create dataframe of r2, residuals, and coeff from linear models - r

Question

Exactly like this question but how do you also get the R squared value for each model? link
Sample data
test <- data.frame(row=c(1:16),
plot = c(1,1,1,1,1,2,2,2,3,3,3,3,3,3,3,3),
logT = c(1.092,1.091,1.0915,1.09,1.08,1.319,1.316,1.301,1.2134,1.213,1.21,1.22,1.23,1.20,1.19,1.19),
utc_datetime = c(2020-03-05T00:00:00Z,2020-03-05T00:30:00Z,2020-03-05T01:00:00Z,2020-03-05T01:30:00Z,2020-03-05T02:00:00Z, 2020-03-06T01:00:00Z,2020-03-06T01:30:00Z,2020-03-06T02:00:00Z,
2020-03-10T02:00:00Z,2020-03-10T02:30:00Z,2020-03-10T03:00:00Z,2020-03-10T03:30:00Z,2020-03-10T04:00:00Z,2020-03-10T04:30:00Z,2020-03-10T05:00:00Z,2020-03-10T05:30:00Z,),
hrs_since = 1,2,3,4,5,1,2,3,1,2,3,4,5,6,7,8))
A deeper explanation of the data I am dealing with is here but I believe the sample data provided above would suffice data. Ideally, I would want to use the utc_datetime as the x axis/IV value but no code I've tried works with using that so I created the hrs_since variable which works.
I am looking for an output datframe that looks something like this:
plot
slope(coeff)
r2 value
rsd
1
2.1
.96
.01
2
1.3
.85
.01
3
.8
.99
.02
When I run the code below...
output <- ddply(test, "plot", function(x) {
model <- lm(logT ~ hrs_since, data = x)
coef(model)
})
I create a dataframe that looks like this:
plot
(Intercept)
hrs_since
1
2.1
.96
2
1.3
.85
3
.8
.99
But when I add summary(model)$r.squared to it, such as below...
output <- ddply(test, "plot", function(x) {
model <- lm(logT ~ hrs_since, data = x)
coef(model)
summary(model)$r.squared
})
I create a dataframe that looks like this:
plot
V1
1
0.98
2
0.97
3
0.89
Where the correct R squared value has been added as column V1 to the df "output", but I have for some reason lost the coeff column? Ideally, I want to also add rsd and maybe st.dev columns but have not attempted yet because getting the R squared and coeff columns correct are the most important parameters I need. Also, originally I tried using r.squared(model) instead of summary(model)$r.squared in the line below coef(model), but this resulted in getting the error "Error in UseMethod("pmodel.response") :
no applicable method for 'pmodel.response' applied to an object of class "lm""
Also, I tried a method using this code as well and it worked but the coeff was not returned in the parameters returned for each plot
output <- test %>%
group_by(plot) %>%
do(glance(lm(lnT~hrs_since, data=.)))
Thank you in advance!

Answer 1

Here's an approach that nests each of the models in a dataframe and captures the results in the dataframe as well. Then uses the broom package to extract the statistics. There are two different broom functions that extract the intercept and r2, so I run them separately and combine into one dataframe.
library(dplyr)
library(modelr)
library(tidyverse)
dat_all <- data.frame()
#nest the datasets as separate dataframes
for (p in unique(test$plot)){
data <- data.frame(x = test$logT[test$plot == p], y = test$hrs_since[test$plot == p])
names(data) <- c("logT", "hrs_since")
dd <- data.frame(plot = p, data = data) %>%
group_by(plot) %>%
nest()
dat_all <- rbind(dat_all, dd)
}
myModel <- function(x){
lm(data.logT ~ data.hrs_since, data = x)
}
#use map to run the model and each of the nested dataframes
dat_all <- dat_all %>%
mutate(model = map(data, myModel))
#extract the intercepts
i <- dat_all %>%
mutate(tidy = map(model, broom::tidy)) %>%
unnest(tidy) %>%
filter(term == "(Intercept)") %>%
select(plot, intercept = estimate)
#extract r2
r <- dat_all %>%
mutate(glance = map(model, broom::glance)) %>%
unnest(glance) %>%
select(plot, r.squared)
#combine statistics by plot
results <- i %>%
left_join(r, by = "plot")
plot intercept r.squared
<dbl> <dbl> <dbl>
1 1 1.10 0.618
2 2 1.33 0.871
3 3 1.22 0.380