I've just started using SPARQL and I've encountered a challenge with inserting.
I want to insert values to empty field from a different field ( it's like a hierarchy, I want to insert data from parent).
Graph is the same for both fields.
I think i searched for examples everywhere and i tried all of them and even got status 200 but there were no values. I One of the queries I tried:
PREFIX rdf:
PREFIX rdfs:
PREFIX edg:
PREFIX metadata:
PREFIX op:
PREFIX owl:
PREFIX c: <http://abc/>
INSERT
{ GRAPH <http://xyz/> {
?subclass1 ?iBT ?Bterm } }
WHERE
{SELECT ?subclass1 ?iBT ?Bterm
WHERE
{
{?subclass rdfs:subClassOf op:BusinessObject.
?subclass rdfs:label ?label.
?subclass op:bT ?BT.
?BT rdfs:label ?Bterm.
?subclass1 rdfs:subClassOf ?subclass.
?subclass1 rdfs:label ?label1.
OPTIONAL{?subclass1 op:bT ?BT1.}
OPTIONAL{?subclass1 op:iBT ?iBT.
?iBT rdfs:label ?ilabel}
FILTER(?label="something").
}
} }
I want to paste values from ?Bterm to ?iBt.
I added filter to check on one example.
I would appreciate any suggestions with this.
INSERT
{
GRAPH <urn:sparql:tests:insert:informative2> { ?book ?p ?v }
}
WHERE
{
GRAPH <urn:sparql:tests:insert:informative>
{
?book <http://purl.org/dc/elements/1.1/date> ?date .
FILTER ( ?date > "1970-01-01T00:00:00-02:00"^^xsd:dateTime )
?book ?p ?v
}
}
I expected the value Bterm (from example above) to be inserted to iBt and I even got status 200 but there were no values inserted.
Related
I'm working on a DBPedia project to locate female singers who would have been active during the 1960s (approx).
Unfortunately when I try to select a range of singers who were active from 1955 - 1972 I miss out on singers who were active before 1955 (the results negate some singers, for instance Umm Kulthum who was active from 1925-1973).
My code is below, and shows where the filter is only including artists who were active exclusively for this date range. I want to create a filter that says "give me all singers who would have been musically active during the this date range in particular, but also include those who might have been active from a period before and including this date range"? I don't want those that were only active before this date range.
PREFIX dbo: <http://dbpedia.org/ontology/>
PREFIX dbp: <http://dbpedia.org/resource/>
PREFIX foaf: <http://xmlns.com/foaf/0.1/>
PREFIX dct: <http://purl.org/dc/terms/>
PREFIX dbc: <http://dbpedia.org/resource/Category:>
SELECT distinct ?name ?person ?thumbnail ?birthDate ?active
where {
?person foaf:name ?name .
?person dct:subject ?subject.
?person dbo:birthDate ?birthDate.
OPTIONAL {?person dbo:thumbnail ?thumbnail}
OPTIONAL {?person dbo:activeYearsStartYear ?active}
{ ?person a dbo:MusicalArtist .
filter exists {?person
dct:subject/skos:broader*dbc:Female_singers_by_nationality}}
filter (?active > '1955-04-18T22:29:33.667Z'^^xsd:dateTime && ?active <
'1974-01-01T21:37:37.708Z'^^xsd:dateTime)} order by ?active
One solution is to also check the reverse in your filter using a boolean or. Like this:
SELECT distinct ?name ?person ?thumbnail ?birthDate ?activeStart ?activeEnd
where {
?person foaf:name ?name .
?person dct:subject ?subject.
?person dbo:birthDate ?birthDate.
?person dbo:activeYearsStartYear ?activeStart.
?person dbo:activeYearsEndYear ?activeEnd
OPTIONAL {?person dbo:thumbnail ?thumbnail }
{ ?person a dbo:MusicalArtist .
filter exists {
?person dct:subject/skos:broader* dbc:Female_singers_by_nationality
}
}
BIND('1955-04-18T22:29:33.667Z'^^xsd:dateTime as ?startPeriod)
BIND('1974-01-01T21:37:37.708Z'^^xsd:dateTime as ?endPeriod)
filter ( (?activeStart > ?startPeriod && ?activeStart < ?endPeriod)
|| (?activeStart < ?startPeriod && ?activeEnd > ?startPeriod))
}
order by ?activeStart
I'm creating an interface in SPARQL to query DBpedia.
For example you can search people who were born in Paris, or people who born in 1966.
My request is generalized and the value changes according to your choice.
According to my example above, here variable1= dbo:birthplace or variable1=dbo:birthDate.
SELECT *
WHERE {
?x a dbo:Person .
?x variable1 ?z.
}
I add a line to write the name of the place you want:
SELECT *
WHERE {
?x a dbo:Person .
?x variable1 ?z.
?z rdfs:label variable2.
}
But this can work only if ?z is an URI, which is not the case for date.
Does someone know a way to make these 2 situations working ?
I tried to add an if statement saying:
If ?z is a URI, add the line ?z rdfs:label variable2.
Otherwise check if ?z = variable2
But it seems that if statement works only to create a new parameter, in this example ?type.
BIND (IF(isURI(?z),"URI","Not")AS ?type).
While I would like something like :
BIND (IF(isURI(?z),?z rdfs:label ?nameobject,?nameobject)AS ?nameobject).
Sorry if my question is not asked correctly, I tried to do it as clear as I could ..
EDIT: Using OPTIONAL, thanks to Stanislav Kralin
I tried with optional, here is my code:
SELECT distinct *
WHERE {
?x a dbo:Person .
?x rdfs:label ?name .
?x dbp:birthName ?z .
OPTIONAL{ ?z rdfs:label ?nameobject .}
OPTIONAL{BIND(?z as ?nameobject) .}
BIND (concat("http://wikipedia.org/wiki/",replace(?name," ","_")) as ?wikilink) .
}
LIMIT 100
So if ?z is an URI, it gives the rdfs:label; if not (that is typed literal or plain literal with language tag), it should keep ?z.
It does the first optional but not the the second one. However if I write this
OPTIONAL{BIND("Try" as ?nameobject) .}
it writes the "Try" statement. So I think I am not far from the solution, perhaps I'm not writing correctly the BIND.
Finally, here is the solution! :)
Here is the beginning of my code :
SELECT distinct *
WHERE {
?x a dbo:Activity .
?x rdfs:label ?name .
?x dbp:skills ?z .
}
ORDER BY?x
LIMIT 100
My problem was that I needed to make 2 different queries according to the data type of my ?z variable.
I tried to do it with IF, but as explained here, in SPARQL IF is an operator and not a statement.
So I tried with OPTIONAL by saying :
OPTIONAL{ ?z rdfs:label ?nameobject .}
OPTIONAL{BIND( ?z as ?nameobject) .}
That means, if rdfs:label of ?z exists, put it in ?nameobject, otherwise, put ?z in ?nameobject.
But that didn't work, probably because of the different types of variables.
Finally my solution is to create 2 columns, to put the data in the same type, and then to put them in the same column:
SELECT distinct *
WHERE {
?x a dbo:Activity .
?x rdfs:label ?name .
?x dbp:skills ?z .
OPTIONAL{ ?z rdfs:label ?nameobjectURI .}
BIND( IF(isURI(?z),"",concat(?z," ")) as ?nameobjectOTH) .
BIND( IF(bound(?nameobjectURI),STR(?nameobjectURI),?nameobjectOTH) as ?nameobject) .
}
ORDER BY?x
LIMIT 100
And that works! I hope it will help someone else :)
EDIT with COALESCE solution, from Stanislav Kralin
It is possible to simplify the code like this :
SELECT distinct *
WHERE {
?x a dbo:Activity .
?x rdfs:label ?name .
BIND(STR(?name) as ?namestr) .
?x dbp:skills ?z .
OPTIONAL{ ?z rdfs:label ?nameobjectURI .}
BIND (COALESCE(STR(?nameobjectURI),concat(?z," ")) as ?nameobject) .
}
I am using:
.updatePivot({sort_order:2}, [some query goes here])
how can I format the query so that only the queried row in the join table is updated? I've tried:
.updatePivot({sort_order:2}, { where: {tagId: 117} })
But that still sets sort_order to 2 for all the rows in the table, not just the row where tagId=117.
The documentation for updatePivot says that the options parameter is a hash of options. so you would need to specify it as
.updatePivot({sort_order:2}, { query: { where: {tagId: 117} } })
alternately I believe you can do something like
.forge({tagId: 117}).related('b2m relationship').updatePivot({sort_order: 2})
I am trying to run an example of inferencing using subClassOf relationship.
For some reason, I am getting the select query results when I use xquery but not when I use sparql.
xquery
let $sq :=
'PREFIX rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#>
PREFIX rdfs: <http://www.w3.org/2000/01/rdf-schema#>
SELECT *
WHERE { ?s rdf:type <http://www.smartlogic.com/geography#Europe> .
} '
let $rs := sem:ruleset-store("rdfs.rules", sem:store())
return sem:sparql($sq, (), (), $rs)
sparql
PREFIX rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#>
PREFIX rdfs: <http://www.w3.org/2000/01/rdf-schema#>
SELECT *
WHERE { ?s rdf:type <http://www.smartlogic.com/geography#Europe> .
}
As of now (MarkLogic 8.0-3), the SPARQL interface does not provide a way to specify a set of inference rules to use. You can configure a default ruleset to use with the database, which will be used with all SPARQL queries.
As you've done, you can use sem:ruleset-store() (XQuery) or sem.rulesetStore() (JavaScript) to specify a ruleset to use.
I have a triple store that contains mail archive data. So let's say I have a lot of persons (foaf:Person) that have sent (ex:hasSent) and received (ex:hasReceived) emails (ex:Email).
Example:
SELECT ?person ?email
WHERE {
?email rdf:type ex:Email.
?person rdf:type foaf:Person;
ex:hasSent ?email.
}
The same works for ex:hasReceived, of course. Now I would like to do some statistics and analytics, i.e. determine how many emails an individual has sent and received. Doing this for only one predicate is a simple aggregation:
SELECT ?person (COUNT(?email) AS ?count)
WHERE {
?email rdf:type ex:Email.
?person rdf:type foaf:Person;
ex:hasSent ?email.
}
GROUP BY ?person
However, I need need the number of received emails as well and I would like to do this without having to issue a separate query. So I tried the following:
SELECT ?person (COUNT(?email1) AS ?sent_emails) (COUNT(?email2) AS ?received_emails)
WHERE {
?person rdf:type foaf:Person.
?sent_email rdf:type ex:Email.
?person ex:hasSent ?sent_email.
?received_email rdf:type ex:Email.
?person ex:hasReceived ?received_email.
}
GROUP BY ?person
This did not seem to be right, as the numbers for the emails sent vs. received were exactly the same. I assume this is because my SPARQL statement results in a cross product of all mails a person has ever sent and received, right?
What do I need to do in order to get the statistics right on a per-individual basis?
COUNT(?email1) isn't counting anything as ?email1 is undefined. Also, there is partial cross product as you mention - DISTINCT will help.
Try (COUNT(DISTINCT ?sent_email) AS ?sent_emails)