let currentDate = moment();
let weekStart = currentDate.clone().startOf('week');
let weekEnd = currentDate.clone().endOf('week');
I want to know the start date and end date of every week for a given month.
expected output
In August month
In Array of object
1. 1 Aug 2021 - 7 Aug 2021
2. 8 Aug 2021 - 14 Aug 2021
3. 15 Aug 2021 - 21 Aug 2021
4. 22 Aug 2021 - 28 Aug 2021
5. 29 Aug 2021 - 31 Aug 2021
moment().startOf('week');
moment().endOf('week');
Refrence:
https://www.itsolutionstuff.com/post/moment-js-get-current-week-start-and-end-date-exampleexample.html
Related
I have a date column that looks like this:
Dates
Sun Jan 30 04:00:35 UTC 2022
Thu Sep 02 20:21:52 UTC 2021
Tue Sep 20 14:41:17 UTC 2022
Thu Apr 08 16:19:21 UTC 2021
Wed Nov 03 16:20:45 UTC 2021
I was trying the following method but cannot figure out how to get ride of the Hour,minute, seconds and the two ":". In the end I just want to have the month (preferably in a 1-12 format), day and year.
mutate(last_login_date = gsub("UTC","",Dates),
last_login_date = substr(Dates,5,25))
It may be easier to automatically convert to Date class with parse_date from parsedate
library(parsedate)
df1$Dates <- as.Date(parse_date(df1$Dates))
This question already has answers here:
How to loop through dates using Bash?
(10 answers)
Closed 1 year ago.
How can I write a shell scripts that calls another script for each day
i.e currently have
#!/bin/sh
./update.sh 2020 02 01
./update.sh 2020 02 02
./update.sh 2020 02 03
but I want to just specify start date (2020 02 01) and let is run update.sh for every day upto current date, but don't know how to manipulate date in shell script.
I made a stab at it, but rather messy, would prefer if it could process date itself.
#!/bin/bash
for j in {4..9}
do
for k in {1..9}
do
echo "update.sh" 2020 0$j 0$k
./update.sh 2020 0$j 0$k
done
done
for j in {10..12}
do
for k in {10..31}
do
echo "update.sh" 2020 $j $k
./update.sh 2020 $j $k
done
done
for j in {1..9}
do
for k in {1..9}
do
echo "update.sh" 2021 0$j 0$k
./update.sh 2021 0$j 0$k
done
done
for j in {1..9}
do
for k in {10..31}
do
echo "update.sh" 2021 0$j $k
./update.sh 2021 0$j $k
done
done
You can use date to convert your input dates into seconds in order to compare. Also use date to add one day.
#!/bin/bash
start_date=$(date -I -d "$1") # Input in format yyyy-mm-dd
end_date=$(date -I) # Today in format yyyy-mm-dd
echo "Start: $start_date"
echo "Today: $end_date"
d=$start_date # In case you want start_date for later?
end_d=$(date -d "$end_date" +%s) # End date in seconds
while [ $(date -d "$d" +%s) -le $end_d ]; do # Check dates in seconds
# Replace `echo` in the below with your command/script
echo ${d//-/ } # Output the date but replace - with [space]
d=$(date -I -d "$d + 1 day") # Next day
done
In this example, I use echo but replace this with the path to your update.sh.
Sample output:
[user#server:~]$ ./dateloop.sh 2021-08-29
Start: 2021-08-29
End : 2021-09-20
2021 08 29
2021 08 30
2021 08 31
2021 09 01
2021 09 02
2021 09 03
2021 09 04
2021 09 05
2021 09 06
2021 09 07
2021 09 08
2021 09 09
2021 09 10
2021 09 11
2021 09 12
2021 09 13
2021 09 14
2021 09 15
2021 09 16
2021 09 17
2021 09 18
2021 09 19
2021 09 20
I am trying to create a rrule for my fullcalendar event, that occur on the 2nd Monday, Wednesday and Friday of the month for every month.
Here is the rrule I have tried
RRULE:FREQ=MONTHLY;COUNT=10;INTERVAL=1;WKST=SU;BYDAY=MO,WE,FR;BYSETPOS=2
events: [{
title: 'rrule event',
rrule: {
freq: RRule.MONTHLY,
count: 10,
interval: 1,
wkst: RRule.SU,
byweekday: [RRule.MO, RRule.WE, RRule.FR],
bysetpos: [2]
},
duration: '02:00',
rendering: 'inverse-background'
}
],
This is what I get
1 Fri, 03 May 2019 12:33:53 GMT
2 Wed, 05 Jun 2019 12:33:53 GMT
3 Wed, 03 Jul 2019 12:33:53 GMT
4 Mon, 05 Aug 2019 12:33:53 GMT
5 Wed, 04 Sep 2019 12:33:53 GMT
6 Fri, 04 Oct 2019 12:33:53 GMT
7 Mon, 04 Nov 2019 12:33:53 GMT
8 Wed, 04 Dec 2019 12:33:53 GMT
9 Fri, 03 Jan 2020 12:33:53 GMT
10 Wed, 05 Feb 2020 12:33:53 GMT
What is expected is
1 Mon, 08 Apr 2019
2 Wed, 10 Apr 2019
3 Fri, 12 Apr 2019
4 Mon, 13 May 2019
5 Wed, 08 May 2019
6 Fri, 10 May 2019.........
RFC 5545, section 3.3.10. states:
Each BYDAY value can also be preceded by a positive (+n) or
negative (-n) integer. If present, this indicates the nth
occurrence of a specific day within the MONTHLY or YEARLY "RRULE".
So the rule you're looking for literally specifies the 2nd Monday (2MO), Wednesday (2WE) and Friday (2FR) of each month.
FREQ=MONTHLY;COUNT=10;BYDAY=2MO,2WE,2FR
(click to see the results)
Note that INTERVAL=1 is the default and WKST=SU is meaningless in this case, so you can just as well omit them.
Btw, your rule basically says, of all Mondays, Wednesdays and Fridays of a month, take the second instance in that month.
I have the following 2 columns as part of a larger data frame. The Timezone_Offset is the difference in hours for the local time (US West Coast in the data I'm looking at). In other words, UTC + Offset = Local Time.
I'm looking to convert the UTC time to the local time, while also correctly changing the day of the week and date, if necessary. For instance, here are the first 5 rows of the two columns.
UTC Timezone_Offset
Sun Apr 08 02:42:03 +0000 2012 -7
Sun Jul 01 03:27:20 +0000 2012 -7
Wed Jul 11 04:40:18 +0000 2012 -7
Sat Nov 17 01:31:36 +0000 2012 -8
Sun Apr 08 20:50:30 +0000 2012 -7
Things get tricky when the day of the week and date also have to be changed. For instance, looking at the first row, the local time should be Sat Apr 07 19:42:03 +0000 2012. In the second row, the month also has to be changed.
Sorry, I'm fairly new to R. Could someone possibly explain how to do this? Thank you so much in advance.
Parse as UTC, then apply the offset in seconds, ie times 60*60 :
data <- read.csv(text="UTC, Timezone_Offset
Sun Apr 08 02:42:03 +0000 2012, -7
Sun Jul 01 03:27:20 +0000 2012, -7
Wed Jul 11 04:40:18 +0000 2012, -7
Sat Nov 17 01:31:36 +0000 2012, -8
Sun Apr 08 20:50:30 +0000 2012, -7", stringsAsFactors=FALSE)
data$pt <- as.POSIXct(strptime(data$UTC, "%a %b %d %H:%M:%S %z %Y", tz="UTC"))
data$local <- data$pt + data$Timezone_Offset*60*60
Result:
> data[,3:4]
pt local
1 2012-04-08 02:42:03 2012-04-07 19:42:03
2 2012-07-01 03:27:20 2012-06-30 20:27:20
3 2012-07-11 04:40:18 2012-07-10 21:40:18
4 2012-11-17 01:31:36 2012-11-16 17:31:36
5 2012-04-08 20:50:30 2012-04-08 13:50:30
>
In RadScheduler [TimeLine View], I have a StartDate = 1st Jan 2014 and EndDate = 30th April 2014 [both inclusive] and I have set the SlotDuration = 31 days.
I need to display 4 (January, February, March, April) slots [i.e. Number Of Slots = no of months between StartDate and EndDate taking above Dates into consideration] in TimeLine View and SlotDuration for each slot needs to be no. of days present in that month.
For January, SlotDuration = 31 [because January has 31 days]
February, SlotDuration = 28 [because February has 28 days or 29 if it's a Leap Year]
March, SlotDuration = 31 [because March has 31 days]
April, SlotDuration = 30 [because April has 30 days]
Case 1:
When I plot an appointment from 1 March 2014 to 31 March 2014, it should start and end in March slot but it starts from February slot because we have set SlotDuration = 31 days and February 2014 has only 28 days.
To fulfill 31 days slot duration, 1st, 2nd and 3rd of March are pushed to February 2014 slot.
Case 2:
When I plot an appointment from 4 March 2014 to 31 March 2014 it starts from March slot which is correct. But March slot also contains 1st, 2nd, and 3rd of April to fulfill 31 days slot duration.
My question is how do I make SlotDuration dynamic for each slot?
Currently, For Case 1 RadScheduler displays my appointment like in TimeLineMonth_Incorrect.png but i want to display it as in TimeLineMonth_Correct.png