gnu make: No rule to make target '%.c' - gnu-make

I need to use pattern rules for gnu make, but I always encounter the same error:
make: *** No rule to make target '%.c', needed by 'test'. Stop.
This is my Makefile:
all: test
test : %.c
gcc -o $# $?
The Makefile is to build an execution file from the .c files in current directory, the third line begins with a 'tab' character. I did make by:
make all
The current directory contains two c files inside:
-rw-rw-r-- 1 user user 43 Nov 27 11:18 test2.c
-rw-rw-r-- 1 user user 109 Nov 27 11:01 test.c
it always responds with the same %.c error.
I have tried:
Assign filenames in Makefile explicitly instead of %.c, replace the %.c with 'test.c test2.c', it works fine.
Create a file %.c in the current directory, and also works fine, because make can find the file of '%.c'.
My make version is:
$make --version
GNU Make 4.2.1
Built for x86_64-pc-linux-gnu
Copyright (C) 1988-2016 Free Software Foundation, Inc.
License GPLv3+: GNU GPL version 3 or later <http://gnu.org/licenses/gpl.html>
This is free software: you are free to change and redistribute it.
There is NO WARRANTY, to the extent permitted by law.
I don't know why the pattern rule function not working.
Any pointers would be appreciated.

A pattern rule is a template that tells make, if you want to build a target that matches this target pattern, and you can either find or build a prerequisite that matches the prerequisite pattern(s), then here's a recipe on how to do it.
A pattern rule is not a definition that says "go look for all files that match this pattern and use this rule for them".
If you want a list of source files then you can either list them by hand in your makefile, or use $(wildcard ...) to find them.

Related

Disable parallel execution in make

I have a building process that creates a header file. In the second stage, several source files are generated from that header file. Then these source files are built into a binary. If anyone is interested these sources are generated with gSOAP utilities (wsdl2h, soapcpp2).
I have made Makefile.am, etc to build these sources, but there are problems when I want to use parallel execution.
Makefile.am would look something like this in a very simplified form
## generate header file
service.h : service.wsdl
wsdl2h -o $# service.wsdl
## list of generated source files
generated_files = source1.cpp source2.cpp source3.cpp
## generate source files
$(generated_files) : service.h
soapcpp2 $^
## build binary
binary: $(generated_files)
gcc -o $# $^
The rules say that service.h will be generated if service.wsdl changes. If service.h changes, soapcpp2 will generate source?.cpp files with one command execution.
Everything works fine until I try to build in parallel (for instance make -j4). The problematic line is the last one which generates many soruce files. If running in parrallel all these files are generated many times, while other make processes already try to compile them.
I followed instructions to disable parallel https://www.gnu.org/software/make/manual/html_node/Parallel-Disable.html, but with no success. If I try
.NOTPARALLEL: $(generated_files)
or
.NOTPARALLEL: service.h
The parallel execution just does not work any more. I also tried with .WAIT, and got no rule to make target .WAIT.
First, the .WAIT special target was introduced in GNU make 4.4. Since you are getting a no rule to make target error for it, it's clear you're using an older version which doesn't support it. It's usually a good idea to include the version of whatever tool you're using when asking for help.
The best thing to do is not disable parallelism but instead tell make that a single invocation of the recipe will generate all the files. If you have GNU make 4.3, then you can use a "grouped target" rule, like this:
## generate source files
$(generated_files) &: service.h
soapcpp2 $^
the &: here tells make that instead of building each target with a different invocation of the recipe, which is the default, a single invocation of the recipe builds all the targets.
If you don't have GNU make 4.3 then you'll need to play a trick to get the same behavior, something like this:
## generate source files
.sentinel : service.h
soapcpp2 $^
#touch $#
$(generated_files) : .sentinel ;
## build binary
binary: $(generated_files)
gcc -o $# $^
This has all the generated files depend on a single file .sentinel (you can name it whatever you want), which is the one make knows is generated by the recipe that also creates all the other source files. This isn't perfect but it will work for simple situations.

GNU Make: Automatically Prerequisites can't work if rename header files

A common Makefile for automatically prereq, looks like:
SRCS := $(wildcard *.c)
OBJS := $(SRCS:%.c=%.o)
DEPS := $(OBJS:%.o=%.d)
$(OBJS): %.o: %.c
$(CC) $(CFLAGS) -c -o $# $<
include $(DEPS)
$(DEPS): %.d: %.c
xxx
the first time, build ok, the generated .d file like this:
config.o config.d: config.c config.h
then I rename config.h to config2.h, and modify config.c:
-#include "config.h"
+#include "config2.h"
make again, Makefile generate error:
make[1]: *** No rule to make target 'config.h', needed by 'config.d'
because config.d depends config.h, How can I modify my Makefile to fix this rename problem.
Pretty simple really. Your .d file needs this additional line:
config.h:
Now when make discovers config.h doesn't exist,
it will run the non-existent recipe and happily believe it has created config.h. Then it carries on.
The manual says:
If a rule has no prerequisites or recipe, and the target of the rule is a nonexistent file, then make imagines this target to have been updated whenever its rule is run.
How to we get this extra line?
Back in the day you would run a perl one-liner over the newly created .d file. Nowadays, for modern gcc variants, just add -MP to the compiler command-line.
-MP This option instructs CPP to add a phony target for each dependency other than the main file, causing each to depend on nothing. These dummy rules work around errors make gives if you remove header files without updating the Makefile to match.
Job's a good 'un.

How to load a module inside an OCaml file?

I wish to use module Std inside my OCaml .ml file.
I tried #load "Std", but the compiler complains.
How can I load a module inside OCaml?
You must compile the module you wish to include first, provide the location of the compiled files to compilation commands of modules depending on it, then provide it in the final compilation command line.
Let's consider for instance file foo/moduleA.ml:
let v = 1
and file bar/moduleB.ml:
open ModuleA
let w = v
The commands:
$ cd foo
$ ocamlc -c moduleA.ml
$ cd ..
will produce moduleA.cmo and moduleA.cmi. The former is the bytecode object of the module (like a .o file in for native object files, but containing bytecode data and text), the later is a bytecode compiled header, produced from an automatically generated .mli file. This bytecode header is necessary for the compiler to compile files which depend on ModuleA.
$ cd bar
$ ocamlc -I ../foo -c moduleB.ml
$ cd ..
will succeed in producing moduleB.cmo, which depends on ModuleA, because the previous command has been successful, and because we indicate the compiler where to look for dependancies with the -I command line parameter, followed by the path of the first module.
The last command below will produce a bytecode executable from both modules:
$ ocamlc -I foo -I bar moduleA.cmo moduleB.cmo -o prog.byte
The modules must be provided in that order, to let the compiler know the dependancies first. The -I parameters this time indicate where to find the .cmo files.
In your case, you must therefore use the -I <location of std.cmi> for the compilation proper phase, and -I <location of std.cmo> (or std.cma, if it is a library) for the second phase (the link phase). If you can combine both phases in one command (ie. ocamlc -I foo foo/moduleA.ml bar/moduleB.ml -o prog.byte), and if both cmo and cmi files are in the same directory, only one parameter will suffice.

(How) Can I determine the version of the c99 compiler on my machine?

Is there a command line flag, or something similar, that I can use to get c99 to print it's version?
I'm looking for output similar to gcc's -v flag, which gives me:
Using built-in specs.
Target: i686-apple-darwin11
Configured with: /private/var/tmp/llvmgcc42/llvmgcc42-2336.11~28/src/configure --disable-checking --enable-werror --prefix=/Applications/Xcode.app/Contents/Developer/usr/llvm-gcc-4.2 --mandir=/share/man --enable-languages=c,objc,c++,obj-c++ --program-prefix=llvm- --program-transform-name=/^[cg][^.-]*$/s/$/-4.2/ --with-slibdir=/usr/lib --build=i686-apple-darwin11 --enable-llvm=/private/var/tmp/llvmgcc42/llvmgcc42-2336.11~28/dst-llvmCore/Developer/usr/local --program-prefix=i686-apple-darwin11- --host=x86_64-apple-darwin11 --target=i686-apple-darwin11 --with-gxx-include-dir=/usr/include/c++/4.2.1
Thread model: posix
gcc version 4.2.1 (Based on Apple Inc. build 5658) (LLVM build 2336.11.00)
I really only care about the Target: line and the last line.
c99 --version
~$c99 --version
gcc (Debian 4.4.5-8) 4.4.5
also try c99 --help
~$ c99 --help
Usage: gcc [options] file...
Options:
-pass-exit-codes Exit with highest error code from a phase
--help Display this information
--target-help Display target specific command line options
--help={target|optimizers|warnings|params|[^]{joined|separate|undocumented}}[,...]
Display specific types of command line options
(Use '-v --help' to display command line options of sub-processes)
--version Display compiler version information
-dumpspecs Display all of the built in spec strings
-dumpversion Display the version of the compiler
-dumpmachine Display the compiler's target processor
-print-search-dirs Display the directories in the compiler's search path
-print-libgcc-file-name Display the name of the compiler's companion library
-print-file-name=<lib> Display the full path to library <lib>
-print-prog-name=<prog> Display the full path to compiler component <prog>
-print-multi-directory Display the root directory for versions of libgcc
-print-multi-lib Display the mapping between command line options and
multiple library search directories
-print-multi-os-directory Display the relative path to OS libraries
-print-sysroot Display the target libraries directory
-print-sysroot-headers-suffix Display the sysroot suffix used to find headers
-Wa,<options> Pass comma-separated <options> on to the assembler
-Wp,<options> Pass comma-separated <options> on to the preprocessor
-Wl,<options> Pass comma-separated <options> on to the linker
-Xassembler <arg> Pass <arg> on to the assembler
-Xpreprocessor <arg> Pass <arg> on to the preprocessor
-Xlinker <arg> Pass <arg> on to the linker
-combine Pass multiple source files to compiler at once
-save-temps Do not delete intermediate files
-pipe Use pipes rather than intermediate files
-time Time the execution of each subprocess
-specs=<file> Override built-in specs with the contents of <file>
-std=<standard> Assume that the input sources are for <standard>
--sysroot=<directory> Use <directory> as the root directory for headers
and libraries
-B <directory> Add <directory> to the compiler's search paths
-b <machine> Run gcc for target <machine>, if installed
-V <version> Run gcc version number <version>, if installed
-v Display the programs invoked by the compiler
-### Like -v but options quoted and commands not executed
-E Preprocess only; do not compile, assemble or link
-S Compile only; do not assemble or link
-c Compile and assemble, but do not link
-o <file> Place the output into <file>
-x <language> Specify the language of the following input files
Permissible languages include: c c++ assembler none
'none' means revert to the default behavior of
guessing the language based on the file's extension
Options starting with -g, -f, -m, -O, -W, or --param are automatically
passed on to the various sub-processes invoked by gcc. In order to pass
other options on to these processes the -W<letter> options must be used.

Out of tree builds with makefiles and static pattern rules

I'm working on some bare-metal embedded code that runs on ARM, and thus has to deal with the whole ARM vs. THUMB mode distinction. The current build system uses static pattern rules to determine whether to compile files in ARM or THUMB mode.
$(ACOBJS) : %.o : %.c
#echo
$(CC) -c $(CFLAGS) $(AOPT) -I . $(IINCDIR) $< -o $#
$(TCOBJS) : %.o : %.c
#echo
$(CC) -c $(CFLAGS) $(TOPT) -I . $(IINCDIR) $< -o $#
Where ACOBJS is a list of output objects that should be in ARM mode and the same for TCOBJS and Thumb mode. These lists are created from the list of sources in the usual manner of
ACOBJS = $(ACSRC:.c=.o)
TCOBJS = $(TCSRC:.c=.o)
Currently this results in the object files from the build being strewn about the source tree, which I don't particularly desire. I've been trying to set this up for out of tree builds but haven't been able to get this to work. I don't necessarily need to get full out of tree builds working, but I would like to at least be able to use an output directory under which all the intermediate files end up going. What is the best strategy to achieve this under these constraints?
One option I'm considering is using either automake or the whole autotools toolchain to build a makefile. This would seem to support creating the type of makefile I want, but seems like overkill. It also seems like there would be an inherent impedance mismatch between autotools, which is designed for portable builds, and bare-metal embedded systems, where things like host tuple are dictated by the target micro.
This is a bit old but I was just trying to do the same thing this was the first google hit. I thought it was worth sharing another approach since neither answer is convenient if you're not using autotools and want to be able to build in any directory with a single command and later just blow away that directory.
Here's an example of a Makefile that refers to files relative to the directory containing the Makefile.
MAKEFILE_DIR := $(shell dirname $(realpath $(lastword $(MAKEFILE_LIST))))
MFD := $(MAKEFILE_DIR)
CXX=g++
CXXFLAGS=-std=c++14 -Wall -Wextra -pedantic -c
test: test.o adjacency_pointers_graph.o
$(CXX) $^ -o $#
%.o: $(MFD)/%.cpp $(MFD)/adjacency_pointers_graph.h
$(CXX) $(CXXFLAGS) $< -o $#
Then to do an sort of source build:
mkdir build
cd build
make -f ../Makefile
Considering/assuming you don't care about portability and are using GNU make, you can use the VPATH feature:
Create the directory where you want to do your build.
Create a 'Makefile' in that directory with (approximately) the following contents:
path_to_source = ..
VPATH = $(path_to_source)
include $(path_to_source)/Makefile
Change the path_to_source variable to point to the root of your source tree.
Additionally you probably need to tweak your original Makefile to make sure that it supports the out of source build. For example, you can't reference to prerequisites from your build rules and instead must use $^ and $<. (See GNU make - Writing Recipes with Directory Search) You might also need to modify the vpath-makefile. For example: adding CFLAGS+=-I$(path_to_source) might be useful.
Also note that if a file is in both your source and build directory, make will use the file in your build directory.
On automake
If you use automake, you're pretty much using the entire autotools. automake cannot work without autoconf.
The Makefiles generated by automake support out-of-source builds and cross-compilation, so you should be able to create subdirectories arm/ and thumb/ and run ../configure --host=arm-host-prefix in arm/ and run ../configure --host=thumb-host-prefix in thumb/. (I don't know the actual host tuples that you'd use for each compiler.)
Using GNU make
Since you're using GNUMake, you could do something like this:
ACOBJS := $(addprefix arm/,$(ACSRC:.c=.o))
TCOBJS := $(addprefix thumb/,$(TCSRC:.c=.o))
Use something like this answer to ensure that the arm/ and thumb/ directories (and any subdirectories) exist.

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