If more than one ID for a match select id with max(date) .
if more than one id for above max dates select max(ID)
Go to TABLE1 to get high-dated IDS
Step 1 : identifying IDs which are having max dates
CREATE MULTISET VOLATILE TABLE TEST_VT
AS
(
SELECT
TABLE1.ID ,
TABLE1.KEY1,
TABLE1.STRT_DT,
TABLE1.TERM_DT,
Rank() OVER (PARTITION BY TABLE1.KEY1 ORDER BY TABLE1.STRT_DT DESC , TABLE1.ID DESC) RNK
FROM TABLE2
INNER JOIN TABLE1
ON TABLE2.KEY1=TABLE1.KEY1
WHERE TABLE1.TERM_DT='8888-12-31'
QUALIFY RNK=1
GROUP BY
1,2,3,4
)
WITH DATA PRIMARY INDEX(ID,KEY1) ON COMMIT PRESERVE ROWS;
Go to TABLE1 to get high-dated KEY1S associated with IDS from ABOVE STEP
Step 2 : If there is more than one max date take max ID out of all matched records in above step
SELECT
TABLE1.ID ,
TABLE1.KEY1,
TABLE1.STRT_DT,
TABLE1.TERM_DT,
RANK() OVER (PARTITION BY TABLE1.KEY1 ORDER BY TABLE1.STRT_DT DESC , TABLE1.ID DESC) AS RNK
FROM TABLE1
INNER JOIN TEST_VT
ON TEST_VT.ID=TABLE1.ID
INNER JOIN TABLE3
ON TABLE3.KEY1=TABLE1.KEY1
WHERE TABLE1.TERM_DT='8888-12-31'
QUALIFY RNK=1
GROUP BY
1,2,3,4
Related
My database structure contains columns: id, name, value, dealer. I want to retrieve row with lowest value for each dealer. I've been trying to mess up with MIN() and GROUP BY, still - no solution.
Solution1:
SELECT t1.* FROM your_table t1
JOIN (
SELECT MIN(value) AS min_value, dealer
FROM your_table
GROUP BY dealer
) AS t2 ON t1.dealer = t2.dealer AND t1.value = t2.min_value
Solution2 (recommended, much faster than solution1):
SELECT t1.* FROM your_table t1
LEFT JOIN your_table t2
ON t1.dealer = t2.dealer AND t1.value > t2.value
WHERE t2.value IS NULL
This problem is very famous, so there is a special page for this in Mysql's manual.
Check this: Rows Holding the Group-wise Maximum/Minimum of a Certain Column
select id,name,MIN(value) as pkvalue,dealer from TABLENAME
group by id,name,dealer;
here you group all rows by id,name,dealer and then you will get min value as pkvalue.
SELECT MIN(value),dealer FROM table_name GROUP BY dealer;
First you need to resolve the lowest value for each dealer, and then retrieve rows having that value for a particular dealer. I would do this that way:
SELECT a.*
FROM your_table AS a
JOIN (SELECT dealer,
Min(value) AS m
FROM your_table
GROUP BY dealer) AS b
ON ( a.dealer= b.dealer
AND a.value = b.m )
Try following:
SELECT dealer, MIN(value) as "Lowest value"
FROM value
GROUP BY dealer;
select id, name, value, dealer from yourtable where dealer
in(select min(dealer) from yourtable group by name, value)
These answers seem to miss the edge case of having multiple minimum values for a dealer and only wanting to return one row.
If you want to only want one value for each dealer you can use row_number partition - group - the table by dealer then order the data by value and id. we have to make the assumption that you will want the row with the smallest id.
SELECT ord_tbl.id,
ord_tbl.name,
ord_tbl.value,
ord_tbl.dealer
FROM (SELECT your_table.*,
ROW_NUMBER() over (PARTITION BY dealer ORDER BY value ASC, ID ASC)
FROM your_table
) AS ord_tbl
WHERE ord_tbl.ROW_NUMBER = 1;
Be careful though that value, id and dealer are indexed. If not this will do a full table scan and can get pretty slow...
I'm very new to learning SQL, I apologize if my question isn't completely accurate.
The question I'm trying to answer with this query is "What is the most popular music genre in each country?" I've had to use a subquery and it works, but I found that for a few countries in the table, more than one genre has the MAX value. I'm stuck with how to edit my query so that all genres with the max value show in the results. Here is my code, using DB Browser for SQLite:
SELECT BillingCountry AS Country , name AS Genre , MAX(genre_count) AS Purchases
FROM (
SELECT i.BillingCountry, g.name, COUNT(g.genreid) AS genre_count
FROM Invoice i
JOIN InvoiceLine il
ON il.InvoiceId = i.InvoiceId
JOIN TRACK t
ON il.trackid = t.TrackId
JOIN Genre g
ON t.genreid = g.GenreId
GROUP BY 1,2
) sub
GROUP BY 1
Here is an example of the result:
| Country | Genre |Purchase|
|---------|-------|--------|
|Agrentina| Punk | 9 |
|Australia| Rock | 22 |
BUT in running just the subquery to COUNT the purchases, Argentina has two Genres with 9 Purchases (the max number for that country). How do I adjust my query to include both and not just the first one in the row?
You can do it with RANK() window function:
SELECT BillingCountry, name, genre_count
FROM (
SELECT i.BillingCountry, g.name, COUNT(*) AS genre_count,
RANK() OVER (PARTITION BY i.BillingCountry ORDER BY COUNT(*) DESC) rnk
FROM Invoice i
INNER JOIN InvoiceLine il ON il.InvoiceId = i.InvoiceId
INNER JOIN TRACK t ON il.trackid = t.TrackId
INNER JOIN Genre g ON t.genreid = g.GenreId
GROUP BY i.BillingCountry, g.name
)
WHERE rnk = 1
This will return the ties in separate rows.
If you want 1 row for each country, you could also use GROUP_CONCAT():
SELECT BillingCountry, GROUP_CONCAT(name) AS name, MAX(genre_count) AS genre_count
FROM (
SELECT i.BillingCountry, g.name, COUNT(*) AS genre_count,
RANK() OVER (PARTITION BY i.BillingCountry ORDER BY COUNT(*) DESC) rnk
FROM Invoice i
INNER JOIN InvoiceLine il ON il.InvoiceId = i.InvoiceId
INNER JOIN TRACK t ON il.trackid = t.TrackId
INNER JOIN Genre g ON t.genreid = g.GenreId
GROUP BY i.BillingCountry, g.name
)
WHERE rnk = 1
GROUP BY BillingCountry
I have a table in my database I do a Select all on:
SELECT * FROM TableA;
I want to append a column that is true or false if there's a related column in anther table. I can do it with this:
SELECT *, (SELECT COUNT(Id) > 0 FROM TableB WHERE Id = TableA.Id) FROM TableA;
But I don't want to have to count EVERY row in TableB to work this out as its ineffient. I essentially want an EXISTS check instead of count.
How do I replace the COUNT with EXISTS?
Thanks!
By using a left join
SELECT a.*, b.id is not null as condition_check
FROM TableA a
LEFT JOIN TableB b ON a.Id = b.Id
Ah - just realised the answer to my own question
SELECT *, EXISTS(SELECT Id FROM TableB WHERE Id= TableA.Id) AS DoesExist FROM TableA
How to achieve the result set in sql query
You could work along
WITH
T1 AS (
SELECT
val,
ROW_NUMBER() OVER (PARTITION BY NULL ORDER BY id) rn
FROM Table1
),
T2 AS (
SELECT
val,
ROW_NUMBER() OVER (PARTITION BY NULL ORDER BY id) rn
FROM Table2
),
T3 AS (
SELECT
val,
ROW_NUMBER() OVER (PARTITION BY NULL ORDER BY id) rn
FROM Table3
)
SELECT
T1.val column1
, T2.val column2
, T3.val column3
FROM T1
JOIN T2
ON T1.rn = T2.rn
JOIN T3
ON T2.rn = T3.rn
ORDER BY T1.rn
;
You'd need to
put the statements, which are now going into the UNION into "T1" through "T3", and
move your current sort orders to the ROW_NUMBER analytic functions respectively.
… and should be done: SQL Fiddle
Please comment, if and as further detail is required.
I have tables - FAKE_CUST, PRE_CUST, NORMAL_CUST. Based on the constraint present in FAKE_CUST table, the value has to be brought to either PRE_CUST or NORMAL_CUST.
I am using the follwing code:
INSERT ALL
INTO PRE_CUST(CUST_ID, TOTAL_COST_TRANS) (SELECT DISTINCT CUST_ID,C FROM (
SELECT CUST_ID, SUM(COST_TRANS) OVER (PARTITION BY CUST_ID) as C FROM FAKE_CUST) WHERE C>1000)
INTO NORMAL_CUST(CUST_ID, TOTAL_COST_TRANS) (SELECT DISTINCT CUST_ID,C FROM (
SELECT CUST_ID, SUM(COST_TRANS) OVER (PARTITION BY CUST_ID) as C FROM FAKE_CUST) WHERE C<1000)
SELECT 1 FROM DUAL;
The syntax which you have used for multi-table insert is not correct to start with.
The WHEN clause, which evaluates the condition for insert, has to come before insert_intoclause.
Your query should look like this:
INSERT ALL
WHEN c > 1000 THEN
INTO pre_cust (cust_id, total_cost_trans)
WHEN c < 1000 THEN
INTO normal_cust (cust_id, total_cost_trans)
SELECT CUST_ID, SUM(COST_TRANS) OVER (PARTITION BY CUST_ID) as C
FROM FAKE_CUST