SASS loop to generate chained :not() from variables string - css

Question

I have a long list of classes I wish to use in a couple of ways.
The list looks something like this (but much longer):
$my-components: '.some-component', '.some-other-component', '.another-component';
One of the ways I need to use this list of class names in SASS (scss), which I can't figure out, is to create a long chained selector of :not()s. The final rendered output should look like this:
.parent {
> * {
&:last-of-type:not(.some-component):not(.some-other-component):not(.another-component):not(etc) {
// style rules
}
}
}
(The goal being to select the last child element of .parent that doesn't have one of the classes in the list).
Question: How can I make the above code DRY by using the $my-components variable?
Note 1: The loop's output needs to be able to be appended to that &:last-of-type, as in above example.
Note 2: I'm using the $my-components variable already in a different function, so I'd like to keep it in the same format if possible.
Note 3: I know this seems hacky and stupid, and that I should just give all of those elements a common shared class instead. But unfortunately I can not currently modify that part of the DOM.

Answer 1

Use a #each loop
scss:
$my-components: '.some-component', '.some-other-component', '.another-component';
.parent {
> * {
$selector: '';
#each $component in $my-components {
$selector: $selector + ":not(#{$component})"
}
&:last-of-type#{$selector} {
color: blue;
}
}
}
css:
.parent > *:last-of-type:not(.some-component):not(.some-other-component):not(.another-component) {
color: blue;
}
What's happening ?
I define a new string variable $selector.
During the #each loop, I'm concatening the string with :not(#{$component}) to add your new selector.