is there any way in robot framework that 1297395061.06 value can be evaluated whether it's in Million, or Billion or in Thousand.
if its in Billion should get as a result 1.30B
You should use the BuiltIn keywords like this
${var}= convert to number 1297395061.06
${b}= evaluate ${var}/100000000
${c} convert to integer ${b}
In this case, ${c} would get the value 12
Related
I am new to Pentaho, so please be gentle.
I am, perhaps naively, wanting to use a Formula to convert a six-character string in the form YYYYMM to the date representing the final day of that month.
I imagine doing this step by step using successive lines of the Formula: checking that the string is of the correct length and, if so:
extracting the year and converting it to integer (with error checking)
extracting the month and converting it to integer (also with error checking)
converting ([year], [month], 1) to a date (the first of the month)
adding a month
subtracting a day
Some of those steps may be combined but, overall, it relies on a succession of steps to achieve a final result.
Formula does not seem to recognise the values achieved along the way though, at least not by enclosing them in square brackets as you do with fields from previous objects in the mapping.
I suppose I could have a series of Formula objects one after the other in the mapping but that seems untidy and inefficient. If a single Formula object cannot have a series of values defined on successive lines, what is the point of even having lines? How do I use a value I have defined on a previous line?
The formula step isn’t the best way to achieve that. The resulting formula will be hard to read and quite cumbersome.
It’s better (and faster) to use a calculator step. A javascript step can also be used, and it will be easier to read, but slower (though that probably won't be a major issue).
So, one way forward is to implement this on a calculator step:
Create a copy of your string field as a Date
Create 2 constant fields: 1 and -1
Add 1 month to the date field
Subtract 1 day to the result
Create a copy of the result as a string.
See screenshot:
I tried using xdmp:random(999999) but it sometimes generates a 5 digit value and sometimes a 6 digit value - Is there any way of getting the every time unique 6 digit value?
Simplest is to pad with zeros using fn:format-number:
format-number(xdmp:random(999999), '000000')
Alternatively, you could also look at sem:uuid-string, which gives better random results with a fixed string-length.
HTH!
If leading zeroes don’t work, make sure your base value is 100,000 and go up to 999,999.
xdmp:random(899999) + 100000
Why this ("Filter" in jqplay.org):
{"key":633447818234478180}
returns this ("Result" in jqplay.org):
{"key": 633447818234478200}
Original JSON doesn't matter.
Why is it changing 180 into 200? How can I overcome this? Is this a bug? A number too big?
I believe this is because jq can only represent legal JSON data and the number you've given is outside the range that can be represented without loss of precision. See also
What is JavaScript's highest integer value that a number can go to without losing precision?
If you need to work with larger numbers as strings in jq you may want to try this library:
jq-bigintA big integer library for working with possibly-signed arbitrarily long decimal strings. Written by Peter Koppstein (#pkoppstein) and released under the MIT license.
I need to modify number which is having more than 5 digits.LENGTH function is for string but not for number of digits.What should be done to count the digits in a number?
select length(to_char(11111)) from dual
Output 5
length is fine, with an implicit or explicit to_char() to convert the number to a string whose characters can then be counted, as OldProgrammer showed.
If you want to treat it as a number you could also do:
trunc(1/log(n, 10)) + 1
... which works for integers above 2. But that's going to be rather less intuitive for someone trying to maintain your code later...
When not just keep things simple?
CASE WHEN mynumber >= 100000 THEN whatever;
I have an ASP page where I have 2 variables, strActualRate and strProposed.
The values are:
strActualRate = 33.30
strProposed = 33.3
So when I write the following line to compare:
if strActualRate <> strProposed then
Response.Writr "Both are not equal!"
end if
I am getting the output "Both are not equal", even though both are the same.
I am sure that I need to use some mathematical conversion function to compare.
Can anyone tell me how to solve this ?
Thanks in advance!
If I understand correctly, you think the two values are equal but because VBScript is comparing strings rather than numbers the two are coming back as not equal.
You're correct in the conversion idea, and here's the code:
if CDbl(strActualRate) <> CDbl(strProposed) then
Response.Write "Both are not equal!"
end if
That will convert your string values to numbers to do the comparison.
Your question doesn't really add up, so I'm not really sure what the problem is. I will try to clear up some things about data types and comparison.
You are using the prefix "str" for your variables which suggests that you intend to store string values in them, however you are instead storing numeric values in them. Either you are confused about how hungarian notation is used to keep track of the data type, or the code that you posted does not look like the code that you are actually using.
The numeric value 33.30 is exactly the same as the value 33.3. If you instead would have used the string values "33.30" and "33.3", they would be two strings that are not equal.
If your code is corrected (Response.Write instead of Response.Writr) so that it runs, it will not produce any output at all. As the values are equal, the condifion in the if statement evaluates to false.
If you do in fact assign string values to the variables, the code would output "Both are not equal!". This is just as expected as the strings are not equal. If you have strings and want to compare them as numerical values, you have to comvert them:
If CDbl(strActualRate) <> CDbl(strProposed) Then
Response.Write "Both are not equal!"
End If
Try casting the values to a double in the comparison statement with CDbl()
Are you intending to perform the comparison as strings, floating point numbers or some other method? If you are comparing them as strings, then clearly they are not equal, as one of them has an extra zero on the end. If you are comparing them as floating point numbers, then you generally want to use a comparison that involves taking the difference and checking that it is smaller than some small value. This is because floating point number calculations involve some degree of inaccuracy and comparisons between them can fail because of the underlying representation.