How do I update the year in a chrono DateTime instance? - datetime

How do I change the year in a DateTime<FixedOffset> instance (from the rust crate chrono)?
That is, create a new instance of DateTime<FixedOffset> that copies the month and day from the old instance.
In other words, how would I complete the following code:
fn datetime_set_year(
datetime: &DateTime<FixedOffset>,
year: &i32
) -> DateTime<FixedOffset>
The code can ignore exceptional cases like leap days (if that is possible).

The passed DateTime<FixedOffset> instance is taken apart to a Date<FixedOffset> instance and a NaiveTime instance. Then FixedOffset.ymd and .and_time create a new DateTime<FixedOffset> instance using the passed year.
Rust Playground
fn datetime_with_year(datetime: &DateTime<FixedOffset>, year: i32) -> DateTime<FixedOffset> {
let date: Date<FixedOffset> = datetime.date();
let time: NaiveTime = datetime.time();
let fixedoffset: &FixedOffset = datetime.offset();
match fixedoffset.ymd(year, date.month(), date.day()).and_time(time) {
Some(datetime_) => {
eprintln!("fixedoffset.ymd() Some {:?}", datetime_);
datetime_
}
None => {
eprintln!("fixedoffset.ymd() None");
datetime.clone()
}
}
}
Update: or use datetime.with_year(year) as recommended by #Jmb.
Doh! 😑

Related

How to please the borrow checker when implementing a 'too large to fit in memory' datastructure?

I am implementing a simple B-tree in Rust (as hobby project).
The basic implementation works well.
As long as everything fits in memory, nodes can store direct references to their children and it is easy to traverse and use them.
However, to be able to store more data inside than fits in RAM, it should be possible to store tree nodes on disk and retrieve parts of the tree only when they are needed.
But now it becomes incredibly hard to return a reference to a part of the tree.
For instance, when implementing Node::lookup_value:
extern crate arrayvec;
use arrayvec::ArrayVec;
use std::collections::HashMap;
type NodeId = usize;
#[derive(Debug, Clone, PartialEq, Eq, Hash)]
pub enum NodeContents<Value> {
Leaf(ArrayVec<Value, 15>),
Internal(ArrayVec<NodeId, 16>)
}
#[derive(Debug, Clone, PartialEq, Eq, Hash)]
pub struct Node<Key, Value> {
pub keys: ArrayVec<Key, 15>,
pub contents: NodeContents<Value>,
}
pub trait Pool<T> {
type PoolId;
/// Invariants:
/// - Ony call `lookup` with a key which you *know* exists. This should always be possible, as stuff is never 'simply' removed.
/// - Do not remove or alter the things backing the pool in the meantime (Adding more is obviously allowed!).
fn lookup(&self, key: &Self::PoolId) -> T;
}
#[derive(PartialEq, Eq, PartialOrd, Ord, Clone, Debug)]
pub struct EphemeralPoolId(usize);
// An example of a pool that keeps all nodes in memory
// Similar (more complicated) implementations can be made for pools storing nodes on disk, remotely, etc.
pub struct EphemeralPool<T> {
next_id: usize,
contents: HashMap<usize, T>,
}
impl<T: Clone> Pool<T> for EphemeralPool<T> {
type PoolId = EphemeralPoolId;
fn lookup(&self, key: &Self::PoolId) -> T {
let val = self.contents.get(&key.0).expect("Tried to look up a value in the pool which does not exist. This breaks the invariant that you should only use it with a key which you received earlier from writing to it.").clone();
val
}
}
impl<Key: Ord, Value> Node<Key, Value> {
pub fn lookup_value<'pool>(&self, key: &Key, pool: &'pool impl Pool<Node<Key, Value>, PoolId=NodeId>) -> Option<&Value> {
match &self.contents {
NodeContents::Leaf(values) => { // Simple base case. No problems here.
self.keys.binary_search(key).map(|index| &values[index]).ok()
},
NodeContents::Internal(children) => {
let index = self.keys.binary_search(key).map(|index| index + 1).unwrap_or_else(|index| index);
let child_id = &children[index];
// Here the borrow checker gets mad:
let child = pool.lookup(child_id); // NodePool::lookup(&self, NodeId) -> Node<K, V>
child.lookup_value(key, pool)
}
}
}
}
Rust Playground
The borrow checker gets mad.
I understand why, but not why to solve it.
It gets mad, because NodePool::lookup returns a node by value. (And it has to do so, because it reads it from disk. In the future there may be a cache in the middle, but elements from this cache might be removed at any time, so returning references to elements in this cache is also not possible.)
However, lookup_value returns a reference to a tiny part of this value. But the value stops being around once the function returns.
In the Borrow Checker's parlance:
child.lookup_value(key, pool)
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ returns a reference to data owned by the current function
How to solve this problem?
The simplest solution would be to change the function in general to always return by-value (Option<V>). However, these values are often large and I would like to refrain from needless copies. It is quite likely that lookup_value is called in quick succession with closely related keys. (And also, there is a more complex scenario which the borrow checker similarly complains about, where we look up a range of sequential values with an interator. The same situation applies there.)
Are there ways in which I can make sure that child lives long enough?
I have tried to pass in an extra &mut HashMap<NodeId, Arc<Node<K, V>>> argument to store all children needed in the current traversal to keep their references alive for long enough. (See this variant of the code on the Rust Playground here)
However, then you end up with a recursive function that takes (and modifies) a hashmap as well as an element in the hashmap. Rust (rightfully) blocks this from working: It's (a) not possible to convince Rust that you won't overwrite earlier values in the hashmap, and (b) it might need to be reallocated when it grows which would also invalidate the references.
So that does not work.
Are there other solutions? (Even ones possibly involving unsafe?)
Minimal Reproducible Example
Your example contained a lot of errors and undefined types. Please provide a proper minimal reproducible example next time to avoid frustration and increase the chance of getting a quality answer.
EDIT: I saw your modified question too late with the proper minimal example, I hope this one fits. If not, I'll take another look. Let me know.
Either way, I attempted to reverse-engineer what your minimal example could have been:
use std::marker::PhantomData;
type NodeId = usize;
#[derive(Debug, Clone, PartialEq, Eq, Hash)]
pub enum NodeContents<Value> {
Leaf(Vec<Value>),
Internal(Vec<NodeId>),
}
#[derive(Debug, Clone, PartialEq, Eq, Hash)]
pub struct Node<Key, Value> {
pub keys: Vec<Key>,
pub contents: NodeContents<Value>,
}
struct NodePool<Key, Value> {
_p: PhantomData<(Key, Value)>,
}
impl<Key, Value> NodePool<Key, Value> {
fn lookup(&self, _child_id: NodeId) -> Node<Key, Value> {
todo!()
}
}
impl<Key, Value> Node<Key, Value>
where
Key: Ord,
{
pub fn lookup_value(&self, key: &Key, pool: &NodePool<Key, Value>) -> Option<&Value> {
match &self.contents {
NodeContents::Leaf(values) => {
// Simple base case. No problems here.
self.keys
.binary_search(key)
.map(|index| &values[index])
.ok()
}
NodeContents::Internal(children) => {
let index = self
.keys
.binary_search(key)
.map(|index| index + 1)
.unwrap_or_else(|index| index);
let child_id = &children[index];
// Here the borrow checker gets mad:
let child = pool.lookup(*child_id); // NodePool::lookup(&self, NodeId) -> Node<K, V>
child.lookup_value(key, pool)
}
}
}
}
error[E0515]: cannot return reference to local variable `child`
--> src/lib.rs:50:17
|
50 | child.lookup_value(key, pool)
| ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ returns a reference to data owned by the current function
Thoughts and Potential Solutions
The main question you have to ask yourself: Who owns the data once it's loaded from disk?
This is not a simple question with a simple answer. It opens many new questions:
If you query the same key twice, should it load from disk twice? Or should it be cached and some other previously cached value should be moved to disk?
If it should be loaded from disk twice, should the entire Node that lookup returned be kept alive until the borrow is returned, or should only the Value be moved out and kept alive?
If your answer is "it should be loaded twice" and "only the Value should be kept alive", you could use an enum that can carry either a borrowed or owned Value:
enum ValueHolder<'a, Value> {
Owned(Value),
Borrowed(&'a Value),
}
impl<'a, Value> std::ops::Deref for ValueHolder<'a, Value> {
type Target = Value;
fn deref(&self) -> &Self::Target {
match self {
ValueHolder::Owned(val) => val,
ValueHolder::Borrowed(val) => val,
}
}
}
In your code, it could look like this:
use std::marker::PhantomData;
type NodeId = usize;
#[derive(Debug, Clone, PartialEq, Eq, Hash)]
pub enum NodeContents<Value> {
Leaf(Vec<Value>),
Internal(Vec<NodeId>),
}
#[derive(Debug, Clone, PartialEq, Eq, Hash)]
pub struct Node<Key, Value> {
pub keys: Vec<Key>,
pub contents: NodeContents<Value>,
}
pub struct NodePool<Key, Value> {
_p: PhantomData<(Key, Value)>,
}
impl<Key, Value> NodePool<Key, Value> {
fn lookup(&self, _child_id: NodeId) -> Node<Key, Value> {
todo!()
}
}
pub enum ValueHolder<'a, Value> {
Owned(Value),
Borrowed(&'a Value),
}
impl<'a, Value> std::ops::Deref for ValueHolder<'a, Value> {
type Target = Value;
fn deref(&self) -> &Self::Target {
match self {
ValueHolder::Owned(val) => val,
ValueHolder::Borrowed(val) => val,
}
}
}
impl<Key, Value> Node<Key, Value>
where
Key: Ord,
{
pub fn lookup_value(
&self,
key: &Key,
pool: &NodePool<Key, Value>,
) -> Option<ValueHolder<Value>> {
match &self.contents {
NodeContents::Leaf(values) => {
// Simple base case. No problems here.
self.keys
.binary_search(key)
.map(|index| ValueHolder::Borrowed(&values[index]))
.ok()
}
NodeContents::Internal(children) => {
let index = self
.keys
.binary_search(key)
.map(|index| index + 1)
.unwrap_or_else(|index| index);
let child_id = &children[index];
// Here the borrow checker gets mad:
let child = pool.lookup(*child_id); // NodePool::lookup(&self, NodeId) -> Node<K, V>
child
.into_lookup_value(key, pool)
.map(|val| ValueHolder::Owned(val))
}
}
}
pub fn into_lookup_value(self, key: &Key, pool: &NodePool<Key, Value>) -> Option<Value> {
match self.contents {
NodeContents::Leaf(mut values) => {
// Simple base case. No problems here.
self.keys
.binary_search(key)
.map(|index| values.swap_remove(index))
.ok()
}
NodeContents::Internal(children) => {
let index = self
.keys
.binary_search(key)
.map(|index| index + 1)
.unwrap_or_else(|index| index);
let child_id = &children[index];
// Here the borrow checker gets mad:
let child = pool.lookup(*child_id); // NodePool::lookup(&self, NodeId) -> Node<K, V>
child.into_lookup_value(key, pool)
}
}
}
}
In all other cases, however, it seems like further thought needs to be put into restructuring the project.
After a lot of searching and trying, and looking at what other databases are doing (great suggestion, #Finomnis!) the solution presented itself.
Use an Arena
The intuition to use a HashMap was a good one, but you have the problems with lifetimes, for two reasons:
A HashMap might be reallocated when growing, which would invalidate old references.
You cannot convince the compiler that new insertions into the Hashmap will not overwrite existing values.
However, there is an alternative datastructure which is able to provide these guarantees: Arena allocators.
With these, you essentially 'tie' the lifetimes of the values you insert into them, to the lifetime of the allocator as a whole.
Internally (at least conceptually), an arena keeps track of a list of memory regions in which data might be stored, the most recent one of which is not entirely full. Individual memory regions are never reallocated to ensure that old references remain valid; instead, when the current memory region is full, a new (larger) one is allocated and added to the list, becoming the new 'current'.
Everything is destroyed at once at the point the arena itself is deallocated.
There are two prevalent Rust libraries that provide arenas. They are very similar, with slightly different trade-offs:
typed-arena allows only a single type T per arena, but runs all Drop implementations when the arena is dropped.
bumpalo allows different objects to be stored in the same arena, but their Drop implementations do not run.
In the common situation of having only a single datatype with no special drop implementation, you might want to benchmark which one is faster in your use-case.
In the original question, we are dealing with a cache, and it makes sense to reduce copying of large datastructures by passing around Arcs between the cache and the arena. This means that you can only use typed-arena in this case, as Arc has a special Drop implementation.

How do I modify a Vector based on information from an item in the Vector?

How can I modify a Vec based on information from an item within the Vec without having both immutable and mutable references to the vector?
I've tried to create a minimal example that demonstrates my specific problem. In my real code, the Builder struct is already the intermediate struct that other answers propose. Specifically, I do not think this question is answered by other questions because:
Why does refactoring by extracting a method trigger a borrow checker error? - What would I put in the intermediate struct? I'm not calculating a separate value from Vec<Item>. The value being modified/operated on is Vec<Item> and is what would need to be in the intermediate struct
Suppose I have a list of item definitions, where items are either a String, a nested list of Items, or indicate that a new item should be added to the list of items being processed:
enum Item {
Direct(String),
Nested(Vec<Item>),
New(String),
}
There is also a builder that holds a Vec<Item> list, and builds an item at the specified index:
struct Builder {
items: Vec<Item>,
}
impl Builder {
pub fn build_item(&mut self, item: &Item, output: &mut String) {
match item {
Item::Direct(v) => output.push_str(v),
Item::Nested(v) => {
for sub_item in v.iter() {
self.build_item(sub_item, output);
}
}
Item::New(v) => self.items.push(Item::Direct(v.clone())),
}
}
pub fn build(&mut self, idx: usize, output: &mut String) {
let item = self.items.get(idx).unwrap();
self.build_item(item, output);
}
}
This doesn't compile due to the error:
error[E0502]: cannot borrow `*self` as mutable because it is also borrowed as immutable
--> src/main.rs:26:9
|
25 | let item = self.items.get(idx).unwrap();
| ---------- immutable borrow occurs here
26 | self.build_item(item, output);
| ^^^^^----------^^^^^^^^^^^^^^
| | |
| | immutable borrow later used by call
| mutable borrow occurs here
error: aborting due to previous error
For more information about this error, try `rustc --explain E0502`.
I don't know how to have the Builder struct be able to modify its items (i.e. have a mutable reference to self.items) based on information contained in one of the items (i.e. an immutable borrow of self.items).
Here is a playground example of the code.
Using Clone
#Stargateur recommended that I try cloning the item in build(). While this does work, I've been trying to not clone items for performance reasons. UPDATE: Without adding the Vec<Item> modification feature with Item::New, I implemented the clone() method in my real code and cloned the value in the equivalent of the example build() method above. I saw a 12x decrease in performance when I do self.items.get(idx).unwrap().clone() vs self.items.get(idx).unwrap(). I will continue looking for other solutions. The problem is, I'm still relatively new to Rust and am not sure how to bend the rules/do other things even with unsafe code.
Code that does work (playground)
impl Clone for Item {
fn clone(&self) -> Self {
match self {
Item::Direct(v) => Item::Direct(v.clone()),
Item::Nested(v) => Item::Nested(v.clone()),
Item::New(v) => Item::New(v.clone()),
}
}
}
and change build to clone the item first:
let item = self.items.get(idx).unwrap().clone();
Whenever approaching problems like this (which you will encounter relatively frequently while using Rust), the main goal should be to isolate the code requiring the immutable borrow from the code requiring the mutable borrow. If the borrow from the items vec in build is unavoidable (i.e. you cannot move the item out of self.items or copy/clone it) and you must pass in a reference to this item to build_item, you might want to consider rewriting your build_item function to not mutate self. In this case, build_item only ever appends new items to the end of self.items, which lets us make an interesting refactor: Rather than have build_item modify items, make it return the items to be added to the original vector, and then have the caller add the newly generated items to the items vector.
impl Builder {
fn generate_items(&self, item: &Item, output: &mut String) -> Vec<Item> {
match item {
Item::Direct(v) => {
output.push_str(v);
Vec::new()
}
Item::Nested(v) => {
v.iter()
.flat_map(|sub_item| self.generate_items(sub_item, output))
.collect()
}
Item::New(v) => vec![Item::Direct(v.clone())],
}
}
pub fn build_item(&mut self, item: &Item, output: &mut String) {
let mut new_items = self.generate_items(item, output);
self.items.append(&mut new_items);
}
pub fn build(&mut self, idx: usize, output: &mut String) {
// Non lexical lifetimes allow this to compile, as the compiler
// realizes that `item` borrow can be dropped before the mutable borrow
// Immutable borrow of self starts here
let item = self.items.get(idx).unwrap();
let mut new_items = self.generate_items(item, output);
// Immutable borrow of self ends here
// Mutable borrow of self starts here
self.items.append(&mut new_items);
}
}
Note that in order to preserve the API, your build_item function has been renamed to generate_items, and a new build_item function that uses generate_items has been created.
If you look carefully, you'll notice that generate_items doesn't even require self, and can be a free-standing function or a static function in Builder.
Playground

How to get Timestamp of the current Date and time in Rust

I simply want to retrieve the current Time and Date and store it in a variable.
For this, I tried to use the chrono::DateTime.
In the documentation I found this:
use chrono::{DateTime, TimeZone, NaiveDateTime, Utc};
let dt = DateTime::<Utc>::from_utc(NaiveDate::from_ymd(2016, 7, 8).and_hms(9, 10, 11), Utc);
This lets me store a specific Date and Time but I couldn't figure out how to retrieve the actual current date and time and put it in my DateTime-Variable.
Use rust, use it now:
use chrono;
fn main() {
println!("{:?}", chrono::offset::Local::now());
println!("{:?}", chrono::offset::Utc::now());
}
To answer the question in the title of how to get the current timestamp:
use chrono::Utc;
let dt = Utc::now();
let timestamp: i64 = dt.timestamp();
println!("Current timestamp is {}", timestamp);
Standart Rust timestamp method:
use std::time::SystemTime;
let now = SystemTime::now()
.duration_since(SystemTime::UNIX_EPOCH)
.unwrap()
.as_millis(); // See struct std::time::Duration methods
println!("{}", now);

How to convert DateTime::now() into NaiveDateTime?

I'm using Diesel and chrono. In my model I have a field of type NaiveDateTime which contains the now(). However, NaiveDateTime doesn't have the function now() or a similar one whereas DateTime does:
Utc::now()
How can I convert Utc::now() into NaiveDateTime?
Utc::now() returns a DateTime<Utc>. You could click into the documentation of DateTime<T> and search for NaiveDateTime. You should find that there are two methods that will return a NaiveDateTime:
fn naive_utc(&self) -> NaiveDateTime
  Returns a view to the naive UTC datetime.
fn naive_local(&self) -> NaiveDateTime
  Returns a view to the naive local datetime.
For instance, if you need the timestamp in UTC:
let naive_date_time = Utc::now().naive_utc();
Note that since you are using diesel, you could use diesel::dsl::now instead, which will evaluate to CURRENT_TIMESTAMP on the SQL side.
//! ```cargo
//! [dependencies]
//! diesel = { version = "1", features = ["sqlite"] }
//! ```
#[macro_use]
extern crate diesel;
use diesel::prelude::*;
use diesel::dsl;
table! {
posts (id) {
id -> Integer,
content -> Text,
published -> Timestamp,
}
}
fn main() {
let conn = SqliteConnection::establish("test.db")
.expect("Cannot open database");
diesel::insert_into(posts::table)
.values((
posts::content.eq("hello"),
posts::published.eq(dsl::now), // <------------------
))
.execute(&conn)
.expect("Insertion failed");
}

How to execute a Command in Task

Is it possible to execute a Command in Sbt Task? If so, how? as Command requires a State, how could I obtain one?
I am trying to override a default task, here's what I've tried
dist := {
println("Turning coverage off")
Command.process("coverageOff")
dist.value
}
The signature of Command.process is (string, state) => _
I havent figure out where to get the State
Yes, you can run a command within a task. Here is what I'm currently doing to achieve it. First, define the following method in your build:
/**
* Convert the given command string to a release step action, preserving and invoking remaining commands
* Note: This was copied from https://github.com/sbt/sbt-release/blob/663cfd426361484228a21a1244b2e6b0f7656bdf/src/main/scala/ReleasePlugin.scala#L99-L115
*/
def runCommandAndRemaining(command: String): State => State = { st: State =>
import sbt.complete.Parser
#annotation.tailrec
def runCommand(command: String, state: State): State = {
val nextState = Parser.parse(command, state.combinedParser) match {
case Right(cmd) => cmd()
case Left(msg) => throw sys.error(s"Invalid programmatic input:\n$msg")
}
nextState.remainingCommands.toList match {
case Nil => nextState
case head :: tail => runCommand(head.commandLine, nextState.copy(remainingCommands = tail))
}
}
runCommand(command, st.copy(remainingCommands = Nil)).copy(remainingCommands = st.remainingCommands)
}
Then, just call any command from within a task using the above defined utility, e.g., runCommandAndRemaining("+myProject/publishLocal")(state.value).
In your specific case, it should boil down to
dist := {
val log = streams.value.log
log.debug("Turning coverage off")
runCommandAndRemaining("coverageOff")(state.value)
dist.value
}
Hope this helps!
State can be obtained by evaluating state.value
To access the current State from a task, use the state task as an
input. For example,
myTask := ... state.value ...
and commands can be called within task using Command.process like so
dist := {
println("Turning coverage off")
Command.process("coverageOff", state.value)
dist.value
}
After getting some help from gitter, it's not possible, one can however do the reverse, call a task in a command.
So if your use case is to run a command and a task sequentially (or vice versa), you can do something like this
lazy val newCommand = Command.command("name") { state =>
val newState = Command.process("comandName", state)
// run task
newState
}

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