Suppose I have the file "FILE_${RUNDATE}_0957_PROD.csv" to check if it doesn't exist, it must bypass the IF statement. If I setenv the variable $FILENAME with the full name it works with the code below, but using the '*' reg-ex ("0957" represents a timestamp which I don't know the exact value) it enters into the IF statement.
#!/bin/csh -f
set RUNDATE = `date +'%Y%m%d'`
setenv FILENAME "DATA_${RUNDATE}_*_PROD.csv"
if ( ! -eq "$FILENAME" ) then
/bin/echo "File NOT Found Locally! \n"
endif
Related
Let's pretend I'm running something like this:
jq -nr --arg target /tmp \
'(["echo","Hello, world"]|#sh)+">\($target)/sample.txt"' \
| sh
Everything is fine unless I forgot to pass variable $target:
$ jq -nr '(["echo","Hello, world"]|#sh)+">\($target)/sample.txt"'
jq: error: $target is not defined at <top-level>, line 1:
(["echo","Hello, world"]|#sh)+">\($target)/sample.txt"
jq: 1 compile error
How can I catch this and use default value?
I've tried:
$target?
($target)?
try $target catch null
$target? // null
But it seems to be parsing-time error, which obviously can't be caught at runtime. Have I've missed any dynamic syntax?
I've found that command-line arguments can be found in $ARGS.name, but there are two drawbacks:
This was introduced in version 1.6, but I have 1.5 on CentOS 7.
It doesn't catch locally defined variables.
Assuming you need to do something more useful with jq than write 'Hello World' over a text file. I propose the following,
Maybe we can learn some programming tips from Jesus:
"Give to Caesar what belongs to Caesar, and give to God what belongs to God"
Suppose that Caesar is bash shell and God is jq, bash is appropriate to work and test the existence of files, directories and environment variables, jq is appropriate to process information in json format.
#!/bin/bash
dest_folder=$1
#if param1 is not given, then the default is /tmp:
if [ -z $dest_folder ]; then dest_folder=/tmp ; fi
echo destination folder: $dest_folder
#check if destination folder exists
if [ ! -d $dest_folder ]
then
echo "_err_ folder not found"
exit 1
fi
jq -nr --arg target $dest_folder '(["echo","Hello, world"]|#sh)+">\($target)/sample.txt"' | sh
#if the file is succesfully created, return 0, if not return 1
if [ -e "$dest_folder/sample.txt" ]
then
echo "_suc_ file was created ok"
exit 0
else
echo "_err_ when creating file"
exit 1
fi
Now you can include this script as a step in a more complex batch, because it is congruent with linux style, returning 0 on success.
I am attempting to make a script that will check to see if there is any tyext within a file. I have developed the following script. I have made it check to see if there is exactly 2 arguments, see if the file exists, but I am having trouble checking the file for text within it. The code is as follows:
#!/bin/ksh
#check if number of arguments are 2
if [ $# -ne 2 ]; then
echo "Does not equal two arguments"
echo "Usage $0 inputfile outputfile"
exit 1
fi
#check if input file exists
if [ ! -f $1 ]; then
echo "$1 not found!"
exit 1
fi
#Check if input file is null
#This next block of code is where the issue is
if [ grep -q $1 -eq 0 ]; then
echo "$1 must have text within the file"
exit 1
fi
Any help would be appreciated
test's "-s" option checks if the file is empty -- see manual. So your last chunk would become
#Check if input file is null
#This next block of code is where the issue is
if [ ! -s $1 ]; then
echo "$1 must have text within the file"
exit 1
fi
Try using stat
stat -c %s filename
i want to set the value of inputLineNumber to 20. I tried checking if no value is given by user by [[-z "$inputLineNumber"]] and then setting the value by inputLineNumber=20. The code gives this message ./t.sh: [-z: not found as message on the console. How to resolve this? Here's my full script as well.
#!/bin/sh
cat /dev/null>copy.txt
echo "Please enter the sentence you want to search:"
read "inputVar"
echo "Please enter the name of the file in which you want to search:"
read "inputFileName"
echo "Please enter the number of lines you want to copy:"
read "inputLineNumber"
[[-z "$inputLineNumber"]] || inputLineNumber=20
for N in `grep -n $inputVar $inputFileName | cut -d ":" -f1`
do
LIMIT=`expr $N + $inputLineNumber`
sed -n $N,${LIMIT}p $inputFileName >> copy.txt
echo "-----------------------" >> copy.txt
done
cat copy.txt
Changed the script after suggestion from #Kevin. Now the error message ./t.sh: syntax error at line 11: `$' unexpected
#!/bin/sh
truncate copy.txt
echo "Please enter the sentence you want to search:"
read inputVar
echo "Please enter the name of the file in which you want to search:"
read inputFileName
echo Please enter the number of lines you want to copy:
read inputLineNumber
[ -z "$inputLineNumber" ] || inputLineNumber=20
for N in $(grep -n $inputVar $inputFileName | cut -d ":" -f1)
do
LIMIT=$((N+inputLineNumber))
sed -n $N,${LIMIT}p $inputFileName >> copy.txt
echo "-----------------------" >> copy.txt
done
cat copy.txt
Try changing this line from:
[[-z "$inputLineNumber"]] || inputLineNumber=20
To this:
if [[ -z "$inputLineNumber" ]]; then
inputLineNumber=20
fi
Hope this helps.
Where to start...
You are running as /bin/sh but trying to use [[. [[ is a bash command that sh does not recognize. Either change the shebang to /bin/bash (preferred) or use [ instead.
You do not have a space between [[-z. That causes bash to read it as a command named [[-z, which clearly doesn't exist. You need [[ -z $inputLineNumber ]] (note the space at the end too). Quoting within [[ doesn't matter, but if you change to [ (see above), you will need to keep the quotes.
Your code says [[-z but your error says [-z. Pick one.
Use $(...) instead of `...`. The backticks are deprecated, and $() handles quoting appropriately.
You don't need to cat /dev/null >copy.txt, certainly not twice without writing to it in-between. Use truncate copy.txt or just plain >copy.txt.
You seem to have inconsistent quoting. Quote or escape (\x) anything with special characters (~, `, !, #, $, &, *, ^, (), [], \, <, >, ?, ', ", ;) or whitespace and any variable that could have whitespace. You don't need to quote string literals with no special characters (e.g. ":").
Instead of LIMIT=`expr...`, use limit=$((N+inputLineNumber)).
why in Cygwin Terminal - the if statement work
and ubuntu - unix - not working for
this code :
#!/bin/sh
valid_password="pass"
echo "Please enter the password:"
read password
if [ "$password" == "$valid_password" ]
then
echo "You have access!"
else
echo "Access denied!"
fi
#emil pointed the answer:
if [ "$password" = "$valid_password" ]
instead of
if [ "$password" == "$valid_password" ]
Also: did you give the script executing permissions? Try
chmod +x script_name
because the correct syntax to [ is:
[ a = b ]
From your error message it sounds like you wrote:
if ["$password" = "$valid_password" ]
change this to:
if [ "$password" = "$valid_password" ]
notice the space after [. if just takes a shell command, try to run it and depending if the exit code from the program is 0 it will run the commands inside the if statement.
In your terminal, write i.e.:
user#localhost$ true; echo $?
0
to test your if statement:
user#localhost$ pass=pass; valid=pass
user#localhost$ if [ "$pass" = "$valid" ]; then echo 'You have access!'; fi
As #nullrevolution said, the ! is evaluated if you use double quotes, it will try to run last command in your shell history, in this case that is matching u.
user#localhost$ uname
Linux
user#localhost$ !u
uname
Linux
user#localhost$ echo "!"
sh: !: event not found
This is because the ! is evaluated before the double quotes are matched, and echo is run. If you still want to use double quotes, you will have to escape the ! outside the quotes:
echo "Access denied"\!
#nullrevolution also said you could try with bash, which has a builtin syntax for the expression inside if statements.
#!/bin/bash
valid_password=pass
echo "Please enter the password:"
read password
if [[ "$password" == "$valid_password" ]]; then
echo 'You have access!'
else
echo 'Access denied!'
fi
Also in your program I guess you do not want to echo the password in the terminal, to turn off echo temporary change:
read password
to
stty -echo
read password
stty echo
if you forgot to write stty echo to turn on echo again, just write reset in your terminal, and it will reset the terminal to default settings.
A useful tutorial for bourn shell script can be found here:
http://www.grymoire.com/Unix/Sh.html
I have a script that has a string in a file name like so:
filename_with_spaces="a file with spaces"
echo test > "$filename_with_spaces"
test_expect_success "test1: filename with spaces" "
run cat \"$filename_with_spaces\"
run grep test \"$filename_with_spaces\"
"
test_expect_success is defined as:
test_expect_success () {
echo "expecting success: $1"
eval "$2"
}
and run is defined as:
#!/bin/zsh
# make nice filename removing special characters, replace space with _
filename=`echo $# | tr ' ' _ | tr -cd 'a-zA-Z0-9_.'`.run
echo "#!/bin/zsh" > $filename
print "$#" >> $filename
chmod +x $filename
./$filename
But when I run the toplevel script test_expect_success... I get cat_a_file_with_spaces.run with:
#!/bin/zsh
cat a file with spaces
The problem is the quotes around a file with spaces in cat_a_file_with_spaces.run is missing. How do you get Z shell to keep the correct quoting?
Thanks
Try
run cat ${(q)filename_with_spaces}
. It is what (q) modifier was written for. Same for run script:
echo -E ${(q)#} >> $filename
. And it is not bash, you don't need to put quotes around variables: unless you specify some option (don't remember which exactly)
command $var
always passes exactly one argument to command no matter what is in $var. To ensure that some zsh option will not alter the behavior, put
emulate -L zsh
at the top of every script.
Note that initial variant (run cat \"$filename_with_spaces\") is not a correct quoting: filename may contain any character except NULL and / used for separating directories. ${(q)} takes care about it.
Update: I would have written test_expect_success function in the following fashion:
function test_expect_success()
{
emulate -L zsh
echo "Expecting success: $1" ; shift
$#
}
Usage:
test_expect_success "Message" run cat $filename_with_spaces