I want to filter my data. Below you can see how is look like my data.
df<-data.frame(
Description=c("15","11","12","NA","Total","NA","9","18","NA","Total"),
Value=c(158,196,NA,156,140,693,854,NA,904,925))
df
Now I want to filter and assign some text in an additional column. Desired output is need to look like the table shown below. Namely, I want to introduce additional columns with the title Sales.In this column, with the if-else statement, I want to introduce two categorical values. First is Sold and the second is Unsold.The first rows until row 'Total' needs to have the value 'Sold' and other values under this need to have Unsold.
I tried to do this with this command but unfortunately is not work that I expected.
df1$Sales <- ifelse(df$Description==c('Total'),'Sold','Unsold')
So can anybody help me how to solve this?
df$Sales <- ifelse(cumsum(dplyr::lag(df$Description, default = "") == "Total") > 0,
"Unsold",
"Sold")
df
#> Description Value Sales
#> 1 15 158 Sold
#> 2 11 196 Sold
#> 3 12 NA Sold
#> 4 NA 156 Sold
#> 5 Total 140 Sold
#> 6 NA 693 Unsold
#> 7 9 854 Unsold
#> 8 18 NA Unsold
#> 9 NA 904 Unsold
#> 10 Total 925 Unsold
To break down the logic:
dplyr::lag checks whether the previous entry was "Total". Setting a default of any string other than "Total" prevents creating NA as the first entry, because that would carry over an unwanted NA into the next step.
cumsum returns how many times "Total" has been seen as the previous entry.
Checking that the result of cumsum is greater than 0 turns step 2 into a binary result: "Total" has either been found, or it hasn't.
If "Total" has been found, it's unsold; otherwise it's sold.
You could also rearrange things:
dplyr::lag(cumsum(df$Description == "Total") < 1, default = TRUE)
gets the same result, with the true & false results in the same order.
If you know there are as many sold as unsold you can use the first solution.
If you want to allow for uneven and unknown numbers of each you could use the second solution.
library(tidyverse)
# FIRST SOLUTION
df |>
mutate(Sales = ifelse(row_number() <= nrow(df) / 2, "Sold", "Unsold"))
# SECOND SOLUTION
df |>
mutate(o = Description == "Total") |>
mutate(Sales = ifelse(row_number() > match(TRUE, o), "Unsold", "Sold")) |>
select(-o)
#> Description Value Sales
#> 1 15 158 Sold
#> 2 11 196 Sold
#> 3 12 NA Sold
#> 4 NA 156 Sold
#> 5 Total 140 Sold
#> 6 NA 693 Unsold
#> 7 9 854 Unsold
#> 8 18 NA Unsold
#> 9 NA 904 Unsold
#> 10 Total 925 Unsold
Related
I've written a function in R using pdftools to read a table from a pdf. The function gets the job done, but unfortunately the table contains a column for notes, which is only partially filled. As a result the data in the resulting table is shifted by one column in the row containing a note.
Here's the table.
And here's the code:
# load library
library(pdftools)
# link to report
url <- "https://www.rymanhealthcare.co.nz/hubfs/Investor%20Centre/Financial/Half%20year%20results%202022/Ryman%20Healthcare%20Limited%20-%20Announcement%20Numbers%20and%20financial%20statements%20-%2030%20September%202022.pdf"
# read data through pdftool
data <- pdf_text(url)
# create a function to read the pdfs
scrape_pdf <- function(list_of_tables,
table_number,
number_columns,
column_names,
first_row,
last_row) {
data <- list_of_tables[table_number]
data <- trimws(data)
data <- strsplit(data, "\n")
data <- data[[1]]
data <- data[min(grep(first_row, data)):
max(grep(last_row, data))]
data <- str_split_fixed(data, " {2,}", number_columns)
data <- data.frame(data)
names(data) <- column_names
return(data)
}
names <- c("","6m 30-9-2022","6m 30-9-2021","12m 30-3-2022")
output <- scrape_pdf(rym22Q3fs,3,5,names,"Care fees","Basic and diluted")
And the output.
6m 30-9-2022 6m 30-9-2021 12m 30-3-2022 NA
1 Care fees 210,187 194,603 398,206
2 Management fees 59,746 50,959 105,552
3 Interest received 364 42 41
4 Other income 3,942 2,260 4,998
5 Total revenue 274,239 247,864 508,797
6
7 Fair-value movement of
8 investment properties 3 261,346 285,143 745,885
9 Total income 535,585 533,007 1,254,682
10
11 Operating expenses (265,148) (225,380) (466,238)
12 Depreciation and
13 amortisation expenses (22,996) (17,854) (35,698)
14 Finance costs (19,355) (15,250) (30,664)
15 Impairment loss 2 (10,784) - -
16 Total expenses (318,283) (258,484) (532,600)
17
18 Profit before income tax 217,302 274,523 722,082
19 Income tax (expense) / credit (23,316) 6,944 (29,209)
20 Profit for the period 193,986 281,467 692,873
21
22 Earnings per share
23 Basic and diluted (cents per share) 38.8 56.3 138.6
How can I best circumvent this issue?
Many thanks in advance!
While readr::read_fwf() is for handling fixed width files, it performs pretty well on text from pdftools too once header / footer rows are removed. Even if it has to guess column widths, though those can be specified too.
library(pdftools)
library(dplyr, warn.conflicts = F)
url <- "https://www.rymanhealthcare.co.nz/hubfs/Investor%20Centre/Financial/Half%20year%20results%202022/Ryman%20Healthcare%20Limited%20-%20Announcement%20Numbers%20and%20financial%20statements%20-%2030%20September%202022.pdf"
data <- pdf_text(url)
scrape_pdf <- function(pdf_text_item, first_row_str, last_row_str){
lines <- unlist(strsplit(pdf_text_item, "\n"))
# remove 0-length lines
lines <- lines[nchar(lines) > 0]
lines <- lines[min(grep(first_row_str, lines)):
max(grep(last_row_str , lines))]
# paste lines back into single string for read_fwf()
paste(lines, collapse = "\n") %>%
readr::read_fwf() %>%
# re-connect strings in first colum if values were split between rows
mutate(X1 = if_else(!is.na(lag(X1)) & is.na(lag(X3)), paste(lag(X1), X1), X1)) %>%
filter(!is.na(X3))
}
output <- scrape_pdf(data[3], "Care fees","Basic and diluted" )
Result:
output %>%
mutate(X1 = stringr::str_trunc(X1, 35))
#> # A tibble: 16 × 5
#> X1 X2 X3 X4 X5
#> <chr> <dbl> <chr> <chr> <chr>
#> 1 Care fees NA 210,187 194,603 398,206
#> 2 Management fees NA 59,746 50,959 105,552
#> 3 Interest received NA 364 42 41
#> 4 Other income NA 3,942 2,260 4,998
#> 5 Total revenue NA 274,239 247,864 508,797
#> 6 Fair-value movement of investmen... 3 261,346 285,143 745,885
#> 7 Total income NA 535,585 533,007 1,254,682
#> 8 Operating expenses NA (265,148) (225,380) (466,238)
#> 9 Depreciation and amortisation ex... NA (22,996) (17,854) (35,698)
#> 10 Finance costs NA (19,355) (15,250) (30,664)
#> 11 Impairment loss 2 (10,784) - -
#> 12 Total expenses NA (318,283) (258,484) (532,600)
#> 13 Profit before income tax NA 217,302 274,523 722,082
#> 14 Income tax (expense) / credit NA (23,316) 6,944 (29,209)
#> 15 Profit for the period NA 193,986 281,467 692,873
#> 16 Earnings per share Basic and dil... NA 38.8 56.3 138.6
Created on 2022-11-19 with reprex v2.0.2
I have what I think is a simple question but I can't figure it out! I have a data frame with multiple columns. Here's a general example:
colony = c('29683','25077','28695','4865','19858','2235','1948','1849','2370','23196')
age = c(21,23,4,25,7,4,12,14,9,7)
activity = c(19,45,78,33,2,49,22,21,112,61)
test.df = data.frame(colony,age,activity)
test.df
I would like for R to calculate average activity based on the age of the colony in the data frame. Specifically, I want it to only calculate the average activity of the colonies that are the same age or older than the colony in that row, not including the activity of the colony in that row. For example, colony 29683 is 21 years old. I want the average activity of colonies older than 21 for this row of my data. That would include colony 25077 and colony 4865; and the mean would be (45+33)/2 = 39. I want R to do this for each row of the data by identifying the age of the colony in the current row, then identifying the colonies that are older than that colony, and then averaging the activity of those colonies.
I've tried doing this in a for loop in R. Here's the code I used:
test.avg = vector("numeric",nrow(test.df))`
for (i in 1:10){
test.avg[i] <- mean(subset(test.df$activity,test.df$age >= age[i])[-i])
}
R returns a list of values where half of them are correct and the the other half are not (I'm not even sure how it calculated those incorrect numbers..). The numbers that are correct are also out of order compared to how they're listed in the dataframe. It's clearly able to do the right thing for some iterations of the loop but not all. If anyone could help me out with my code, I would greatly appreciate it!
colony = c('29683','25077','28695','4865','19858','2235','1948','1849','2370','23196')
age = c(21,23,4,25,7,4,12,14,9,7)
activity = c(19,45,78,33,2,49,22,21,112,61)
test.df = data.frame(colony,age,activity)
library(tidyverse)
test.df %>%
mutate(result = map_dbl(age, ~mean(activity[age > .x])))
#> colony age activity result
#> 1 29683 21 19 39.00000
#> 2 25077 23 45 33.00000
#> 3 28695 4 78 39.37500
#> 4 4865 25 33 NaN
#> 5 19858 7 2 42.00000
#> 6 2235 4 49 39.37500
#> 7 1948 12 22 29.50000
#> 8 1849 14 21 32.33333
#> 9 2370 9 112 28.00000
#> 10 23196 7 61 42.00000
# base
test.df$result <- with(test.df, sapply(age, FUN = function(x) mean(activity[age > x])))
test.df
#> colony age activity result
#> 1 29683 21 19 39.00000
#> 2 25077 23 45 33.00000
#> 3 28695 4 78 39.37500
#> 4 4865 25 33 NaN
#> 5 19858 7 2 42.00000
#> 6 2235 4 49 39.37500
#> 7 1948 12 22 29.50000
#> 8 1849 14 21 32.33333
#> 9 2370 9 112 28.00000
#> 10 23196 7 61 42.00000
Created on 2021-03-22 by the reprex package (v1.0.0)
The issue in your solution is that the index would apply to the original data.frame, yet you subset that and so it does not match anymore.
Try something like this: First find minimum age, then exclude current index and calculate average activity of cases with age >= pre-calculated minimum age.
for (i in 1:10){
test.avg[i] <- {amin=age[i]; mean(subset(test.df[-i,], age >= amin)$activity)}
}
You can use map_df :
library(tidyverse)
test.df %>%
mutate(map_df(1:nrow(test.df), ~
test.df %>%
filter(age >= test.df$age[.x]) %>%
summarise(av_acti= mean(activity))))
I am very, very new to any type of coding language. I am used to Pivot tables in Excel, and trying to replicate a pivot I have done in Excel in R. I have spent a long time searching the internet/ YouTube, but I just can't get it to work.
I am looking to produce a table in which I the left hand side column shows a number of locations, and across the top of the table it shows different pages that have been viewed. I want to show in the table the number of views per location which each of these pages.
The data frame 'specificreports' shows all views over the past year for different pages on an online platform. I want to filter for the month of October, and then pivot the different Employee Teams against the number of views for different pages.
specificreports <- readxl::read_excel("Multi-Tab File - Dashboard
Usage.xlsx", sheet = "Specific Reports")
specificreportsLocal <- tbl_df(specificreports)
specificreportsLocal %>% filter(Month == "October") %>%
group_by("Employee Team") %>%
This bit works, in that it groups the different team names and filters entries for the month of October. After this I have tried using the summarise function to summarise the number of hits but can't get it to work at all. I keep getting errors regarding data type. I keep getting confused because solutions I look up keep using different packages.
I would appreciate any help, using the simplest way of doing this as I am a total newbie!
Thanks in advance,
Holly
let's see if I can help a bit. It's hard to know what your data looks like from the info you gave us. So I'm going to guess and make some fake data for us to play with. It's worth noting that having field names with spaces in them is going to make your life really hard. You should start by renaming your fields to something more manageable. Since I'm just making data up, I'll give my fields names without spaces:
library(tidyverse)
## this makes some fake data
## a data frame with 3 fields: month, team, value
n <- 100
specificreportsLocal <-
data.frame(
month = sample(1:12, size = n, replace = TRUE),
team = letters[1:5],
value = sample(1:100, size = n, replace = TRUE)
)
That's just a data frame called specificreportsLocal with three fields: month, team, value
Let's do some things with it:
# This will give us total values by team when month = 10
specificreportsLocal %>%
filter(month == 10) %>%
group_by(team) %>%
summarize(total_value = sum(value))
#> # A tibble: 4 x 2
#> team total_value
#> <fct> <int>
#> 1 a 119
#> 2 b 172
#> 3 c 67
#> 4 d 229
I think that's sort of like what you already did, except I added the summarize to show how it works.
Now let's use all months and reshape it from 'long' to 'wide'
# if I want to see all months I leave out the filter and
# add a group_by month
specificreportsLocal %>%
group_by(team, month) %>%
summarize(total_value = sum(value)) %>%
head(5) # this just shows the first 5 values
#> # A tibble: 5 x 3
#> # Groups: team [1]
#> team month total_value
#> <fct> <int> <int>
#> 1 a 1 17
#> 2 a 2 46
#> 3 a 3 91
#> 4 a 4 69
#> 5 a 5 83
# to make this 'long' data 'wide', we can use the `spread` function
specificreportsLocal %>%
group_by(team, month) %>%
summarize(total_value = sum(value)) %>%
spread(team, total_value)
#> # A tibble: 12 x 6
#> month a b c d e
#> <int> <int> <int> <int> <int> <int>
#> 1 1 17 122 136 NA 167
#> 2 2 46 104 158 94 197
#> 3 3 91 NA NA NA 11
#> 4 4 69 120 159 76 98
#> 5 5 83 186 158 19 208
#> 6 6 103 NA 118 105 84
#> 7 7 NA NA 73 127 107
#> 8 8 NA 130 NA 166 99
#> 9 9 125 72 118 135 71
#> 10 10 119 172 67 229 NA
#> 11 11 107 81 NA 131 49
#> 12 12 174 87 39 NA 41
Created on 2018-12-01 by the reprex package (v0.2.1)
Now I'm not really sure if that's what you want. So feel free to make a comment on this answer if you need any of this clarified.
Welcome to Stack Overflow!
I'm not sure I correctly understand your need without a data sample, but this may work for you:
library(rpivotTable)
specificreportsLocal %>% filter(Month == "October")
rpivotTable(specificreportsLocal, rows="Employee Team", cols="page", vals="views", aggregatorName = "Sum")
Otherwise, if you do not need it interactive (as the Pivot Tables in Excel), this may work as well:
specificreportsLocal %>% filter(Month == "October") %>%
group_by_at(c("Employee Team", "page")) %>%
summarise(nr_views = sum(views, na.rm=TRUE))
I'm trying to extend some code to be able to:
1) read in a vector of prices
2) left join that vector of prices to a data frame of years (or years and months)
3) append/fill the prices for missing years with interpolated data based on the last year of available prices plus a specified inflation rate. Consider an example like this one:
prices <- data.frame(year=2018:2022,
wti=c(75,80,90,NA,NA),
brent=c(80,85,94,93,NA))
What I need is something that will fill the missing rows of each column with the last price plus inflation (suppose 2%). I can do this in a pretty brute force way as:
i_rate<-0.02
for(i in c(1:nrow(prices))){
if(is.na(prices$wti[i]))
prices$wti[i]<-prices$wti[i-1]*(1+i_rate)
if(is.na(prices$brent[i]))
prices$brent[i]<-prices$brent[i-1]*(1+i_rate)
}
It seems to me there should be a way to do this using some combination of apply() and/or fill() but I can't seem to make it work.
Any help would be much appreciated.
As noted by #camille, the problem with dplyr::lag is that it doesn't work here with consecutive NAs because it uses the "original" ith element of a vector instead of the "revised" ith element. We'd have to first create a version of lag that will do this by creating a new function:
impute_inflation <- function(x, rate) {
output <- x
y <- rep(NA, length = length(x)) #Creating an empty vector to fill in with the loop. This makes R faster to run for vectors with a large number of elements.
for (i in seq_len(length(output))) {
if (i == 1) {
y[i] <- output[i] #To avoid an error attempting to use the 0th element.
} else {
y[i] <- output[i - 1]
}
if (is.na(output[i])) {
output[i] <- y[i] * (1 + rate)
} else {
output[i]
}
}
output
}
Then it's a pinch to apply this across a bunch of variables with dplyr::mutate_at():
library(dplyr)
mutate_at(prices, vars(wti, brent), impute_inflation, 0.02)
year wti brent
1 2018 75.000 80.00
2 2019 80.000 85.00
3 2020 90.000 94.00
4 2021 91.800 93.00
5 2022 93.636 94.86
You can use dplyr::lag to get the previous value in a given column. Your lagged values look like this:
library(dplyr)
inflation_factor <- 1.02
prices <- data_frame(year=2018:2022,
wti=c(75,80,90,NA,NA),
brent=c(80,85,94,93,NA)) %>%
mutate_at(vars(wti, brent), as.numeric)
prices %>%
mutate(prev_wti = lag(wti))
#> # A tibble: 5 x 4
#> year wti brent prev_wti
#> <int> <dbl> <dbl> <dbl>
#> 1 2018 75 80 NA
#> 2 2019 80 85 75
#> 3 2020 90 94 80
#> 4 2021 NA 93 90
#> 5 2022 NA NA NA
When a value is NA, multiply the lagged value by the inflation factor. As you can see, that doesn't handle consecutive NAs, however.
prices %>%
mutate(wti = ifelse(is.na(wti), lag(wti) * inflation_factor, wti),
brent = ifelse(is.na(brent), lag(brent) * inflation_factor, brent))
#> # A tibble: 5 x 3
#> year wti brent
#> <int> <dbl> <dbl>
#> 1 2018 75 80
#> 2 2019 80 85
#> 3 2020 90 94
#> 4 2021 91.8 93
#> 5 2022 NA 94.9
Or to scale this and avoid doing the same multiplication over and over, gather the data into a long format, get lags within each group (wti, brent, or any others you may have), and adjust values as needed. Then you can spread back to the original shape:
prices %>%
tidyr::gather(key = key, value = value, wti, brent) %>%
group_by(key) %>%
mutate(value = ifelse(is.na(value), lag(value) * inflation_factor, value)) %>%
tidyr::spread(key = key, value = value)
#> # A tibble: 5 x 3
#> year brent wti
#> <int> <dbl> <dbl>
#> 1 2018 80 75
#> 2 2019 85 80
#> 3 2020 94 90
#> 4 2021 93 91.8
#> 5 2022 94.9 NA
Created on 2018-07-12 by the reprex package (v0.2.0).
I currently have the following dataframe below:
Country Information Export Import
Andorra Small 10 20
Medium 50 30
Large 40 50
Total NA 100 100
Antigua Small 60 70
Medium 20 10
Large 5 10
X-Large 15 10
Total NA 100 100
I would like to repeat the Country name up until it reaches the character string "Total", so i would have Andorra repeated for rows in the column named $Country up until it reaches the row "Total"
As you can see the rows differ for nearly every country ( i have 252 of them) so i need to find a way to ensure that the country name is repeated for that specific country up until it reaches "total"
(e.g. Antigua has 4 rows not 3 like Andorra - so would require Antigua to be repeated 4 times in the $Country column)
Is there a quick and efficient way to do this?
Any help is appreciated.
Thank you
I'm assuming you have NA values and not blank values in those cases that country values are missing.
You need to use function na.locf from package zoo and apply it on your country column, like this:
library(zoo)
# example of column values
country = c("Andorra",NA,NA,"Total","Antigua",NA,NA,NA,"Total")
# apply fucntion and update your variable
country = na.locf(country)
# see updated values
country
# [1] "Andorra" "Andorra" "Andorra" "Total" "Antigua" "Antigua" "Antigua" "Antigua" "Total"
What it does is replacing NA values with the previous non-NA value.
I would use the fill function from the tidyr package
Input Data
df <- data.table::fread("Country Information Export Import
Andorra Small 10 20
NA Medium 50 30
NA Large 40 50
Total NA 100 100
Antigua Small 60 70
NA Medium 20 10
NA Large 5 10
NA X-Large 15 10
Total NA 100 100")
Code to Fill in missing information using fill from tidyr
library(tidyr)
fill(df, Country, .direction = "down")
Output
Country Information Export Import
1: Andorra Small 10 20
2: Andorra Medium 50 30
3: Andorra Large 40 50
4: Total <NA> 100 100
5: Antigua Small 60 70
6: Antigua Medium 20 10
7: Antigua Large 5 10
8: Antigua X-Large 15 10
9: Total <NA> 100 100
If there are zero length string values, instead of NA, you can use the na_if function from the dplyr package to change them to NA
library(dplyr)
df %>%
mutate(Country = na_if(Country,"")) %>%
fill(Country, .direction = "down")