Making 2-way graph (ggplot2) out of a tabyl table changing values - r

male FALSE TRUE
0 50.0% 66.7%
1 50.0% 33.3%
structure(list(male = 0:1, `FALSE` = c("50.0%", "50.0%"), `TRUE` = c("66.7%",
"33.3%")), row.names = c(NA, -2L), core = structure(list(male = 0:1,
`FALSE` = c(1, 1), `TRUE` = c(4, 2)), class = "data.frame", row.names = c(NA,
-2L)), tabyl_type = "two_way", var_names = list(row = "male",
col = "dummy"), class = c("tabyl", "data.frame"))
How can I make a plot using ggplot2 of this table constructed with janitor? The thing is that I would like two plots side-by-side: one for dummy=TRUE and the other for dummy=FALSE (but changing the labels such that TRUE is replaced by a and FALSE by b -- i am having difficulties with this because TRUE and FALSE are logical). I would also like to replace the values 0 and 1 for c and d respectively.


You can try a tidyverse. The trick is to transform the data from wide to long since this is the prefered input for ggplot. Here I used pivot_longer, but you can also use reshape or melt.
library(tidyverse)
df %>%
pivot_longer(-1) %>%
mutate(name = ifelse(name, "a", "b")) %>%
ggplot( aes(factor(male), value, fill =name)) +
geom_col(position = position_dodge())
Using base R you can try
# transform percentages to numerics
df$a <- as.numeric(gsub("%", "", df$`TRUE`))
df$b <- as.numeric(gsub("%", "", df$`FALSE`))
barplot(cbind(a, b) ~ male, df, beside=T,legend.text = TRUE)

Related

Plot multiple geom_line and geom_smooth objects in one plot

I have somewhat messy looking dataframes, like this one:
df0
# A tibble: 3 x 9
# Groups: Sequ [1]
Sequ Speaker Utterance A_intpl A_dur B_intpl B_dur C_intpl C_dur
<int> <chr> <chr> <chr> <chr> <chr> <chr> <chr> <chr>
1 2 ID16.A cool >wha… 31.44786152… 10.5,17,1… 32.86993284… 9.5,16,17… 58.3368399… 14,17,17…
2 2 NA (0.228) 32.75735987… 15.5,17,1… 30.83469006… 14.5,16.9… 26.0386462… 3,17,16,…
3 2 ID16.B u:m Tenne… 32.05752604… 4.5,17,16… 29.95825107… 3.5,16,17… 55.9298614… 8,17,17,…
I want to plot the *_intpl values for each speaker (A, B, or C) for each of the three Utterances in a single chart both as line charts and as trend lines.
I'm just half successful doing this:
library(tidyr)
library(ggplot2)
library(dplyr)
df0 %>%
pivot_longer(cols = contains("_"),
names_to = c("Event_by", ".value"),
names_pattern = "^(.*)_([^_]+$)") %>%
separate_rows(c(intpl, dur), sep = ",", convert = TRUE) %>%
mutate(Time = cumsum(dur)) %>%
mutate(Utterance = paste0(sub(".*(.)$", "\\1",Speaker), ": ", Utterance),
Utterance = factor(Utterance, levels = unique(Utterance))) %>%
ggplot(aes(x = Time, y = log2(intpl),
group = Event_by,
colour = Event_by)) +
geom_line()+
geom_smooth(method = 'lm', color = "red", formula = y~x)+
facet_wrap(~ Utterance, ncol = 1, scales= "free_x")
Half successful because the line plots and trend lines are side-by-side, as if in three columns, whereas they should be in rows, one below the other - how can that be achieved?
Reproducible data:
structure(list(Sequ = c(2L, 2L, 2L), Speaker = c("ID16.A", NA,
"ID16.B"), Utterance = c("cool >what part?<", "(0.228)", "u:m Tennessee="
), A_intpl = c("31.4478615210995,31.5797510648522,31.7143985369445,31.651083739602,31.5806035086034,36.8956763912703,36.2882129597292,35.2124499461012,34.1366869324732,34.1366869324732,32.1927035724058,30.2487202123383,28.3047368522709,26.3607534922035,30.5278334848495,30.5919390424853,30.8898529369568,31.578968913188,31.9011198738002,32.1543265113196,31.9708002079533,31.966536408565,31.8762658607759,31.8994741472105,31.4215913971938,32.1510578328563,31.7863350712876,32.4685052625667,31.7422271490296,32.3286054977263,31.9998974949481,32.5177992323864,32.4727499785435,32.9310888953766,32.7592010033585,33.2231711877427,33.1593949301066,33.2432973964816,33.2569729073414,33.492144800249,33.317650964723,33.4835787832119,33.2377190454279,32.9200836384356,32.9684568771567,32.6400987016883,27.5447101464944,29.3948945479171,35.3449171857603,33.5932932239592,31.8416692621581,30.0900453003569,32.7850431084597,32.7589003618266,32.8365550655013,32.386716057622,32.8420792704881,32.6909995562489,32.6269434402016,32.7370944106334,32.7529759209752,32.6528826975113,32.3663573764448,32.7326853004792,32.6930038462418,32.8975978772676,33.1752899475416,33.2034433355001,33.0667431432803,32.6322933080614,33.2503168843178,32.7573598713719",
"32.7573598713719,32.7531704791313,32.7366130631104,32.918942216354,32.8309939530596,32.3856893430525,32.5368873543441,32.5628510484821,32.5628510484821,32.5628510484821,32.5506564332008,32.7477119716583,32.3458470743288,32.0575260428013",
"32.0575260428013,32.1628824338111,32.0093334061923,32.1461460586991,31.9080762250966,31.9469105074833,31.7431187667232,31.7194255656503,31.7394296413187,31.8594986292975,31.7498243274746,31.9069142374258,32.0835520942767,31.6257067057109,31.757232379438,31.9036689124911,32.1319749301918,31.7203280774998,31.7877137245706,32.3030946636177,32.2800139298454,32.164646135728,32.3636504940227,32.5657818936495,32.3859453482697,32.4797898358193,32.5319835105237,32.92233491509,32.8240561109448,32.664496027779,33.1835064752029,33.0366413969703,33.0406288190821,33.3232964677672,33.2206260057731,33.1537134269402,33.2783471506207,33.2933281566788,33.5322350394609,33.3815736723684,33.7905544185063,33.6143820666896,33.7490659591585,33.7260102344634,34.0721931066557,34.0455026427054,34.3735788774521,34.2888420421073,34.3913721165542,34.5982135545306,34.4417202731001,34.6586347152449,31.1590521215434,31.3276405983897,28.2379253186548,31.133030931336,34.0715906921349,35.8967950760285,35.9334551147377,35.8565504335515,35.7446081905229,35.6300325834155,35.8390086948751,35.9711743270411,36.0029493274176,35.8891056768339"
), A_dur = c("10.5,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,0.5",
"15.5,17,17,16,17,17,16,17,17,16,17,17,16,12.5", "4.5,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,5.5"
), B_intpl = c("32.8699328424689,32.8154348109057,32.5454364786882,32.408257038977,32.5304564519672,32.3270203236281,31.9233218634346,32.0166346064182,31.7360745988363,31.7546527359571,31.8603220354065,31.6520061326962,31.5603191463274,31.3357561466519,31.0976090032219,31.1405090978825,31.1697180784961,31.0863999545386,31.3126984044729,30.580776446803,30.7137016246273,31.0801914571091,31.2343922096768,31.2749857511594,31.3488604642844,30.9327390960718,31.0750482778561,31.1849119826023,31.4180114886183,31.5284273181104,31.147361398529,31.1128597713973,31.5551385744611,31.7479939892741,31.5890352680344,31.5470790538009,31.5427330200078,31.3901913024084,31.5423214446953,31.4814325586741,31.4937336232021,31.3483738841556,31.2516462059018,31.2233881922543,31.2572951780583,31.0087226975291,31.1197589042273,31.053748381687,30.8202174718598,30.845143129195,30.8727194789634,30.4231467151428,30.7254093759809,30.2757746547116,30.6047530953025,29.6835591414008,28.257421076205,29.4634886416064,29.183064807185,28.6935506287734,29.3989017421637,30.8936090542518,30.6884831327852,30.805770713392,30.6938909098627,30.8317757801268,30.8509115577427,30.6836198471168,30.7979978629801,31.0260101704105,30.6248844591805,30.8346900656087",
"30.8346900656087,30.9826158466835,29.814086001996,29.7839590794955,30.7928804535206,31.1589874726521,31.0547403039501,31.2268131145794,31.155503802286,31.3036925274762,31.4782621660348,31.0928322383151,31.589958621025,29.9582510795225",
"29.9582510795225,29.9796434055214,29.9405638729798,30.2602098442174,30.5011865525849,30.6753859842987,28.9331380886365,30.7736467776919,30.8457967803438,30.843630408183,30.8767570425033,30.9178344980247,30.734598946287,30.8877440413271,30.9225051837881,30.9534076039184,31.0172861192043,30.9371712793451,30.9806052132295,31.0593603717961,31.1156928565737,30.4713263393479,26.028518302418,28.1426546887905,29.4308434671559,30.7190322455213,31.2289674937063,31.7389027418913,32.2488379900763,32.7587732382613,33.2687084864463,33.7786437346312,34.2885789828162,34.7985142310012,35.3084494791862,35.8183847273712,36.3283199755562,36.8382552237412,37.3481904719262,37.8581257201112,38.3680609682962,25.5986933949893,29.7968031963901,30.5336819967028,30.1876589408847,30.4260367500101,30.2997107671214,30.3429716412578,30.3537316791924,30.4111899964144,30.7293520851914,30.7778983966343,30.9712137067708,30.9072589183658,31.0696990205164,30.5713926084448,31.3458855877875,31.4169903025083,31.5148974986093,31.5972499257413,31.2293401943969,31.2033325602348,31.1657434266985,30.6784877073261,30.6991365599664,30.6763195188897"
), B_dur = c("9.5,16,17,17,16,17,17,16,17.0000000000146,16.9999999999854,16,17,16.9999999999854,16.0000000000146,17,17,16,17,17,16,17,17,16,17.0000000000146,16.9999999999854,16,17,16.9999999999854,16.0000000000146,17,17,16,17,17,16,17,17,16,17.0000000000146,16.9999999999854,16,17,16.9999999999854,16.0000000000146,17,17,16,17,17,16,17,17,16,17.0000000000146,16.9999999999854,16,17,16.9999999999854,16.0000000000146,17,17,16,17,17,16,17,17,16,17.0000000000146,16.9999999999854,16,2.5",
"14.5,16.9999999999854,16.0000000000146,17,17,16,17,17,16,17,17,16,17.0000000000146,13.4999999999854",
"3.5,16,17,16.9999999999854,16.0000000000146,17,17,16,17,17,16,17,17,16,17.0000000000146,16.9999999999854,16,17,16.9999999999854,16.0000000000146,17,17,16,17,17,16,17,17,16,17.0000000000146,16.9999999999854,16,17,16.9999999999854,16.0000000000146,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,7.5"
), C_intpl = c("58.3368399069697,58.249224089011,59.5198368051218,58.8722012497097,58.4418996252205,58.5849059154389,59.2752163985494,52.8407480422202,51.6276603912397,48.0255346632529,44.753541512539,41.4815483618252,38.2095552111114,34.9375620603975,31.6655689096837,28.3935757589698,25.121582608256,19.4712933827274,22.0108873782783,24.5504813738291,24.8441573376901,24.6902151101703,24.4029572181118,24.9753161974674,24.8664406826514,24.8486668451201,25.1137001504163,25.1142578332509,25.4902077628339,25.4075561268027,25.6622548410237,61.2421678149908,25.1600975771354,25.6667198263373,25.442560744158,25.8736383423437,25.5859074180431,24.7860400673889,24.4337707697216,24.3214953242744,23.915753514736,23.7363185577661,23.7186569801299,23.4313514771952,23.5730151254578,62.5124513171595,23.3260531660862,23.4498217326665,23.2145314844252,57.5586745434594,63.4646233226955,23.0706406704345,23.3318690599491,62.044649715831,62.2720656330432,22.2532276715887,62.7059140614625,22.9511208849958,22.5603175709988,23.3456453893988,63.2523901625561,60.6655429980934,60.2358824325868,59.957910796633,57.3999702562457,54.8277282980263,43.0269305132552,31.2261327284841,19.425334943713,22.7319906068577,26.0386462700023",
"26.0386462700023,29.345301933147,32.6519575962917,35.9586132594364,48.3773995023798,60.7961857453232,49.4980424442242,55.9907960862667,57.2956837917999,58.1409925994177,59.025022056064,60.0098263540792,60.4028460580062,61.2629030450653,55.9298614021542",
"55.9298614021542,55.3877180252389,61.3547152702855,61.7847919095391,56.2457623439544,62.5477315546977,62.3078007189967,62.4272469013149,57.6479672147315,62.9844338801191,58.0081708266629,63.3872796098875,59.0138830718112,58.0612924481098,58.38680047729,58.687179350318,63.8724230039733,63.4126777597892,63.6865154626743,63.5670658627636,63.4496590540706,63.7595297692908,58.9069708176601,63.4547681163061,64.3198376700797,63.415319961042,64.0985879957056,64.1201809531605,63.677902665454,64.1934303628317,64.4682003346273,64.2868853545462,24.8444135816353,64.1579626357752,63.8897139146875,58.5472675827292,64.5784992977498,64.0848591719068,63.8841268679761,64.2901359712354,64.395692486112,64.5425896391638,64.8060565909917,64.3618830026368,64.7088481705444,64.5005944199885,64.5540289192148,64.7408010459365,63.378880767685,63.3415589069662,63.5362700331647,63.5924807719723,63.575801461932,63.6799360982113,64.0041021410894,64.3144923757986,63.8692943755376,63.8594574363473,64.2731841085802,63.3314657812309,64.2758880216293,64.1011768977101,64.0261661917799,64.2865302330478,63.724697791255,64.1202175712152"
), C_dur = c("14,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,14",
"3,17,16,17,17,16,17,17,16,17,17,16,17,17,8", "8,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,17,16,17,2"
)), row.names = c(NA, -3L), groups = structure(list(Sequ = 2L,
.rows = structure(list(1:3), ptype = integer(0), class = c("vctrs_list_of",
"vctrs_vctr", "list"))), row.names = c(NA, -1L), class = c("tbl_df",
"tbl", "data.frame"), .drop = TRUE), class = c("grouped_df",
"tbl_df", "tbl", "data.frame"))

There's a possible solution with use of grid.arrange() func from library(gridExtra) library(grid) packages.
I've wrapped your data into unique charts and combined them together into arranged chart.
df1 = df0 %>%
pivot_longer(cols = contains("_"),
names_to = c("Event_by", ".value"),
names_pattern = "^(.*)_([^_]+$)") %>%
separate_rows(c(intpl, dur), sep = ",", convert = TRUE) %>%
mutate(Time = cumsum(dur)) %>%
mutate(Utterance = paste0(sub(".*(.)$", "\\1",Speaker), ": ", Utterance),
Utterance = factor(Utterance, levels = unique(Utterance)))
Set chart objects into enviroment:
for (i in unique(df1$Event_by)){
for (j in levels(df1$Utterance)){
assign(x = paste0(i,j), value = ggplot(data = df1[df1$Event_by == i & df1$Utterance == j,], aes(x = Time, y = log2(intpl))) +
geom_line()+
geom_smooth(method = 'lm', color = "red", formula = y~x))
}
}
Create grided chart:
library(gridExtra) library(grid)
grid.arrange(
`AA: cool >what part?<`,
`AB: u:m Tennessee=` ,
`ANA: (0.228)` ,
`BA: cool >what part?<` ,
`BB: u:m Tennessee=` ,
`BNA: (0.228)` ,
`CA: cool >what part?<` ,
`CB: u:m Tennessee=` ,
`CNA: (0.228)` ,
nrow = 3)
Although i think there should be better solution for that.
You can also try to explore below articlesfor arranging plots:
http://www.sthda.com/english/articles/24-ggpubr-publication-ready-plots/81-ggplot2-easy-way-to-mix-multiple-graphs-on-the-same-page/
https://ggplot2-book.org/facet.html
Moreover, there's is no themming added to my solution

Create a multiline plot from a dataset with time on one axis and genes on the other

I have a dataset with mean gene counts for each decade as shown below:
structure(list(decade_0 = c(92.500989948184, 2788.27384875413,
28.6937227408861, 1988.03831525414, 1476.83143096418), decade_1 = c(83.4606306426572,
537.725421951383, 10.2747132062782, 235.380422949258, 685.043600629146
), decade_2 = c(188.414375201462, 2091.84249935145, 17.080858894829,
649.55107199935, 1805.3484565514), decade_3 = c(43.3316024314987,
141.64396529835, 2.77851259926935, 94.7748265692319, 413.248354335235
), decade_4 = c(54.4891626582901, 451.076574268175, 12.4298374245007,
346.102609621018, 769.215535857077), decade_5 = c(85.5621750431284,
131.822699578988, 13.3130607062134, 151.002200923853, 387.727911723968
), decade_6 = c(112.860998806804, 4844.59668489898, 19.7317645111144,
2084.76584309876, 766.375852567831), decade_7 = c(73.2198969730458,
566.042952305845, 3.2457873699886, 311.853982701609, 768.801733767044
), decade_8 = c(91.8161648275608, 115.161700090147, 10.7289451320065,
181.747670625714, 549.21661120626), decade_9 = c(123.31045087146,
648.23694540667, 17.7690326882018, 430.301803845829, 677.187054208271
)), row.names = c("ANK1", "NTN4", "PTPRH", "JAG1", "PLAT"), class = "data.frame")
I would like to plot a line graph with the changes in counts over time for each of >30 genes as shown here in excel.
To do this with ggplot I have to convert it to col1: decade, col2: gene, col3: counts.
My question is, either how to convert my table into this ggplot friendly table, or if there is a better way to produce the plot with a different tool?
Thanks!

One possibility: transpose your data frame, convert rownames to columns, then gather ("make long"). Plotting is then easy.
library(tidyverse)
mydat <- structure(list(decade_0 = c(92.500989948184, 2788.27384875413,
28.6937227408861, 1988.03831525414, 1476.83143096418), decade_1 = c(83.4606306426572,
537.725421951383, 10.2747132062782, 235.380422949258, 685.043600629146
), decade_2 = c(188.414375201462, 2091.84249935145, 17.080858894829,
649.55107199935, 1805.3484565514), decade_3 = c(43.3316024314987,
141.64396529835, 2.77851259926935, 94.7748265692319, 413.248354335235
), decade_4 = c(54.4891626582901, 451.076574268175, 12.4298374245007,
346.102609621018, 769.215535857077), decade_5 = c(85.5621750431284,
131.822699578988, 13.3130607062134, 151.002200923853, 387.727911723968
), decade_6 = c(112.860998806804, 4844.59668489898, 19.7317645111144,
2084.76584309876, 766.375852567831), decade_7 = c(73.2198969730458,
566.042952305845, 3.2457873699886, 311.853982701609, 768.801733767044
), decade_8 = c(91.8161648275608, 115.161700090147, 10.7289451320065,
181.747670625714, 549.21661120626), decade_9 = c(123.31045087146,
648.23694540667, 17.7690326882018, 430.301803845829, 677.187054208271
)), row.names = c("ANK1", "NTN4", "PTPRH", "JAG1", "PLAT"), class = "data.frame")
newdat <- mydat %>% t() %>% as.data.frame() %>% tibble::rownames_to_column('decade') %>%
pivot_longer(-decade, names_to = 'gene', values_to = 'count')
ggplot(newdat) + geom_line(aes(decade, count, color = gene, group = gene))
Created on 2020-02-14 by the reprex package (v0.3.0)

Comparing "Unlimited" value to numerical values in ggplot

I am trying to make a visual comparison between an input vector and my database.However, the input vector or the database may contain the "UL" character, which means, an infinite number. Think of it as your unlimited voice plan, with which you can make an unlimited number of calls.
Here is the code I have used to try to make a visual comparison between "UL" and other numerical values.
# d is the database data.frame, with which we want to compare the input vector
d = structure(list(Type = c("H1", "H2", "H3"),
P1 = c(2000L, 1500L, 1000L),
P2 = c(60L, 40L, 20L),
P3 = c("UL", 3000L, 2000L)),
class = "data.frame",
row.names = c(NA, -3L))
# d2 is the input vector
d2 = structure(list(Type = "New_offre", P1 = 1200L, P2 = "UL", P3 = 2000),
class = "data.frame",
row.names = c(NA, -1L))
#Check if there are some unlimited values in both d and d2
y1 <-rbind(d,d2)
y <- y1
if("UL" %in% y$P3){
max_P3_scale <- max(as.numeric(y[y$P3!="UL","P3"]))
y[y$P3=="UL","P3"]= 2*max_P3_scale
}
if("UL" %in% y$P2){
max_P2_scale <- max(as.numeric(y[y$P2!="UL","P2"]))
y[y$P2=="UL","P2"]= 2*max_P2_scale
}
y <- transform(y,P1=as.numeric(P1),
P2=as.numeric(P2),
P3=as.numeric(P3))
d <- y[1:nrow(d),]
d2<- y[nrow(d)+1,]
d %>% gather(var1, current, -Type) %>%
mutate(new = as.numeric(d2[cbind(rep(1, max(row_number())),
match(var1, names(d2)))]),
slope = factor(sign(current - new), -1:1)) %>%
gather(var2, val, -Type, -var1, -slope) %>%
ggplot(aes(x = factor(var2,levels = c("new","current")), y = val, group = 1)) +
geom_point(aes(fill = var2), shape = 2,size=4) +
geom_line(aes(colour = slope)) +
scale_colour_manual(values = c("green","green", "red")) +
facet_wrap(Type ~ var1,scales = "free")
My first attempt was to find if there is "UL" values in P2 and P3. If yes, I try to find the maximum numeric value other than "UL". Then, I replace all "UL" occurrences by this maximum value* 2, so the graphical representations will always show that "UL" is maximum.
The issue with this is that I am not able to differentiate between actual values and "UL" ones.
Here is how my plot looks like using this solution

Subset Data.Frame With Multiple Conditions

End Goal:
Create a plot for each region of StressCumulative, BaseCumulative, StressQoQ, and BaseQoQ over the date range from rows 1:167.
Problem:
I'm having difficulty subsetting my data.frame. My issue is that the condition by which I'm subsetting is logical, and thus will only return the first element after the condition.
subset_region_1 <- subset.data.frame(HPF, HPF$region == 1, select = BaseCumulative, HPF$StressCumulative, StressQoQ, BaseQoQ)
Warning messages:
1: In if (drop) warningc("drop ignored") :
the condition has length > 1 and only the first element will be used
2: drop ignored
This returns only the first column, BaseCumulative.
Data:
Here you get a glimpse of what I'm working with. This is the table I am looking to subset from. My data.frame is in a tall format
I would like to create a subset in order to graph BaseCumulative, StressCumulative, BaseQoQ, and StressQoQ variables over the range of dates from rows 1:167. The date column uses the same dates for all 100 regions. My issue is that when I go to plot in ggplot, I get an error that my aes mappings are not of the same size. The full table has date = 18370 rows long, but the values repeat every 167 rows (for each unique region). Further, the BaseCumulative variable is also 18370 rows long but is unique for all regions, i.e. every 167 rows. I want to know how I can subset by region while obtaining the correct row size for the variables I am interested in measuring.
Data Pts:
#Rows 1-3 (Region 1 Sample):
dput(head(HPF[1:3, ]))
structure(list(region = c(1, 1, 1), path = c(1, 1, 1), date = c(20140215,
20140515, 20140815), index_value = c(1, 1.033852765, 1.041697122
), index = 0:2, counter = 1:3, BaseQoQ = c(NA, 0.033852765, 0.00758749917354029
), BaseCumulative = c(100, 103.3852765, 104.1697122), StressCumulative = c(110,
113.3852765, 114.1697122), StressQoQ = c(NA, 0.0307752409090909,
0.00691832065162346)), .Names = c("region", "path", "date", "index_value",
"index", "counter", "BaseQoQ", "BaseCumulative", "StressCumulative",
"StressQoQ"), row.names = c(NA, -3L), class = c("tbl_df", "tbl",
"data.frame"))
#Rows 168:200 (Region 2 Sample):
dput(head(HPF[168:200, ]))
structure(list(region = c(2, 2, 2, 2, 2, 2), path = c(1, 1, 1,
1, 1, 1), date = c(20140215, 20140515, 20140815, 20141115, 20150215,
20150515), index_value = c(1, 1.014162265, 1.01964828, 1.009372314,
1.007210703, 1.018695493), index = 0:5, counter = 1:6, BaseQoQ = c(NA,
0.014162265, 0.00540940556489744, -0.0100779515854232, -0.0021415398163972,
0.0114025694582001), BaseCumulative = c(100, 101.4162265, 101.964828,
100.9372314, 100.7210703, 101.8695493), StressCumulative = c(110,
111.4162265, 111.964828, 110.9372314, 110.7210703, 101.8695493
), StressQoQ = c(NA, 0.0128747863636363, 0.00492389230216839,
-0.00917785181610786, -0.00194849914020834, -0.0799443229370588
)), .Names = c("region", "path", "date", "index_value", "index",
"counter", "BaseQoQ", "BaseCumulative", "StressCumulative", "StressQoQ"
), row.names = c(NA, -6L), class = c("tbl_df", "tbl", "data.frame"
))
Question:
How do I subset other columns in addition to specifying region == #? I have tried the following but then the issue is that values recycle for the dates and my charts are incorrect:
ggplot(HPF, aes(x = date, y= BaseCumulative, linetype = factor(region == 1))) +
geom_line() +
theme_light()
Further, I am also unsuccessful if I try to subset within the ggplot such as:
ggplot(HPF[HPF$region == 1, ], aes(x = HPF$date[1:167, ], y= HPF$BaseCumulative[1:167, ], linetype = factor(region == 1))) +
geom_line() +
theme_light()
Any help is appreciated.

I'm not entirely sure what you're trying to show in your plot; is this what you're after?
library(tidyverse);
df %>%
gather(what, value, 7:10) %>%
ggplot(aes(date, value, colour = what)) + geom_line() + theme_light()
Explanation: Convert your data from wide to long format, then pass what as a colour (or linetype) aesthetic to get different line plots for columns 7, 8, 9, 10 in one plot.
If you want separate plots for region, you could add + facet_wrap(~ as.factor(region)), e.g.
df %>%
gather(what, value, 7:10) %>%
ggplot(aes(date, value, colour = what)) + geom_line() + theme_light() + facet_wrap(~ as.factor(region))
Sample data
df1 <- structure(list(region = c(1, 1, 1), path = c(1, 1, 1), date = c(20140215,
20140515, 20140815), index_value = c(1, 1.033852765, 1.041697122
), index = 0:2, counter = 1:3, BaseQoQ = c(NA, 0.033852765, 0.00758749917354029
), BaseCumulative = c(100, 103.3852765, 104.1697122), StressCumulative = c(110,
113.3852765, 114.1697122), StressQoQ = c(NA, 0.0307752409090909,
0.00691832065162346)), .Names = c("region", "path", "date", "index_value",
"index", "counter", "BaseQoQ", "BaseCumulative", "StressCumulative",
"StressQoQ"), row.names = c(NA, -3L), class = c("tbl_df", "tbl",
"data.frame"));
df2 <- structure(list(region = c(2, 2, 2, 2, 2, 2), path = c(1, 1, 1,
1, 1, 1), date = c(20140215, 20140515, 20140815, 20141115, 20150215,
20150515), index_value = c(1, 1.014162265, 1.01964828, 1.009372314,
1.007210703, 1.018695493), index = 0:5, counter = 1:6, BaseQoQ = c(NA,
0.014162265, 0.00540940556489744, -0.0100779515854232, -0.0021415398163972,
0.0114025694582001), BaseCumulative = c(100, 101.4162265, 101.964828,
100.9372314, 100.7210703, 101.8695493), StressCumulative = c(110,
111.4162265, 111.964828, 110.9372314, 110.7210703, 101.8695493
), StressQoQ = c(NA, 0.0128747863636363, 0.00492389230216839,
-0.00917785181610786, -0.00194849914020834, -0.0799443229370588
)), .Names = c("region", "path", "date", "index_value", "index",
"counter", "BaseQoQ", "BaseCumulative", "StressCumulative", "StressQoQ"
), row.names = c(NA, -6L), class = c("tbl_df", "tbl", "data.frame"
))
df <- rbind.data.frame(df1, df2);

How to plot multiple curves and color them as group using R ggplot

I have a data frame like this.
ID read1 read2 read3 read4 class
1 5820350 0.3791915 0.3747022 0.3729779 0.3724259 1
2 5820364 0.3758676 0.3711775 0.3695976 0.3693112 2
3 5820378 0.3885081 0.3823900 0.3804273 0.3797707 2
4 5820392 0.3779945 0.3729582 0.3714910 0.3709072 1
5 5820425 0.2954782 0.2971604 0.2973882 0.2973216 3
6 5820426 0.3376101 0.3368173 0.3360203 0.3359517 3
Each row represents one sample with four values,and the last column is the classification of this sample. I want to visualize each sample curve and set the class as the color.
I tried to reshape the data frame, but I then lost the class feature which I need.
Could you please give me some hint or show me how to do that in R?
Thanks in advance.

You are going to want to tidy your data first (shown below with tidyr::gather). Then, when you plot, you will want to set your group = ID and color = factor(class) (for discrete colors):
library(tidyr)
library(ggplot2)
df <- structure(list(ID = c(5820350L, 5820364L, 5820378L, 5820392L, 5820425L, 5820426L),
read1 = c(0.3791915, 0.3758676, 0.3885081, 0.3779945, 0.2954782, 0.3376101),
read2 = c(0.3747022, 0.3711775, 0.38239, 0.3729582, 0.2971604, 0.3368173),
read3 = c(0.3729779, 0.3695976, 0.3804273, 0.371491, 0.2973882, 0.3360203),
read4 = c(0.3724259, 0.3693112, 0.3797707, 0.3709072, 0.2973216, 0.3359517),
class = c(1L, 2L, 2L, 1L, 3L, 3L)),
.Names = c("ID", "read1", "read2", "read3", "read4", "class"),
class = "data.frame", row.names = c("1", "2", "3", "4", "5", "6"))
df <- gather(df, reading, value, -c(ID, class))
ggplot(df, aes(x = reading, y = value, color = factor(class))) +
geom_line(aes(group = ID))

Here's a function that may do what you want:
PlotMultiCurve = function(x, classes, cols = NULL, colSet = "Set1", ...) {
if(!is.factor(classes)) classes = as.factor(classes)
nClasses = length(levels(classes))
if(is.null(cols)) cols = brewer.pal(nClasses, colSet)
plot(1:ncol(x), x[1,], col = cols[classes[1]], type = "l",
ylim = range(x), xaxt = "n", ...)
axis(1, 1:ncol(x), 1:ncol(x))
for(i in 2:nrow(x)) {
par(new = T)
plot(1:ncol(x), x[i,], col = cols[classes[i]], type = "l",
ylim = range(x), axes = F, xlab = "", ylab = "")
}
}
It uses chooses colors automatically from the RColorBrewer package unless you provide the colors. I copied your data directly into a text file and then ran the following:
# Prepare data
require(RColorBrewer)
myData = read.table("Data.2016-05-03.txt")
x = myData[,2:5]
classes = as.factor(myData$class)
# Plot into PNG file[![enter image description here][1]][1]
png("Plot.2016-05-03.png", width = 1000, height = 1000, res = 300)
par(cex = 0.8)
PlotMultiCurve(x = x, classes = classes, xlab = "Read", ylab = "Response")
dev.off()

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