Figma: stroke length in percents - is it possible? - stroke

Can you help me make stroke on rectangle (with rounded corners) but not all the rectangle, only part of it (for example 74% of shape stroke length)?
Thank you for help!
May be there is some plugin...
example

Related

Is there a way to create a hollowed circle in A-Frame?

I'm trying to build a Flower of Life VR example using A-Frame.
The closest thing that I found is using the opacity property in <a-circle>.
Is there a way to create just the border of the circle?
Not sure if it fits your use case but you could use a cylinder with a small height:
https://aframe.io/docs/1.0.0/primitives/a-cylinder.html
Or a tube:
https://github.com/donmccurdy/aframe-extras/tree/master/src/primitives
Or just a flat plane with png texture with a circle with transparency

Qt Qpixmap generates a blurry image

As part of a larger project i'm trying to draw basic shapes on a QPixmap but the generated image always appears blurry ie. the circle is not a pure red circle, the edges are blurred and the colour is not true red as expected. This becomes an issue later on with what I need the image for. Here's the relevant code snippet, i've played around with antialiasing options and render hints but i've not had any luck. Any help would be much appreciated!
QPixmap pixmap(QSize(300,300));
QPainter painter( &pixmap);
painter.setRenderHint(QPainter::Antialiasing);
painter.setRenderHint(QPainter::SmoothPixmapTransform);
painter.fillRect( QRectF(0, 0, 300, 300),Qt::white);
painter.setPen(Qt::red);
painter.drawEllipse( QPoint(150,150), 75, 75);
painter.setPen(Qt::green);
QLineF line(30, 30, 30, 270);
painter.drawLine(line);
pixmap.save("test1.jpg", "jpg", 100);
I've been asked to include an image to show the issue, here's a close up of the image which shows the green line not being true green and the red circle not being true red and with blurred edges.
The problem that you have with the red color is that Qt by default uses chroma color subsampling (2x2 blocks) when saving to JPG format.
The only way to avoid this problem is using another format. Saving the same image with PNG format returns a pure red circle (255,0,0).
Regarding to the blurry circle, it occurs because of QPainter::Antialiasing RenderHint. In your case, not using any renderHints shows a sharp image. Below you can see your image with pure red color (PNG format) and sharp edges (not RenderHints). Take into account that the blurriest approach will be using QPainter::Antialiasing so avoid it if you are aiming to image sharpeness. Depending on your needs you could try QPainter::HighQualityAntialiasing RenderHint, but nothing else.

Increasing svg circle stroke-width brings down inner circle size

My understanding is, svg circle with stroke-width renders two concentric circles (or a doughnut like image) with its internal radius as r and its external radius as r plus stroke-width.
It looks like,
But, as one can see when the stroke-width increases from 4 to 24, the inner circle has become smaller?
Plunker code is here.
So, what is wrong with the formula,
external radius = r + stroke-width
More importantly, why does inner circle size depend on stroke width?
I'm afraid your understanding is wrong.
An SVG circle with stroke-width renders two concentric circles (or a doughnut like image) with its internal radius as r - ½ the stroke width and its external radius as r + ½ stroke-width.

How can I set the backgroundColor of a WKInterfaceController programmatically?

I couldn't find any way of changing the overall background color of the Watch app interface programmatically.
I therefore tried creating a fullscreen WKInterfaceGroup and changing the backgroundColor of that.
centralGroup.setBackgroundColor(UIColor(red: 1.0, green: 1.0, blue: 1.0, alpha: 1.0))
However, I still have unfilled rounded corners and lines on borders.
Is there any way to achieve my goal, of an edge-to-edge background color that fills the screen?
While you can set a background color for a WKInterfaceController in the storyboard, there is no API that lets you programmatically set it in the present Xcode 6.2 beta 3.
However, you can create a full screen WKInterfaceGroup and set the color of that programmatically. If you also setCornerRadius: to 0 you get the following result:
Clearly, there are still black lines at the edges here. The other possibility was that setting a solid color image as the background might perhaps scale to fill the full screen with one of the scaling options, but I tested this and the result is identical to the above.
However, it is important to consider the hardware this will be running on. Apple have said more than once in their public statements about the Watch that the intersection between the laminated screen and the edges is so seamless that you essentially can't tell where the screen ends and the edges begin. Taking this at face value, as long as you set the background color of the WKInterfaceController to clear or black in interface builder, so that these edges are black to match the screen surround, then these black lines should be invisible to the end user and are something you can safely ignore.
This is how I done it:
Add WKInterfaceGroup and setCornerRadius to 0
Go to WKInterfaceController Attribute Inspector and change Left/Right insets to 0 (Fig.1) (This will remove the extra black line on the left & right side)
Change the color of the WKInterfaceGroup to whatever you want :)
Fig.1
Change insets of Your WKInterfaceController to custom and set all to 0. Also, change corner radius of group to 0 too. Enjoy.
Try changing the corner radius of the WKInterfaceGroup to 0. You can use setCornerRadius: to change the corner radius.

How to make a diagonal css gradient without the colors blending together(a sharp color change) that's displaced 70% to the right?

I can't find any css gradient color generators that do what i'm trying to do.
A diagonal gradient with no blending, just a sharp color change from #252525 to #0099ff(for example), with the line where the two colors meet being about 70% from the left of the container, so the line would start a little more than halfway across the x axis of the container, and the line would end maybe halfway down the y axis of the right side of the container.
If you would be able to emphasize what numbers are specifically for calculating the degree of tilt, and the x y coordinates of the beginning of the gradient, that would be so extremely helpful. I'm just confused at this point.

Resources