What are hybrid-integer? [closed] - math

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what are Hybrid Integers mentioned in this problem and what are applications of Hybrid Integers?

"what are Hybrid Integers?" They are defined in the first line of the problem description.
"what are applications of Hybrid Integers?"
They serve describing a programming challenge, which you have found.

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Why is the equation y^2dy = 0 an exact equation? [closed]

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I’m not sure why y^2.dy = 0 is an exact differential equation. It popped up in my lecture but I don’t understand why it is one even though it doesn’t contain an x variable.
I asked my friend but he doesn’t remember this section very well and I have searched online for a solution or a similar example but can’t find anything.

Can one Cranberry wireless AP (Access Point) have multiple BSSID? [closed]

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I am not sure if this is the right platform to ask this question (does anyone of you know a community like this one where I can post questions solely related to Networking?), but can one AP have multiple bssid?
I checked the bssid of one particular AP, but it's bssid is showing different (does not match with its MAC that is there on company sticker it comes with).

vehicle is driving pass another vehicle without overtaking [closed]

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enter image description here
am trying to simulate vehicle overtaking others, but for some reason the fast vehicle is going through other slow ones
I have set both car sources to the same road, and same lane[0],

how to calculate pitch angle if I have two antennas? [closed]

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Please provide detailed information about the formula, and some illustrations would be more intuitive and easier to understand.
I want to calculate the pitch angle from two antennas. I googled some, but I didn't get the answer.

How do I calculate the value of b from this formula? [closed]

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Closed 4 months ago.
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I have the following forumla:
(((a*(1/b))-1)/(a-1))*1000 = c
But I need to retrospectively go back through some data to find the value of b, which was not recorded (a and c were). How can I do this?
((c/1000)*(a-1)+1)/a=1/b
then
b=a/((c/1000)*(a-1)+1)

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