Is there any way to visualise the solution uh in this code
https://gridap.github.io/Tutorials/dev/pages/t001_poisson/ 3
other than writinfg it as vtk file.
plot is not working.
Related
I am new to Octave and was practising trying to represent the function y=e^(-t) as a Fourier series. When I use a series of three terms I get this plot
Plot with 3 terms
However, when I start adding more terms, the plot shows discountinuities.
Plot with 5 terms
Any ideas? Thanks
clear all
t0=0;T=3;w=2*pi/T;
syms t
x=exp(-t);
ezplot(x,[t0 t0+T])
title('')
hold
for k=-2:2
a(k+3)=(1/T)*int(x*exp(-j*k*w*t),t,t0,t0+T);
ex(k+3)=exp(j*k*w*t);
end
xx=sum(a.*ex);
ezplot(xx,[t0 t0+T])
title('')
axis([0 3 0 1.3])
I have the following GPS Trajectory Data (fraction of the whole dataset):
# safegraph_id latitude longitude horizontal_accuracy id_type utc_timestamp geo_hash
# ef3a28742059bdcd65aad91ab77ffc180956b13336e93c2b75a1c6dbc56db0e1 18.458185 -66.731697 8 idfa 1506268248 de2912pqw
# 72860c415b90a7788dcfd0de748181b37f6878ba09c50ab36ddf142c82febf3d 18.412485 -66.119324 120.5433266 idfa 1505389477 de2bxrvkk
# 431e6e49111f1f7a49b9cda05f1b016f6e006b2b4c4f5b1d45a33cd65a0a4abe 18.314985 -66.091981 6 idfa 1504664544 de300n1k9
# 431e6e49111f1f7a49b9cda05f1b016f6e006b2b4c4f5b1d45a33cd65a0a4abe 18.414039 -66.103403 6 idfa 1505101204 de2bzb0vx
I'm new with R and I would like to plot a flow map so I can see the movement of the population. I have looked through some examples but is a little difficult to understand since the data used is different. Can somebody help me with this? I need to know what do I need from dataset to make the plot. Thank you.
I have been searching for this quite a while, but cannot find an answer to my problem or a minimum example. I would like to make a 3D-plot of a matrix.
An extract of my data looks like this. There are the years, which I would like to use as X-Axis. There is Y, which I would like to use as Y and I would like to plot z.
Year y z
2000 1 467
2000 2 10678
2000 2 25
...
How can I make this a surface plot?
Best
Have you tried searching for how to plot a surface plot in R? It turns out there's at least a persp function, a package called plot3D, wireframe in lattice and plotly.
For starters, try (from the plot3D package vignette)
library(plot3D)
example(persp3D)
example(surf3D)
example(slice3D)
example(scatter3D)
example(segments3D)
example(image2D)
example(image3D)
example(contour3D)
example(colkey)
example(jet.col)
example(perspbox)
example(mesh)
example(trans3D)
example(plot.plist)
example(ImageOcean)
example(Oxsat)
In R package,
is there any way to smoothen the polygon in a polar.plot?
I tried to use the splines, but could not find a way to insert the curved line in the polar.plot..
(I am a begginer in R programming)
I know that mathematically with polar plotting you can get smoothed polygons. An example here is for the square if you plot: 1 + Sin[4*x]/20 from 0 to 2 $\pi$ you will get a smoothed square. Change 4 to 5 and adjust the other constants by interpolation and you may find yourself happy.
I have plotted a graph in R. What should I do if I want the coordinates of the point of mouse click on the graph?
I searched a bit for this and understand that 'identify' function is being used for this but I didn't quite understand how to use it. Please give a detailed answer, this is my first time using R
script I used for plotting the graph:
data <- read.csv('C:\\project\\data.csv', header=T)
plot(data$time, data$param1, ylim=c(-1,1))
points(data$time, data$param2, col='red')
points(data$time, data$param3, col='green')
points(data$time, data$param4, col='blue')
the data is like:
time,param1,param2,param3,param4
1,-0.000963631,0.00340714,8.39E-05,0.999994
2,0.0841218,0.990477,0.0119087,0.108337
3,0.077221,0.995096,0.027441,0.0553834
4,0.0669772,0.996577,0.0441491,-0.0199725
5,0.0523895,0.989463,0.0645968,-0.118515
and the graph looks like:
The reason I'm doing this is to identify the cycles in this time series data and mark them as cycle1, cycle2..cyclen in the data file.