lift value out of / or into ZIO to assert it - zio

I have a ZIO that looks like this:
ZIO[transactor.Transactor[Task], Serializable, String]
and I need to assert the String, that is in that ZIO with another plain String.
So my question is:
How can I assert the plain String, with the String in the ZIO, or
can I lift the String into that same ZIO, to assert it with this one:
ZIO[transactor.Transactor[Task], Serializable, String]
I´m working with ZIO-Test as my testing framework.

I got this based on the rock the jvm zio course. Important things are highlighted in the comments
package com.w33b
import zio.test._
import zio._
object ZIOAssert extends ZIOSpecDefault {
class ATask
abstract class Transact[ATask] {
def get(): String
def put(ATask: ATask): ATask
}
// This is the mock service that we will use to create a ZLayer
val mockTransact = ZIO.succeed(new Transact[ATask] {
override def get(): String = "hello"
override def put(aTask: ATask): ATask = new ATask
})
// This is the method we are testing and we need a service (Zlayer) associated with it.
// We then use the service to invoke a method to get our return value
def methodUnderTest: ZIO[Transact[ATask], Serializable, String] = {
for {
trans <- ZIO.service[Transact[ATask]]
tVal = trans.get()
} yield tVal
}
def spec = suite("Let's test that ZIO lift")(
test("lets test that lift") {
assertZIO(methodUnderTest)(Assertion.equalTo("hello"))
}
).provide(ZLayer.fromZIO(mockTransact)) // Important to provide the layer or we can't test
}

with ZIO 2.x
val spec = suite("tetst")(
test("whatever"){
val effect: ZIO[transactor.Transactor[Task], Serializable, String] = ???
val expected: String = ???
for {
value <- effect
} yield assertTrue(value == expected)
}
)
In general, you just create here a ZIO with the assertion in the success channel.

Related

How do I convert an ApiFuture to a ZIO Task?

I am working with Firebase so I have a lot of return types of type ApiFuture<A>. I'd like to turn them into a Task[A] to work with ZIO effects.
We can create a method to convert all of them using Typeclasses:
trait EffectUtils[F[_]] {
def toEffect[A](a: F[A]): Task[A]
}
object EffectUtils {
implicit val apiFuture: EffectUtils[ApiFuture] = new EffectUtils[ApiFuture] {
override def toEffect[A](a: ApiFuture[A]): Task[A] = Task.effectAsync[A]( cb =>
ApiFutures.addCallback(a, new ApiFutureCallback[A] {
override def onFailure(t: Throwable): Unit = cb(Task.fail(t))
override def onSuccess(result: A): Unit = cb(Task.succeed(result))
})
)
}
implicit class ApiFutureOps[A](f: ApiFuture[A]) {
def toEffect(implicit instance: EffectUtils[ApiFuture]) = instance.toEffect(f)
}
}
Now, when we make an API request and want to convert the result to a ZIO type, it's easy:
import EffectUtils._
object App {
// calling a Firebase function
val record: Task[UserRecord] = firebase.getInstance().auth().getUserByEmailAsync(email).toEffect

How to change a member field with Kotlin reflection?

I'm porting a class from Java to Kotlin. This class declares hundreds of objects. Each object has a name property which is identical with the declared variable name of the object. Java reflection allows to use the declared name via reflection to set the object member name. Just saves one parameter in hundreds of constructors.
I try to do the same in Kotlin but can't figure out how to do the property setting. Here is some simplified test code:
import kotlin.reflect.full.companionObject
import kotlin.reflect.full.declaredMemberProperties
class MyTestObject() {
var name: String = "NotInitialized"
companion object {
val Anton = MyTestObject()
val Berta = MyTestObject()
val Caesar = MyTestObject()
}
}
fun main(args : Array<String>) {
println(MyTestObject.Anton.name) // name not yet initialized
// Initialize 'name' with the variable name of the object:
for (member in MyTestObject::class.companionObject!!.declaredMemberProperties) {
if (member.returnType.toString() == "myPackage.MyTestObject") {
println("$member: ${member.name}")
// Set 'name' property to 'member.name':
// ???
}
}
println(MyTestObject.Anton.name) // now with the initialized name
}
The ??? line is where I would like to get access to the name property of MyTestObject to set it to to member.name. I'm looking for a function similar to (member.toObject() as MyTestObject).name = member.name.
While kotlin-reflection strives to be type-safe, sometimes the type system and the inference logic are not enough to allow for the things like what you are trying to do in a type-safe way. So, you have to make unchecked casts, stating that your knowledge about the types is more than the compiler can infer.
In your case, it's enough to cast member so that you can pass the companion object instance into its .get(...) and use the result as a MyTestObject, replace the // ??? line with:
#Suppress("UNCHECKED_CAST")
(member as KProperty1<Any, MyTestObject>)
.get(MyTestObject::class.companionObject!!.objectInstance!!)
.name = member.name
If you can replace MyTestObject::class.companionObject!! with MyTestObject.Companion::class (i.e. your actual use case does not involve getting .companionObject from different classes), the unchecked cast is not needed, and you can replace the statement above with this:
(member.get(MyTestObject.Companion) as MyTestObject).name = member.name
As an alternative that does not require companion object reflection at all, you can do the same binding logic with the delegation. Implementing provideDelegate allows you to customize the logic of initializing the property, and that's where you can assign the names:
operator fun MyTestObject.provideDelegate(
thisRef: MyTestObject.Companion,
property: KProperty<*>
) = apply { name = property.name }
operator fun MyTestObject.getValue(
thisRef: MyTestObject.Companion,
property: KProperty<*>
) = this
Then declare your properties as
val Anton by MyTestObject()
val Berta by MyTestObject()
val Caesar by MyTestObject()
Here is the final test code based on hotkey's solution:
package myPackage
import kotlin.reflect.full.declaredMemberProperties
class MyTestObject() {
lateinit var name: String
companion object {
val Anton = MyTestObject()
val Berta = MyTestObject()
val Caesar = MyTestObject()
init {
for (member in MyTestObject.Companion::class.declaredMemberProperties) {
if (member.returnType.toString() == "myPackage.MyTestObject") {
(member.get(MyTestObject.Companion) as MyTestObject).name = member.name
}
}
}
}
}
fun main(args : Array<String>) {
println(MyTestObject.Anton.name)
println(MyTestObject.Caesar.name)
}

How do I call a Scala Object method using reflection?

say, I have the following:
trait SomeTrait {
def someMethod: String;
}
object SomeObject extends SomeTrait {
def someMethod = "something";
}
I would like to call "someMethod" using reflection as I have the object name as a String.
Something like:
val objectName = "SomeObject"
val someTrait:SomeTrait = ???.asInstanceOf[SomeTrait]
someTrait.someMethod
or something similar.
Thanks
def companion[T](name : String)(implicit man: Manifest[T]) : T =
Class.forName(name + "$").getField("MODULE$").get(man.erasure).asInstanceOf[T]
val result = companion[SomeTrait]("SomeObject").someMethod
Since scala 2.10, we can use the reflection of Module:
import scala.reflect.runtime.universe
val runtimeMirror = universe.runtimeMirror(getClass.getClassLoader)
val module = runtimeMirror.staticModule("SomeObject")
val obj = runtimeMirror.reflectModule(module)
val someTrait:SomeTrait = obj.instance.asInstanceOf[SomeTrait]
someTrait.someMethod
For classes, this can be done pretty easily using the standard java reflection classOf method. For Scala objects, it is a bit more work, but it still can be done:
trait SomeTrait { def someMethod: String}
object SomeObject extends SomeTrait { def someMethod = "something"}
class SomeClass extends SomeTrait { def someMethod = "something"}
object Main {
def main(args:Array[String]) = {
val someClassTrait:SomeTrait = Class.forName("SomeClass").newInstance().asInstanceOf[SomeTrait]
println("calling someClassTrait: " + someClassTrait.someMethod)
val objectName = "SomeObject$"
val cons = Class.forName(objectName).getDeclaredConstructors();
cons(0).setAccessible(true);
val someObjectTrait:SomeTrait = cons(0).newInstance().asInstanceOf[SomeTrait]
println("calling someObjectTrait: " + someObjectTrait.someMethod)
}
}
//prints:
calling someClassTrait: something
calling someObjectTrait: something

Scala: How do I dynamically instantiate an object and invoke a method using reflection?

In Scala, what's the best way to dynamically instantiate an object and invoke a method using reflection?
I would like to do Scala-equivalent of the following Java code:
Class class = Class.forName("Foo");
Object foo = class.newInstance();
Method method = class.getMethod("hello", null);
method.invoke(foo, null);
In the above code, both the class name and the method name are passed in dynamically. The above Java mechanism could probably be used for Foo and hello(), but the Scala types don't match one-to-one with that of Java. For example, a class may be declared implicitly for a singleton object. Also Scala method allows all sorts of symbols to be its name. Both are resolved by name mangling. See Interop Between Java and Scala.
Another issue seems to be the matching of parameters by resolving overloads and autoboxing, described in Reflection from Scala - Heaven and Hell.
There is an easier way to invoke method reflectively without resorting to calling Java reflection methods: use Structural Typing.
Just cast the object reference to a Structural Type which has the necessary method signature then call the method: no reflection necessary (of course, Scala is doing reflection underneath but we don't need to do it).
class Foo {
def hello(name: String): String = "Hello there, %s".format(name)
}
object FooMain {
def main(args: Array[String]) {
val foo = Class.forName("Foo").newInstance.asInstanceOf[{ def hello(name: String): String }]
println(foo.hello("Walter")) // prints "Hello there, Walter"
}
}
The answers by VonC and Walter Chang are quite good, so I'll just complement with one Scala 2.8 Experimental feature. In fact, I won't even bother to dress it up, I'll just copy the scaladoc.
object Invocation
extends AnyRef
A more convenient syntax for reflective
invocation. Example usage:
class Obj { private def foo(x: Int, y: String): Long = x + y.length }
You can call it reflectively one of
two ways:
import scala.reflect.Invocation._
(new Obj) o 'foo(5, "abc") // the 'o' method returns Any
val x: Long = (new Obj) oo 'foo(5, "abc") // the 'oo' method casts to expected type.
If you call the oo
method and do not give the type
inferencer enough help, it will most
likely infer Nothing, which will
result in a ClassCastException.
Author Paul Phillips
The instanciation part could use the Manifest: see this SO answer
experimental feature in Scala called manifests which are a way to get around a Java constraint regarding type erasure
class Test[T](implicit m : Manifest[T]) {
val testVal = m.erasure.newInstance().asInstanceOf[T]
}
With this version you still write
class Foo
val t = new Test[Foo]
However, if there's no no-arg constructor available you get a runtime exception instead of a static type error
scala> new Test[Set[String]]
java.lang.InstantiationException: scala.collection.immutable.Set
at java.lang.Class.newInstance0(Class.java:340)
So the true type safe solution would be using a Factory.
Note: as stated in this thread, Manifest is here to stay, but is for now "only use is to give access to the erasure of the type as a Class instance."
The only thing manifests give you now is the erasure of the static type of a parameter at the call site (contrary to getClass which give you the erasure of the dynamic type).
You can then get a method through reflection:
classOf[ClassName].getMethod("main", classOf[Array[String]])
and invoke it
scala> class A {
| def foo_=(foo: Boolean) = "bar"
| }
defined class A
scala>val a = new A
a: A = A#1f854bd
scala>a.getClass.getMethod(decode("foo_="),
classOf[Boolean]).invoke(a, java.lang.Boolean.TRUE)
res15: java.lang.Object = bar
In case you need to invoke a method of a Scala 2.10 object (not class) and you have the names of the method and object as Strings, you can do it like this:
package com.example.mytest
import scala.reflect.runtime.universe
class MyTest
object MyTest {
def target(i: Int) = println(i)
def invoker(objectName: String, methodName: String, arg: Any) = {
val runtimeMirror = universe.runtimeMirror(getClass.getClassLoader)
val moduleSymbol = runtimeMirror.moduleSymbol(
Class.forName(objectName))
val targetMethod = moduleSymbol.typeSignature
.members
.filter(x => x.isMethod && x.name.toString == methodName)
.head
.asMethod
runtimeMirror.reflect(runtimeMirror.reflectModule(moduleSymbol).instance)
.reflectMethod(targetMethod)(arg)
}
def main(args: Array[String]): Unit = {
invoker("com.example.mytest.MyTest$", "target", 5)
}
}
This prints 5 to standard output.
Further details in Scala Documentation.
Working up from #nedim's answer, here is a basis for a full answer,
main difference being here below we instantiate naive classes. This code does not handle the case of multiple constructors, and is by no means a full answer.
import scala.reflect.runtime.universe
case class Case(foo: Int) {
println("Case Case Instantiated")
}
class Class {
println("Class Instantiated")
}
object Inst {
def apply(className: String, arg: Any) = {
val runtimeMirror: universe.Mirror = universe.runtimeMirror(getClass.getClassLoader)
val classSymbol: universe.ClassSymbol = runtimeMirror.classSymbol(Class.forName(className))
val classMirror: universe.ClassMirror = runtimeMirror.reflectClass(classSymbol)
if (classSymbol.companion.toString() == "<none>") // TODO: use nicer method "hiding" in the api?
{
println(s"Info: $className has no companion object")
val constructors = classSymbol.typeSignature.members.filter(_.isConstructor).toList
if (constructors.length > 1) {
println(s"Info: $className has several constructors")
}
else {
val constructorMirror = classMirror.reflectConstructor(constructors.head.asMethod) // we can reuse it
constructorMirror()
}
}
else
{
val companionSymbol = classSymbol.companion
println(s"Info: $className has companion object $companionSymbol")
// TBD
}
}
}
object app extends App {
val c = Inst("Class", "")
val cc = Inst("Case", "")
}
Here is a build.sbt that would compile it:
lazy val reflection = (project in file("."))
.settings(
scalaVersion := "2.11.7",
libraryDependencies ++= Seq(
"org.scala-lang" % "scala-compiler" % scalaVersion.value % "provided",
"org.scala-lang" % "scala-library" % scalaVersion.value % "provided"
)
)

How to create a decent toString() method in scala using reflection?

To make debug-time introspection into classes easy, I'd like to make a generic toString method in the base class for the objects in question. As it's not performance critical code, I'd like to use Reflection to print out field name/value pairs ("x=1, y=2" etc).
Is there an easy way to do this? I tried several potential solutions, and ran up against security access issues, etc.
To be clear, the toString() method in the base class should reflectively iterate over public vals in any classes that inherit from it, as well as any traits that are mixed in.
Example:
override def toString() = {
getClass().getDeclaredFields().map { field:Field =>
field.setAccessible(true)
field.getName() + ": " + field.getType() + " = " + field.get(this).toString()
}.deepMkString("\n")
}
Uses Java Reflection API, so don't forget to import java.lang.reflect._
Also, you may need to catch IllegalAccessException on the field.get(this) calls in some scenarios, but this is just meant as a starting point.
Are you aware the Scala case classes get these compiler-generated methods:
toString(): String
equals(other: Any): Boolean
hashCode: Int
They also get companion objects for "new-less" constructors and pattern matching.
The generated toString() is pretty much like the one you describe.
import util._ // For Scala 2.8.x NameTransformer
import scala.tools.nsc.util._ // For Scala 2.7.x NameTransformer
/**
* Repeatedly run `f` until it returns None, and assemble results in a Stream.
*/
def unfold[A](a: A, f: A => Option[A]): Stream[A] = {
Stream.cons(a, f(a).map(unfold(_, f)).getOrElse(Stream.empty))
}
def get[T](f: java.lang.reflect.Field, a: AnyRef): T = {
f.setAccessible(true)
f.get(a).asInstanceOf[T]
}
/**
* #return None if t is null, Some(t) otherwise.
*/
def optNull[T <: AnyRef](t: T): Option[T] = if (t eq null) None else Some(t)
/**
* #return a Stream starting with the class c and continuing with its superclasses.
*/
def classAndSuperClasses(c: Class[_]): Stream[Class[_]] = unfold[Class[_]](c, (c) => optNull(c.getSuperclass))
def showReflect(a: AnyRef): String = {
val fields = classAndSuperClasses(a.getClass).flatMap(_.getDeclaredFields).filter(!_.isSynthetic)
fields.map((f) => NameTransformer.decode(f.getName) + "=" + get(f, a)).mkString(",")
}
// TEST
trait T {
val t1 = "t1"
}
class Base(val foo: String, val ?? : Int) {
}
class Derived(val d: Int) extends Base("foo", 1) with T
assert(showReflect(new Derived(1)) == "t1=t1,d=1,??=1,foo=foo")
Scala doesn't generate any public fields. They're all going to be private. The accessor methods are what will be public, reflect upon those. Given a class like:
class A {
var x = 5
}
The generated bytecode looks like:
private int x;
public void x_$eq(int);
public int x();

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