Multi-Label-Classification Approach to complex tabular data structure in R - r

I have a set of two dataframes that both contain duplicates but need to be merged into one big dataframe in order to use it as input for an ML algorithm.
Connecting the two dataframes is a big problem in the first place. Furthermore, it is difficult to predict multiple classes from the resulting dataset.
Since the original dataset has its origin in the medical field and is confidential, I added a fictional (though realistic) example code for a reproduction of the problem below.
library(data.table)
library(dplyr)
library(tidyr)
data1 <- data.table("color" = c("green", "green", "red", "red", "blue", "blue", "blue", "red", "pink"),
"type" = c("SUV", "SUV", "SEDAN", "SEDAN", "SEDAN", "TRUCK", "TRUCK", "CABRIO", "CABRIO"),
"NUM_SEATS" = c(4,4,5,4,4,3,3,2,2),
"MODELL_ID" = c("xyz", "xyz", "abc", "abc", "abc", "rtz", "rtz", "ghj", "ghj"))
data2 <- data.table("BRAND" = c("VW", "VW", "VW", "AUDI", "AUDI", "BMW", "BMW", "GM", "GM"),
"year_quarter" = c("20173", "20173", "20174", "20174", "20171", "20181", "20162", "20172", "20192"),
"MODELL_ID" = c("xyz", "xyz", "abc", "abc", "abc", "rtz", "rtz", "ghj", "ghj"))
data1 <- data1 %>% group_by(MODELL_ID) %>% mutate(time = row_number()) %>% ungroup()
data2 <- data2 %>% group_by(MODELL_ID) %>% mutate(time = row_number()) %>% ungroup()
data1_temp <- data1 %>% pivot_wider(names_from = time, values_from = c(-MODELL_ID), names_sort = TRUE, names_sep = "-")
data2_temp <- data2 %>% pivot_wider(names_from = time, values_from = c(-MODELL_ID), names_sort = TRUE, names_sep = "-")
data_join <- inner_join(data1_temp, data2_temp, by = c("MODELL_ID")) %>% select(-starts_with(c("n.", "time"))) %>% pivot_wider(names_from = "MODELL_ID", values_from = "MODELL_ID", names_prefix = "MODELL_ID-") %>% as.matrix()
data_join[is.na(data_join)] <- "0"
x_data <- data_join %>% as.data.table() %>% select(-starts_with("MODELL_ID-"))
y_data <- data_join %>% as.data.table() %>% select(starts_with("MODELL_ID-"))
x_data # input (unvectorized)
y_data # output (unvectorized)
x_data %>% data.matrix()-1 # input (vectorized)
y_data %>% data.matrix()-1 # output (vectorized)
X is my input (x_data), Modell_ID (y_data) my output. I want my ML solution to predict all possible Modell_IDs when given a row of X.
It would be great to get some advise on how to actually implement a solution for this. Every approach so far (Feed-Forward Net, etc.) has not delivered noticeable results...
I am really looking for a game-changing command, approach, example code rather than just superficial tips.

Related

R: How to create a Drilldown Highchart using loops

when doing a job I have found a problem that I don't know how to solve.
I have a data frame that has 2 columns:
date
value
And it has a total of 1303 rows.
For each date there are 12 values (1 for each month), except in the last year that only has 7
The work I have to do would be to create a 'drilldown' style chart using the 'highcharter' library. The problem is that I don't know how to do it efficiently.
The solution that comes to my mind is not very efficient, below I show my solution so you can see what I mean.
dataframe
# Load packages
library(tidyverse)
library(highcharter)
library(lubridate)
# Load dataset
df <- read.csv('example.csv')
# Prepare df to use
dfDD <- tibble(name = year(df$date),
y = round(df$value, digits = 2),
drilldown = name)
# Create a data frame to use in 'drilldown' (for each year)
df1913 <- df %>%
filter(year(date) == 1913) %>%
data.frame()
df1914 <- df %>%
filter(year(date) == 1914) %>%
data.frame()
# Create a drilldown chart using Highcharter library
highchart() %>%
hc_chart(type = "column") %>%
hc_title(text = "Example Drilldown") %>%
hc_xAxis(type = "category") %>%
hc_legend(enabled = FALSE) %>%
hc_plotOptions(series = list(boderWidth = 2,
dataLabels = list(enabled = TRUE))) %>%
hc_add_series(data = dfDD,
name = "Mean",
colorByPoint = TRUE) %>%
hc_drilldown(allowPointDrilldown = TRUE,
series = list(list(id = 1913,
data = list_parse2(df1913)),
list(id = 1914,
data = list_parse2(df1914))))
Seeing my solution for the first time, I realized that in order to complete the graph I would have to create a subset of values for each year. Having realized that I tried to find a more efficient solution using a 'for loop' but so far I can't get it to work.
Is there a more efficient way to create this graph using a 'loop'!?
If it can be done in another way than using loops, I would also like to know.
Thank you for reading my question and I hope I explained myself well.
Using split and purrr::imap you could split your data by years and loop over the resulting list to convert your data to the nested list object required by hc_drilldown. Note: It's important to make the id a numeric and to pass a unnamed list.
library(tidyverse)
library(highcharter)
library(lubridate)
series <- split(df, year(df$date)) %>%
purrr::imap(function(x, y) list(id = as.numeric(y), data = list_parse2(x)))
# Unname list
names(series) <- NULL
highchart() %>%
hc_chart(type = "column") %>%
hc_title(text = "Example Drilldown") %>%
hc_xAxis(type = "category") %>%
hc_legend(enabled = FALSE) %>%
hc_plotOptions(series = list(boderWidth = 2,
dataLabels = list(enabled = TRUE))) %>%
hc_add_series(data = dfDD,
name = "Mean",
colorByPoint = TRUE) %>%
hc_drilldown(allowPointDrilldown = TRUE,
series = series)

how to make customised pretty flexable function

I am loving flextable however, incorporating it within my workflow is causing issues in that I am not able to write general purpose functions.
I want a function that would automatically highlight the header and the last row of the table. I am able to do this but I have to specify the name of the first column name. This is simply too much work, is there a work around?
library(tidyverse)
require(flextable)
require(rlang)
# Function that works
my_table <- function(x){
require(flextable)
require(rlang)
x %>%
flextable() %>%
# Header colour and bold
bg(bg = "#e05297", part = "header") %>%
flextable::color(color = "white", part = "header") %>%
# Last row bold and highlight
bold(i = ~rowname == "Total", bold = TRUE) %>%
bg(i = ~rowname == "Total",
bg = "grey",
part = "body")
}
mtcars %>%
rownames_to_column() %>%
adorn_totals("row") %>%
my_table()
# This is a general purpose function which is not working
my_table <- function(x){
require(flextable)
require(rlang)
first_col_name <- colnames(x) %>% .[1]
x %>%
flextable() %>%
# Header colour and bold
bg(bg = "#e05297", part = "header") %>%
flextable::color(color = "white", part = "header") #%>%
# Last row bold and highlight
bold(i = ~eval(rlang::sym(first_col_name)) == "Total", bold = TRUE) %>%
bg(i = ~eval(rlang::sym(first_col_name)) == "Total",
bg = "grey",
part = "body")
}
Any ideas how to make the general purpose my_table function to work
i argument also accepts position (row number) of the dataframe to highlight so you may use nrow to get the last row in the dataframe.
library(flextable)
library(janitor)
my_table <- function(x){
x %>%
flextable() %>%
# Header colour and bold
bg(bg = "#e05297", part = "header") %>%
flextable::color(color = "white", part = "header") %>%
bold(i = nrow(x), bold = TRUE) %>%
bg(i = nrow(x),bg = "grey",part = "body")
}
mtcars %>%
rownames_to_column() %>%
adorn_totals("row") %>%
my_table()

Unnest multiple nested dataframes in R

I am looking for a way to unnest a nested list with dataframes. The challenge is that I have to do unnest_wider() first and unnest() next, and both of them can only take one column at the time. I have to do over 30 columns and each of them contains a nested dataframes.
This is the replicate case that looks similar to my dataframe.
df <- tibble(
character = c("Toothless", "Dory"),
metadata = list(
list(
species = "dragon",
color = "black",
films = c(
"How to Train Your Dragon",
"How to Train Your Dragon 2",
"How to Train Your Dragon: The Hidden World"
)
),
list(
species = "blue tang",
color = "blue",
films = c("Finding Nemo", "Finding Dory")
)
)
)
df$mtcars <- list(mtcars)
df$iris <- list(iris)
df$longley <- list(longley)
My current working
df1 <- df %>%
unnest_wider(mtcars, names_sep = "_") %>%
unnest_wider(iris, names_sep = "_") %>%
unnest_wider(longley, names_sep = "_")
df2 <- df1 %>%
unnest(mtcars_mpg) %>%
unnest(mtcars_cyl) %>%
unnest(mtcars_disp)
Any advice to do it efficiently will be highly appreciated.

Disaggregate in the context of a time series

I have a dataset that I want to visualize overall and disaggregated by a few different variables. I created a flexdashboard with a toy shiny app to select the type of disaggregation, and working code to plot the correct subset.
My approach is repetitive, which is a hint to me that I'm missing out on a better way to do this. The piece that's tripping me up is the need to count by date and expand the matrix. I'm not sure how get group counts by week in one pipe. I do it in several steps and combine.
Thoughts?
(ps. I asked this question on RStudio Community, but I think it's probably more of a "SO question". I don't have permissions to delete it from RSC, so apologies for the cross-post.)
---
title: "test"
output:
flexdashboard::flex_dashboard:
theme: bootstrap
runtime: shiny
---
```{r setup, include=FALSE}
library(flexdashboard)
library(tidyverse)
library(tibbletime)
library(dygraphs)
library(magrittr)
library(xts)
```
```{r global, include=FALSE}
set.seed(1)
dat <- data.frame(date = seq(as.Date("2018-01-01"),
as.Date("2018-06-30"),
"days"),
sex = sample(c("male", "female"), 181, replace=TRUE),
lang = sample(c("english", "spanish"), 181, replace=TRUE),
age = sample(20:35, 181, replace=TRUE))
dat <- sample_n(dat, 80)
```
Sidebar {.sidebar}
=====================================
```{r}
radioButtons("diss", label = "Disaggregation",
choices = list("All" = 1, "By Sex" = 2, "By Language" = 3),
selected = 1)
```
Page 1
=====================================
```{r}
# all
all <- reactive(
dat %>%
mutate(new = 1) %>%
arrange(date) %>%
# time series analysis
as_tbl_time(index = date) %>% # convert to tibble time object
select(date, new) %>%
collapse_by('1 week', side="start", clean=TRUE) %>%
group_by(date) %>%
mutate(total = sum(new, na.rm=TRUE)) %>%
distinct(date, .keep_all = TRUE) %>%
ungroup() %>%
# expand matrix to include weeks without data
complete(date = seq(date[1],
date[length(date)],
by = "1 week"),
fill = list(total = 0))
)
# males only
males <- reactive(
dat %>%
filter(sex=="male") %>%
mutate(new = 1) %>%
arrange(date) %>%
# time series analysis
as_tbl_time(index = date) %>%
select(date, new) %>%
collapse_by('1 week', side="start", clean=TRUE) %>%
group_by(date) %>%
mutate(total_m = sum(new, na.rm=TRUE)) %>%
distinct(date, .keep_all = TRUE) %>%
ungroup() %>%
# expand matrix to include weeks without data
complete(date = seq(date[1],
date[length(date)],
by = "1 week"),
fill = list(total_m = 0))
)
# females only
females <- reactive(
dat %>%
filter(sex=="female") %>%
mutate(new = 1) %>%
arrange(date) %>%
# time series analysis
as_tbl_time(index = date) %>%
select(date, new) %>%
collapse_by('1 week', side="start", clean=TRUE) %>%
group_by(date) %>%
mutate(total_f = sum(new, na.rm=TRUE)) %>%
distinct(date, .keep_all = TRUE) %>%
ungroup() %>%
# expand matrix to include weeks without data
complete(date = seq(date[1],
date[length(date)],
by = "1 week"),
fill = list(total_f = 0))
)
# english only
english <- reactive(
dat %>%
filter(lang=="english") %>%
mutate(new = 1) %>%
arrange(date) %>%
# time series analysis
as_tbl_time(index = date) %>%
select(date, new) %>%
collapse_by('1 week', side="start", clean=TRUE) %>%
group_by(date) %>%
mutate(total_e = sum(new, na.rm=TRUE)) %>%
distinct(date, .keep_all = TRUE) %>%
ungroup() %>%
# expand matrix to include weeks without data
complete(date = seq(date[1],
date[length(date)],
by = "1 week"),
fill = list(total_e = 0))
)
# spanish only
spanish <- reactive(
dat %>%
filter(lang=="spanish") %>%
mutate(new = 1) %>%
arrange(date) %>%
# time series analysis
as_tbl_time(index = date) %>%
select(date, new) %>%
collapse_by('1 week', side="start", clean=TRUE) %>%
group_by(date) %>%
mutate(total_s = sum(new, na.rm=TRUE)) %>%
distinct(date, .keep_all = TRUE) %>%
ungroup() %>%
# expand matrix to include weeks without data
complete(date = seq(date[1],
date[length(date)],
by = "1 week"),
fill = list(total_s = 0))
)
# combine
totals <- reactive({
all <- all()
females <- females()
males <- males()
english <- english()
spanish <- spanish()
all %>%
select(date, total) %>%
full_join(select(females, date, total_f), by = "date") %>%
full_join(select(males, date, total_m), by = "date") %>%
full_join(select(english, date, total_e), by = "date") %>%
full_join(select(spanish, date, total_s), by = "date")
})
# convert to xts
totals_ <- reactive({
totals <- totals()
xts(totals, order.by = totals$date)
})
# plot
renderDygraph({
totals_ <- totals_()
if (input$diss == 1) {
dygraph(totals_[, "total"],
main= "All") %>%
dySeries("total", label = "All") %>%
dyRangeSelector() %>%
dyOptions(useDataTimezone = FALSE,
stepPlot = TRUE,
drawGrid = FALSE,
fillGraph = TRUE)
} else if (input$diss == 2) {
dygraph(totals_[, c("total_f", "total_m")],
main = "By sex") %>%
dyRangeSelector() %>%
dySeries("total_f", label = "Female") %>%
dySeries("total_m", label = "Male") %>%
dyOptions(useDataTimezone = FALSE,
stepPlot = TRUE,
drawGrid = FALSE,
fillGraph = TRUE)
} else {
dygraph(totals_[, c("total_e", "total_s")],
main = "By language") %>%
dyRangeSelector() %>%
dySeries("total_e", label = "English") %>%
dySeries("total_s", label = "Spanish") %>%
dyOptions(useDataTimezone = FALSE,
stepPlot = TRUE,
drawGrid = FALSE,
fillGraph = TRUE)
}
})
```
Update:
#Jon Spring suggested writing a function to reduce some repetition (applied below), which is a nice improvement. The basic approach is the same, however. Segment, calculate, combine, plot. Is there a way to do this without breaking apart and putting back together?
---
title: "test"
output:
flexdashboard::flex_dashboard:
theme: bootstrap
runtime: shiny
---
```{r setup, include=FALSE}
library(flexdashboard)
library(tidyverse)
library(tibbletime)
library(dygraphs)
library(magrittr)
library(xts)
```
```{r global, include=FALSE}
# generate data
set.seed(1)
dat <- data.frame(date = seq(as.Date("2018-01-01"),
as.Date("2018-06-30"),
"days"),
sex = sample(c("male", "female"), 181, replace=TRUE),
lang = sample(c("english", "spanish"), 181, replace=TRUE),
age = sample(20:35, 181, replace=TRUE))
dat <- sample_n(dat, 80)
# Jon Spring's function
prep_dat <- function(filtered_dat, col_name = "total") {
filtered_dat %>%
mutate(new = 1) %>%
arrange(date) %>%
# time series analysis
tibbletime::as_tbl_time(index = date) %>% # convert to tibble time object
select(date, new) %>%
tibbletime::collapse_by("1 week", side = "start", clean = TRUE) %>%
group_by(date) %>%
mutate(total = sum(new, na.rm = TRUE)) %>%
distinct(date, .keep_all = TRUE) %>%
ungroup() %>%
# expand matrix to include weeks without data
complete(
date = seq(date[1], date[length(date)], by = "1 week"),
fill = list(total = 0)
)
}
```
Sidebar {.sidebar}
=====================================
```{r}
radioButtons("diss", label = "Disaggregation",
choices = list("All" = 1, "By Sex" = 2, "By Language" = 3),
selected = 1)
```
Page 1
=====================================
```{r}
# all
all <- reactive(
prep_dat(dat)
)
# males only
males <- reactive(
prep_dat(
dat %>%
filter(sex == "male")
) %>%
rename("total_m" = "total")
)
# females only
females <- reactive(
prep_dat(
dat %>%
filter(sex == "female")
) %>%
rename("total_f" = "total")
)
# english only
english <- reactive(
prep_dat(
dat %>%
filter(lang == "english")
) %>%
rename("total_e" = "total")
)
# spanish only
spanish <- reactive(
prep_dat(
dat %>%
filter(lang == "spanish")
) %>%
rename("total_s" = "total")
)
# combine
totals <- reactive({
all <- all()
females <- females()
males <- males()
english <- english()
spanish <- spanish()
all %>%
select(date, total) %>%
full_join(select(females, date, total_f), by = "date") %>%
full_join(select(males, date, total_m), by = "date") %>%
full_join(select(english, date, total_e), by = "date") %>%
full_join(select(spanish, date, total_s), by = "date")
})
# convert to xts
totals_ <- reactive({
totals <- totals()
xts(totals, order.by = totals$date)
})
# plot
renderDygraph({
totals_ <- totals_()
if (input$diss == 1) {
dygraph(totals_[, "total"],
main= "All") %>%
dySeries("total", label = "All") %>%
dyRangeSelector() %>%
dyOptions(useDataTimezone = FALSE,
stepPlot = TRUE,
drawGrid = FALSE,
fillGraph = TRUE)
} else if (input$diss == 2) {
dygraph(totals_[, c("total_f", "total_m")],
main = "By sex") %>%
dyRangeSelector() %>%
dySeries("total_f", label = "Female") %>%
dySeries("total_m", label = "Male") %>%
dyOptions(useDataTimezone = FALSE,
stepPlot = TRUE,
drawGrid = FALSE,
fillGraph = TRUE)
} else {
dygraph(totals_[, c("total_e", "total_s")],
main = "By language") %>%
dyRangeSelector() %>%
dySeries("total_e", label = "English") %>%
dySeries("total_s", label = "Spanish") %>%
dyOptions(useDataTimezone = FALSE,
stepPlot = TRUE,
drawGrid = FALSE,
fillGraph = TRUE)
}
})
```
Thanks for explaining more about your goals. I think the approach #simon-s-a suggests will simplify things. If we can run the grouping dynamically, and structure it so that we don't need to know the possible components in those groups beforehand, it will be a lot easier to maintain.
Here's a minimum viable product that rebuilds the plotting function to include the grouping logic inside it.
Once grouped by date and whatever our grouping variable is, it counts how many rows each group has, then spreads those so each group gets a column.
Then I use padr::pad to pad out any missing time rows in between, and replace all the NA's with zeros.
Finally, that data frame is converted to an xts object and fed into dygraph, which seems to handle the multiple columns automatically.
Here:
---
title: "test"
output:
flexdashboard::flex_dashboard:
theme: bootstrap
runtime: shiny
---
```{r setup, include=FALSE}
library(flexdashboard)
library(tidyverse)
library(tibbletime)
library(dygraphs)
library(magrittr)
library(xts)
```
```{r global, include=FALSE}
# generate data
set.seed(1)
dat <- data.frame(date = seq(as.Date("2018-01-01"),
as.Date("2018-06-30"),
"days"),
sex = sample(c("male", "female"), 181, replace=TRUE),
lang = sample(c("english", "spanish"), 181, replace=TRUE),
age = sample(20:35, 181, replace=TRUE))
dat <- dplyr::sample_n(dat, 80)
```
Sidebar {.sidebar}
=====================================
```{r}
radioButtons("diss", label = "Disaggregation",
choices = list("All" = "Total",
"By Sex" = "sex",
"By Language" = "lang"),
selected = "Total")
```
Page 1
=====================================
```{r plot}
renderDygraph({
grp_col <- rlang::sym(input$diss) # This converts the input selection to a symbol
dat %>%
mutate(Total = 1) %>% # This is a hack to let us "group" by Total -- all one group
# Here's where we unquote the symbol so that dplyr can use it
# to refer to a column. In this case I make a dummy column
# that's a copy of whatever column we want to group
mutate(my_group = !!grp_col) %>%
# Now we make a group for every existing combination of week
# (using lubridate::floor_date) and level of our grouping column,
# count how many rows in each group, and spread that to wide format.
group_by(date = lubridate::floor_date(date, "1 week"), my_group) %>%
count() %>% spread(my_group, n) %>% ungroup() %>%
# padr:pad() fills in any missing weeks in the sequence with new rows
# Then we replace all the NA's with zeroes.
padr::pad() %>% replace(is.na(.), 0) %>%
# Finally we can convert to xts and feed the wide table into digraph.
xts::xts(order.by = .$date) %>%
dygraph() %>%
dyRangeSelector() %>%
dyOptions(
useDataTimezone = FALSE, stepPlot = TRUE,
drawGrid = FALSE, fillGraph = TRUE
)
})
```
This is a good place to make a function, to shorten your code and make it less prone to error.
http://r4ds.had.co.nz/functions.html
A complicating bit is that programming with dplyr often requires wading into a framework called tidyeval, which is very powerful but can be intimidating.
https://dplyr.tidyverse.org/articles/programming.html
(Here's an alternative approach that sidesteps tidyeval: https://cran.r-project.org/web/packages/seplyr/vignettes/using_seplyr.html)
In your scenario, it's possible to avoid these challenges entirely by doing a bit of manipulation before and after your function. It's not as elegant, but works.
BTW, I can't guarantee it'll work since you didn't share a verifiable reprex (e.g. including a sample of data with the same form as yours), but it worked with the fake data I made up. (See bottom.) Sorry, I missed the chunk where your sample data was provided.
prep_dat <- function(filtered_dat, col_name = "total") {
filtered_dat %>%
mutate(new = 1) %>%
arrange(date) %>%
# time series analysis
tibbletime::as_tbl_time(index = date) %>% # convert to tibble time object
select(date, new) %>%
tibbletime::collapse_by("1 week", side = "start", clean = TRUE) %>%
group_by(date) %>%
mutate(total = sum(new, na.rm = TRUE)) %>%
distinct(date, .keep_all = TRUE) %>%
ungroup() %>%
# expand matrix to include weeks without data
complete(
date = seq(date[1], date[length(date)], by = "1 week"),
fill = list(total = 0)
)
}
Then you could call it with your filtered data and the name of the total column. This fragment should be able to replace the ~20 lines you're currently using:
males <- prep_dat(dat_fake %>%
filter(sex == "male")) %>%
rename("total_m" = "total")
Fake data that I tested on:
dat_fake <- tibble(
date = as.Date("2018-01-01") + runif(500, 0, 100),
new = runif(500, 0, 100),
sex = sample(c("male", "female"),
500, replace = TRUE),
lang = sample(c("english", "french", "spanish", "portuguese", "tagalog"),
500, replace = TRUE)
)
I think you can make some gains by changing the order of your preparation. Right now the flow of your app is approximately:
Data => prepare all combinations => select desired visualization => make plot
Consider instead:
Data => select desired visualization => prepare required combination => make plot
This would make use of Shiny's reactivity to (re)prepare the data required for the requested plot in response to changes in the user's selection.
By way of code snippets (Sorry, I don't have sufficient familiarity with flexdashboard and tibbletime to ensure this code runs, but I hope it is enough to highlight the approach):
Your control selects the column you want to focus on (note we use "All" = "'1'" so this evaluates to a constant in the group-by, else it has to be handled separately):
radioButtons("diss", label = "Disaggregation",
choices = list("All" = "'1'",
"By Sex" = "sex",
"By Language" = "lang",
"By other" = "column_name_of_'other'"),
selected = 1)
And then use this in your group by to prepare only the data required for the present visualization (you'll need to adjust the function suggested by #Jon_Spring in response to this earlier group-by):
preped_dat = reactive({
dat %>%
group_by_(input$diss) %>%
# etc
})
Before plotting (you'll need to adjust the plotting function in response to the possible change in data format):
renderDygraph({
totals = preped_data()
dygraph(totals) %>%
dySeries("total", label = ) %>%
dyRangeSelector()
})
With regard to group_by you can use group_by_ if all your arguments are text strings, or group_by(!! sym(input$diss), other_column_name) if you want to mix the text string input from your control with other column names.
One possible disadvantage of this change in approach is reduced responsiveness during interactivity if your data set is large. The present approach does all the computation up front and then minimal computation each selection - this may be preferable if you have a large amount of processing. My suggested approach will have minimal up front processing and moderate computation each selection.

R officer - Nest Dataframe Into Grouped List And Export Tables to Word With Group Headers

I read a similar question that helped me get to the point I'm at now, but am struggling with the next step. I have a dataframe similar to below -
Product = c("Apple", "Apple", "Banana", "Banana", "Banana", "Carrot",
"Carrot")
Category = c(1, 2, 1, 2, 3, 1, 2)
Slope = c(2.988, 2.311, 2.181, 6.387, 2.615, 7.936, 3.267)
df = data.frame(Product, Category, Slope)
My objective is to have a Word report with a table for each product. To do this, I create a list with the data and flextables, as below -
library(tidyverse)
library(flextable)
library(officer)
test <- df %>%
group_by(Product) %>%
nest() %>%
mutate(data$Product)
mutate(ftables = map(data, flextable)) %>%
mutate(ftables = map(ftables, ~ bg(.,
bg = '#bfbfbf',
part = 'header')))
I can then pass this into word like this -
my_doc <- read_docx()
for (i in seq_along(test$ftables)) {
body_add_flextable(my_doc, test$ftables[[i]]) %>%
body_add_par(value = "")
}
The output is great, but unfortunately I lose any method of identifying which product each table belongs to.
I would either like to have the Product name as a title or within the tables. Doesn't matter which, but I can't figure out how to do either.
I've tried to look for ways to reintroduce the grouped field post-nest and also tried doubling up on my for loop for the headers, but ended up just repeating all the tables under each header -
for (i in seq_along(test$ProductLine)) {
my_doc <- body_add_par(my_doc, value = test$ProductLine[[i]], style =
'heading 1') %>%
body_add_par(value = "")
for (j in seq_along(test$ftables)) {
my_doc <- body_add_flextable(my_doc, test$ftables[[i]])
}
}
Does anybody know a way that I can accomplish this?
in your second try of a loop, don't add the first loop, just add the command to your chain...
Product = c("Apple", "Apple", "Banana", "Banana", "Banana", "Carrot",
"Carrot")
Category = c(1, 2, 1, 2, 3, 1, 2)
Slope = c(2.988, 2.311, 2.181, 6.387, 2.615, 7.936, 3.267)
df = data.frame(Product, Category, Slope)
library(tidyverse)
library(flextable)
library(officer)
test <-
df %>%
group_by(Product) %>%
nest() %>%
mutate(ftables = map(data, flextable)) %>%
mutate(ftables = map(ftables, ~ bg(.,
bg = '#bfbfbf',
part = 'header')))
my_doc <- read_docx()
for (i in seq_along(test$Product)) {
my_doc <-
my_doc %>%
body_add_par(value = test$Product[[i]], style = 'heading 1') %>%
body_add_par(value = "") %>%
body_add_flextable(test$ftables[[i]]) %>%
body_add_par(value = "")
}
print(my_doc, target = "my_doc.docx")

Resources