pdt.startTime is datetime
s_first.FromTimeOfDay is a time
I want to subtract the time drom the datetime. When i run the code below, Snowflake gives me this error invalid type [CAST(S_FIRST.FROMTIMEOFDAY AS TIMESTAMP_NTZ(9))] for parameter 'TO_TIMESTAMP_NTZ'
select (pdt.StartTime - (SELECT s_first.FromTimeOfDay::datetime FROM Shift s_first))
from RAW_CPMS_AAR.POWERBI_DowntimeTable AS PDT
When i try this:
select (pdt.StartTime::TIMESTAMP_NTZ(9) - (SELECT s_first.FromTimeOfDay::TIMESTAMP_NTZ(9) FROM Shift s_first))
from RAW_CPMS_AAR.POWERBI_DowntimeTable AS PDT
I get more or less the same error: invalid type [CAST(S_FIRST.FROMTIMEOFDAY AS TIMESTAMP_NTZ(9))] for parameter 'TO_TIMESTAMP_NTZ'
How do I convert the time into a datetime format so that I can subtract the two. It doesnt seem to me that there is a clear way to convert time into datetime in snowflake.
Is this what you're after?
select current_timestamp() as sample_timestamp
, time(sample_timestamp) as sample_time
, date(sample_timestamp) as sample_date;
A user pointed me in the right direction. i didnt realize i could use "dateadd" to also subtract time.
dateadd(HOUR, - (HOUR(current_timestamp())), temp.DateTime)
Related
Is there any way in BigQuery to get the current UTC timezone offset from a timezone name? For example using the input:
`Australia/Victoria`
How could I currently return:
+10:00
Below example for BigQuery STandard SQL
#standardSQL
WITH `project.dataset.table` AS (
SELECT 'Australia/Victoria' tz_string
)
SELECT tz_string, DATETIME_DIFF(CURRENT_DATETIME(tz_string), CURRENT_DATETIME(), hour) tz_hours
FROM `project.dataset.table`
with result
Row tz_string tz_hours
1 Australia/Victoria 10
Another way to do this is to use the (at least, now) built in FORMAT_TIMESTAMP() function and the %Ez format element.
SELECT FORMAT_TIMESTAMP('%Ez', CURRENT_TIMESTAMP(), 'Australia/Victoria');
Result:
+11:00
A is in the format of timestamp(6). I need it in timestamp(0). The code I am using is the following:
cast(cast(A AS date) as timestamp(0))
FROM 'table'
where A >= '?StartDT'
After inputing the date I want for the parameter I get the 'Invalid timestamp' error.
If A is truly a Timestamp(6) then casting it first as a DATE will affectively trim off the time elements, so when you cast the result to a TIMESTAMP(0) you are going to end up with a time of 00:00:00.
You'll need to also cast the TIMESTAMP(6) field as a time and then add the results together like:
CAST(CAST(A AS DATE) AS TIMESTAMP(0)) + (CAST(A AS TIME(6)) - TIME '00:00:00' HOUR TO SECOND)
You can also use SUBSTRING() to snip off the last 6 characters of the TIMESTAMP(6) field and cast that resulting string to a TIMESTAMP(0):
CAST(SUBSTRING(CAST(A AS CHAR(26)) FROM 1 FOR 19) AS TIMESTAMP(0))
This doesn't address the INVALID TIMESTAMP error you are getting though. Are you certain that field A is a TIMESTAMP(6) and not a VARCHAR() that looks like a Timestamp? What happens when you remove the outer cast, are their any dates in the result that look like they wouldn't convert nicely to a timestamp? Something is not quite right here, and I suspect that it's in your data.
How could I get only time of a varchar2? I do:
select to_date(substr(fecha,10,16),'HH:MI:SS AM') from total;
But it gives me:
01/06/2014 5:50:01
01/06/2014 5:50:05
01/06/2014 5:50:05
01/06/2014 5:50:50
And I would like to have:
5:50:01
5:50:05
5:50:05
5:50:50
Any help? Please
Although it may not be what you expected, the code is working correctly. In Oracle, if you don't specify the day-month-year portion of a date it defaults to the first day of the current month. An Oracle DATE must always have a day/month/year - there's no way to have a time without a date in a DATE column or variable.
SQLFiddle here.
If you really want to have it display only the time portion of the date you'll just have to extract only the hours-minutes-seconds using TO_CHAR(date_value, 'HH24:MI:SS') and treat it as a character string.
Share and enjoy.
i think you should use both, to_char and to_date:
select to_char(to_date(fecha,'dd-mm-yyyy HH:MI:SS AM'),'HH:MI:SS AM')
time from total;
Select distinct Format(DateAdd(""s""," & columnname & ",""1/1/1980 12:00:00 AM""), 'dd-MMM-yyyy') as A
I have assumed that the seconds to add and the original date are hard coded values below whilst awaiting clarifications requested in the comments.
To add a number of seconds to a date you can use:
select datetime('1980-01-01 00:00:00', "345000 seconds");
This gives the result: 1980-01-04 23:50:00
The example above is just under 4 days in seconds, if you want to truncate the result to just the date as implied by the query in your questions then you can wrap this inside a date function. However, this would give the result in the format "YYYY-MM-DD" rather than "DD-MMM-YYYY" as your access query does.
Unfortunately I cannot find any native SQLite function to convert a numeric month value to mmm format. You can do this manually with replace (similar to the answer to this question), but this is a bit messy.
If you are happy to live with the numeric months then you can simply use:
select strftime('%d-%m-%Y', '1980-01-01 00:00:00', "345000 seconds");
This gives the result: 04-01-1980
More information on the SQLite date / time functions can be found here.
I am trying to convert the following timestamp(in milliseconds since epoch) to normal date-time. Am using sqlite3 on windows xp.
I am using this query:
select datetime((timestamp/86400000)+25569) from table;
(timestamp is the column name which contains the values like 1289325613669,1289325823860,
1289327180545).
I dont seem to be getting the right values. Am i doing something wrong?
Do this:
select datetime('1289325613', 'unixepoch');
The unixepoch modifier expects a value in seconds.
Currently, what you provide to datetime is interpreted as a Julian Day number.
The reference for date and time functions is here