Rust Polars: how to change column value from string to datetime - datetime

Question

I'm reading my CSV file with polars, but there's a column with values that I need to convert to DateTime. I've managed to manipulate the String (remove dots) now I need to strptime to convert to DateTime. How can I do this in rust polars?
My old project in Python did this, but I want to rewrite this in Rust Polars:
df["Meetdatum"] = df["Meetdatum"].str.replace(".", "", regex=False)
df["Datum"] = pd.to_datetime(df["Meetdatum"], format="%d %b %Y")

Answer 1

You can use something like this:
Cargo.toml:
[dependencies]
polars = { version = "*", features = [
"lazy",
"dtype-datetime",
"strings",
"lazy_regex",
] }
main.rs:
use polars::prelude::*;
fn main() {
let df = DataFrame::new(vec![Series::new(
"date_str",
&[
"5. Oct, ...2022",
"..31 ..Oct.., 2022.",
"E.R.R.O.R",
"31 Sep, 2022",
],
)])
.unwrap()
.lazy();
let df = df.with_column(
col("date_str")
.str()
.replace_all(lit("."), lit(""), true)
.str()
.strptime(StrpTimeOptions {
date_dtype: DataType::Date,
fmt: Some("%d %b, %Y".into()),
strict: false,
exact: true,
})
.alias("date"),
);
println!("{:?}", df.collect().unwrap());
}
Result:
shape: (4, 2)
┌─────────────────────┬────────────┐
│ date_str ┆ date │
│ --- ┆ --- │
│ str ┆ date │
╞═════════════════════╪════════════╡
│ 5. Oct, ...2022 ┆ 2022-10-05 │
├╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌┼╌╌╌╌╌╌╌╌╌╌╌╌┤
│ ..31 ..Oct.., 2022. ┆ 2022-10-31 │
├╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌┼╌╌╌╌╌╌╌╌╌╌╌╌┤
│ E.R.R.O.R ┆ null │
├╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌╌┼╌╌╌╌╌╌╌╌╌╌╌╌┤
│ 31 Sep, 2022 ┆ null │
└─────────────────────┴────────────┘