Obtaining predictions from a pooled imputation model - r

I want to implement a "combine then predict" approach for a logistic regression model in R. These are the steps that I already developed, using a fictive example from pima data from faraway package. Step 4 is where my issue occurs.
#-----------activate packages and download data-------------##
library(faraway)
library(mice)
library(margins)
data(pima)
Apply a multiple imputation by chained equation method using MICE package. For the sake of the example, I previously randomly assign missing values to pima dataset using the ampute function from the same package. A number of 20 imputated datasets were generated by setting "m" argument to 20.
#-------------------assign missing values to data-----------------#
result<-ampute(pima)
result<-result$amp
#-------------------multiple imputation by chained equation--------#
#generate 20 imputated datasets
newresult<-mice(result,m=20)
Run a logistic regression on each of the 20 imputated datasets. Inspecting convergence, original and imputated data distributions is skipped for the sake of the example. "Test" variable is set as the binary dependent variable.
#run a logistic regression on each of the 20 imputated datasets
model<-with(newresult,glm(test~pregnant+glucose+diastolic+triceps+age+bmi,family = binomial(link="logit")))
Combine the regression estimations from the 20 imputation models to create a single pooled imputation model.
#pooled regressions
summary(pool(model))
Generate predictions from the pooled imputation model using prediction function from the margins package. This specific function allows to generate predicted values fixed at a specific level (for factors) or values (for continuous variables). In this example, I could chose to generate new predicted probabilites, i.e. P(Y=1), while setting pregnant variable (# of pregnancies) at 3. In other words, it would give me the distribution of the issue in the contra-factual situation where all the observations are set at 3 for this variable. Normally, I would just give my model to the x argument of the prediction function (as below), but in the case of a pooled imputation model with MICE, the object class is a mipo and not a glm object.
#-------------------marginal standardization--------#
prediction(model,at=list(pregnant=3))
This throws the following error:
Error in check_at_names(names(data), at) :
Unrecognized variable name in 'at': (1) <empty>p<empty>r<empty>e<empty>g<empty>n<empty>a<empty>n<empty>t<empty
I thought of two solutions:
a) changing the class object to make it fit prediction()'s requirements
b) extracting pooled imputation regression parameters and reconstruct it in a list that would fit prediction()'s requirements
However, I'm not sure how to achieve this and would enjoy any advice that could help me getting closer to obtaining predictions from a pooled imputation model in R.

You might be interested in knowing that the pima data set is a bit problematic (the Native Americans from whom the data was collected don't want it used for research any more ...)
In addition to #Vincent's comment about marginaleffects, I found this GitHub issue discussing mice support for the emmeans package:
library(emmeans)
emmeans(model, ~pregnant, at=list(pregnant=3))
marginaleffects works in a different way. (Warning, I haven't really looked at the results to make sure they make sense ...)
library(marginaleffects)
fit_reg <- function(dat) {
mod <- glm(test~pregnant+glucose+diastolic+
triceps+age+bmi,
data = dat, family = binomial)
out <- predictions(mod, newdata = datagrid(pregnant=3))
return(out)
}
dat_mice <- mice(pima, m = 20, printFlag = FALSE, .Random.seed = 1024)
dat_mice <- complete(dat_mice, "all")
mod_imputation <- lapply(dat_mice, fit_reg)
mod_imputation <- pool(mod_imputation)

Related

Unequal Data for Model Compare in R

I'm fairly new to R and am trying to compare two models with the modelCompare function. However, the data set that I am working with is a bit large and has unevenly distributed missing values. When I try the following code for example:
Model_A <- lm(DV~var1*var2 + cont.var, data=df)
Model_C <- lm(DV~ cont.var, data=df)
modelCompare(Model_C,Model_A)
I get an error that the models have different N values and cannot be compared because data is differentially omitted between the two models. Is there an easy way to remove this variation, as I will be running a number of regression analyses with this data set?
What are you looking to compare? If you want to compare intercepts between the models just:
Model_A
Model_C
If you want to compare accuracy of the model, use a training and testing dataset!

Is there an R function that performs LASSO regression on multiple imputed datasets and pools results together?

I have a dataset with 283 observation of 60 variables. My outcome variable is dichotomous (Diagnosis) and can be either of two diseases. I am comparing two types of diseases that often show much overlap and i am trying to find the features that can help differentiate these diseases from each other. I understand that LASSO logistic regression is the best solution for this problem, however it can not be run on a incomplete dataset.
So i imputed my missing data with MICE package in R and found that approximately 40 imputations is good for the amount of missing data that i have.
Now i want to perform lasso logistic regression on all my 40 imputed datasets and somehow i am stuck at the part where i need to pool the results of all these 40 datasets.
The with() function from MICE does not work on .glmnet
# Impute database with missing values using MICE package:
imp<-mice(WMT1, m = 40)
#Fit regular logistic regression on imputed data
imp.fit <- glm.mids(Diagnosis~., data=imp,
family = binomial)
# Pool the results of all the 40 imputed datasets:
summary(pool(imp.fit),2)
The above seems to work fine with logistic regression using glm(), but when i try the exact above to perform Lasso regression i get:
# First perform cross validation to find optimal lambda value:
CV <- cv.glmnet(Diagnosis~., data = imp,
family = "binomial", alpha = 1, nlambda = 100)
When i try to perform cross validation I get this error message:
Error in as.data.frame.default(data) :
cannot coerce class ‘"mids"’ to a data.frame
Can somebody help me with this problem?
A thought:
Consider running the analyses on each of the 40 datasets.
Then, storing which variables are selected in each in a matrix.
Then, setting some threshold (e.g., selected in >50% of datasets).

LASSO analysis (glmnet package). Can I loop the analysis and the results extraction?

I'm using the package glmnet, I need to run several LASSO analysis for the calibration of a large number of variables (%reflectance for each wavelength throughout the spectrum) against one dependent variable. I have a couple of doubts on the procedure and on the results I wish to solve. I show my provisional code below:
First I split my data in training (70% of n) and testing sets.
smp_size <- floor(0.70 * nrow(mydata))
set.seed(123)
train_ind <- sample(seq_len(nrow(mydata)), size = smp_size)
train <- mydata[train_ind, ]
test <- mydata[-train_ind, ]
Then I separate the target trait (y) and the independent variables (x) for each set as follows:
vars.train <- train[3:2153]
vars.test <- test[3:2153]
x.train <- data.matrix(vars.train)
x.test <- data.matrix(vars.test)
y.train <- train$X1
y.test <- test$X1
Afterwords, I run a cross-validated LASSO model for the training set and extract and writte the non-zero coefficients for lambdamin. This is because one of my concerns here is to note which variables (wavebands of the reflectance spectrum) are selected by the model.
install.packages("glmnet")
library(glmnet)
cv.lasso.1 <- cv.glmnet(y=y.train, x= x.train, family="gaussian", nfolds =
5, standardize=TRUE, alpha=1)
coef(cv.lasso.1,s=cv.lasso.1$lambda.min) # Using lambda min.
(cv.lasso.1)
install.packages("broom")
library(broom)
c <- tidy(coef(cv.lasso.1, s="lambda.min"))
write.csv(c, file = "results")
Finally, I use the function “predict” and apply the object “cv.lasso1” (the model obtained previously) to the variables of the testing set (x.2) in order to get the prediction of the variable and I run the correlation between the predicted and the actual values of Y for the testing set.
predict.1.2 <- predict(cv.lasso.1, newx=x.2, type = "response", s =
"lambda.min")
cor.test(x=c(predict.1.2), y=c(y.2))
This is a simplified code and had no problem so far, the point is that I would like to make a loop (of one hundred repetitions) of the whole code and get the non-zero coefficients of the cross-validated model as well as the correlation coefficient of the predicted vs actual values (for the testing set) for each repetition. I've tried but couldn't get any clear results. Can someone give me some hint?
thanks!
In general, running repeated analyses of the same type over and over on the same data can be tricky. And in your case, may not be necessary the way in which you have outlined it.
If you are trying to find the variables most predictive, you can use PCA, Principal Component Analysis to select variables with the most variation within the a variable AND between variables, but it does not consider your outcome at all, so if you have poor model design it will pick the least correlated data in your repository but it may not be predictive. So you should be very aware of all variables in the set. This would be a way of reducing the dimensionality in your data for a linear or logistic regression of some sort.
You can read about it here
yourPCA <- prcomp(yourData,
center = TRUE,
scale. = TRUE)
Scaling and centering are essential to making these models work right, by removing the distance between your various variables setting means to 0 and standard deviations to 1. Unless you know what you are doing, I would leave those as they are. And if you have skewed or kurtotic data, you might need to address this prior to PCA. Run this ONLY on your predictors...keep your target/outcome variable out of the data set.
If you have a classification problem you are looking to resolve with much data, try an LDA, Linear Discriminant Analysis which looks to reduce variables by optimizing the variance of each predictor with respect to the OUTCOME variable...it specifically considers your outcome.
require(MASS)
yourLDA =r <- lda(formula = outcome ~ .,
data = yourdata)
You can also set the prior probabilities in LDA if you know what a global probability for each class is, or you can leave it out, and R/ lda will assign the probabilities of the actual classes from a training set. You can read about that here:
LDA from MASS package
So this gets you headed in the right direction for reducing the complexity of data via feature selection in a computationally solid method. In looking to build the most robust model via repeated model building, this is known as crossvalidation. There is a cv.glm method in boot package which can help you get this taken care of in a safe way.
You can use the following as a rough guide:
require(boot)
yourCVGLM<- cv.glmnet(y = outcomeVariable, x = allPredictorVariables, family="gaussian", K=100) .
Here K=100 specifies that you are creating 100 randomly sampled models from your current data OBSERVATIONS not variables.
So the process is two fold, reduce variables using one of the two methods above, then use cross validation to build a single model from repeated trials without cumbersome loops!
Read about cv.glm here
Try starting on page 41, but look over the whole thing. The repeated sampling you are after is called booting and it is powerful and available in many different model types.
Not as much code and you might hope for, but pointing you in a decent direction.

Predicting with plm function in R

I was wondering if it is possible to predict with the plm function from the plm package in R for a new dataset of predicting variables. I have create a model object using:
model <- plm(formula, data, index, model = 'pooling')
Now I'm hoping to predict a dependent variable from a new dataset which has not been used in the estimation of the model. I can do it through using the coefficients from the model object like this:
col_idx <- c(...)
df <- cbind(rep(1, nrow(df)), df[(1:ncol(df))[-col_idx]])
fitted_values <- as.matrix(df) %*% as.matrix(model_object$coefficients)
Such that I first define index columns used in the model and dropped columns due to collinearity in col_idx and subsequently construct a matrix of data which needs to be multiplied by the coefficients from the model. However, I can see errors occuring much easier with the manual dropping of columns.
A function designed to do this would make the code a lot more readable I guess. I have also found the pmodel.response() function but I can only get this to work for the dataset which has been used in predicting the actual model object.
Any help would be appreciated!
I wrote a function (predict.out.plm) to do out of sample predictions after estimating First Differences or Fixed Effects models with plm.
The function is posted here:
https://stackoverflow.com/a/44185441/2409896

Error in missing value imputation using MICE package

I have a huge data (4M x 17) that has missing values. Two columns are categorical, rest all are numerical. I want to use MICE package for missing value imputation. This is what I tried:
> testMice <- mice(myData[1:100000,]) # runs fine
> testTot <- predict(testMice, myData)
Error in UseMethod("predict") :
no applicable method for 'predict' applied to an object of class "mids"
Running the imputation on whole dataset was computationally expensive, so I ran it on only the first 100K observations. Then I am trying to use the output to impute the whole data.
Is there anything wrong with my approach? If yes, what should I do to make it correct? If no, then why am I getting this error?
Neither mice nor hmisc provide the parameter estimates from the imputation process. Both Amelia and imputeMulti do. In both cases, you can extract the parameter estimates and use them for imputing your other observations.
Amelia assumes your data are distributed as a multivariate normal (eg. X \sim N(\mu, \Sigma).
imputeMulti assumes that your data is distributed as a multivariate multinomial distribution. That is the complete cell counts are distributed (X \sim M(n,\theta)) where n is the number of observations.
Fitting can be done as follows, via example data. Examining parameter estimates is shown further below.
library(Amelia)
library(imputeMulti)
data(tract2221, package= "imputeMulti")
test_dat2 <- tract2221[, c("gender", "marital_status","edu_attain", "emp_status")]
# fitting
IM_EM <- multinomial_impute(test_dat2, "EM",conj_prior = "non.informative", verbose= TRUE)
amelia_EM <- amelia(test_dat2, m= 1, noms= c("gender", "marital_status","edu_attain", "emp_status"))
The parameter estimates from the amelia function are found in amelia_EM$mu and amelia_EM$theta.
The parameter estimates in imputeMulti are found in IM_EM#mle_x_y and can be accessed via the get_parameters method.
imputeMulti has noticeably higher imputation accuracy for categorical data relative to either of the other 3 packages, though it only accepts multinomial (eg. factor) data.
All of this information is in the currently unpublished vignette for imputeMulti. The paper has been submitted to JSS and I am awaiting a response before adding the vignette to the package.
You don't use predict() with mice. It's not a model you're fitting per se. Your imputed results are already there for the 100,000 rows.
If you want data for all rows then you have to put all rows in mice. I wouldn't recommend it though, unless you set it up on a large cluster with dozens of CPU cores.

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