Updating Dates and Date Intervals in R - r

Question

Not even sure if I've described the problem accurately in the title, but here goes.
Suppose I have the following data.table/data.frame:
library(data.table)
library(lubridate)
DT <- data.table(begin = c("2019-06-01 09:00:00","2019-06-01 09:00:00", "2019-06-01 09:00:00",
"2019-06-01 09:00:00", "2016-06-01 09:00:00","2016-06-01 09:00:00"),
end = c("2019-06-03 14:00:00", "2019-06-03 14:00:00", "2019-06-03 14:00:00",
"2019-06-02 05:00:00", "2019-06-02 05:00:00", "2016-06-01 23:15:00"),
person = c("A", "A","A", "B", "B", "C"))
begin end person
1: 2019-06-01 09:00:00 2019-06-03 14:00:00 A
2: 2019-06-01 09:00:00 2019-06-03 14:00:00 A
3: 2019-06-01 09:00:00 2019-06-03 14:00:00 A
4: 2019-06-01 09:00:00 2019-06-02 05:00:00 B
5: 2016-06-01 09:00:00 2019-06-02 05:00:00 B
6: 2016-06-01 09:00:00 2016-06-01 23:15:00 C
This is essentially a dataset summarizing time stamps of when a period began and ended for each person. The number of rows are repeated for each person by the number of days which the time period spans. For example, person A has three entries for the same "shift" because their shift spans three distinct dates, 06-01, 06-02, and 06-03. The entries are repeated by the number of dates which the shifts span, but some shifts begin and end within the same day.
What I want is to update the begin and end dates of the above dataset, so that I can see what time each shift began and ended at the day level. So the dataset should look like:
begin end person
1: 2019-06-01 09:00:00 2019-06-02 00:00:00 A
2: 2019-06-02 00:00:00 2019-06-03 00:00:00 A
3: 2019-06-03 00:00:00 2019-06-03 14:00:00 A
4: 2019-06-01 09:00:00 2019-06-02 00:00:00 B
5: 2016-06-02 00:00:00 2019-06-02 05:00:00 B
6: 2016-06-01 09:00:00 2016-06-01 23:15:00 C
Any help would be greatly appreciated!

Answer 1

First, fixing the dates (and I already fixed row 5's starting in 2016 and going through to 2019, seems unlikely),
DT[, c("begin", "end"):=lapply(.SD, as.POSIXct), .SDcols=c("begin", "end")]
## we get this
DT <- as.data.table(structure(list(begin = structure(c(1559394000, 1559394000, 1559394000, 1559394000, 1559394000, 1464786000), class = c("POSIXct", "POSIXt"), tzone = ""), end = structure(c(1559584800, 1559584800, 1559584800, 1559466000, 1559466000, 1464837300), class = c("POSIXct", "POSIXt"), tzone = ""), person = c("A", "A", "A", "B", "B", "C")), row.names = c(NA, -6L), class = c("data.table", "data.frame")))
Second, we then create this function
func <- function(st, en) {
midns <- lubridate::ceiling_date(seq(st, en, by = "day"), unit = "day")
times <- unique(sort(c(midns[ st < midns & midns < en], st, en)))
data.table(begin = times[-length(times)], end = times[-1])
}
Lastly, we use it, using by=.(person) to preserve that column in the output. I use DT since we do not need (or even want) duplicates for each shift/day:
unique(DT)[, rbindlist(Map(func, begin, end)), by = .(person)]
# person begin end
# <char> <POSc> <POSc>
# 1: A 2019-06-01 09:00:00 2019-06-02 00:00:00
# 2: A 2019-06-02 00:00:00 2019-06-03 00:00:00
# 3: A 2019-06-03 00:00:00 2019-06-03 14:00:00
# 4: B 2019-06-01 09:00:00 2019-06-02 00:00:00
# 5: B 2019-06-02 00:00:00 2019-06-02 05:00:00
# 6: C 2016-06-01 09:00:00 2016-06-01 23:15:00

Answer 2

Assuming you had a typo for row 5 person B (begin 2019 not 2016):
library(data.table)
library(lubridate)
> DT <- data.table(begin = c("2019-06-01 09:00:00","2019-06-01 09:00:00", "2019-06-01 09:00:00",
+ "2019-06-01 09:00:00", "2019-06-01 09:00:00","2016-06-01 09:00:00"),
+ end = c("2019-06-03 14:00:00", "2019-06-03 14:00:00", "2019-06-03 14:00:00",
+ "2019-06-02 05:00:00", "2019-06-02 05:00:00", "2016-06-01 23:15:00"),
+ person = c("A", "A","A", "B", "B", "C"))
>
> DT[, `:=`(min=as.numeric(difftime(end,begin, units="mins")),
+ days=as.numeric(as_date(end)-as_date(begin)+1))][, min_day:=min/days]
>
> unique(DT)
begin end person min days min_day
1: 2019-06-01 09:00:00 2019-06-03 14:00:00 A 3180 3 1060
2: 2019-06-01 09:00:00 2019-06-02 05:00:00 B 1200 2 600
3: 2016-06-01 09:00:00 2016-06-01 23:15:00 C 855 1 855