I'm trying rotate a div with a border.
The border has the same color as the background.
A very thin line appears between the border outline and the background.
Here is my code below.
I'm trying to get rid of the weird line.
body {
background-color: black;
}
div {
width: 50px;
height: 50px;
background-color: white;
border: 50px solid black;
transform: rotate(45deg);
}
<div></div>
I tried multiple browsers.
I could fix this by using another div instead of a border, but I'm more interested in getting the border to work as expected.
A simple fix of this is by using backface-visibility: hidden.
When an element rotates, it seems that the rendering of transform: rotate() may cause the back face of it to be shown, as if in 3D perspective.
This possibly lead to the background-color of the back face (a mirror image the element's front face) overflowing the border edge in this case.
backface-visibility: hidden fix it by rendering the back face invisible, as shown in below example.
On side note, MDN did mention that backface-visibility has no effect on 2D transforms, which indicates that this behavior of transform: rotate() to have perspective is more accidental than expected.
Example:
body {
background-color: black;
display: flex;
gap: 100px;
}
div {
width: 50px;
height: 50px;
background-color: white;
border: 50px solid black;
transform: rotate(45deg);
}
div + div {
/* 👇 fixed here */
backface-visibility: hidden;
}
<div></div>
<div></div>
That's an interesting one as it only appears with the rotate transformation. You can remove it using outline to paint over the thin line with a border which will also not affect the positioning of it as follows:
body {
background-color: black;
}
div {
width: 50px;
height: 50px;
background-color: white;
border: 50px solid black;
transform: rotate(45deg);
outline-offset:-1px;
outline: 2px solid black;
}
<div></div>
Firefox only
My best guess is that there are rounding issues with the 3D rotation on the Z-axis in browser graphics functions. Rotation on the X-axis and Y-axis show no issues. It seems the size of the element drawn is rounded down (smaller), while the browser calculates with the actual or rounded up values. The difference will be a narrow gap where the element background-color is able to bleed through. I used red in the snippet to show this.
Both transform: rotate(..) and transform: rotateZ(..) show the same issue when rotation is other than 0deg (usually the purpose of rotation).
To resolve the issue (Firefox only!!) use transform-style: preserve-3d with the element being rotated.
body {
background-color: black;
padding: 3rem;
}
div {
width: 50px;
height: 50px;
background-color: red;
border: 50px solid black;
transform: rotate(45deg);
}
.test {
transform-style: preserve-3d; /* voila! background colored border is gone... */
margin-top: 4rem; /* create some distance */
}
<div></div>
<div class="test"></div>
try like below, no need border, just simply use margin.
body {
background-color: black;
}
div{
width: 50px;
height: 50px;
background-color: white;
transform: rotate(45deg);
border: 0px;
/* border: 50px solid black; */
margin: 50px;
}
<div></div>
body {
background-color: black;
}
div {
width: 50px;
height: 50px;
background-color: white;
transform: rotate(45deg);
border: 0px;
/* border: 50px solid black; */
margin: 50px;
}
<div></div>
Related
I've tried the perspective solution here How to transform each side of a shape separately? but can't get it to work probably due to the irregularness of the shape. Only the top and right side columns are slanted, vertical and bottom are straight. How can I do this with CSS?
Using CSS borders you can create triangles and trapezoids.
You can achieve your shape joining a triangle and a trapezoid.
.triangle {
border: 0 solid red;
border-left-width: 500px;
border-top-width: 30px;
border-top-color: transparent;
}
.trapezoid {
border: 0 solid red;
width: 500px;
border-bottom-width: 150px;
border-right-width: 30px;
border-right-color: transparent;
}
<div class="triangle"></div>
<div class="trapezoid"></div>
Method 1: Clip path
You could make use of CSS clip-path feature to clip a rectangle into the required polygon shape.
div {
box-sizing: border-box;
height: 150px;
width: 250px;
background: red;
padding: 10px;
-webkit-clip-path: polygon(0% 0%, 90% 10%, 100% 100%, 0% 100%);
clip-path: polygon(0% 0%, 90% 10%, 100% 100%, 0% 100%);
}
div#image {
background: url(http://lorempixel.com/400/200);
}
/* Just for demo */
div{
float: left;
margin: 10px;
transition: all 1s;
}
div:hover{
height: 200px;
width: 300px;
}
<div>Some text</div>
<div id="image"></div>
Pros:
Supports non-solid color fills inside the shape and also allow text to be present inside.
The shape is responsive and can adapt even if the container's dimensions change.
Cons:
Poor browser support for the CSS clip-path feature. This can be overcome by using inline SVG for the clip-path like in the below snippet as this has much better browser support.
div {
box-sizing: border-box;
height: 150px;
width: 250px;
padding: 10px;
background: red;
-webkit-clip-path: url(#clip);
clip-path: url(#clip);
}
div#image {
background: url(http://lorempixel.com/400/200);
}
/* Just for demo */
div{
float: left;
margin: 10px;
transition: all 1s;
}
div:hover{
height: 200px;
width: 300px;
}
<svg width="0" height="0">
<defs>
<clipPath id="clip" clipPathUnits="objectBoundingBox">
<path d="M0 0, 0.9 0.1, 1 1, 0 1z" />
</clipPath>
</defs>
</svg>
<div>
Some text
</div>
<div id="image"></div>
Method 2: CSS Transforms
Generally it is better not to use transforms when there is going to be content like image or text inside the shape (or) when the shape's background is not going to be a solid color because then we would either have to (a) reverse transform the child elements separately to make them look normal or (b) use absolute positioning.
For this particular shape, having text inside the shape is not a problem even while using transforms but having non solid background colors would be.
Option 1: Using two pseudo-elements
You could use a couple of pseudo-elements with skew transforms, position one on the top and the other on the right to produce the required shape. Hover the shape in snippet to see how it is created.
div {
position: relative;
height: 150px;
width: 250px;
background: red;
margin: 40px 40px 0px 0px;
}
div:after,
div:before {
position: absolute;
content: '';
background: red;
z-index: -1;
backface-visibility: hidden;
}
div:before {
height: 12.5%;
width: 100%;
top: 0px;
left: 0px;
transform-origin: right top;
transform: skewY(3deg);
}
div:after {
height: 100%;
width: 12.5%;
right: -1px;
top: -1px;
transform-origin: right top;
transform: skewX(10deg);
}
/* Just for demo */
div{
transition: all 1s;
}
div:hover{
height: 250px;
width: 300px;
}
div:hover:after{
background: blue;
}
div:hover:before{
background: green;
}
<div>Some text</div>
Pros:
Shape can be created with a single element and can have text inside it without any trouble.
Cons:
Having gradients (or) images as background for the shape is complex because they would need reverse rotation as mentioned earlier.
Shape is not 100% scalable as dimensions of the container should change proportionately for the shape to be maintained (hover on the shape in the snippet to see what I mean). Reason is same as mentioned here.
Option 2: Using one pseudo-element
This is pretty similar to the previous option except that this uses a single pseudo-element along with a overflow: hidden on the parent.
div {
position: relative;
box-sizing: border-box;
height: 200px;
width: 300px;
padding: 10px;
overflow: hidden;
}
div:after {
position: absolute;
content: '';
top: 0px;
left: -20px;
height: 100%;
width: 100%;
background: red;
transform-origin: left bottom;
transform: skewY(5deg) skewX(7.5deg);
z-index: -1;
}
div:hover {
height: 300px;
width: 500px;
transition: all 1s;
}
<div>Some text</div>
Pros:
Shape can be created with a single element and can have text inside it without any trouble.
Shape is responsive and can adapt even if the container's dimensions change .
Cons:
Same constraint as the previous option for gradient and image backgrounds.
Not suitable if the overflow: hidden on the parent is a constraint.
A solution is:
div {
width: 300px;
height: 100px;
margin:50px;
background-color: yellow;
border: 1px solid black;
}
.thisdiv {
-ms-transform: skewX(-20deg); /* IE 9 */
-webkit-transform: skewX(-20deg); /* Safari */
transform: skewX(-20deg); /* Standard syntax */
}
<div class="thisdiv">
This is the div I will skew
</div>
This is how to skew an element, if you want to make the shape you added, try using two overlaping div's, position, scale, rotate and skew, like this:
.outer-div{
position:relative;
margin:50px;
width:200px;
height:200px;
border:2px black dashed;
}
.inner-one{
position:absolute;
left:0;
bottom:0;
width:180px;
height:180px;
background:red;
}
.inner-two{
position:absolute;
bottom:2px;
right:0px;
width:200px;
height:195px;
background:red;
transform: rotate(7deg) skew(14deg) scale(0.905); /* Standard syntax */
}
<div class="outer-div">
<div class="inner-one">
</div>
<div class="inner-two">
</div>
</div>
2 Triangle Solution for Irregular Quadrilateral in CSS
In looking at your image, I notice that the skew at the top and right are really just long, narrow triangles overlaying the rectangle.
So what I did was create triangles using CSS border properties and absolutely position them over the rectangle.
#rectangle {
width: 400px;
height: 200px;
background-color: red;
margin-top: 25px;
position: relative;
}
#triangle-down {
border-left: 30px solid red;
border-right: 0;
border-top: 200px solid transparent;
position: absolute;
right: -30px;
top: 0;
}
#triangle-left {
border-top: 0;
border-bottom: 15px solid red;
border-right: 400px solid transparent;
position: absolute;
right: 0;
top: -15px;
}
<div id="rectangle">
<div id="triangle-down"></div>
<div id="triangle-left"></div>
</div>
jsFiddle demo
You could check out the clip-path property (see below from MDN), but support is very patchy. Chrome 24+ supports with prefix and FF, but only URL values, which reference a path in an SVG. You can read more about clip-path here.
Here's a basic pen - this will only work in Chrome.
From MDN
The clip-path CSS property prevents a portion of an element from getting displayed by defining a clipping region to be displayed i.e, only a specific region of the element is displayed. The clipping region is a path specified as a URL referencing an inline or external SVG, or shape method such as circle(). The clip-path property replaces the now deprecated clip property.
developer.mozilla.org/en-US/docs/Web/CSS/clip-path (sorry, not enough rep to link)
Any idea how to make the div shape like this ?
Just create a rectangle and skew the Y axis using the CSS3 transform property.
In this case, transform: skewY(-20deg) will work.
.shape {
border: 2px solid;
height: 200px;
width: 100px;
transform: skewY(-20deg);
margin: 2em 0;
}
<div class="shape"></div>
This will work in all modern browsers and will fall back to a rectangle in older browsers.
.skewed {
border: solid 5px black;
height: 200px;
margin-top: 50px;
width: 100px;
transform: skewY(-30deg);
}
<div class="skewed"></div>
Imagine the following CSS:
#foo {
border: 1px solid black;
border-right: 1px solid blue;
}
In this case, at least under Chrome, the top and bottom right corner pixels of the element are blue, not black. Is it possible to make them black?
You can't do it with the normal CSS border options, but if you want to, you can still have a pure CSS solution:
Basically, what you are going to do is create two pseudo elements with CSS, and cover the corners:
#foo {
border: 100px solid black;
border-right: 100px solid blue;
height:300px;
position:relative;
}
#foo:after, #foo:before{
content:'';
background:black;
width:100px;
height:100px;
display:block;
position:absolute;
}
#foo:after{
bottom:-100px;
right:-100px;
}
#foo:before{
top:-100px;
right:-100px;
}
It might be a little messy, but it works. Set the :after and :before elements width height and position to the width of the border.
And that gives this effect:
JSFiddle Demo
I hope my crappy photoshop skills explain borders to you.
If you look in the 4 corners of the square you can see little lines, thats where one border starts and the next one begins.
This will always be in issue :P
You could either make it a background image (crappy way)
or you can use other divs to make the borders (crappy as well)
The first solution would be using a pseudo-element, which you will position absolutely to cover the right border. In order to ensure that it covers the border entirely, you will have to offset its top, bottom and right positions by the negative value of the border width. In this case I have used a width of 5px to better illustrate the example:
#foo {
background-color: #eee;
border: 5px solid grey;
width: 100px;
height: 100px;
position: relative;
}
#foo::before {
content: '';
position: absolute;
top: -5px;
bottom: -5px;
right: -5px; /* move by border width */
background-color: blue;
width: 5px;
}
<div id="foo"></div>
Alternatively, you can use CSS box shadow:
#foo {
background-color: #eee;
box-shadow: inset 0 0 0 5px grey;
width: 100px;
height: 100px;
position: relative;
}
#foo::before {
content: '';
position: absolute;
top: 0;
bottom: 0;
right: 0;
width: 5px;
background-color: blue;
}
<div id="foo"></div>
As others have pointed out, your problem is how borders are drawn in CSS.
<div id="foo">Problem</div>
#foo {
border: 30px solid black;
border-right: 30px solid blue;
}
The simplest way to work around this is to use a pseudo element. Since this workaround is entirely dependent on the value of the border-width, I’ll show an example using an SCSS variable to help make it clear where that width value is coming in.
Note: You don’t need SCSS to solve this problem, using a variable just helps readability/maintainability.
HTML:
<div id="foo"></div>
SCSS:
/* Set SCSS variable */
$border-width: 30px;
#foo {
border: $border-width solid black;
position: relative; /* anchor the absolute positioned ::after element */
}
#foo:after {
content: '';
background: blue;
width: $border-width;
height: 100%;
position: absolute;
right: -$border-width;
}
Demo: http://jsbin.com/cimaxe/6
Hopefully it’s clear that everywhere you see $border-width you can replace it with a value like 30px.
This question already has answers here:
How to bevel the corner of a block div?
(4 answers)
Closed 8 years ago.
I am trying to create a Parallelogram with a straight right side in css but so far I am struggling to achieve this.
I am using css ...
-webkit-transform: skew(-18deg);
-moz-transform: skew(-18deg);
-o-transform: skew(-18deg);
...to 'skew' the rectangle to create the Parallelogram.
I am wondering if the right side can be made straight?
Would it require :before and :after in the css?
Any help of this would be great.
Thanks,
Phil
You can achieve this by adding a triangle shaped element and positioning it next to the rectangular element.
Option 1: (Using the border hack)
In the example below, I have added a blue color for the triangular shape only to illustrate how the shape is achieved. Please replace the color in the below line to achieve the parallelogram with a slanted edge on one side and a straight edge on the other.
Change the below
border-color: transparent blue blue transparent;
to
border-color: transparent red red transparent;
Note: When using this method, it is difficult to add an extra outer border to the shape.
Snippet:
.trapezoid{
position: relative;
height: 100px;
width: 100px;
background: red;
margin-left: 50px;
color: white;
}
.trapezoid:after{
position: absolute;
content: '';
left: -50px;
top: 0px;
border-style: solid;
border-color: blue transparent blue transparent;
border-width: 100px 0px 0px 50px;
}
<div class="trapezoid">Some dummy text</div>
Option 2: (Using skew)
.trapezoid{
position: relative;
height: 100px;
width: 100px;
background: beige;
border: 1px solid red;
border-left-width: 0px;
margin-left: 50px;
}
.trapezoid:before{
position: absolute;
content: '';
left: -25px;
top: -1px;
height: 100px;
width: 50px;
background: beige;
border: 1px solid red;
z-index: -1;
-webkit-transform: skew(20deg);
-moz-transform: skew(20deg);
transform: skew(20deg);
}
<div class="trapezoid">Some dummy text.</div>
Add this id to any div youll see the expected result
#trapezoid {
border-bottom: 100px solid red;
border-left: 50px solid transparent;
height: 0;
width: 100px;
}
JSFIDDLe
Need to draw angular sides of menubar as
inner content may be the some labels or links.
How about using CSS3 transform skew?
Demo
.shape {
width: 200px;
height: 50px;
-webkit-transform: skew(30deg);
-moz-transform: skew(30deg);
transform: skew(30deg);
background: #000;
margin: 20px;
}
Nothing much to explain here, it's a simple div element, which I've skewed by 30deg which will result in the shape you expected.
Note: It's a CSS3 property, so older browsers, as well as IE will spoil your things, make sure you use CSS3 Pie.
Other way to achieve this is by using :after and :before pseudo and CSS Triangles along with content property.
Demo 2 (Kept red triangles for demo purpose)
Demo 3 (Color Changed)
Demo 4 (As you commented, you need to use top: 0; for :before and :after pseudo as well, because when you add text, it will shift both the triangles from the top. So inorder to prevent that, use top: 0;)
Here, am using a simple div element and placing 2 CSS triangles which are positioned absolute to the container. This is more compatible than above, if you are going for a NON CSS3 solution, you can choose this. Make sure you use display: block; for :before as well as :after. And ofcourse you can merge the common styles but I've kept both separate, so that you can get easability to customize them separately.
.shape {
width: 200px;
height: 50px;
background: #000;
margin: 50px;
position: relative;
}
.shape:before {
display: block;
content: "";
height: 0;
width: 0;
border: 25px solid #f00;
border-bottom: 25px solid transparent;
border-left: 25px solid transparent;
position: absolute;
left: -50px;
}
.shape:after {
display: block;
content: "";
height: 0;
width: 0;
border: 25px solid #f00;
border-top: 25px solid transparent;
border-right: 25px solid transparent;
position: absolute;
right: -50px;
}
HTML
<div class="shape">
<div class="text">
text goes here
</div>
</div>
CSS
.shape {
width: 200px;
height: 30px;
-webkit-transform: skew(30deg);
-moz-transform: skew(30deg);
transform: skew(30deg);
background: #000;
margin: 20px;
color:#fff;
}
.text{
width: 150px;
height: 30px;
margin:0px auto;
-webkit-transform: skew(-30deg);
-moz-transform: skew(-30deg);
transform: skew(-30deg);
color:#fff;
}
One major gripe I have with using triangular borders is that there is no easy way to have multiple triangles with different colours, even using javascript [because JS can't access the pseudo-elements :before and :after], the alternative being that I use 3 divs, align them properly, and give all of them the same colour, etc... Too much hassle.
The best way would be using transform: skew() for newer browsers.
But you need to keep in mind that this will transform every element inside that div as well. So the text inside your menu-bar would also come up skewed. To counter that, add a reverse-skew on the inner div like this:
.menu-container {
...
transform: skewX(30deg);
...
}
.menu-inner {
...
transform: skewX(-30deg);
...
}
Have fun experimenting... :)