Error with ggscatterplot() function from ggpubr package - r

Question

I try to use ggscatter() function from ggpubr package with the following code
ggscatter(mtcars,
x = "hp", y = "carb",
cor.coef = TRUE, cor.method = "spearman",
xlab = "x1", ylab = "x2")
but I get the following error.
Error in parse(text = text[[i]]) : :1:16: unexpected ','
1: italic(R)~=~0,
Thanks in advance for the help.

Answer 1

Not sure about your question as your code is working fine.
Sample data:
data(mtcars)
Sample code:
library(ggpubr)
ggscatter(mtcars,
x = "hp", y = "carb",
cor.coef = TRUE, cor.method = "spearman",
xlab = "x1", ylab = "x2")
Plot:

Answer 2

I think the most likely answer to your problem is that you have set your output decimal to a comma with options(OutDec = ",")
I had the exact same problem. Here is my question with the following answer: Error in parse(text ...) unexpected comma "," when plotting ggplot with ggpubr::stat_cor and output decimal set to comma (options(OutDec = ","))
This is a bug in the package ggpubr as it cannot handle commas as
decimal seperators. For more information see here or in the comments:
MrFlick: Specifically I think it's in this line
https://github.com/kassambara/ggpubr/blob/ac5a01f586a5f0b47260fed071e79be36ef3f8ea/R/stat_cor.R#L207
. Those values should be wrapped in quotes to prevent the parsing
error. And the problem with the persistent decimal point in the
p-values comes from
https://github.com/kassambara/ggpubr/blob/ac5a01f586a5f0b47260fed071e79be36ef3f8ea/R/stat_cor.R#L219
. It doesn't look like the package really support a comma separator. –
However, there is a workaround (pointed out by #MrFlick) by passing the argument , output.type="text" in the stat_cor function e.g.:
stat_cor(show.legend = F ,label.y = c(18), method = "pearson",
output.type="text") However, there is an edge case where this does not
work, if p < 2.2e-16 (as with the example data) as the value of p is
passed as a string and not a number. Otherwise it works though.