Do you know any Keyword or any Logic in Robot Framework to get the last day of the Each month.
Actually, I am working on a Calendar and in that Whenever it will be last day of the month I need to click on Next Button.
Thanks in Advance!
Python's calendar library can provide this information.
In your Robot test script you can call
calendar.monthrange(year, date)
which will return a list of two numbers, the 0th element is the weekday of the first day of the month, and the 1st element is the days in the month.
In example
${year}= Set Variable 2022
${month}= Set Variable 2
${tupleContainingEndDate}= Evaluate calendar.monthrange(${year}, ${month})
${numberOfDays}= Set Variable ${tupleContainingEndDate}[1]
Log ${numberOfDays}
${numberOfDays} is:
28
Related
im using spotfire software and i have a datetime column like:
DateTime
21/07/2022 12:11:01
21/07/2022 14:32:01
04/12/2022 10:22:01
30/06/2022 16:22:01
how can i created a new calculated column where it instead changes the date to the monday of the week for all values?
many thanks
i can do this in power bi by dropping the time and using the function
Start of Week Monday = 'Data'[DateTime ]+1-WEEKDAY('Data'[DateTime ]-1)
this results in all the values changing to the monday of its given week/month/year
how can i do this in spotfire?
Assuming you have the following functions available to you: DateAdd, DayOfWeek (*)
You could try:
DateAdd("dd",1 - (If(DayOfWeek([original_Date])=0,7,DayOfWeek([original_Date]))),[original_Date])
This resets the date (including the time portion) to the previous Monday.
Initially I had tried the simpler formula:
DateAdd("dd",1 - DayOfWeek([original_Date]),[original_Date])
but Sunday is mapped to a zero, so whenever the original day was a Sunday, it was pushed to the following Monday.
It does depend on your original settings so you may have to play around with the numbers a bit.
(*) depending on what the source of your data is, equivalent functions may be available.
I have a dataset that includes dates and count of reports. I am tasked with generating matched-pairs using these guidelines:
Reports will need to be matched to the week immediately prior to or following. (For example: Jan 23, 2000 will be matched with Jan 16, 2000 and Jan 30, 2000)
Holidays must not be included in the final matched-pairs generation.
I have been able to identify the holidays within the dataset but am still stuck on how to generate the matched pairs. Any advice would be much appreciated!
Example of the Data
I am making assumptions as I could not ask for clarifications.
Assumptions I made
a> You wanted to get a formula bash
b> You wanted the date closest matching the previous week to the specific date. for example a Monday event needed to match closer to an event on Monday the previous week. As the data set you gave showed multiple reports through the week. It was not clear what pattern of the previous week you wanted to match.
Solution based on Assumptions.
1> You can mathematically turn each date to a grouping of which week they were in for the year. Then match them to one another. For example 1/1/2003 would be 1.1. A date in 14/1/2003 would be 2.1.
You can then patten match on if 1.1 = 2.1 if that hits it's a match if not it would loop until it saw an entry in the range of 2.[0-9]. You can place an if statment to check if there is a holiday on the match, if there is one it will continue the loop.
I have a line chart that has 3 series - the first shows cumulative sales for last week - the next shows the daily sales for this week and the next shows cumulative sales for this week.
This shows the days of the week at the bottom.
Last weeks cumulative sales show fine as there is data for each day of the week.
For this week's daily and cumulative sales I don't want a point drawn if the day hasn't happened yet.
I loop through the days of the week and if the day hasn't happened yet I want to assign the value to null instead of 0 and I don't want the line to show anything for these series if the day hasn't happened yet.
Does anyone have advice on this point?
After much looking I found how to do this. It was very easy and described in the below documentation from shieldui.com:
Example using null in dataSeries
I had earlier tried all manner of sending empty strings, null value strings and in the end it was as simple as setting that data member to null like this and shieldui handled it correctly:
dailyincome = null;
In MySQL I am using
week(date,3)
to get correct values of week grouping.
How to translate this to PL/SQL? I'v tried the following but what about this 3 from week function in mysql?
TRUNC (created_dt, 'IW')
Oracle is using the NLS setting of the database to determinate how the week number should be calculated and therefor there is no need (according to Oracle) for the '3' part pf the MySQL function. I can image that there still should be useful to have this option but this is once again a sign of the fact that Oracle does not fully understand the needs of working outside USA.
Based on your MYSQL statment above, it returns the week of the specified date e.g. 2012-12-07, 3 as the second argument defines that the third day of the week is assumed as Monday...
If you look at this article it says there are 8 ways MYSQL WEEK() function can behave. So you gotta let us know what results you are trying to achieve by looking for MYSQL Week equivalent function in PL/SQL.
In most staright forward manner, MYSQL WEEK(date[mode]) returns the week number for a given date.
From re-reading your question, the only thing I grabbed that you want to achieve the first feature within PL/SQL and so you are looking for an equivalent function.
And with Oracle it gets slightly RAMEN...
W Week of month (1-5) where week 1 starts on the first day of the month and ends on the seventh. It goes on with how the year starts. E.g. 2012 started on a Sunday, ORACLE THINKS.............. that weeks are Sundays to Saturday.
iw Week of year (1-52, 1-53) based on the ISO standard. Hence the weeks do not necessarily start on Sunday.
WW Week of the year (1-53) where week 1 starts on the first day of the year and continues to the seventh day of the year.
By default Oracle NLS settings are set to following:
NLS_CALENDAR : Gregorian
NLS_DATE_LANGUAGE: AMERICAN
NLS_TERRITORY: AMERICA
So you can suggest Oracle to follow the calendar by manipulating your query level....
You could something like this:
select trunc('2012-12-07','YY') AS week_number,
to_number(to_char(trunc('2012-12-07','YY')+rownum-1,'D')) AS dayNumber_in_week
from dual connect by level <= 365
where to_char('2012-12-07','IW') = 3
and to_char('2012-12-07','DY') = 'MON';
Essentially, I have a query that is responsible for fetching all records (with specific filters) within the last month. I'm using Oracle's interval keyword and all was working great until today (December 31st, 2009). The code I'm using is
select (sysdate - interval '1' month) from dual
and the error I get it
ORA-01839: date not valid for month specified
How can I use the interval keyword to be compatible with any date? Or if anyone has a better way of approaching the issue, I'm all ears.
Thank you.
try
select add_months(sysdate,-1) from dual
Being pedantic...
The requirements are not quite specified perfectly unambiguously. What does the business mean by "within the last month"? Most people would take that to mean "within the current calendar month" in which case I'd use:
TRUNC(SYSDATE,'MM')
Otherwise, perhaps they want an arbitrary period of 1 month prior to the current date - but then how do you define that? As you've found, INTERVAL '1' MONTH simply subtracts one from the month portion of the date - e.g. 15-JAN-2009 - INTERVAL '1' MONTH returns 15-DEC-1999. For some dates, this results in an invalid date because not all months have the same number of days.
ADD_MONTHS resolves this by returning the last day in the month, e.g. ADD_MONTHS(31-DEC-2009,-1) returns 30-NOV-2009.
Another possibility is that the business actually wants to use an average month period - e.g. 365/12 which is approximately 30.4. They might want you to use SYSDATE-30, although of course twelve iterations of this will only cover 360 days of the year.