Initalizing 0 UTC Time generates a negative time when printed - datetime

Question

In the provided code snippet the t2 time initialized explicitly to 0 UTC is negative when printed.
I don't understand why that is, could someone explain it for me?
func main() {
const IsoDatetimeFormat = "2006-01-02T15:04:05"
t1 := time.Time{}
t2 := time.Date(0, 0, 0, 0, 0, 0, 0, time.UTC)
fmt.Println(t1.Format(IsoDatetimeFormat))
fmt.Println(t2.Format(IsoDatetimeFormat))
}
Output:
0001-01-01T00:00:00
-0001-11-30T00:00:00
playground link

Answer 1

time.Time documents that the zero value for time.Time represents / means January 1, year 1, 00:00:00.000000000 UTC:
The zero value of type Time is January 1, year 1, 00:00:00.000000000 UTC. As this time is unlikely to come up in practice, the IsZero method gives a simple way of detecting a time that has not been initialized explicitly.
There is no year 0, so if you use year, month and day values smaller than 1, they will roll over to negative. The time package accepts and normalizes values given outside of valid ranges. Quoting from time.Date():
The month, day, hour, min, sec, and nsec values may be outside their usual ranges and will be normalized during the conversion. For example, October 32 converts to November 1.
The zero value to be January 1, year 1 was an arbitrary choice. As to reasoning why year 1 was chosen:
// The zero value for a Time is defined to be
// January 1, year 1, 00:00:00.000000000 UTC
// which (1) looks like a zero, or as close as you can get in a date
// (1-1-1 00:00:00 UTC), (2) is unlikely enough to arise in practice to
// be a suitable "not set" sentinel, unlike Jan 1 1970, and (3) has a
// non-negative year even in time zones west of UTC, unlike 1-1-0
// 00:00:00 UTC, which would be 12-31-(-1) 19:00:00 in New York.