Extract salary from a vector Rstudio - vector

I would like to know if somebody can help me extract only the salary rate from a vector or the characters after the symbol $; thank you for your time.
Example:
jobdescription <- "Receptionist - ClinicIntermountain Healthcare1,241 reviews, ID$16.00 - $20.80 an hour - Full-timeIntermountain"

Related

My data does not convert to time series in R

My data contains several measurements in one day. It is stored in CSV-file and looks like this:
enter image description here
The V1 column is factor type, so I'm adding a extra column which is date-time -type: vd$Vdate <- as_datetime(vd$V1) :
enter image description here
Then I'm trying to convert the vd-data into time series: vd.ts<- ts(vd, frequency = 365)
But then the dates are gone:
enter image description here
I just cannot get it what I am doing wrong! Could someone help me, please.
Your dates are gone because you need to build the ts dataframe from your variables (V1, ... V7) disregarding the date field and your ts command will order R to structure the dates.
Also, I noticed that you have what is seems like hourly data, so you need to provide the frequency that is appropriate to your time not 365. Considering what you posted your frequency seems to be a bit odd. I recommend finding a way to establish the frequency correctly. For example, if I have hourly data for 365 days of the year then I have a frequency of 365.25*24 (0.25 for the leap years).
So the following is just as an example, it still won't work properly with what I see (it is limited view of your dataset so I am not sure 100%)
# Build ts data (univariate)
vs.ts <- ts(vd$V1, frequency = 365, start = c(2019, 4)
# check to see if it is structured correctly
print(vd.ts, calendar = T)
Finally my time series is working properly. I used
ts <- zoo(measurements, date_times)
and I found out that the date_times was supposed to be converted with as_datetime() as otherwise they were character type. The measurements are converted into data.frame type.

Convert date in vector to Excel date number (R)

I have a vector of date values:
dates=c("43018","43343","42272","06/27/17","01/10/18","10/11/18")
This is a mixture of actual dates and the Excel number-value of dates (ie: number of days since January 1, 1900). I want to convert all of these values to the Excel format of dates, so we would have an output that looks like the following:
dates
[1] "43018" "43343" "42272" "42913" "43110" "43384"
My goal is to take these values and subtract them from another vector with an equal number of date values that are all the same to get an age of each observation.
Can anyone help point me in the right direction? Thank you!
Figured it out - use the "janitor" library and the excel_numeric_to_date function.
Badda bing badda boom.

Changing a string of factors to time

I am trying to take a column of my data that is in factor format and change it to time in the format
hours:minutes:seconds:milliseconds
I tried:
start.times <- as.POSIXct(as.character(start.times), format="%H:%M:%OS")
but it returned values with todays date and left out the milliseconds in them and that is not what I want.
I also tried downloading chron and running the code:
start.times <- times(start.times)
but this just returned NA's.....
Please help!
My data is all about start times and end times of dolphin vocalizations and I am trying to find the mean whistle duration and the inter whistle interval. Anyways, I don't really know how to get my data into the format I need it in. Thank you!
Assuming you have a factor that looks like:
start.time <- c("0:13:45.9", "3:09:44.9")
Then what you wrote should work if you change the last colon to a period
as.POSIXct(start.time, format ="%H:%M:%S.%OS")

Different age calculation for different rows

I'm an absolute R beginner here working on a Master's project.
I have a data.frame that contains information on trotting horses (their wins, earnings, time records and such). The data is organised in a way that every row contains information for a specific year the horse competed and including a first row for each horse of "Total", so there's a summary for every variable for it's total competing life. It looks like this:
I created a new variable with their age using the age_calc function in the eeptools package:
travdata$Age<-age_calc(as.Date(travdata$Birth.date), enddate=as.Date("2016-12-31"),
units="years")
With no problems. What I'm trying to figure out is if there is any way I can calculate the age of the horses for each specific year I have info on them-that is, the "Total" row would have their age up until 2016-12-31, for the year 2015 it would have their age at that time and so on. I've been trying to include if statements in age_calc but it won't work and I'm really at a loss on how best to do this.
Any literature or help you could point me to would be much, much appreciated.
MWE
travdata <- data.frame(
"Id.Number"=c(rep("1938-98",3),rep("1803-97",7),rep("1221-03",4)),
"Name"=c(rep("Muuttuva",3),rep("Pelson Poika",7),rep("Muusan Muisto",4)),
"Sex"=c(rep("Mare",3),rep("Gelding",7),rep("Gelding",4)),
"Birth.year"=c(rep(1998,3),rep(1997,7),rep(2003,4)),
"Birth.date"=c(rep("1998-07-01",3),rep("1997-07-14",7),rep("2003-05-07",4)),
"Competition.year" = c("Total",2005,2004,"Total",2003,2004,2006,2005,2002,2001,2008,2010,"Total",2009),
"starts"=c(20,11,9,44,21,6,7,5,3,2,1,1,4,2),
"X1st.placements"=c(0,0,0,3,3,0,0,0,0,0,0,0,0,0),
"X2nd.placements"=c(2,2,0,1,0,1,0,0,0,0,0,0,0,0),
"X3rd.placements"=c(2,2,0,1,1,0,0,0,0,0,0,0,0,0),
"Earnings.euro"=c(1525,1425,100,2078,1498,580,0,0,0,0,0,0,10,10)
)
The trick is to filter out the "Total" rows and specify a format for the as.Date() function
library(eeptools)
travdata <- data.frame(
"Id.Number"=c(rep("1938-98",3),rep("1803-97",7),rep("1221-03",4)),
"Name"=c(rep("Muuttuva",3),rep("Pelson Poika",7),rep("Muusan Muisto",4)),
"Sex"=c(rep("Mare",3),rep("Gelding",7),rep("Gelding",4)),
"Birth.year"=c(rep(1998,3),rep(1997,7),rep(2003,4)),
"Birth.date"=c(rep("1998-07-01",3),rep("1997-07-14",7),rep("2003-05-07",4)),
"Competition.year" = c("Total",2005,2004,"Total",2003,2004,2006,2005,2002,2001,2008,2010,"Total",2009),
"starts"=c(20,11,9,44,21,6,7,5,3,2,1,1,4,2),
"X1st.placements"=c(0,0,0,3,3,0,0,0,0,0,0,0,0,0),
"X2nd.placements"=c(2,2,0,1,0,1,0,0,0,0,0,0,0,0),
"X3rd.placements"=c(2,2,0,1,1,0,0,0,0,0,0,0,0,0),
"Earnings.euro"=c(1525,1425,100,2078,1498,580,0,0,0,0,0,0,10,10)
)
travdata$Age<-age_calc(as.Date(travdata$Birth.date),
enddate=as.Date("2016-12-31"), units="years")
competitions <- travdata[travdata$Competition.year!="Total",]
competitions$Competition.age<-age_calc(
as.Date(competitions$Birth.date),
enddate=as.Date(competitions$Competition.year, format="%Y"),
units="years",F)

calculate date differences in R

I am trying to calculate the day differences between the two columns of Last.Start and Last.Stop. What I did is first convert the column of Last.Start to Character variable, then convert it to a Date type variable (as the last column of LastStart).
enter image description here
SMFull$Last.Start <- as.character(SMFull$Last.Start)
SMFull$LastStart <- as.Date(SMFull$Last.Start, format="%Y/%m/%d")
Can someone advise me Why the format of LastStart was off?
Thanks in advance!

Resources