How to change this pass by reference into pointer as function parameter - pointers

Question

wanting to ask how to change this pass by reference into pass by pointer, cause some of my school works need pass by pointer and i doesn't really understand how to modified this code using pass by pointer
void convert(string &s){
for (int i =0; i<s.length(); i++){
s[i] = toupper(s[i]);
}
}
int main(){
string name;
cout<<"Enter your name"<<endl;
getline(cin,name);
convert(name);
cout<<name<<endl;
return 0;
}

Answer 1

First of all, there are some minor errors in the code.
Inlcude necessary headers.
Use std:: namespace prefix.
#include <iostream>
#include <string>
#include <cctype>
void convert(std::string &s){
for (int i =0; i < s.length(); i++){
s[i] = std::toupper(s[i]);
}
}
int main(){
std::string name;
std::cout << "Enter your name: ";
std::getline(std::cin, name);
convert(name);
std::cout << name << std::endl;
return 0;
}
Using pointer version?
#include <iostream>
#include <cstdio>
#include <cstring>
#include <cctype>
#define SIZE 100
void convert(char *s, size_t size){
for (int i =0; i < size; i++){
s[i] = std::toupper(s[i]);
}
}
int main(){
char name[SIZE];
std::cout << "Enter your name: ";
std::fgets(name, SIZE, stdin);
convert(name, strlen(name));
std::cout << name << std::endl;
return 0;
}
Another version using pointers
#include <iostream>
#include <string>
#include <cctype>
void convert(std::string *s){
for (int i =0; i < s -> length(); i++){
(*s)[i] = std::toupper((*s)[i]);
}
}
int main(){
std::string *name = new std::string();
std::cout << "Enter your name: ";
std::getline(std::cin, *name);
convert(name);
std::cout << *name << std::endl;
delete name;
return 0;
}