Comparing rows of an R matrix with a predefined vector - r

Question

I have made a matrix with values 1 and 0, and I want to check if there is one or more rows identical to (0, 0, 0, 0, 0, 0, 0, 0, 0, 0).
How can I do this?
Here's my code so far for making the matrix:
moeda <- c(0, 1)
n <- 100
casosTotais <- 0
casosFav <- 0
caras <- c(0, 0, 0, 0, 0, 0, 0, 0, 0, 0) ## the vector to compare with
matriz <- matrix(nrow = n, ncol = 10)
i <- 1
lin <- 1
col <- 1
while(i <= n * 10){
matriz[lin, col] <- sample(moeda,1)
if(col==10){
lin <- lin + 1
col <- col - 10
}
i <- i + 1
col <- col + 1
}
matriz

Answer 1

I will first assume a general caras with zeros and ones:
## a vector of TRUE/FALSE; TRUE means a row of `matriz` is identical to `caras`
comp <- colSums(abs(t(matriz) - caras)) == 0
Then if caras is a simply a vector of zeros:
## a vector of TRUE/FALSE; TRUE means a row of `matriz` only contains zeros
comp <- rowSums(matriz) == 0
If you want to summarize the comparison:
To know which rows of matriz are identical to caras, do which(comp).
To know if any row of matriz is identical to caras, do any(comp).
To know how many rows of matriz is identical to caras, do sum(comp).
Note: You can generate this random matrix using:
## an n x 10 random matrix of zeros and ones
matriz <- matrix(rbinom(n * 10, size = 1, prob = 0.5), ncol = 10)