I need to compare a string partially to check for a given condition.
Like my $1 will be checked if it has a part of a string BLR
while my file input has $1 entries as BLR21 BLR64 IND23
I only need a true condition when $1 is equal to BLR**
where these stars can be anything.
I used a simple if condition
if($1=="BLR21")
{print $2}
Now this only works when whole BLR21 is there in row.
I need to ckeck not for BLR21 but only BLR.
Please Help
Your question is not great, I hope I understood.
Quick and easy solution
grep BLR input.txt
This will output all the lines in which "BLR" is found, in file input.txt. It will match "BLR" with any prefix and suffix, whatever they might be (spaces, alphanumerical, tabs, ...).
"Complicated" solution
A bit more complicated. It does the same thing, but makes sure input.txt exists, and is in the form of a script.
Input file, input.txt:
BLR21 BLR64 IND23
Your script could be:
#!/bin/bash
#
# Arguments
inputfile="input.txt"
if [[ $# -ne 1 ]]
then
echo "Usage: myscript.bash <STRING>"
exit 1
else
string="$1"
fi
# Validation, and processing...
if [[ ! -f "$inputfile" ]]
then
echo "ERROR: file >>$inputfile<< does not exist."
exit 2
else
grep "$string" "$inputfile"
fi
And to call the script, you do:
./myscript.bash BLR
But really, a simple grep does the job here.
Taking it even further...
#!/bin/bash
#
# Arguments
inputfile="input.txt"
if [[ $# -ne 1 ]]
then
echo "Usage: check.bash <STRING>"
exit 1
else
string="$1"
fi
# Validation, and processing...
if [[ ! -f "$inputfile" ]]
then
echo "ERROR: file >>$inputfile<< does not exist."
exit 2
else
while read -r line
do
if [[ "$line" =~ $string ]]
then
echo "$line"
fi
done <"$inputfile"
fi
Now this one is like going to the moon via mars...
It reads each line of the file, one by one. Then it checks if that line contains the string, using the =~ operator inside the if.
But this is crazy, when a simple grep would do.
Related
I’m wanting to do basically what this function does. It comes from the zsh manual page and other zsh documentation. I’m trying to “vaguely understand” without diving into the fine details what this function is doing and how it works.
In this case, I understand everything more or less except the _wanted line and in particular, is the tag "dynamic-dirs" any arbitrary tag or does it need to match what the higher level driving functions are looking for? I read briefly about tags and it seems like they would need to match up but I can’t find dynamic-dirs anywhere in any code that I’ve grep’ed. Nor have a found any type of list of tags that are used and what they means except the example of “files” and “directories” mentioned in the first few paragraphs of zshcompsys(1).
zsh_directory_name() {
emulate -L zsh
setopt extendedglob
local -a match mbegin mend
if [[ $1 = d ]]; then
# turn the directory into a name
if [[ $2 = (#b)(/home/pws/perforce/)([^/]##)* ]]; then
typeset -ga reply
reply=(p:$match[2] $(( ${#match[1]} + ${#match[2]} )) )
else
return 1
fi
elif [[ $1 = n ]]; then
# turn the name into a directory
[[ $2 != (#b)p:(?*) ]] && return 1
typeset -ga reply
reply=(/home/pws/perforce/$match[1])
elif [[ $1 = c ]]; then
# complete names
local expl
local -a dirs
dirs=(/home/pws/perforce/*(/:t))
dirs=(p:${^dirs})
_wanted dynamic-dirs expl 'dynamic directory' compadd -S\] -a dirs
return
else
return 1
fi
return 0
}
The other question is about the ’n’ section. It is going to return a reply even if the directory doesn’t exist. Am I reading the code right?
I guess this would be nice if I was going to do mkdir ~p:foodog ?
If the argument is 0 then script should check directory called “App0” is in the windows path variable. If not exists, then add \App0 in the path. I Am Struggling To Understand ( If the argument is 0 ).
My Work So Far.
if [ -d "${Appo}" ]; then
echo "Appo Doesn't Exist."
mkdir Appo
echo "File Created"
fi
Thank You
#!/bin/sh
if [[ $# == 0 ]]
then
echo "zero args"
fi
for arg in "$#" # You might get more than one argument.
do
dir="App${arg}" # Make the name by combining the strings.
if [[ -d $dir ]]
then
echo "App$arg exists"
else
mkdir "$dir" # Be careful the name supplied may contain spaces.
echo "Created directory: $dir"
fi
done
I am attempting to make a script that will check to see if there is any tyext within a file. I have developed the following script. I have made it check to see if there is exactly 2 arguments, see if the file exists, but I am having trouble checking the file for text within it. The code is as follows:
#!/bin/ksh
#check if number of arguments are 2
if [ $# -ne 2 ]; then
echo "Does not equal two arguments"
echo "Usage $0 inputfile outputfile"
exit 1
fi
#check if input file exists
if [ ! -f $1 ]; then
echo "$1 not found!"
exit 1
fi
#Check if input file is null
#This next block of code is where the issue is
if [ grep -q $1 -eq 0 ]; then
echo "$1 must have text within the file"
exit 1
fi
Any help would be appreciated
test's "-s" option checks if the file is empty -- see manual. So your last chunk would become
#Check if input file is null
#This next block of code is where the issue is
if [ ! -s $1 ]; then
echo "$1 must have text within the file"
exit 1
fi
Try using stat
stat -c %s filename
#!/bin/bash
LOCATION=$1
FILECOUNT=0
DIRCOUNT=0
if [ "$#" -lt "1" ]
then
echo "Usage: ./test2.sh <directory>"
exit 0
fi
I don't actually get what the If statement is saying can anyone help me to explain this?Thank you
$1 refers to the first argument of the bash file. In this case, you can pass your directory path by issuing the following command:
# ./test2.sh /path/of/your/directory
#!/bin/bash
LOCATION=$1 #first argument of the script
FILECOUNT=0
DIRCOUNT=0
if [ "$#" -lt "1" ] #if the number of argument(s) ($#) is less than 1
then
echo "Usage: ./test2.sh <directory>"
exit 0
fi
You can read this article for more information about parameter passing.
Hope it helps.
$1 is the first argument that is passed to the bash script. If you start the script like ./test2.sh argument1 argument2 the $1 will refer argument1.
The if-statement checks, if the count of arguments (that's the $#) is smaller than 1, then it will output the usage statement (as it seems you can't run the script without any argument).
I have the following lines in a file:
abcdef ghi jkl
uvw xyz
I want to grep for the string "xyz" if the previous line is not contains the string "jkl".
I know how to grep for a string if the line doesn't contains a specific string using -v option. But i don't know how to do this with different lines.
grep is really a line-oriented tool. It might be possible to achieve what you want with it, but it's easier to use Awk:
awk '
/xyz/ && !skip { print }
{ skip = /jkl/ }
' file
Read as: for every line, do
if the current line matches xyz and we haven't just seen jkl, print it;
set the variable skip to indicate whether we've just seen jkl.
sed '/jkl/{N;d}; /xyz/!d'
If find jkl, remove that line and next
print only remaining lines with xyz
I think you're better off using an actual programming language, even a simple one like Bash or AWK or sed. For example, using Bash:
(
previous_line_matched=
while IFS= read -r line ; do
if [[ ! "$previous_line_matched" && "$line" == *xyz* ]] ; then
echo "$line"
fi
if [[ "$line" == *jkl* ]] ; then
previous_line_matched=1
else
previous_line_matched=
fi
done < input_file
)
Or, more tersely, using Perl:
perl -ne 'print if m/xyz/ && ! $skip; $skip = m/jkl/' < input_file