Tailwind: combine 2 styles for text-decoration-line - css

I want to a certain span of text to have both strike-throughs and underlines. This is possible in vanilla CSS like:
text-decoration-line: underline line-through;
I assumed with tailwind it would work similarly if I used the class like
class="underline line-through"
but it does not work. Only one of the styles apply at a time. Is there any way to get that behaviour with tailwind classes?

Right now those utilities are not composable, you can either create your own plugin, or use arbitrary properties to achieve the result you want:
<div class="[text-decoration:underline_line-through]">hello</div>
Here is a quick playground link with the solution: https://play.tailwindcss.com/baW2CzoBur

Related

Angular ngx-datatable CSS

How to style a row in ngx-datatable component? Here is an example in component's documentation:
https://swimlane.github.io/ngx-datatable/#css
When I run same demo only one row has background color set.
Here is my demo
In order to style properly the child component from the parent component, you can use one of the methods specified in this link. Preferably use the answer 3 in the link which will prevent the use of deprecated selector like :deep:. You can fix the color not appearing in even rows by
/deep/ .age-is-ten { background: #ffc91f !important;}

Remove some base class CSS on hover

I have 2 icons - a filled thumbs-down (reject) and an unfilled thumbs-up (approve). I need to have both a thumbs up and down image which fills in on hover.
I am trying to use FontAwesome's flip CSS to achieve this. The icons themselves are from an iconfont generated using ico-moon and relate to classes .icon-approve and .icon-reject.
.icon-approve-hover-fill {
#extend .icon-approve;
}
.icon-approve-hover-fill:hover {
#extend .icon-reject;
#extend .fa-flip-vertical;
}
.icon-reject-hover-fill {
#extend .icon-approve;
#extend .fa-flip-vertical;
}
.icon-reject-hover-fill:hover {
#extend .icon-reject;
}
My issue is that for the reject-hover-fill case that the .icon-reject-hover-fill:hover is still flipping due to the .fa-flip-vertical; in the .icon-reject-hover-fill base class.
I need .icon-reject-hover-fill:hover to effectively be it's own class and not inherit the useless extra flip from .icon-reject-hover-fill. I assume there's a way to achieve this without me needing to re-create my font with flipped icons? I need it to work down to IE 8 and can be either basic CSS or SASS (though it needs to work with Sencha's flavour of SASS in ExtJS 6).
The .icon-reject-hover-fill:hover selector is stronger than .icon-reject-hover-fill. If .icon-reject-hover-fill has CSS properties you don't want when the element is hovered, just specify the desired value inside .icon-reject-hover-fill:hover{}, in your custom CSS.
However, instead of adding a class that has properties you want to unset, just create another class, of your own, that contains only the stuff you want from the class you are importing. Trying to unset properties that have been set is the fastest path to CSS mess-up, quickly escalating into code that is almost impossible to maintain.
The usual way to reset an already set property in CSS is {property-name: initial;}. Please note that not all CSS properties can take initial as value.

Is there any class called 'barone' in bootstrap?

When I am learning Bootstrap, I saw a class "barone" in a tutorial, but they didn't explained the use of that class. This is the site
http://www.w3resource.com/twitter-bootstrap/tutorial.php
Is there any class in Bootstrap in this name?
Thanks
From what I know, classes are used to group elements together. As you can see in the following example:
p.exampleID3 { background-color: #013370; color: white;}
<p class='exampleID3'>These paragraphs all have the same styling applied to them and we used classes because we wanted to reuse our styling!</p>
<p class='exampleID3'>These paragraphs all have the same styling applied to them and we used classes because we wanted to reuse our styling!</p>
<p class='exampleID3'>These paragraphs all have the same styling applied to them and we used classes because we wanted to reuse our styling!</p>
The class is exampleID3 and is present in the css file. In your case "row barone" should be somewhere in the css file, but it's not shown in the tutorial and you don't really know what it contains.

How can I override CSS styles in GWT/Bootstrap?

I just started to port twitter's bootstrap to GWT (see the github project here and a very ugly demo here), but, I was having a log of issues with bootstrap styles vs Gwt styles.
Bootstrap put a border-top in tr/td elements, and GWT components basically use tables everywhere. In the demo you can see that bug in the left VerticalPanel.
So, I was looking for a way to make GWT components ignore bootstrap styles, and I have no idea how to do this.
Is there a simple way to make it work right?
Thanks in advance.
It's possible, but somewhat complex to do something with a Linker in GWT. The high-level idea would be:
Put all your GWT components in a <div id="gwt">...</div>
Add a linker to the GWT Module file that will process CSS files.
In the linker, transform the GWT CSS (e.g., standard.css) to insert a #gwt before each selector rule.
The first part is easy, just add an id to your root element.
The second part is also easy, simply add code that looks like this to your Module.gwt.xml file:
<define-linker name="cssLinker" class="com.you.bootstrap.linker.CssRenamingLinker" />
<add-linker name="cssLinker"/>
The hard part is implementing the Linker. It's possible to do parse it by hand, but you might find it easier to use something like SAC.
Using the Linker, you can transform your CSS by inserting a #gwt before each selector. Using SAC, you might do that by overriding all the DocumentHandler methods to simply emit each of their arguments to an OutputStream. In DocumentHandler.startSelector() you would first emit "#gwt " before each selector.
[Edit]
This assumes that GWT's standard.css defines styles that override the bootstrap styles. If not, you might have to 'enhance' the GWT CSS with defaults. There's a list of W3C recommended defaults here.
The benefit is that this is future-resistant - if GWT styles change or if bootstrap styles change, this should be robust.
Hope that helps,
Adam
You can simply add a style to one of your root GWT objects and then simply override the bootstrap styles to remove those messy borders:
<div class="gwt">
... some other GWT-content
</div>
and in your CSS:
.gwt tr, .gwt td {
border-top: 0px;
}
Of course if you need to embed some bootstrap elements in your GWT elements then you will have to hack around and do:
<div class="gwt">
... some other GWT-content
<div class="bootstrap">...
... Bootstrap elements
</div>
</div>
and in your CSS:
.bootstrap tr, .bootstrap td {
border-top: 1px; // Whatever bootstrap style puts
}

css class within another class as a property

I'm wanting to use properties from other css classes without having to rewrite the code...I'm not too savvy with css so please forgive me for the simple question.
Is it possible to do something like this or similar to it in css?
.class_a {
background:red;
}
.class_b{
.class_a;
}
The best way (that I know of) to re-use css classes is to decide on the css attributes you want to re-use, and put this in a seperate class, like so:
.class_a {
background:red;
}
Then, every time you want to re-use these attributes, you add the class to the html element, with spaces in between different class names, like so:
<div class="text class_a">This will be red, and have the properties of the text class</div>
<div class="text">This will only have the properties of the text class</div>
You can use the same property list for more than one selector:
.class_a, .class_b {
background:red;
}
There are CSS tools which allow you to code in the way you describe. You just do some post-processing of your code to produce valid CSS.
Check out LESS.
Not possible using CSS. However, you can achieve this using something like Sass. Sass allows you write CSS with enhancements such as the one you described. Unfortunately, this introduces an extra step since Sass files must be converted to CSS before you can use them on your page. Could help save you a lot of typing though :)

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