Subtract rows and create a new row name - r

I would like to subtract Bay County from Florida in this data frame and create a new row with the name "Florida (-Bay County)".
Maybe group_modify and add_row (dplyr) would be a possibility?
year <- c(2005,2006,2007,2005,2006,2007,2005,2006,2007,2005,2006,2007)
county <- c("Alachua County","Alachua County","Alachua County","Baker County","Baker County","Baker County","Bay County","Bay County","Bay County","Florida","Florida","Florida")
pop <- c(3,6,8,9,8,4,5,8,10,17,22,22)
gdp <- c(3,6,8,9,8,4,5,8,10,17,22,22)
area <- c(3,6,8,9,8,4,5,8,10,17,22,22)
density<-c(3,6,8,9,8,4,5,8,10,17,22,22)
df <- data.frame(year, county,pop,gdp,area,density, stringsAsFactors = FALSE)
year
county
pop
gdp
area
density
2005
Alachua County
3
3
3
3
2005
Baker County
9
9
9
9
2005
Bay County
5
5
5
5
2005
Florida
17
17
17
17
2005
Florida (-Bay County)
12
12
12
12
2006
Alachua County
6
6
6
6
2006
Baker County
8
8
8
8
2006
Bay County
8
8
8
8
2006
Florida
22
22
22
22
2006
Florida (-Bay County)
14
14
14
14
2007
Alachua County
8
8
8
8
2007
Baker County
4
4
4
4
2007
Bay County
10
10
10
10
2007
Florida
22
22
22
22
2007
Florida (-Bay County)
12
12
12
12

If you wanted to try something with group_modify and add_row, you could consider something like this. Here, when using add_row, use map to sum up the data within the group, but not including "Florida" or "Bay County".
library(tidyverse)
df %>%
group_by(year) %>%
group_modify(
~ .x %>%
add_row(
county = "Florida (-Bay County)",
!!! map(.x %>%
filter(!county %in% c("Florida", "Bay County")) %>%
select(-county),
sum)
)
)
Output
year county pop gdp area density
<dbl> <chr> <dbl> <dbl> <dbl> <dbl>
1 2005 Alachua County 3 3 3 3
2 2005 Baker County 9 9 9 9
3 2005 Bay County 5 5 5 5
4 2005 Florida 17 17 17 17
5 2005 Florida (-Bay County) 12 12 12 12
6 2006 Alachua County 6 6 6 6
7 2006 Baker County 8 8 8 8
8 2006 Bay County 8 8 8 8
9 2006 Florida 22 22 22 22
10 2006 Florida (-Bay County) 14 14 14 14
11 2007 Alachua County 8 8 8 8
12 2007 Baker County 4 4 4 4
13 2007 Bay County 10 10 10 10
14 2007 Florida 22 22 22 22
15 2007 Florida (-Bay County) 12 12 12 12

You could do:
df %>%
filter(county != 'Florida' & county != 'Bay County') %>%
group_by(year) %>%
bind_rows(summarise(., county = 'Florida (-Bay County)',
across(where(is.numeric), sum))) %>%
arrange(year)
#> # A tibble: 9 x 6
#> # Groups: year [3]
#> year county pop gdp area density
#> <dbl> <chr> <dbl> <dbl> <dbl> <dbl>
#> 1 2005 Alachua County 3 3 3 3
#> 2 2005 Baker County 9 9 9 9
#> 3 2005 Florida (-Bay County) 12 12 12 12
#> 4 2006 Alachua County 6 6 6 6
#> 5 2006 Baker County 8 8 8 8
#> 6 2006 Florida (-Bay County) 14 14 14 14
#> 7 2007 Alachua County 8 8 8 8
#> 8 2007 Baker County 4 4 4 4
#> 9 2007 Florida (-Bay County) 12 12 12 12

Related

Canculating the compound annual growth rate

I'm trying to calculate the compound annual growth rate of my data (snipet shown below), does anyone know the best way to do this or if there is a function that does part of the job?
Data: (only woried about the preds column here, others can be ignored)
year month timestep ymin ymax preds date
1 1998 1 1 17.84037 18.58553 18.21295 1998-01-01
2 1998 2 2 17.05009 17.70642 17.37826 1998-02-01
3 1998 3 3 16.97067 17.61320 17.29193 1998-03-01
4 1998 4 4 18.38551 19.00838 18.69695 1998-04-01
5 1998 5 5 21.39082 21.97338 21.68210 1998-05-01
6 1998 6 6 24.77679 25.35464 25.06571 1998-06-01
7 1998 7 7 27.27057 27.82818 27.54938 1998-07-01
8 1998 8 8 28.24703 28.76702 28.50702 1998-08-01
9 1998 9 9 27.72370 28.24619 27.98494 1998-09-01
10 1998 10 10 25.83783 26.33969 26.08876 1998-10-01
11 1998 11 11 22.94968 23.42268 23.18618 1998-11-01
12 1998 12 12 19.50499 20.05466 19.77982 1998-12-01
13 1999 1 13 17.98323 18.50530 18.24426 1999-01-01
14 1999 2 14 17.20124 17.61746 17.40935 1999-02-01
15 1999 3 15 17.11064 17.53492 17.32278 1999-03-01

Is it possible to make groups based on an ID of a person in R?

I have this data:
data <- data.frame(id_pers=c(4102,13102,27101,27102,28101,28102, 42101,42102,56102,73102,74103,103104,117103,117104,117105),
birthyear=c(1992,1994,1993,1992,1995,1999,2000,2001,2000, 1994, 1999, 1978, 1986, 1998, 1999))
I want to group the different persons by familys in a new column, so that persons 27101,27102 (siblings) are group/family 1 and 42101,42102 are in group 2, 117103,117104,117105 are in group 3 so on.
Person "4102" has no siblings and should be a NA in the new column.
It is always the case that 2 or more persons are siblings if the ID's are not further apart than a maximum of 6 numbers.
I have a far larger dataset with over 3000 rows. How could I do it the most efficient way?
You can use round with digits = -1 (or -2) if you have id_pers that goes above 10 observations per family. If you want the id to be integers from 1; you can use cur_group_id:
library(dplyr)
data %>%
group_by(fam_id = round(id_pers - 5, digits = -1)) %>%
mutate(fam_gp = cur_group_id())
output
# A tibble: 15 × 3
# Groups: fam_id [10]
id_pers birthyear fam_id fam_gp
<dbl> <dbl> <dbl> <int>
1 4102 1992 4100 1
2 13102 1994 13100 2
3 27101 1993 27100 3
4 27102 1992 27100 3
5 28101 1995 28100 4
6 28106 1999 28100 4
7 42101 2000 42100 5
8 42102 2001 42100 5
9 56102 2000 56100 6
10 73102 1994 73100 7
11 74103 1999 74100 8
12 103104 1978 103100 9
13 117103 1986 117100 10
14 117104 1998 117100 10
15 117105 1999 117100 10
It looks like we can the 1000s digit (and above) to delineate groups.
library(dplyr)
data %>%
mutate(
famgroup = trunc(id_pers/1000),
famgroup = match(famgroup, unique(famgroup))
)
# id_pers birthyear famgroup
# 1 4102 1992 1
# 2 13102 1994 2
# 3 27101 1993 3
# 4 27102 1992 3
# 5 28101 1995 4
# 6 28102 1999 4
# 7 42101 2000 5
# 8 42102 2001 5
# 9 56102 2000 6
# 10 73102 1994 7
# 11 74103 1999 8
# 12 103104 1978 9
# 13 117103 1986 10
# 14 117104 1998 10
# 15 117105 1999 10

R - calculate annual population conditional on survival in every year

I have a data frame with three columns: birth_year, death_year, gender.
I have to calculate total alive male and female population for every year in a given range (1950:1980).
The data frame looks like this:
birth_year death_year gender
1934 1988 male
1922 1993 female
1890 1966 male
1901 1956 male
1946 2009 female
1909 1976 female
1899 1945 male
1887 1949 male
1902 1984 female
The person is alive in year x if death_year > x & birth year <= x
The output I am looking for is something like this:
year male female
1950 3 4
1951 2 3
1952 4 3
1953 4 5
.
.
1980 6 3
Thanks!
Does this work:
library(tidyr)
library(purrr)
library(dplyr)
df %>% mutate(year = map2(1950,1980, seq)) %>% unnest(year) %>%
mutate(isalive = case_when(year >= birth_year & year < death_year ~ 1, TRUE ~ 0)) %>%
group_by(year, gender) %>% summarise(alive = sum(isalive)) %>%
pivot_wider(names_from = gender, values_from = alive) %>% print( n = 50)
`summarise()` regrouping output by 'year' (override with `.groups` argument)
# A tibble: 31 x 3
# Groups: year [31]
year female male
<int> <dbl> <dbl>
1 1950 4 3
2 1951 4 3
3 1952 4 3
4 1953 4 3
5 1954 4 3
6 1955 4 3
7 1956 4 2
8 1957 4 2
9 1958 4 2
10 1959 4 2
11 1960 4 2
12 1961 4 2
13 1962 4 2
14 1963 4 2
15 1964 4 2
16 1965 4 2
17 1966 4 1
18 1967 4 1
19 1968 4 1
20 1969 4 1
21 1970 4 1
22 1971 4 1
23 1972 4 1
24 1973 4 1
25 1974 4 1
26 1975 4 1
27 1976 3 1
28 1977 3 1
29 1978 3 1
30 1979 3 1
31 1980 3 1
Data used:
df
# A tibble: 9 x 3
birth_year death_year gender
<dbl> <dbl> <chr>
1 1934 1988 male
2 1922 1993 female
3 1890 1966 male
4 1901 1956 male
5 1946 2009 female
6 1909 1976 female
7 1899 1945 male
8 1887 1949 male
9 1902 1984 female
Here's a simple base R solution. Summing a logical vector will get you your count of alive or dead because TRUE is 1 and FALSE is 0.
number_alive <- function(range, df){
sapply(range, function(x) sum((df$death_year > x) & (df$birth_year <= x)))
}
output <- data.frame('year' = 1950:1980,
'female' = number_alive(1950:1980, df[df$gender == 'female']),
'male' = number_alive(1950:1980, df[df$gender == 'male']))
# year female male
# 1 1950 4 3
# 2 1951 4 3
# 3 1952 4 3
# 4 1953 4 3
# 5 1954 4 3
# 6 1955 4 3
# 7 1956 4 2
# 8 1957 4 2
# 9 1958 4 2
# 10 1959 4 2
# 11 1960 4 2
# 12 1961 4 2
# 13 1962 4 2
# 14 1963 4 2
# 15 1964 4 2
# 16 1965 4 2
# 17 1966 4 1
# 18 1967 4 1
# 19 1968 4 1
# 20 1969 4 1
# 21 1970 4 1
# 22 1971 4 1
# 23 1972 4 1
# 24 1973 4 1
# 25 1974 4 1
# 26 1975 4 1
# 27 1976 3 1
# 28 1977 3 1
# 29 1978 3 1
# 30 1979 3 1
# 31 1980 3 1
This approach uses an ifelse to determine if alive (1) or dead (0).
Data:
df <- "birth_year death_year gender
1934 1988 male
1922 1993 female
1890 1966 male
1901 1956 male
1946 2009 female
1909 1976 female
1899 1945 male
1887 1949 male
1902 1984 female"
df <- read.table(text = df, header = TRUE)
Code:
library(dplyr)
library(tidyr)
library(tibble)
library(purrr)
df %>%
mutate(year = map2(1950,1980, seq)) %>%
unnest(year) %>%
select(year, birth_year, death_year, gender) %>%
mutate(
alive = ifelse(year >= birth_year & year <= death_year, 1, 0)
) %>%
group_by(year, gender) %>%
summarise(
is_alive = sum(alive)
) %>%
pivot_wider(
names_from = gender,
values_from = is_alive
) %>%
select(year, male, female)
Output:
#> # A tibble: 31 x 3
#> # Groups: year [31]
#> year male female
#> <int> <dbl> <dbl>
#> 1 1950 3 4
#> 2 1951 3 4
#> 3 1952 3 4
#> 4 1953 3 4
#> 5 1954 3 4
#> 6 1955 3 4
#> 7 1956 3 4
#> 8 1957 2 4
#> 9 1958 2 4
#> 10 1959 2 4
#> # … with 21 more rows
Created on 2020-11-11 by the reprex package (v0.3.0)

grouping data in R and summing by decade

I have the following dataset:
ireland england france year
5 3 2 1920
4 3 4 1921
6 2 1 1922
3 1 5 1930
2 5 2 1931
I need to summarise the data by 1920's and 1930's. So I need total points for ireland, england and france in the 1920-1922 and then another total point for ireland,england and france in 1930,1931.
Any ideas? I have tried but failed.
Dataset:
x <- read.table(text = "ireland england france
5 3 2 1920
4 3 4 1921
6 2 1 1922
3 1 5 1930
2 5 2 1931", header = T)
How about dividing the years by 10 and then summarizing?
library(dplyr)
x %>% mutate(decade = floor(year/10)*10) %>%
group_by(decade) %>%
summarize_all(sum) %>%
select(-year)
# A tibble: 2 x 5
# decade ireland england france
# <dbl> <int> <int> <int>
# 1 1920 15 8 7
# 2 1930 5 6 7
An R base solution
As A5C1D2H2I1M1N2O1R2T1 mentioned, you can use findIntervals() to set corresponding decade for each year and then, an aggregate() to group py decade
txt <-
"ireland england france year
5 3 2 1920
4 3 4 1921
6 2 1 1922
3 1 5 1930
2 5 2 1931"
df <- read.table(text=txt, header=T)
decades <- c(1920, 1930, 1940)
df$decade<- decades[findInterval(df$year, decades)]
aggregate(cbind(ireland,england,france) ~ decade , data = df, sum)
Output:
decade ireland england france
1 1920 15 8 7
2 1930 5 6 7

Add lines with NA values

I have a data frame like this:
indx country year death value
1 1 Italy 2000 hiv 1
2 1 Italy 2001 hiv 2
3 1 Italy 2005 hiv 3
4 1 Italy 2000 cancer 4
5 1 Italy 2001 cancer 5
6 1 Italy 2002 cancer 6
7 1 Italy 2003 cancer 7
8 1 Italy 2004 cancer 8
9 1 Italy 2005 cancer 9
10 4 France 2000 hiv 10
11 4 France 2004 hiv 11
12 4 France 2005 hiv 12
13 4 France 2001 cancer 13
14 4 France 2002 cancer 14
15 4 France 2003 cancer 15
16 4 France 2004 cancer 16
17 2 Spain 2000 hiv 17
18 2 Spain 2001 hiv 18
19 2 Spain 2002 hiv 19
20 2 Spain 2003 hiv 20
21 2 Spain 2004 hiv 21
22 2 Spain 2005 hiv 22
23 2 Spain ... ... ...
indx is a value linked to the country (same country = same indx).
In this example I used only 3 countries (country) and 2 disease (death), in the original data frame are many more.
I would like to have one row for each country for each disease from 2000 to 2005.
What I would like to get is:
indx country year death value
1 1 Italy 2000 hiv 1
2 1 Italy 2001 hiv 2
3 1 Italy 2002 hiv NA
4 1 Italy 2003 hiv NA
5 1 Italy 2004 hiv NA
6 1 Italy 2005 hiv 3
7 1 Italy 2000 cancer 4
8 1 Italy 2001 cancer 5
9 1 Italy 2002 cancer 6
10 1 Italy 2003 cancer 7
11 1 Italy 2004 cancer 8
12 1 Italy 2005 cancer 9
13 4 France 2000 hiv 10
14 4 France 2001 hiv NA
15 4 France 2002 hiv NA
16 4 France 2003 hiv NA
17 4 France 2004 hiv 11
18 4 France 2005 hiv 12
19 4 France 2000 cancer NA
20 4 France 2001 cancer 13
21 4 France 2002 cancer 14
22 4 France 2003 cancer 15
23 4 France 2004 cancer 16
24 4 France 2005 cancer NA
25 2 Spain 2000 hiv 17
26 2 Spain 2001 hiv 18
27 2 Spain 2002 hiv 19
28 2 Spain 2003 hiv 20
29 2 Spain 2004 hiv 21
30 2 Spain 2005 hiv 22
31 2 Spain ... ... ...
I.e. I would like to add lines with value = NA at the missing years for each country for each disease.
For example, it lacks data of HIV in Italy between 2002 and 2004 and then I add this lines with value = NA.
How can I do that?
For a reproducible example:
indx <- c(rep(1, times=9), rep(4, times=7), rep(2, times=6))
country <- c(rep("Italy", times=9), rep("France", times=7), rep("Spain", times=6))
year <- c(2000, 2001, 2005, 2000:2005, 2000, 2004, 2005, 2001:2004, 2000:2005)
death <- c(rep("hiv", times=3), rep("cancer", times=6), rep("hiv", times=3), rep("cancer", times=4), rep("hiv", times=6))
value <- c(1:22)
dfl <- data.frame(indx, country, year, death, value)
Using base R, you could do:
# setDF(dfl) # run this first if you have a data.table
merge(expand.grid(lapply(dfl[c("country", "death", "year")], unique)), dfl, all.x = TRUE)
This first creates all combinations of the unique values in country, death, and year and then merges it to the original data, to add the values and where combinations were not in the original data, it adds NAs.
In the package tidyr, there's a special function that does this for you with a a single command:
library(tidyr)
complete(dfl, country, year, death)
Here is a longer base R method. You create two new data.frames, one that contains all combinations of the country, year, and death, and a second that contains an index key.
# get data.frame with every combination of country, year, and death
dfNew <- with(df, expand.grid("country"=unique(country), "year"=unique(year),
"death"=unique(death)))
# get index key
indexKey <- unique(df[, c("indx", "country")])
# merge these together
dfNew <- merge(indexKey, dfNew, by="country")
# merge onto original data set
dfNew <- merge(df, dfNew, by=c("indx", "country", "year", "death"), all=TRUE)
This returns
dfNew
indx country year death value
1 1 Italy 2000 cancer 4
2 1 Italy 2000 hiv 1
3 1 Italy 2001 cancer 5
4 1 Italy 2001 hiv 2
5 1 Italy 2002 cancer 6
6 1 Italy 2002 hiv NA
7 1 Italy 2003 cancer 7
8 1 Italy 2003 hiv NA
9 1 Italy 2004 cancer 8
10 1 Italy 2004 hiv NA
11 1 Italy 2005 cancer 9
12 1 Italy 2005 hiv 3
13 2 Spain 2000 cancer NA
14 2 Spain 2000 hiv 17
15 2 Spain 2001 cancer NA
...
If df is a data.table, here are the corresponding lines of code:
# CJ is a cross-join
setkey(df, country, year, death)
dfNew <- df[CJ(country, year, death, unique=TRUE),
.(country, year, death, value)]
indexKey <- unique(df[, .(indx, country)])
dfNew <- merge(indexKey, dfNew, by="country")
dfNew <- merge(df, dfNew, by=c("indx", "country", "year", "death"), all=TRUE)
Note that it rather than using CJ, it is also possible to use expand.grid as in the data.frame version:
dfNew <- df[, expand.grid("country"=unique(country), "year"=unique(year),
"death"=unique(death))]
tidyr::complete helps create all combinations of the variables you pass it, but if you have two columns that are identical, it will over-expand or leave NAs where you don't want. As a workaround you can use dplyr grouping (df %>% group_by(indx, country) %>% complete(death, year)) or just merge the two columns into one temporarily:
library(tidyr)
# merge indx and country into a single column so they won't over-expand
df %>% unite(indx_country, indx, country) %>%
# fill in missing combinations of new column, death, and year
complete(indx_country, death, year) %>%
# separate indx and country back to how they were
separate(indx_country, c('indx', 'country'))
# Source: local data frame [36 x 5]
#
# indx country death year value
# (chr) (chr) (fctr) (int) (int)
# 1 1 Italy cancer 2000 4
# 2 1 Italy cancer 2001 5
# 3 1 Italy cancer 2002 6
# 4 1 Italy cancer 2003 7
# 5 1 Italy cancer 2004 8
# 6 1 Italy cancer 2005 9
# 7 1 Italy hiv 2000 1
# 8 1 Italy hiv 2001 2
# 9 1 Italy hiv 2002 NA
# 10 1 Italy hiv 2003 NA
# .. ... ... ... ... ...

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