jq element matching with in a nested array - jq

Question

I have an array of array as following
[
{
"devices": [
{
"files": [
{
"id": "2",
"type": "file"
}
],
"path": "/tmp/file1"
},
{
"files": [
{
"id": "3",
"type": "file"
}
],
"path": "/tmp/file2"
}
],
"name": "a"
},
{
"devices": [
{
"files": [
{
"id": "4",
"type": "file"
}
],
"path": "/tmp/tfile"
},
{
"files": [
{
"id": "5",
"type": "file"
}
],
"path": "/var/mfile"
}
],
"name": "b"
}
]
I'm looking for output like this
a /tmp/file1 2
a /tmp/file2 3
b /tmp/tfile 4
b /var/mfile 5
What I have tried
cat myfile.json | jq '.[] | "\(.name), \(.devices[].path) \(.devices[].files[].id)"'
and result is
"a, /tmp/file1 2"
"a, /tmp/file2 2"
"a, /tmp/file1 3"
"a, /tmp/file2 3"
"b, /tmp/tfile 4"
"b, /var/mfile 4"
"b, /tmp/tfile 5"
"b, /var/mfile 5"
but I'm unable to select a key for the value is in parent map.
I want to for each of the elements matching name == a, for each of a[path], get a[path][id].

Answer 1

Using .devices[] twice will iterate over the same .devices twice, giving you the cartesian product. Extract from within one iteration.
You can nest string iterpolation; otherwise collect into an array (here you'd need , as separator) and use join(" ") to concatenate
Use the -r (or --raw-output) flag to output raw text
jq -r '.[] | "\(.name) \(.devices[] | "\(.path) \(.files[].id)")"'
a /tmp/file1 2
a /tmp/file2 3
b /tmp/tfile 4
b /var/mfile 5
Demo