I am finding the following problem trying to save a new document into Firestore database by calling the related POST API and manually setting the document ID.
I am using Python but I suppose that the problem is not related to the language.
I try to explain what I have done and what is not working. My first attempt (that works but automatically set the document ID on Firestore) was:
First of all, I created this JSON document that will be the payload of my API:
# Convert the record to a dictionary
doc = {
'fields': {
'surname': {'stringValue':record[2]},
'firstName': {'stringValue':record[1]},
'socialSecurityCode': {'stringValue':codici_fiscali_list_as_string},
'city': {'stringValue':record[4]},
'personalPhone': {'stringValue':record[5]},
'personalPhone2': {'stringValue':record[6]},
'personalEmail': {'stringValue':emails_list_as_string},
'pazPres': {'stringValue':record[7]},
'pazNotes': {'stringValue':record[8]},
'pazMemo': {'stringValue':record[9]},
'isArchived': {'booleanValue':isArchived},
'isMigrated': {'booleanValue':True},
#'decomposition_keyword_search_list':{'arrayValue':{'values':decomposition_keyword_search_list}}
"decomposition_keyword_search_list":{
"arrayValue":{
"values":[
]
}
}
}
}
then I perform the API call by these lines:
api_endpoint = 'https://firestore.googleapis.com/v1/projects/MY-PROJECT-NAME/databases/(default)/documents/test/'
response = requests.post(api_endpoint, json=doc)
It works fine and it put the expected document into my test collection. But in this way, the ID was automatically generated by Firestore. For some reason, I have to use the content of a variable as ID (my ID must be the value of my record[0] that is a unique string)
So I tried to change the previous API endpoint in the following way:
api_endpoint = 'https://firestore.googleapis.com/v1/projects/MY-PROJECT-NAME/databases/(default)/documents/test/'+ record[0]
I expected that it creates a document using the record[0] as a document ID but it seems that I am wrong since I am obtaining the following error message:
Error saving document: {
"error": {
"code": 400,
"message": "Document parent name \"projects/MY-PROJECT-NAME/databases/(default)/documents/test\" lacks \"/\" at index 71.",
"status": "INVALID_ARGUMENT"
}
}
So, what is wrong? What am I missing? How can correctly manually set the ID of the document that I am creating calling the previous API?
Take a look at the documentation for creating documents. If you want to specify a document ID, it says you should pass that as a query parameter called documentId:
The client-assigned document ID to use for this document.
Optional. If not specified, an ID will be assigned by the service.
Related
Let's say I have a data model with some optional properties. This could be for example a user object with a "firstname", a "lastname" and an optional "website" property.
In Cloud Firestore only user documents with a known website would have the "website" property set, for all other user documents this property would not exist.
My questions is now, how to query for all user documents without a "website" property?
Documents can contain properties with a null value data type (see data types documentation). This will then allow you to construct a query to limit results where the website property is null.
This is not quite the same as a missing property, but if you use custom objects to write data to Firestore, empty properties will automatically be saved as null rather than not at all. You can also manually/programmatically write a null value to the database.
In Android, I tested this using the following:
FirebaseFirestore.getInstance().collection("test").whereEqualTo("website", null).get();
Where my database structure looked like:
This returned only the document inuwlZOvZNTHuBakS6GV, because document 9Hf7uwORiiToOKz6zcsX contains a string value in the website property.
I believe you usually develop in Swift, where unfortunately custom objects aren't supported, but you can use NSNull() to write a null value to Firestore. For example (I'm not proficient in Swift, so feel free to correct any issues):
// Writing data
let docData: [String: Any] = [
"firstname": "Example",
"lastname": "User",
"website": NSNull()
]
db.collection("data").document("one").setData(docData) { err in
if let err = err {
print("Error writing document: \(err)")
} else {
print("Document successfully written!")
}
}
// Querying for null values
let query = db.collection("test").whereField("website", isEqualTo: NSNull())
The documentation doesn't mention a method to query for values that don't exist, so this seems like the next best approach. If anyone can improve or suggest alternatives, please do.
I have website written in plain javascript to keep daily to-do tasks and the app crashed lately because different tasks of the same date was created on accident. My question is...
how can i write an if statement that checks if a document from a collection has a property (in my case the date) that is equal to the one in the input field of my form. i guess it should check after i click submit? if it exists, creation should be denyed, if not, ok to proceed.
i am using cloud firestore by the way... many thanks in advance for the help!
First, make a query to get a document that has same date:
var query = db.collection("yourCollectionName").where("date", "==", dateInInputfield);
query.get().then(function(querySnapshot) {
if (querySnapshot.empty) {
//empty
} else {
// not empty
}
});
If empty{you can proceed}, if notEmpty{some other task already exist on same date}
If you are making an app like this, a cleaner approach will be to name the id of a document as it's date, for eg. if a task is created at timestamp of 1234567, create a document named 1234567 and inside it, store all the necessary information.
By following this approach, if you create a new task, simply fetch a document by the name in inputfield,
var docRef = db.collection("yourCollectionName").doc("date");
docRef.get().then(function(doc) {
if (doc.exists) {
//this means some other document already exists
} else {
//safe to create a new document by this date.
}
}).catch(function(error) {
console.log("Error:", error);
});
Let's say I have a data model with some optional properties. This could be for example a user object with a "firstname", a "lastname" and an optional "website" property.
In Cloud Firestore only user documents with a known website would have the "website" property set, for all other user documents this property would not exist.
My questions is now, how to query for all user documents without a "website" property?
Documents can contain properties with a null value data type (see data types documentation). This will then allow you to construct a query to limit results where the website property is null.
This is not quite the same as a missing property, but if you use custom objects to write data to Firestore, empty properties will automatically be saved as null rather than not at all. You can also manually/programmatically write a null value to the database.
In Android, I tested this using the following:
FirebaseFirestore.getInstance().collection("test").whereEqualTo("website", null).get();
Where my database structure looked like:
This returned only the document inuwlZOvZNTHuBakS6GV, because document 9Hf7uwORiiToOKz6zcsX contains a string value in the website property.
I believe you usually develop in Swift, where unfortunately custom objects aren't supported, but you can use NSNull() to write a null value to Firestore. For example (I'm not proficient in Swift, so feel free to correct any issues):
// Writing data
let docData: [String: Any] = [
"firstname": "Example",
"lastname": "User",
"website": NSNull()
]
db.collection("data").document("one").setData(docData) { err in
if let err = err {
print("Error writing document: \(err)")
} else {
print("Document successfully written!")
}
}
// Querying for null values
let query = db.collection("test").whereField("website", isEqualTo: NSNull())
The documentation doesn't mention a method to query for values that don't exist, so this seems like the next best approach. If anyone can improve or suggest alternatives, please do.
I started working with Firebase and Vue also with VueFire and i dont understand how to update child nodes at Firebase.
I opened a firebase project and connected to it and i can push data to it.
Firebase
I made a vue component
import db from '../FireBase'
let team = db.ref('Teams');//Reference to Teams at firebase
let miss = db.ref().child('Teams'); //Attempt to get to the children of Teams
export default {
name: "App",
firebase: {
Teams_loc: db.ref('Teams'),
Mission: this.Teams_loc.child('Teams'),
missionKey: db.ref().child('Teams').push("").key,
},
...
I manage to get the Teams from firebase and send data to it:
this.$firebaseRefs.Teams_loc.push({
"test": "tester"
});
Which works but when i try to update the children inside
this.miss.push({
"where": "am i"
})
I get the following error
Cannot read property 'child' of undefined
And when i try to update a child
this.$firebaseRefs.missionKey.update(arr[0]);//arr[0] is an object
I tried looking at quite a few places but nothing seems to do the trick.
Thanks,
When you do the following you are doing an error at the second line.
Teams_loc: db.ref('Teams'),
Mission: this.Teams_loc.child('Teams'),
There is no child of the Teams node that has a key with the value `Teams.
So if you want to update an item, you first have to get its key (e.g. -LEzOBT-mp.....) and do as follows, as explained in the doc:
updateItem: function (item) {
// create a copy of the item
const copy = {...item}
// remove the .key attribute
delete copy['.key']
//possibly update (or add) some values of (to) the item
this.$firebaseRefs.Teams_loc.child(item['.key']).set(copy)
}
Also (if I am not mistaking) doing db.ref() will generate an error because you have to pass a value to ref().
I suggest that you study a bit more the doc and the example: https://github.com/vuejs/vuefire and https://github.com/vuejs/vuefire/blob/master/examples/todo-app/index.html
Update following your comment. Details on how to "know the random generated key"
According to the documentation:
Each record in the bound array will contain a .key property which
specifies the key where the record is stored. So if you have data at
/Teams/-LEzOBT-mp...../, the record for that data will have a .key of
"-LEzOBT-mp.....".
Look at this part of the doc: https://github.com/vuejs/vuefire#array-bindings.
So with this you will get all the keys of the Teams object. You have now to choose the item you want to update.
You could also declare a query in your firebase object, like:
firebase: {
team21483: this.database
.ref('Teams')
.orderByChild('teamCode')
.equalTo('21483')
}
and you would get an array with only one team, the one with TeamCode = 21483.
The best approach, in this latest case, is to manually bind to this Firebase query with the $bindAsArray (or possibly the $bindAsObject) instance methods, using a variable that you pass to equalTo().
Let's say I have a data model with some optional properties. This could be for example a user object with a "firstname", a "lastname" and an optional "website" property.
In Cloud Firestore only user documents with a known website would have the "website" property set, for all other user documents this property would not exist.
My questions is now, how to query for all user documents without a "website" property?
Documents can contain properties with a null value data type (see data types documentation). This will then allow you to construct a query to limit results where the website property is null.
This is not quite the same as a missing property, but if you use custom objects to write data to Firestore, empty properties will automatically be saved as null rather than not at all. You can also manually/programmatically write a null value to the database.
In Android, I tested this using the following:
FirebaseFirestore.getInstance().collection("test").whereEqualTo("website", null).get();
Where my database structure looked like:
This returned only the document inuwlZOvZNTHuBakS6GV, because document 9Hf7uwORiiToOKz6zcsX contains a string value in the website property.
I believe you usually develop in Swift, where unfortunately custom objects aren't supported, but you can use NSNull() to write a null value to Firestore. For example (I'm not proficient in Swift, so feel free to correct any issues):
// Writing data
let docData: [String: Any] = [
"firstname": "Example",
"lastname": "User",
"website": NSNull()
]
db.collection("data").document("one").setData(docData) { err in
if let err = err {
print("Error writing document: \(err)")
} else {
print("Document successfully written!")
}
}
// Querying for null values
let query = db.collection("test").whereField("website", isEqualTo: NSNull())
The documentation doesn't mention a method to query for values that don't exist, so this seems like the next best approach. If anyone can improve or suggest alternatives, please do.