How can I change PATH variable in zsh? - zsh

I want to change my PATH variable in zsh.
Problem: I don't understand where in the .zshrc file I have to make modifications.
Normally, I would look for the assignment to the PATH variable and set the values from scratch how I would like them to be (leaving all the systems binaries directories untouched).
The first lines in my .zshrc file are as follows:
# If you come from bash you might have to change your $PATH.
# export PATH=$HOME/bin:/usr/local/bin:$PATH
# Path to your oh-my-zsh installation.
export ZSH="/Users/Sam/oh-my-zsh"
export PATH=$PATH:/Applications/Postgres.app/Contents/Versions/13/bin
etc.
My actual PATH variable is:
/Library/Frameworks/Python.framework/Versions/3.9/bin:/Library/Frameworks/Python.framework/Versions/3.8/bin:/usr/local/bin:/usr/bin:/bin:/usr/sbin:/sbin:/Applications/Postgres.app/Contents/Versions/13/bin
I want to delete the directory where python3.8 is in, it's redundant.
My questions:
Do I have to change line 2 or line 7 in my .zshrc file?
Line 2 is commented out...is it executed anyway at the start of the terminal?
I have tried to comment out line 7. But the postgres directory still remained in my PATH variable which I don't understand.

The .zshrc is located in the home dir. The dot at the beginning keeps it hidden. Type ls -a from ~ directory to see it. To edit just run vim, nvim, etc as usual.
nvim ~/.zshrc
This is the command for Neovim. For your editor, sub nvim for the proper command.
Once you get in, you need only add the same export command that you would add from the command line.
export PATH=$PATH:/whatever/you/are/adding
EDIT
To remove a path variable:
First, run the command:
echo $PATH
from the command line.
Next, Copy the output to clipboard.
Finally, at the very end of the .zshrc file, add the following:
export PATH=<paste-what-you-copied-here>
Because you didn't reference $PATH after the =, this will set the path to EXACTLY what you pasted, no more, no less. Adding $PATH: as in the first example will just add whatever to the end of what is already there.
Since this gives you access to every item in the path array, deleting is just a matter of a literal highlight/select and of whatever you want deleted.
Finally, be sure that there is only one place in the file where you are editing PATH. If there are more than one, the result can be confusing to say the least.
That said, I believe the script runs top-to-bottom, so only the last mention should persist. You can take advantage of this in some situations, but for this purpose, one will suffice. XD

Be careful when you decide to fiddle with the PATH in .zshrc: Since the file is processed by every interactive subshell, the PATH would get longer and longer for each subshell, with the same directory occuring in it several times. This can become a nightmare if you later try to hunt down PATH-related errors.
Since you are using zsh, you can take advantage that the scalar variable PATH is mirrored in the array variable path, and that you can ask zsh to keep entries in arrays unique.
Hence, the first thing I would do is put a
typeset -aU path
in your .zshrc; this (due to mirroring) also keeps the entries in PATH unique. You can put this statement anywhere, but I have it for easier maintenance before my first assignment to PATH or path.
It is up to you to decide where exactly you add a new entry to PATH or path. The entries are searched in that order which is listed in the variable. You have to ask yourself two questions:
Are some directories located on a network share, where you can sometimes expect access delays (due to bad network conditions)? Those directories should better show up near the end of the path.
Do you have commands which occur in more than one directoryin your path? In this case, a path search will always find the first occurance only.
Finally, don't forget that your changes will be seen after zsh processes the file. Therefore, you could create a new subshell after having edited the file, or source .zshrc manually.

Related

How get zsh prompt of form: [working-directory] # under macOS

In macOS Catalina (10.15.6), I want to use zsh for Terminal sessions. Formerly I had been using the default bash. For bash, I had a .profile containing the line
export PS1="[\u#\h:\w]$ "
which gave a prompt of the form:
[me#myhost:current-dir]$
I want something similar for zsh, but without the user-name#host-name prefix and with # instead of $ for the actual prompt.
In a zsh Terminal session, the command
PROMPT='[%/]%% '
gives the expected prompt, with the current directory enclosed in square brackets.
Of course I don't want to enter that manually each time. Instead, I want to set this in .zprofile. So in .zprofile I included the line
export PROMPT='[%/]%% '
However, that does not work as expected -- the prompt now has the form:
me#myhost current-dir %
Question: How can I get the zsh prompt to have the desired form as follows?
[current-dir] %
Just add the following export to ~/.zshrc, otherwise it won't work.
export PROMPT='[%1~] %%'
That will give you the following, my directory name is test-workflow-branch-only
[test-workflow-branch-only] %
NOTE: This will give you [~] % when in ~/ directory so don't be alarmed when you see that
UPDATE - per comment questions
We add it to ~/.zshrc as this file gets sourced in all interactive shell configurations. The file ~/.zprofile are for commands that we want to execute when we log in, therefore a non-login shell won't source this file.
Thanks for info from Edward Romero. My critique of answer is that it contains four wasted characters, '[',']',' ','%'. Using instead PROMPT='%d>' yields the nice clear absolute path, something like this:
/Users/myuser/test-workflow-branch-only>
In any case, nice to get this headache behind me, and begin reaping the wonderful benefits of using zsh, whatever they may be.

Finding and Replacing a filename in a css File with Bash script

I want to write a bash script that takes a user input (which will be a filename) and replaces a path to a file inside a css file with that filename. For simplicity, the two files will be in the same folder and in the css code only the filename at the end of the path should be changed.
I thought of using regex to match any line of code that has a specific pattern and then change the end of it. I know about sed, but since the filename always changes I'm not sure how to solve this problem other than regex. I also thought of adding a variable in the css file that holds the filename as a value and then adding that variable at the end of the path, but I'm not sure then how to access that variable from a bash script.
Any recommendations on how to tackle this problem?
Thanks!
Edit Adding more Information:
Here is the line in the css file I want to edit. The part to be changed is the fileName.png at the end. Since it will change I thought of using a regex to "find" the correct spot in the css file.
background: #2c001e url(file:////usr/share/backgrounds/fileName.png/);
A regex matching only this line in this specific file is the following. It could probably be simplified, but I don't see a reason why since it should work too:)
(background)\:\s\#.{6}\s(url)\((file)\:\/{4}(usr)\/(share)\/backgrounds\/.+\.(png)\/\)\;
So, there are some ways to do that. You can check topic in links below. sed command is also good idea. But before executing it, you can build a new variable (or multiple variables) to use them in regex sed -e syntax.
Getting the last argument passed to a shell script
Maybe, if you will add some input and output examples, I could be more specific in this case.
To replace the input in the file at run-time you could use this line in a script
sed "s/stringToReplace/$1/g" templateFile >fileToUse
the $1 is referencing the 2nd bash script argument (the first being $0, the name of the invoking script). stringToReplace would be written in verbatim in the templateFile.
You could also use a script with two runtime arguments ($1, $2), and you would change the original contents of the fileToUse using the -i option. But this requires storage of the last file path to be used as argument $1.

How to get absolute path on a zsh prompt?

I'm switching from bash to zsh.
I want to update my new zsh prompt and looked around to find a way, but I have only found "solutions" via oh-my-zsh.
The goal:
Location: ~/dir_1/dir_1_1/dir_1_1_1
What I have:
Location: dir_1_1_1
The code (source):
PS1='${SSH_CONNECTION+"%{$fg_bold[green]%}%n#%m:"}%{$fg_bold[green]%}Location: %c%{$reset_color%}$(git_prompt_info) '
To preserve original prompt format (colors, git info and potentially other customisations before this one) except related to path info, you could append following to the end of ~/.zshrc:
PROMPT=${PROMPT/\%c/\%~}
As pointed out by #caleb-adams and #fend25 the key is replacing %c (just folder name) with %~ to include full path (or absolute from $HOME when under ~). See http://zsh.sourceforge.net/Doc/Release/Prompt-Expansion.html for more info
As Horacio Chavez mentioned in the comment above, you want to look here: http://zsh.sourceforge.net/Doc/Release/Prompt-Expansion.html for the details on how to change your displayed path in zsh.
In this case if you are looking for a path that is relative to your home folder, include a %~ in your zsh-theme file. Your prompt would now look like this:
PS1='${SSH_CONNECTION+"%{$fg_bold[green]%}%n#%m:"}%{$fg_bold[green]%}Location: %~%{$reset_color%}$(git_prompt_info) '
note, I only changed one character in your prompt. the %c was swapped for the %~. %c will only give your current directory (see the document link above, or here)
For a full path you could use %/
Simplest way to add bash-style dir path to the prompt. Just add this to ~/.zshrc:
setopt PROMPT_SUBST
PROMPT='%n#%m: ${(%):-%~} '
The part with the path is ${(%):-%~}. Colouring could be added according with your lifestyle:)

Setting path in bash_profile

Why does setting a PATH require the :${PATH} at the end?
PATH="/Library/Frameworks/Python.framework/Versions/2.7/bin:${PATH}"
When I append a path to this I would do
PATH=$PATH:...
How do I append a PATH without going to a new line. That is, how would I append a PATH to the original PATH statement.
If I wanted to put the following all in the first line, for instance. How does this interact with the :${PATH} part?
PATH=$PATH:/usr/local/mysql/bin
There's a difference between appending an existing path to the front or the end of the $PATH environment variable. The way bash resolves execution paths is by starting from the front of the list. That means if you have these two directories in your path:
PATH="/dir1/bin:/dir2/bin"
And they both have the executable test.sh in it, then when you run test.sh, it'll execute the one in /dir1/bin/test.sh since that directory appears first in the path.
Additionally, ${PATH} is the same as $PATH.
PATH="/Library/Frameworks/Python.framework/Versions/2.7/bin:${PATH}"
is simply adding /Library/Frameworks/Python.framework/Versions/2.7/bin to the front of the path and
PATH=$PATH:/usr/local/mysql/bin
is simply adding /usr/local/mysql/bin to the end of the path.
So how do you do both in one line? Something like this:
PATH="/Library/Frameworks/Python.framework/Versions/2.7/bin:${PATH}:/usr/local/mysql/bin"

Change to xth directory terminal

Is there a way in a unix shell (specifically Ubuntu) to change directory into the xth directory that was printed from the ls command?
I know you can sort a directory in multiple ways, but using the output from ls to get the xth directory?
An example shell:
$ ls
$ first_dir second_dir third_really_long_and_complex_dir
where I want to move into the third_really_long_and_complex_dir by passing 3 (or 2 in proper array format).
I know I could simply copy and paste, but if I'm already using the keyboard, it would be easier to type something like "cdls 2" or something like that if I knew the index.
The main problem with cd in an interactive session is that you generally want to change the current directory of the shell that is processing the command prompt. That means that launching a sub-shell (e.g. a script) would not help, since any cd calls would not affect the parent shell.
Depending on which shell you are using, however, you might be able to define a function to do this. For example in bash:
function cdls() {
# Save the current state of the nullglob option
SHOPT=`shopt -p nullglob`
# Make sure that */ expands to nothing when no directories are present
shopt -s nullglob
# Get a list of directories
DIRS=(*/)
# Restore the nullblob option state
$SHOPT
# cd using a zero-based index
cd "${DIRS[$1]}"
}
Note that in this example I absolutely refuse to parse the output of ls, for a number of reasons. Instead I let the shell itself retrieve a list of directories (or links to directories)...
That said, I suspect that using this function (or anything to this effect) is a very good way to set yourself up for an enormous mess - like using rm after changing to the wrong directory. File-name auto-completion is dangerous enough already, without forcing yourself to count...

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