Placing a gradient background on an image with transparent background - css

What I would like to achieve is basically have a gradient appear on the text as opposed to the background of an image. I have created an example here:
https://codepen.io/BenSagiStuff/pen/BaYKbNj
body{
background: black;
}
img{
padding: 30px;
background: linear-gradient(to right, #E50000 8%, #FF8D00 28%, #FFEE00 49%, #008121 65%, #004CFF 81%, #760188 100%);
}
<img src="https://upload.wikimedia.org/wikipedia/commons/9/95/Transparent_google_logo_2015.png" >
As you can see, currently the background of the image has the gradient, but, what I would like is for the text "Google" to have the gradient and the background of the png should stay as black.
Ultimately the goal would be to have the gradient transition underneath the image as well, so the gradient slides horizontally under the image as well.

Use the image as a mask on a common element
body{
background: black;
}
.box{
--img:url(https://upload.wikimedia.org/wikipedia/commons/9/95/Transparent_google_logo_2015.png);
width:300px;
aspect-ratio:3;
background: linear-gradient(to right, #E50000 8%, #FF8D00 28%, #FFEE00 49%, #008121 65%, #004CFF 81%, #760188 100%);
-webkit-mask: var(--img) 50%/cover;
mask: var(--img) 50%/cover;
}
<div class="box"></div>

There's a little problem with your implementation.
PNG is transparent, but it's a square piece of image. You might be successful using a svg image or just applying this gradient background in a text tag.
on your HTML you make this way:
<div>
<h1>Google</h1>
</div>
Your CSS this way
body{
background: black;
font-family:helvetica;
}
h1{
background: linear-gradient(to right, #E50000 8%, #FF8D00 28%, #FFEE00 49%, #008121 65%, #004CFF 81%, #760188 100%);
font-size: 160px;
-webkit-background-clip: text;
-webkit-text-fill-color: transparent;
}
div {
display:flex;
}
It's also better for performance.
Also, you can animate easily.
Such as the example in this codepen https://codepen.io/shshaw/pen/YpERQQ
:)

Related

Display Sunset Effect with Gradients Above Background Image in Body

I'm trying to create a gradient based sunset effect on my website's background.
Example Link (with sunset effect, in the background) https://web.archive.org/web/20161017071941/https://www.embroideryaffair.com/about/
Try to scroll down on the example link & you will notice the "sunset" effect.
This is what I've achieved so far: https://sirsakisan101.provenreviews.com/
I was able to display the two palm images, side-by-side, by using the following code.
body {
background-image: url(https://sirsakisan101.provenreviews.com/wp-content/uploads/2019/01/left.png), url(https://sirsakisan101.provenreviews.com/wp-content/uploads/2019/01/right.png), url(https://sirsakisan101.provenreviews.com/wp-content/uploads/2019/01/sunsetbgbottom.png);
background-repeat: no-repeat, no-repeat, repeat-x;
background-attachment: fixed, fixed;
background-position: left top, right top, bottom;
}
Now, I'm trying to use the following code (mentioned below) for achieving the sunset effect on my background images, but it is not working. I've also tried removing the "before" element & adding the background images, along with gradients but then, it is appearing above the background images.
body:before {
background: linear-gradient(bottom, rgb(255,203,112) 0%, rgb(107,138,169) 30%, rgb(1,44,87) 100%);
background: -o-linear-gradient(bottom, rgb(255,203,112) 0%, rgb(107,138,169) 30%, rgb(1,44,87) 100%);
background: -moz-linear-gradient(bottom, rgb(255,203,112) 0%, rgb(107,138,169) 30%, rgb(1,44,87) 100%);
background: -webkit-linear-gradient(bottom, rgb(255,203,112) 0%, rgb(107,138,169) 30%, rgb(1,44,87) 100%);
background: -ms-linear-gradient(bottom, rgb(255,203,112) 0%, rgb(107,138,169) 30%, rgb(1,44,87) 100%);
filter: progid:DXImageTransform.Microsoft.gradient(startColorstr='#012c57', endColorstr='#ffcb70');
background: -webkit-gradient( linear, left bottom, left top, color-stop(0, rgb(255,203,112)), color-stop(0.3, rgb(107,138,169)), color-stop(1, rgb(205,217,230)) ) !important;
}
I want to display this code behind my background images, to achieve the sunset effect from the example website. I can't understand why it is not working. I will be grateful for any help.
Thank You.
You can do it with another html element inside the background image one.
<div> // has your background image
<div class="gradient"> // will have the gradiant style
</div>
</div>
css
.gradient {
background: linear-gradient( rgba(255,255,255,0.23) 0%, rgba(164,49,34, .85) 100%);
}
Here is an example fiddle
Note i just simplified the gradient css. Keep your own styling.
Consider the way you use the body tag like you currently do. You need to make sure the div inside (with the gradient) spans directly on top of the other div. Maybe you have to do something like
.parent {
// The element with the image
position: relative;
}
.child {
// the element with the gradient
position absolute;
left: 0;
right: 0;
top: 0;
bottom: 0;
}
You can directly add the gradient to the other background-images (since the gradient property is considered a background image) like this:
body {
background-image: url(https://sirsakisan101.provenreviews.com/wp-content/uploads/2019/01/left.png),
url(https://sirsakisan101.provenreviews.com/wp-content/uploads/2019/01/right.png),
url(https://sirsakisan101.provenreviews.com/wp-content/uploads/2019/01/sunsetbgbottom.png),
-webkit-linear-gradient(bottom, rgb(255,203,112) 0%, rgb(107,138,169) 30%, rgb(1,44,87) 100%);
}
That worked for me and it's much easier than adding additional elements ;)

CSS to apply gradient as mask to DIV

I am having a div which comes with the following color definition:
div{
background-color: #009688;
height: 100px;
}
<div></div>
Now I want to overlay a alpha gradient on this base color to get a similar effect like I would have with this definition:
div{
background: linear-gradient(-45deg, rgba(0,105,96,1) 0%, rgba(11,155,159,1) 50%, rgba(2,142,145,1) 51%, rgba(0,203,175,1) 100%);
height:100px;
}
<div></div>
The idea is that I do not want to calculate the linear-gradient behavior for every base color. Instead I want to use arbitrary base colors and add default masks to them. Is this possible with CSS3?
You can approximate it by using some white/black color over the background color. Simply adjust the alpha of each color to have the needed effect:
.b1 {
background-color: #009688
}
.b2 {
background-color: red
}
div{
background-image:
linear-gradient(-45deg, rgba(0,0,0,0.3) 0%, rgba(0,0,0,0.2) 50%, rgba(0,0,0,0.3) 51%, rgba(255,255,255,0.3) 100%);
height:100px;
}
<div class="b1"></div>
<div class="b2"></div>

CSS Linear Gradient with Triangle starting 46%

On a wordpress website, i would like to make a header with a gradient which covers the menu in 100% but then in the breadcrumbs i would like it to be white triangle shape.
I have create a fiddle as it is quite hard to explain.
https://jsfiddle.net/hoststage/o04qfpr9/
The body CSS and the CSS class triangle header is what i'm currently running to make it work but with negative margin which I really don't like.
body {
background-color: #F4F4F4;
background-image: -moz-linear-gradient( 97deg, rgb(145,79,145) 0%, rgb(168,100,168) 100%);
background-image: -webkit-linear-gradient( 97deg, rgb(145,79,145) 0%, rgb(168,100,168) 100%);
background-image: -ms-linear-gradient( 97deg, rgb(145,79,145) 0%, rgb(168,100,168) 100%);
position: absolute;
z-index: 270;
background-repeat: no-repeat !important;
background-size:1920px 270px;
background-position: center top;
}
.triangle-header {
width:1920px !important;
height:195px;
background: linear-gradient(to top left, white 50%, transparent 0%),
transparent 0%;
margin-top: -170px
}
SO basically, i would like to start the triangle at 46% of the body gradient and merge the 2 CSS codes into the body class.
The onecodebody is my current attempt at merging the 2 properties but it doesn't work as I suspect i can't pass the argument to the bottom left inside an already defined linear.
Is there a way to define one gradient property for the body tag which would make it look like what I have in my fiddle?
Great day to you all!
Use multiple gradient like this to have transparency:
body {
height:200px;
background:
linear-gradient(rgb(145,79,145),rgb(145,79,145)) top/100% 46% no-repeat,
linear-gradient(to bottom right,rgb(145,79,145) 50%,transparent 50.5%) bottom/100% 55% no-repeat;
}
Or like this if you want to keep both colors and have the white part above to create the triangle shape:
body {
height:200px;
background:
linear-gradient(to bottom right,transparent 50%,white 50.5%) bottom/100% 55% no-repeat,
linear-gradient(97deg, rgb(145,79,145) 0%, rgb(168,100,168) 100%) top/100% 100% no-repeat;
}

Setting linear gradient height AND width

I am aware that you can set the width of a linear gradient using
.grey-block { background: linear-gradient(to right, #f9f9f9 0%, #f9f9f9 35%, white 35%, white 100%); }
As well as the height
.grey-block { background: linear-gradient(to bottom, #f9f9f9 0%, #f9f9f9 65%, white 65%, white 100%); }
However, is there a way you can set BOTH the height and the width using a the same css line?
To clarify, the code in the question is not setting the height and width of the gradient. It's adjusting the color stops, which results in a grey rectangle.
In order to adjust the actual dimensions of the gradient, we need to use the background-size property (as well as background-repeat) to set the height and width of the gradient.
With background-size in control of the gradient's dimensions, we can rewrite the CSS to be as follows:
.grey-block {
background-color: white;
background-image: linear-gradient(#f9f9f9, #f9f9f9);
background-size: 35% 65%;
background-repeat: no-repeat;
}
What's happening is that we're defining a "gradient" of a solid color and confining it's size. The background-repeat is disabled so that it will only render a single grey block.
.grey-block {
background-color: white;
background-image: linear-gradient(#f9f9f9, #f9f9f9);
background-size: 35% 65%;
background-repeat: no-repeat;
}
/* non-relevant styles */
body {
background-color: #222;
}
.grey-block {
height: 200px;
width: 200px;
}
<div class="grey-block"></div>
You can specify an angle. That should do the trick.
.grey-block { background: linear-gradient( 135deg, #f9f9f9 0%, #f9f9f9 65%, white 65%, white 100%); }

CSS tricks: underline with alpha-gradient on both ends

I need to underline my elements (menu items) with a line which has an gradient on BOTH ends.
It can't simply be a graphic (even stretched one), since the width of elements may vary significantly.
The desired effect:
What I did, was to create a line, 1000px wide, with gradient on both ends, then append following HTML <div><div class="right"> </div></div> to every element to be underlined.
The CSS is following
#navmenu li div
{
height: 1px;
background-image: url('images/1000glight.png');
background-repeat: no-repeat;
}
#navmenu li div.right
{
width:35px;
float: right;
background-position: -965px 0;
background-image: url('images/1000glight.png');
background-color: #212121;
}
This however is not truly alpha. I need to specify the background color of "right-side" div in order to "cover" the image (1000px line) which is below.
Any ideas how could I improve it, keeping pure CSS?
Using an approach similar to this, with the gradient being the background image of a wrapping div with padding-bottom to show only the lower part of the background:
<div class="wrap">
<div class="content">Some Text!</div>
</div>
And CSS:
.wrap {
float: left;
padding-bottom: 5px;
/* IE10 */
background-image: -ms-linear-gradient(right, #fff 0%, #000 25%, #000 75%, #fff 100%);
/* Mozilla Firefox */
background-image: -moz-linear-gradient(right, #fff 0%, #000 25%, #000 75%, #fff 100%);
/* Opera */
background-image: -o-linear-gradient(right, #fff 0%, #000 25%, #000 75%, #fff 100%);
/* Webkit (Safari/Chrome 10) */
background-image: -webkit-gradient(linear, right top, left top, color-stop(0, #fff), color-stop(0.25, #000), color-stop(0.75, #000), color-stop(1, #fff));
/* Webkit (Chrome 11+) */
background-image: -webkit-linear-gradient(right, #fff 0%, #000 25%, #000 75%, #fff 100%);
/* Proposed W3C Markup */
background-image: linear-gradient(right, #fff 0%, #000 25%, #000 75%, #fff 100%);
}
.content {
background-color: #fff;
}
Works, but does omit IE<10; which might be do-able with some kind of filter, but that'll take more reading before I can post such.
JS Fiddle demo of current implementation.
Unfortunately the DX.transform option doesn't appear able to allow for multiple stops that the above uses, reference: Simulating color stops in gradients for IE
So, perhaps you'd have to use a background-image fallback for IE<10, which is far less than ideal.
Use the border-image gradient CSS3.
div {
width:200px;
border-style:solid;
border-width:15px;
text-align: center;
-webkit-border-image:
-webkit-linear-gradient(left, rgba(255,255,255,1) 1%,rgba(0,0,0,1) 50%,rgba(255,255,255,1) 100%) 0 0 100% 0/0 0 15px 0 stretch;
}
Demo here.
This will only work with Webkit browsers (Chrome, Safari etc). There should be some vendor specific equivalents.
You can use an empty div with a CSS3 Gradient... check out the presets here: http://www.colorzilla.com/gradient-editor/ - of course you'll have to change the orientation of the gradient. I use this a lot for similar issues. It's a great alternative to images.

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