNewFilePaths is a column containing the new folder path for each file.
# function to copy a single file
copySingleFile <- function(oldPath, newPath) {
file.copy(from=oldPath, to=newPath,
copy.mode = TRUE)
}
# copy each file to its new folder path
mapply(copySingleFile, allFilePathsWithRoot, allNewFilePaths)
I am trying to loop through many folders in a directory, looking for a particular xml file buried in one of the folders. I would then like to save the location of that file and then run my code against that file (I will not include that code in this). What I am asking here is to loop through all the folders and then open the specific file.
For example:
My main folder would be: C:\Parsing
It has two folders named "folder1" and "folder2".
each folder has an xml file that I am interested in, lets say its called "needed.xml"
I would like to have a scrip that loops through the directory and finds those particular scripts.
Do you know how I could that in R.
Using list.files and greplyou could look recursively through all sub-folders
rootPath="C:\Parsing"
listFiles=list.files(rootPath,recursive=TRUE)
searchFileName="needed.xml"
presentFile=grepl(searchFileName,listFiles)
if(nchar(presentFile)) cat("File",searchFileName,"is present at", presentFile,"\n")
Is this what you're looking for?
require(XML)
fol <- list.files("C:/Parsing")
for (i in fol){
dir <- paste("C:/Parsing" , i, "/needed.xml", sep = "")
if(file.exists(dir) == T){
needed <- xmlToList(dir)
}
}
This will locate your xml file and read it into R as a list. I wasn't clear from your question if you wanted the output to be the data itself or just the directory location of your data which could then be supplied to another function/script. If you just want the location, remove the 'xmlToList' function.
I would do something like this (replace *.xml with your filename.xml if you want):
list.files(path = "C:\Parsing", pattern = "*.xml", recursive = TRUE, full.names = TRUE)
This will recursively look for files with extension .xml in the path C:\Parsing and return the full path of the matched files.
I want to copy/paste a file from one folder to another folder in windows using R, but it's not working. My code:
> file.rename(from="C:/Users/msc2/Desktop/rabata.txt",to="C:/Users/msc2/Desktop/Halwa/BADMASHI/SCOP/rabata.tx")
[1] FALSE
If you wanted a file.rename()-like function that would also create any directories needed to carry out the rename, you could try something like this:
my.file.rename <- function(from, to) {
todir <- dirname(to)
if (!isTRUE(file.info(todir)$isdir)) dir.create(todir, recursive=TRUE)
file.rename(from = from, to = to)
}
my.file.rename(from = "C:/Users/msc2/Desktop/rabata.txt",
to = "C:/Users/msc2/Desktop/Halwa/BADMASHI/SCOP/rabata.txt")
Please just be aware that file.rename will actually delete the file from the "from" folder. If you want to just make a duplicate copy and leave the original in its place, use file.copy instead.
Use file.copy() or fs::file_copy()
file.copy(from = "path_to_original_file",
to = "path_to_move_to")
Then you can remove the original file with file.remove():
file.remove("path_to_original_file")
Update 2021-10-08: you can also use fs::file_copy(). I like {fs} for consistent file and directory management from within R.
You can try the filesstrings library. This option will move the file into a directory. Example code:
First, we create a sample directory and file:
dir.create("My_directory")
file.create("My_file.txt")
Second, we can move My_file.txt into the created directory My_directory:
file.move("My_file.txt", "My_directory")
You are missing a "t" letter in the second extension. Try this:
file.rename(from="C:/Users/msc2/Desktop/rabata.txt",to="C:/Users/msc2/Desktop/Halwa/BADMASHI/SCOP/rabata.txt").
Additionally, it could be worth it to try the file.copy() function. It is specifically designed to copy files instead of renaming.