I am trying to do something like the picture below. I would like a div with 3 borders, but the outer 2 borders are truncated in the way displayed in the picture. I am wondering if it is possible to get this effect with a pure CSS solution:
Here is a one element easy solution:
.box {
width:200px;
height:150px;
margin:80px;
border:10px solid red;
position:relative;
}
.box:before,
.box:after {
content:"";
position:absolute;
inset:-30px;
border:10px solid #0000;
border-image:linear-gradient(-45deg,blue 20%,#0000 0 80%,blue 0) 10;
}
.box:after {
inset:-50px;
border-image:linear-gradient(-45deg,green 20%,#0000 0 80%,green 0) 10;
}
<div class="box"></div>
Not sure if it is the simplest solution, but looks like I was able to do it with a background linear-gradient. Border colors help show the different components of the linear-gradient. Example here: https://jsfiddle.net/pn6a8rqj/171/
*{
--bw:15px;
}
.corners>div{
position:absolute;
}
.corners>div:nth-child(1),.corners>div:nth-child(2) {
position:absolute;
background:
/*top left*/
linear-gradient(to right, red var(--bw), transparent 0px) 0 0,
linear-gradient(135deg, blue calc(.7071*var(--bw)), transparent 0px) 0 var(--ch),
linear-gradient(to bottom, green var(--bw), transparent 0) 0 0,
linear-gradient(135deg, orange calc(.7071*var(--bw)), transparent 0px) var(--cw) 0,
/*bottom right*/
linear-gradient(to left, red var(--bw), transparent 0) 100% 100%,
linear-gradient(315deg, blue calc(.7071*var(--bw)), transparent 0px) 100% calc(100% - var(--ch)),
linear-gradient(to top, green var(--bw), transparent 0) 100% 100%,
linear-gradient(315deg, orange calc(.7071*var(--bw)), transparent 0px) calc(100% - var(--cw)) 100%;
background-repeat: no-repeat;
background-size: var(--cw) var(--ch);
}
.corners>div:nth-child(1){
top:0;
left:0;
--ch:var(--corner1Height);
--cw:var(--corner1Width);
width: calc(var(--width) + 8*var(--bw));
height: calc(var(--height) + 8*var(--bw));
}
.corners>div:nth-child(2){
top:calc(2*var(--bw));
left:calc(2*var(--bw));
--ch:var(--corner2Height);
--cw:var(--corner2Width);
width: calc(var(--width) + 4*var(--bw));
height: calc(var(--height) + 4*var(--bw));
}
.corners>div:nth-child(3){
box-sizing:border-box;
top:calc(4*var(--bw));
left:calc(4*var(--bw));
border: var(--bw) solid black;
width: var(--width);
height: var(--height);
}
#div1 {
--corner1Height:50px;
--corner1Width:100px;
--corner2Height:100px;
--corner2Width:200px;
--width:500px;
--height:300px;
width: var(--width);
height: var(--height);
}
Related
I am trying to take a screenshot of a page that has images overlayed by linear-gradient with the help of html2canvas. The height of the image varies but the width is fixed to 210px so, i need to use calc to calculate the positons of the gradient, which is not rendering in the way it looks on the screen.
Example with static values: https://jsfiddle.net/vpj3bz7s/1/
.linearGradient {
height: 200px;
width: 210px;
background-image: linear-gradient(to top left,
yellow 0%,
yellow 80px,
red 80px,
red 110px,
yellow 110px,
yellow 100%);
}
html2canvas(document.body).then(function(canvas) {
document.body.appendChild(canvas);
}
);
<div class="linearGradient"></div>
Example with calc values: https://jsfiddle.net/dk309pf6/2/
.linearGradient {
height: 200px;
width: 210px;
background-image: linear-gradient(to top left,
yellow 0%,
yellow calc(50% - 10px),
red calc(50% - 10px),
red calc(50% + 10px),
yellow calc(50% + 10px),
yellow 100%);
}
html2canvas(document.body).then(function(canvas) {
document.body.appendChild(canvas);
}
);
<div class="linearGradient"></div>
Edit:
Actual image overlayed on gradient looks like this:
The way it looks like in a screenshot is this:
The JS fiddle with my actual code is as follows (But the screenshot is a little different from my original one)
https://jsfiddle.net/nrfjh8m3/1/
Here is a different idea to obtain the same gradient. There is a ton of ways but the below is the only one that worked with html2canvas:
body {
margin: 0px;
}
.linearGradient {
height: 200px;
width: 210px;
background-color:red;
overflow:hidden;
position:relative;
}
.linearGradient::before,
.linearGradient::after {
content:"";
position:absolute;
top:0;
left:0;
bottom:0;
right:0;
background-repeat:no-repeat;
}
.linearGradient::before {
background:linear-gradient(to bottom right,yellow 49%, transparent 50%);
bottom:10px;
right:10px;
}
.linearGradient::after {
background:linear-gradient(to top left,yellow 49%, transparent 50%);
top:10px;
left:10px;
}
<div class="linearGradient"></div>
Working code with html2canvas:
https://jsfiddle.net/k79ybnup/1/
I am working on a custom shape and am pretty sure I can achieve it using the radial-gradient CSS function. Until now, I have been able to make half of the work, which looks like this :
... using this CSS code :
.block {
width: 600px;
height: 200px;
position: relative;
margin: 50px auto;
z-index: 1000;
background-image: -moz-radial-gradient(
-23px 50%, /* the -23px left position varies by your "gap" */
circle closest-corner, /* keep radius to half height */
transparent 0, /* transparent at center */
transparent 55px, /*transparent at edge of gap */
transparent 56px, /* start circle "border" */
white 57px /* end circle border and begin color of rest of background */
);
background-image: -webkit-radial-gradient(-23px 50%, circle closest-side, rgba(0, 0, 0, 0) 0, rgba(0, 0, 0, 0) 55px, transparent 56px, white 57px);
background-image: -ms-radial-gradient(-23px 50%, circle closest-corner, rgba(0, 0, 0, 0) 0, rgba(0, 0, 0, 0) 55px, transparent 56px, white 57px);
background-image: -o-radial-gradient(-23px 50%, circle closest-corner, rgba(0, 0, 0, 0) 0, rgba(0, 0, 0, 0) 55px, transparent 56px, white 57px);
background-image: radial-gradient(-23px 50%, circle closest-corner, rgba(0, 0, 0, 0) 0, rgba(0, 0, 0, 0) 55px, transparent 56px, white 57px);
}
Now, I'd like to make the same circle shape on the right corner (symmetrical to the circle shape of the left corner). I have tried separating my radial-gradient functions with commas but can't find a way to make it symmetrical to the other one... Can you help?
Thanks!
You can do it like below. 2 backgrounds layer, each one taking half the width (a little bigger than the half to avoid having gap issue)
.box {
width:400px;
height:200px;
margin:20px auto;
background:
radial-gradient(circle at left, transparent 50px,white 51px) left,
radial-gradient(circle at right,transparent 50px,white 51px) right;
background-size:51% 100%;
background-repeat:no-repeat;
}
body {
background:blue;
}
<div class="box">
</div>
Like below if you want to control the origin of the circle:
.box {
width:400px;
height:200px;
margin:20px auto;
background:
radial-gradient(circle at -23px 50%,transparent 50px,white 51px) left,
radial-gradient(circle at calc(100% + 23px) 50%,transparent 50px,white 51px) right;
background-size:51% 100%;
background-repeat:no-repeat;
}
body {
background:blue;
}
<div class="box">
</div>
And with CSS variables for better control and avoid repeating the same code:
.box {
--rad:transparent 50px,white 51px; /* Gradient*/
/* Position */
--x:-23px;
--y:50%;
/**/
width:400px;
height:200px;
margin:20px auto;
background:
radial-gradient(circle at var(--x) var(--y),var(--rad)) left,
radial-gradient(circle at calc(100% - var(--x)) var(--y),var(--rad)) right;
background-size:51% 100%;
background-repeat:no-repeat;
}
body {
background:blue;
}
<div class="box">
</div>
Another syntax without the at for better browser support (safari doesn't support it)
.box {
--rad:transparent 50px,white 51px; /* Gradient*/
/* Position */
--x:-23px;
--y:50%;
/**/
width:400px;
height:200px;
margin:20px auto;
background:
radial-gradient(circle,var(--rad)) left calc(150% + var(--x)) top var(--y),
radial-gradient(circle,var(--rad)) right calc(150% + var(--x)) top var(--y);
background-size:150% 200%;
background-repeat:no-repeat;
}
body {
background:blue;
}
<div class="box">
</div>
Another idea with pseudo element and scale where you need only one gradient:
.box {
width:400px;
height:200px;
margin:20px auto;
position:relative;
}
.box::before,
.box::after{
content:"";
position:absolute;
top:0;
left:0;
bottom:0;
width:50%;
background:radial-gradient(circle at -23px 50%,transparent 50px,white 51px);
}
.box::after {
transform:scaleX(-1);
transform-origin:right;
}
body {
background:blue;
}
<div class="box">
</div>
Happy new year!
Im trying to substitute this background picture with a css for scaling purposes.
Im having a problem with gradients logic.
the div properties:
.bg {
border: 1px solid white;
border-radius:10px;
padding:10px;
width:100%;
}
then im trying to color it
the background color is #065BDB
the 'bubble reflection' color is a gradient from rgba(87,144,231,1) to rgba(87,144,231,0) - same color with fading opacity.
to make the right shape of the 'bubble' i need to draw circle-square-circle with gradients, the circles draw ok, but the rectangle is problemetic
background:
radial-gradient(2em 2em at 3% 25%, rgba(87,144,231,1) 50%, transparent 50%),
linear-gradient(to bottom, transparent 3%, rgba(87,144,231,1) , transparent 97%),
radial-gradient(2em 2em at 97% 25%, rgba(87,144,231,1) 50%, transparent 50%);
im having multiple issues with this, cannot figure out how to draw a square from top to bottom with a margin on left and right, and how to add transparency from top to bottom to it, + adding a seconds background, maybe its better to make 2 divs instead of 1.
You can rely on a pseudo element and easily obtain the result:
.bg {
border: 1px solid white;
border-radius: 50px;
height:60px;
background: #065BDB;
position:relative;
z-index:0;
}
.bg::before {
content:"";
position:absolute;
z-index:-1;
top:5px;
left:15px;
right:15px;
height:30px;
border-radius:inherit;
background:linear-gradient(to bottom, rgba(87,144,231,1), rgba(87,144,231,0));
}
<div class="bg">
</div>
With multiple background you can try this:
.bg {
border: 1px solid white;
border-radius: 50px;
height:60px;
background:
radial-gradient(30px 30px at right,transparent 50%, #065BDB 52%) 0% 10px/35px 30px,
radial-gradient(30px 30px at left,transparent 50%, #065BDB 52%) 100% 10px/35px 30px,
linear-gradient(to bottom, rgba(87,144,231,1), rgba(87,144,231,0)) 0 10px/100% 30px,
#065BDB;
background-repeat:no-repeat;
box-sizing:border-box;
}
<div class="bg"></div>
We can add some CSS variable to control the shape:
.bg {
--h:30px; /*the height of the bubble*/
--d:35px; /*the distance from the sides*/
--t:10px; /*the distance from the top*/
margin:5px;
border-radius: 50px;
height:60px;
background:
radial-gradient(var(--h) var(--h) at right,transparent 50%, #065BDB 52%) 0% var(--t)/var(--d) var(--h),
radial-gradient(var(--h) var(--h) at left,transparent 50%, #065BDB 52%) 100% var(--t)/var(--d) var(--h),
linear-gradient(to bottom, rgba(87,144,231,1), rgba(87,144,231,0)) 0 var(--t)/100% var(--h),
#065BDB;
background-repeat:no-repeat;
box-sizing:border-box;
}
<div class="bg"></div>
<div class="bg" style="--h:20px;--d:50px;--t:20px"></div>
<div class="bg" style="--h:40px;--d:100px;--t:5px"></div>
try with ::before
.bg {
width:100%;
height:50px;
position:relative;
background:royalblue;
border-radius:20px;
}
.bg::before {
content:'';
width:97%;
height:25px;
background:linear-gradient(rgba(255,255,255,.15),rgba(255,255,255,.07));
position:absolute;
top:7px;
left:50%;
transform:translateX(-50%);
border-radius:20px;
}
<div class="bg"></div>
I thought about creating a background with arrows. Something that looks like in this codepen: http://codepen.io/DaSch/pen/rrWAmy
.top {
height: 5em;
background:
repeating-linear-gradient(
45deg,
lightgray,
lightgray 25%,
gray 0,
gray 50%
);
background-size: 5em 5em;
}
.bottom {
height: 5em;
background:
repeating-linear-gradient(
135deg,
lightgray,
lightgray 25%,
gray 0,
gray 50%
);
background-size: 5em 5em;
}
In the given example there are two elements but together to make it look like I want it to. If I but the gradients together I just get strips. I tried a lot but I can't figure out how to create arrows. with multiple gradients an background-blend-mode.
I'm not sure if this is possible. But I'm looking for a solution without external background-images. If it's not possible a good explanation why would be great.
Here is what I have. It looks like an arrow, and can be repeated using JavaScript. I can't do this with pure CSS. Maybe this solution gives you an idea for your code.
.top {
height: 5em;
width:80px;
margin-left:120px;
background:
repeating-linear-gradient(
45deg,
white,
white 25%,
gray 0,
gray 50%
);
background-size: 5em 5em;
}
.bottom {
height: 5em;
width:80px;
margin-left:120px;
background:
repeating-linear-gradient(
135deg,
white,
white 25%,
gray 0,
gray 50%
);
background-size: 5em 5em;
}
.middle
{
background-color:gray;
height:30px;
width:200px;
margin-right:10px;
}
.maskCornerTop
{
width:40px;
height:40px;
position:relative;
background-color:white;
float:right;
}
.maskCornerBottom
{
width:40px;
height:40px;
background-color:white;
float:right;
margin-top:40px;
position:relative;
}
<div class="top"><div class="maskCornerTop"></div></div>
<div class="middle"></div>
<div class="bottom"><div class="maskCornerBottom"></div></div>
<br/>
<div class="combo"></div>
After some research I found, that the solution is to overlay different backgrounds and use only the half hight for the upper one.
It'll look like this
.combo {
height: 10em;
background:
repeating-linear-gradient(
45deg,
lightgray,
lightgray 33.33%,
gray 33.33%,
gray 66.66%
),
repeating-linear-gradient(
135deg,
gray,
gray 25%,
lightgray 25%,
lightgray 50%
);
background-size: 10em 50%, 10em 100%;
background-repeat: repeat-x, repeat-x;
}
Still this maybe isn't the best solution as it only works if the height of the container is known and fixed.
I want a design like this:
So in fact a left side with background-color, a right side with background-color (divs of course, easy).
But can I do a diagonal line with CSS?
You can achieve this shape with a skewed pseudo element :
DEMO
HTML :
<div>
<h1>Your title here</h1>
</div>
CSS :
div{
padding:0 10px 10px;
background:#E7E5DD;
}
h1{
margin:0;
display:inline-block;
position:relative;
z-index:1;
padding:10px 50px 10px;
overflow:hidden;
}
h1:before{
content:'';
width:100%; height:100%;
position:absolute;
top:0; left:0;
background:#fff;
z-index:-1;
-webkit-transform: skewX(-20deg);
-ms-transform: skewX(-20deg);
transform: skewX(-20deg);
-webkit-transform-origin:0 0;
-ms-transform-origin:0 0;
transform-origin:0 0;
}
If you want to have with with pure CSS - see
http://css-tricks.com/snippets/css/css-triangle/ and
http://apps.eky.hk/css-triangle-generator/
(You would need a white top-left triangle on the gray area)
width: 0;
height: 0;
border-style: solid;
border-width: 200px 200px 0 0;
border-color: #fff transparent transparent transparent;
Please note that some browsers will not use anti-aliasing when drawing the borders.
A simpler approach in this case would be to have images for background - one for the text with the diagonal line, another one for the grey area.
http://jsfiddle.net/nuxcbqqq/1/
<div class="crossed"></div>
.crossed {
width: 100px;
height: 100px;
background:
linear-gradient(to top left,
rgba(0,0,0,0) 0%,
rgba(0,0,0,0) calc(50% - 0.8px),
rgba(0,0,0,1) 50%,
rgba(0,0,0,0) calc(50% + 0.8px),
rgba(0,0,0,0) 100%),
linear-gradient(to top right,
rgba(0,0,0,0) 0%,
rgba(0,0,0,0) calc(50% - 0.8px),
rgba(0,0,0,1) 50%,
rgba(0,0,0,0) calc(50% + 0.8px),
rgba(0,0,0,0) 100%);
}
Code from here draw diagonal lines in div background with CSS